This is most definitely a physiological hazard

please help im dying

This is the answer hope you get it:)

1. According to Newton's third law of motion, how are action

and reaction forces related?

2. How is momentum conserved?

3. Suppose you and a friend, who has exactly twice your mass,

are on skates. You push away from your friend. How does the

force with which you push your friend compare to the force

with which your friend

pushes you? How do your

accelerations compare?

4. Thinking Critical be ly comparing and Contrasting

Which has more momentum, a 250-kg dolphin swimming

at 6 m/s, or a 450-kg manatee swimming at 2 m/s?

(need 1-4 answered ASAP)

**Answer:**

you couldn't do this on your own or search it up on google

Find the resultant of an easterly force of 100 N and a southeast force of 80 N acting at 65 degrees to the 100 N force

**Answer:**

Resultant is 152 N at 28.5 degrees south to the 100 N force

**Explanation:**

Which event is an example of condensation?

A. Wet clothes are drying on a clothesline.

B. A mirror fogs up when someone takes a hot shower.

C. Water drips from an icicle on the edge of a roof.

O D. Rain turns to sleet as it nears the ground.

**Answer:**

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of **gaseous water** to its liquid form is called condensation. The **fogs** formed on the **mirror** from the hot shower is an example of** condensation**.

**Condensation** is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When **water vaporizers** from resources and cools from the sky, and the vapor condenses to form **liquid droplets**. Similarly we can observe water droplets in the window pane due to the similar effect.

The **water vapor** arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror **fogs up** by the hot shower is an example of condensation.

To find more on** condensation**, refer here:

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Will was riding his bike when a dog ran out in front of him. He slammed on his brakes. During this quick stop, some of the mechanical energy (his motion) was changed into

A) heat energy.

B) light energy.

C) kinetic energy.

D) gravitational energy.

**Answer:**

A

**Explanation:**

big brain

During this quick stop, some of the mechanical energy (his motion) was changed into** heat energy. **

**Energy** is the ability to do work. There are different types of **energy** such as **Heat energy**, light energy, kinetic energy, and** gravitational energy.**

**Heat** is the energy that moves from one body to another when temperatures are different. Heat passes from the** hotter **to the** colder **body when two bodies with differing **temperatures** are brought together.

The** joule** is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the **amount** of heat necessary to raise the temperature of one gram of water from **14.5 degrees** Celsius to 15.5 degrees Celsius," is another common unit of **heat** measurement.

Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into** heat energy. **

To learn more about **heat energy**, refer to the link:

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Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs.

Which statement about work and power describes Hiro’s actions?

He did more work running than walking.

He did more work walking than running.

He had more power running than walking.

He had more power walking than running.

Answer:

C) he had more power running than walking

Explanation:

saw it on a quizlet. not 100% sure tho

**Hiro** walks up a flight of **stairs** in his apartment building. Later in the day, he runs up the same **flight** of stairs so He had more **power** running than walking.

In **physics**, power is the amount of **energy** transferred or converted per unit of time. In the **International** System of Units, the unit of **power** is the watt, **equal** to one joule per second. In older **works**, power is sometimes called activity. Power is a **scalar** quantity.

**Power** is related to other **quantities**; for example, the power **involved** in moving a ground **vehicle** is the product of the **traction** force on the **wheels** and the velocity of the **vehicle**.

The **output** power of a motor is the **product** of the torque that the motor generates and the **angular** velocity of its output **shaft**

Since we know that **Hiro** will run on stairs to **minimize** the time of reaching his **home** so if time decreases then he has to **increase** his power as power is the ratio of **work** and time.

Hence **Hiro** walks up a flight of stairs in his **apartment** building. Later in the day, he runs up the **same** flight of stairs so He had more power running than **walking**.

To know more about **power** follow

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can we add 2 atoms together? 3? How do particles combine to form the variety of matter one observes?

yes you can add two atoms together

yes you can add them together

A dog is 60 m away while moving at a constant velocity of 10 m/s towards you. How Long will it be before the dog is close enough to your face?

**Answer:**

6 seconds

**Explanation:**

The answer is 6 because if the dog is going 10 m/s it will take 6 seconds to get from 60 meters away to you.

can you help me doing an essay about actual self

**Answer:**

yes absolutely

**Explanation:**

why not

What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds

Question 2 options:

PNF

ballistic

dynamic

static

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the decay constant and half-life T1/2; (b) How many atoms of the isotope were contained in the freshly prepared sample? (c) What is the sample's activity 30 hours after it is prepared?

