-4x - 4(6x-14) +8(6x-10) - (20x -18)
Answer:
I believe it is -6
Step-by-step explanation:
What method can be used to prove the triangles are congruent?
Options: AAS, ASA, SSS, SAS, HL or Not Possible
Answer:
An method would be ASA
Step-by-step explanation:
If 4x - 3y = -18 and 6x + 7y = -4, then what is the value of y?
Answer:
y = 2
Step-by-step explanation:
4x - 3y = -18, then 4x = 3y - 18, x = (3y - 18)/4
6x + 7y = -4
substitute for x:
6((3y - 18)/4) + 7y = -4
(18y - 108)/4 + 7y = -4
4.5y - 27 + 7y = -4
combine like terms:
11.5y = 23
y = 2
check:
x = (3(2) - 18)/4 = -12/4 = -3
6(-3) + 7(2) = -4
-18 - 14 - -4
-4 = -4
so y = 2 is correct
What is the answer
How do you solve it
Answer:
-50y+(-80)
Step-by-step explanation:
20. Find the mean, median, and mode for the following
data set:
83 98 22 89 99 98
Answer:
GOT U
Step-by-step explanation:
Mean = 81.5
Median =93.5
Mode = 98
The sale at Publix states that you'll get a 22% discount when you buy a cooking pot for $25. How much did you save?
Answer:
im think it would be $5.50
Can someone please solve this for me?
107 + 12
Show your work and I'll give brianliest (I know the answer i just need someone to show their work on how to get it)
What is the answer to this
There is a sale on sneakers. The price tag says $150. There is a 25% off sale. What is the final price with the discount? USE AN EXPRESSION.
Expression: ___________________
Answer:_______________________
Answer:
Step-by-step explanation:
Find the value of x.
20. Give an example of a function from N to N that is a) one-to-one but not onto. b) onto but not one-to-one. c) both onto and one-to-one (but different from the identity function). d) neither one-to-one nor onto.
Answer:
Step-by-step explanation:
a) To provide an example of a function N → N that is one-to-one but not onto.
Suppose [tex]f:N\to N[/tex] to be [tex]f(n)=n^2[/tex]
Then; [tex]\text{a function } \ f: A \to B\ \text{is one-to-one if and only if } f(a) = f(b) \implies a = b \ for \ a, b \ \epsilon \ A.[/tex]
[tex]\text{a function } \ f: A \to B\ \text{is onto if and only if for every element } b \ \epsilon \ B \\ \text{there exist an element a} \ \epsilon\ A \ such \ that f(a) = b}[/tex]
Now, assuming [tex]a \ \Big {\varepsilon} \ N \& \ b \ \epsilon \ N;[/tex]
Then [tex]f(a) = f(b)[/tex]
[tex]a^2 = b^2 \\ \\ a = b[/tex]
The above function is said to be one-to-one
[tex]\text{it is equally understandable that not every natural number is the square of a natural number}[/tex]e.g
2 is not a perfect square, hence, it is not regarded as the image of any natural no.
As such, f is not onto.
We can thereby conclude that the function [tex]f(n) = n^2[/tex] is one-to-one but not onto
b)
[tex]Suppose f: N \to N[/tex] be
[tex]f(n) = [n/2] \\ \\ For \ n =1, f(1) = [1/2] = [0.5] = 1 \\ \\ For \ n=2 , f(2) = [2/2] = [1] = 1[/tex]
It implies that the function is not one-to-one since there exist different natural no. having the same image.
So, for [tex]n \epsilon N[/tex] , there exists an image of 2n in N
i.e.
[tex]f(2n) = [2n/2] = [n] = n[/tex]
Hence, the function is onto
We thereby conclude that the function [tex]f(n) = [n/2] \text{ is onto but not one-to-one}[/tex]
c)
[tex]let f: N\to N[/tex] be [tex]f(n) = \left \{ {{n+1, \ if \ n \ is \ even } \atop n-1 , \ if \ n \ is \ odd} \right.[/tex]
So, if n, m is odd:
Then:
[tex]f(n) = f(m) \\ \\ n-1 = m-1 \\ \\ n = m[/tex]
Likewise, if n, m is even:
Then;
[tex]f(n) = f(m) \\ \\ n+1 = m+ 1 \\ \\ n = m[/tex]
The function is then said to be one-to-one.
However, For [tex]n \epsilon N[/tex] and is odd, there exists an image of [tex]n - 1[/tex]that is even;
[tex]f(n - 1) = n -1 + 1 =n[/tex]
For [tex]n \epsilon N[/tex] and is even, there exists an image of [tex]n + 1[/tex]that is odd;
[tex]f(n - 1) = n +1 - 1 = n[/tex]
where(; implies such that)
Hence, this function is said to be onto.
We can therefore conclude that the function [tex]f(n) = \left \{ {{n+1, \ if \ n \ is \ even } \atop n-1 , \ if \ n \ is \ odd} \right.[/tex] is both onto and one-to-one.
d)
Here, to provide an example where the [tex]f:N \to N[/tex] is neither one-to-one nor onto.