**Answer:**

(a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

**Explanation:**

**Given that,**

Activity [tex]R_{0}=10\ mCi[/tex]

Time [tex]t_{1}=4\ hours[/tex]

Activity R= 8 mCi

**(a). We need to calculate the decay constant**

**Using formula of activity**

[tex]R=R_{0}e^{-\lambda t}[/tex]

[tex]\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})[/tex]

[tex]\lambda=0.0000154\ s^{-1}[/tex]

[tex]\lambda=1.55\times10^{-5}\ s^{-1}[/tex]

**We need to calculate the half life**

**Using formula of half life**

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}[/tex]

Put the value into the formula

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}[/tex]

[tex]T_{\dfrac{1}{2}}=44.719\times10^{3}\ s[/tex]

[tex]T_{\dfrac{1}{2}}=11.3\ hr[/tex]

**(b). We need to calculate the value of N₀**

**Using formula of [tex]N_{0}[/tex]**

[tex]N_{0}=\dfrac{3.70\times10^{6}}{\lambda}[/tex]

Put the value into the formula

[tex]N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}[/tex]

[tex]N_{0}=2.38\times10^{11}\ nuclei[/tex]

**(c). We need to calculate the sample's activity **

**Using formula of activity**

[tex]R=R_{0}e^{-\lambda\times t}[/tex]

Put the value intyo the formula

[tex]R=10e^{-(1.55\times10^{-5}\times30\times3600)}[/tex]

[tex]R=1.87\ mCi[/tex]

**Hence, (a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]**

**The half life is 11.3 hr.**

**(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]**

**(c). The sample's activity is 1.87 mCi.**

Which property describes the number of waves that move past a point each second.

A) Speed

B) Frequency

C) Period

D) Wavelength

**Answer:B) Frequency**

**Explanation:**

**Answer:**

B) Frequency

**Explanation:**

In economics, _________ is the amount of a resource that firms and producers are willing and able to provide to the marketplace

sectors are the amount of resources

A student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons. What is the force of the wall pushing back on the student? What is the acceleration of the student as she moves away from the wall?

**Answer:**

F=-100N; a=1.3m/s^2

**Explanation:**

Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.

The **force **of the wall pushing back on the student would be 100 Newtons, and the **acceleration **of the student as she moves away from the wall would be 1.33 m/s²

Newton's third law of **motion **state that for every action force there exists a complementary **reaction **force that balances it.

As given in the problem a student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a **force **of 100 Newtons,

The force of the wall **pushing **back the student = 100 Newtons

The **acceleration **of the student = 100/75

=1.33 m/s²

Thus, The student would be pushed back against the wall by a force of 100 Newtons, and she would **accelerate **away from the wall at a rate of 1.33 m/s².

Learn more about **Newton's third law of motion **here, refer to the link;

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2

How is acceleration related to force when mass is constant, according to Newton's second law of motion?

A. The acceleration is directly proportional to the net force,

OB

The acceleration is inversely proportional to the net force.

C. The acceleration is inversely proportional to the square root of the net force.

OD

The acceleration is directly proportional to the square root of the net force.

Reset

Next Question

**Answer:**

A

**Explanation:**

The acceleration of an object is directly proportional to its net force.

[tex]a = \frac{f}{m} [/tex]

**Answer:**

*Correct choice: A. The acceleration is directly proportional to the net force*

**Explanation:**

Newton's Second Law of Motion

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force **F** and inversely proportional to the object's mass **m**:

[tex]\displaystyle a=\frac{F}{m}[/tex]

**Correct choice: A. The acceleration is directly proportional to the net force**

Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and

dimes (d) Yodelin has?

**Answer:**

**q + d = 50
**

**
25q + 10d = 980
**

**Explanation:**

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

= 32

The **system** of the **equations** could be

**q + d = 50**

**25q + 10d = 980**

Since Yodelin has **fifty quarters** and **dimes**. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to **Multiplying** (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

= 32

Learn more about **equation** here; https://brainly.com/question/18648019

protons are present in sodium atom.

a 11

b 10

C 12

d 9

11

**Explanation:**

There are 11 protons in a sodium atom

7. A car is moving at 50.0 mph when the driver applies brakes. Determine the distance it

covers before coming to a halt. Coefficient of static friction between the tires and surface of

the road is 0.514. Mass of the car is 1000 kg.

**Answer:**

The distance to come to a halt is approximately 49.53 meters

**Explanation:**

Thee given parameters are;

The speed of the car, v = 50 mph = 22.35 m/s

The mass of the car, m = 1000 kg

The coefficient of friction, = 0.514

The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N

The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J

The work done by the brake = Force of the brake × Distance, d, to come to halt

By conservation of energy, we have;

The work done by the brake = The initial kinetic energy of the car

∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt

The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt

∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters

The distance to come to a halt ≈ 49.53 meters.

The car will cover **49.65 m **distance before** stopping** due to application of brake.

**Given data:**

The **mass** of car is, **M = 1000 kg**.

The initial **speed **of car is, **u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s**.

The coefficient of static friction is, [tex]\mu = 0.514[/tex].

The given problem can be solved using the third kinematic equation of motion. Which is,

[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)

Here, **v **is the final speed, **v = 0 **(Because car is finally stopping)

**s **is the **distance** covered before stopping and **a **is the magnitude of **acceleration**.

Now, since **frictional force** opposes the motion. Then,

[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]

Substituting the values in equation (1) as,

[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]

Thus, the car will cover **49.65 m **distance before** stopping** due to application of **brake**.