SO;
Let [tex]f : N \to N[/tex] is defined to be [tex]f(n)=0[/tex]
Then, since every integer has the same image as zero(0), the function is not one-to-one.
Similarly, the function is not onto since every positive integer is not an image of any natural number.
We, therefore conclude that, the function [tex]f(n)=0[/tex] is neither one-to-one nor onto.
there are 4 red balls in a bag and 8 yellow balls a ball is drawn random from the bag find the probability of not red ball
Answer:
2/3
Step-by-step explanation:
There are 4 red balls and 8 yellow balls.
Therefore, there are total 12 balls in the bag.
n(S) = 12
Let A be the event when the ball drawn is not a red ball.
The balls which are not red will be yellow balls and there are 8 yellow balls so,
n(A) = 8
Probability that the ball drawn randomly from the bag is not a red ball,
p(A) = n(A) / n(S)
= 8/12
= 2/3
Therefore, the probability of the ball drawn randomly is not a red ball is 2/3.
Please help I need it by today...
also sorry...
Answer:
Step-by-step explanation:
A \greenD{3\,\text{cm} \times 10\,\text{cm}}3cm×10cmstart color #1fab54, 3, start text, c, m, end text, times, 10, start text, c, m, end text, end color #1fab54 rectangle sits inside a circle with radius of \blueD{12\,\text{cm}}12cmstart color #11accd, 12, start text, c, m, end text, end color #11accd.
What is the area of the shaded region?
Round your final answer to the nearest hundredth.
They are nine red and six Green marbles in a bag Reach in the bag and randomly takes out one mobile what is the probability of the child get an a green marble
Answer:
[tex]P(Green) = \frac{6}{15}[/tex]
Step-by-step explanation:
Given
[tex]Red = 9[/tex]
[tex]Green = 6[/tex]
Required
The probability of selecting green marble
This is calculated as:
[tex]P(Green) = \frac{Green}{Green + Red}[/tex]
[tex]P(Green) = \frac{6}{9+6}[/tex]
[tex]P(Green) = \frac{6}{15}[/tex]
Identify whether the statement describes inferential statistics or descriptive statistics a) A diet high in fruits and vegetables will lower blood pressure (Source: Institute of Medicine). [ Select ] b) The national average annual medicine expenditure per person is $1052 (Source: The Greensburg Tribune Review). [ Select ] c) There is a relationship between smoking cigarettes and getting emphysema. [ Select ]
If FX) = 3x+6, which of the following is the inverse of Fx)?
A. F1(x) = 6 - 3x
B. F1(x) = 3x - 6
C. F'(x) = x - 6 / 3
D. F'(x) = x - 3 / 6
Answer:
C. F'(x) = x - 6 / 3
Step-by-step explanation:
[tex]y = 3x + 6[/tex]
[tex]x = 3y + 6 \\ x - 6 = 3y + 6 - 6[/tex]
[tex] \frac{x - 6}{3} = \frac{3y}{3} [/tex]
[tex]y = \frac{x - 6}{3} [/tex]
[tex]f1 = \frac{x - 6}{3} [/tex]
Juan's car used 12 gallons of gasoline to travel 456 miles. How many miles do I travel for each gallon of gasoline?
Answer:
38 miles per gallon
Step-by-step explanation:
465 miles / 12 gallons
38 miles / gallon
A basketball player makes 85% of her foul shots. If 10 of her foul shots are randomly selected, what is the probability that 8 of them are successful shots?
0.06
0.28
0.85
0.98
Answer: 0.28
Step-by-step explanation: Reviewed my quiz, got you covered
if a football team played 160 matches and won 65 percent of them,how many matches did it win
Answer:
65 x 160 / 100 = 104
Step-by-step explanation:
Please answer this correctly without making mistakes
Answer:
w-(v+4)
Step-by-step explanation:
please give brainliest
3. A deli sells small, medium, and large box lunches. Each can of soda costs $1 and each bag of chips costs $1. Each sandwich costs s dollars. Some customers buy box lunches, and some customers buy items separately. Use this and the information below to solve Parts A, B, and C.
• Michelle buys 6 sandwiches and 2 sodas. Her total cost is 6s+ 2.
• Beyunka buys 6 small box lunches. These box lunches include 1 sandwich, 1 soda, and 1 bag of chips. Her total cost is 6(s + 2).
Duff buys 3 medium box lunches. These box lunches do not include soda. His total cost is 3(2s + 3).
3. PART A: Each medium box lunch purchased by Duff contains two sandwiches and three bags of chips. If sandwiches cost $7.75, what is Duff's total cost?
Answer:
55.50
Step-by-step explanation:
2(7.75) = 15.5
15.5+3 = 18.5
3(18.5) =55.5
$55.50
I need help with this.
Y=6x -7
When attending a movie, patrons are interested in avoiding the pre-movie trivia games, ads, and previews. It is known that the previews begin at the scheduled movie start time and they last between 5 and 15 minutes. Assume that the time of the previews is uniformly distributed. What is the probability that on a given day the previews last between 10 and 12 minutes
Answer:
0.2 = 20% probability that on a given day the previews last between 10 and 12 minutes
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
It is known that the previews begin at the scheduled movie start time and they last between 5 and 15 minutes.