Learn more about the Kinematic equations of motion here:

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1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?

A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final

position is 32 m.

B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final

velocity is 16 m/s

C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a

distance of 16 m

A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final

velocity is 24 m/s

E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final

position is 30 m.

1 of 14

2

3

5 6 7 8

9

**Answer:**

12

**Explanation:**

12

chemical formulawhat is the chemical formula

a set of chemical symbols showing the elements present in a compound and their relative proportions, and in some cases the structure of the compound.

That’s the definition

That’s the definition

**Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule**

Protons are found only in the atomic nucleus.

TRUE

FALSE

**Answer:**

true

**Explanation:**

Protons and neutrons are found in the nucleus

Question 4 of 20

Luke wraps a magnetized steel nail with several coils of insulated wire and

then connects the loose ends of the wire to a 10 W lightbulb. Which step

could he take next to get the lightbulb to light up?

O A. Replace the magnetized nail with a nonmagnetic metal to cause

an electric current to flow in the wire.

O B. Remove the magnetized nail from the wire coil to induce a

magnetic field that will flow through the wire.

C. Move the magnetized nail back and forth within the wire coil to

induce an electric current in the wire.

D. Add several more coils of the wire around the magnetized nail to

make a stronger electric current.

SUBMIT

Answer:

C. Move the magnetized nail back and forth within the wire coil to induce an electric current in the wire.

Hope this helps.

Give reasons.

a. A stretched catapult has potential energy.

b A stone on ground has zero energy.

C. Rolling a drum is work against friction.

d. Lifting a stone is work against gravity.

e. Work and energy both have same unit.

a. A stretched catapult can do work when released so it must have potential energy.

b. A stone on the ground will not move on its own ever again so it has zero energy.

c. In order to roll an object there must be a friction force between the object and the ground (otherwise it will slide)

d. To lift a stone you must overcome the weight which is the force due to gravity.

e. Work and energy are both measured in Joules.

b. A stone on the ground will not move on its own ever again so it has zero energy.

c. In order to roll an object there must be a friction force between the object and the ground (otherwise it will slide)

d. To lift a stone you must overcome the weight which is the force due to gravity.

e. Work and energy are both measured in Joules.

Three toy boats with the same mass were in a lake. Two boats were moving and one was stopped. Each boat got bumped by another boat, but not in the same direction. All the boats changed speed as a result of being bumped. Use the information in the diagram to answer. Which toy boat exprienced the strongest force when it was bumped ? How do you know ?

The answer is " The orange and gray toy boats experienced the strongest force because both gained the same force as they sped up the blue boat lost force so it slow down

**Explanation:**

Trust me I did this one for an assignment

The **boat** that will experience the** strongest force** is the boat that has the** highest speed**.

According to **Newton's second law** of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

[tex]F = \frac{mv}{t}[/tex]

where;

The **force** **experienced** by the **boats **is directly proportional to the **velocity** of their motion. Since the **boats** have the same **mass**, the force experienced by each boat will depend on the **speed** with which the boat moves.

Thus, the **boat** that will experience the** strongest force** is the boat that has the** highest speed**.

Learn more here:https://brainly.com/question/11657305

￼Calculate the TOTAL mechanical energy of pendulum is it swings from his highest point to its lowest point. ￼Pendulum mass is 4 kg. Use your equations for gravitational potential energy and kinetic energy to determine these values based on the data given below. Total energy is the sum of gravitational potential energy and kinetic energy. In this problem, round gravity to: g = 10 m/s^2.

**Answer:**

its should be 2.0 and 4.5 on it

matter makes up all ? and ?

and All lives matter

how much force is needed to accelerate 300 kg at a rate of 4 m/s/s

**Answer:**

1200

**Explanation:**

Force = Mass x Acceleration

**Answer:**

[tex]\boxed {\tt 1,200 \ Newtons }[/tex]

**Explanation:**

Force can be found by multiplying the mass by the acceleration.

[tex]F=m*a[/tex]

The mass is 300 kilograms.

The acceleration is 4 meters per second squared.

[tex]m= 300 \ kg\\a= 4 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 300 \ kg * 4 \ m/s^2[/tex]

Multiply.

[tex]F= 1200 \ kg * m/s^2[/tex]

1 Newton is equal to 1 kilograms meters per second squared, so our current answer of 1200 kg m/s² is equal to 1200 Newtons.

[tex]F= 1200 \ N[/tex]

The force needed is **1,200 Newtons.**

At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2. What can the staff member estimate for the original speed of the race car if it came to a stop during the skid?

**Answer:**

27.1 m/s

**Explanation:**

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

help do number 16 and 17

**Answer:**

16 is d and i have no idea for 17

16. True/False: Protons are exchanged between objects by induction

False: only electrons move through induction.

(iii) Why do right angle mirrors produce three images of the object?
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