This means that [tex]a = 5, b = 15[/tex]
What is the probability that on a given day the previews last between 10 and 12 minutes?
[tex]P(10 \leq X \leq 12) = \frac{12 - 10}{15 - 5} = \frac{2}{10} = 0.2[/tex]
0.2 = 20% probability that on a given day the previews last between 10 and 12 minutes
Tanisha scored 31 out of 35 points on a recent math quiz. The percent that Tanisha answered
correctly is closest to
1) 86%
2) 89%
3)91%
4)93%
Answer:
2) 89%
Step-by-step explanation:
Help me please I give brainliest and be serious
Answer:
15, y = 1/2x + 3.75
Step-by-step explanation:
Am not 100% sure but for #15
cuz I graphed it & it looks alike
Windsor the dog ate 4 3/4 snack bones each day for a week . How many bones did Windsor eat that week ?
Answer:
4*3/4* 7=21 bones per week
Answer:
= 4 ¾ × 7
= 33.25 snack bones
Can a triangle have the following side lengths? Explain.
5 feet, 2 feet, 10 feet
Answer:
No, this can not be a triangle because if you use the Pythagorean theorem 5 squared plus 2 squared doesn't equal 10 squared.
Step-by-step explanation:
You take 5 squared and 2 squared and add them, you then find the square root and that should equal 10, if not its not a triangle.
62% of owned dogs in the United States are spayed or neutered. Round your answers to four decimal places. If 48 owned dogs are randomly selected, find the probability that
a. Exactly 30 of them are spayed or neutered.
b. At most 33 of them are spayed or neutered.
c. At least 31 of them are spayed or neutered.
d. Between 24 and 30 (including 24 and 30) of them are spayed or neutered.
Answer:
a) 0.1180 = 11.80% probability that exactly 30 of them are spayed or neutered.
b) 0.8665 = 86.65% probability that at most 33 of them are spayed or neutered.
c) 0.4129 = 41.29% probability that at least 31 of them are spayed or neutered.
d) 0.5557 = 55.57% probability that between 24 and 30 of them are spayed or neutered.
Step-by-step explanation:
To solve this question, we use the binomial probability distribution, and also it's approximation to the normal distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
62% of owned dogs in the United States are spayed or neutered.
This means that [tex]p = 0.62[/tex]
48 owned dogs are randomly selected
This means that [tex]n = 48[/tex]
Mean and standard deviation, for the approximation:
[tex]\mu = E(x) = np = 48*0.62 = 29.76[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{48*0.62*0.38} = 3.36[/tex]
a. Exactly 30 of them are spayed or neutered.
This is P(X = 30), which is not necessary the use of the approximation.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 30) = C_{48,30}.(0.62)^{30}.(0.38)^{18} = 0.1180[/tex]
0.1180 = 11.80% probability that exactly 30 of them are spayed or neutered.
b. At most 33 of them are spayed or neutered.
Now we use the approximation. This is, using continuity correction, [tex]P(X \leq 33 + 0.5) = P(X \leq 33.5)[/tex], which is the pvalue of Z when X = 33.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{33.5 - 29.76}{3.36}[/tex]
[tex]Z = 1.11[/tex]
[tex]Z = 1.11[/tex] has a pvalue of 0.8665
0.8665 = 86.65% probability that at most 33 of them are spayed or neutered.
c. At least 31 of them are spayed or neutered.
Using continuity correction, this is [tex]P(X \geq 31 - 0.5) = P(X \geq 30.5)[/tex], which is 1 subtracted by the pvalue of Z when X = 30.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{30.5 - 29.76}{3.36}[/tex]
[tex]Z = 0.22[/tex]
[tex]Z = 0.22[/tex] has a pvalue of 0.5871
1 - 0.5871 = 0.4129
0.4129 = 41.29% probability that at least 31 of them are spayed or neutered.
d. Between 24 and 30 (including 24 and 30) of them are spayed or neutered.
This is, using continuity correction, [tex]P(24 - 0.5 \leq X \leq 30 + 0.5) = P(23.5 \leq X \leq 30.5)[/tex], which is the pvalue of Z when X = 30.5 subtracted by the pvalue of Z when X = 23.5.
X = 30.5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{30.5 - 29.76}{3.36}[/tex]
[tex]Z = 0.22[/tex]
[tex]Z = 0.22[/tex] has a pvalue of 0.5871
X = 23.5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{23.5 - 29.76}{3.36}[/tex]
[tex]Z = -1.86[/tex]
[tex]Z = -1.86[/tex] has a pvalue of 0.0314
0.5871 - 0.0314 = 0.5557
0.5557 = 55.57% probability that between 24 and 30 of them are spayed or neutered.
|x+3 , if x = 2. Plz help I will pick brainlist
Answer:
1(2)+3=5
Step-by-step explanation:
find the next three terms in each sequence. then, write the rule for finding the nth terms. 1. 1, 4, 7, 10