Solve the inequality:

3z−1≤−7

Select one:

z≥2

z≥−2

z≤−2

z≤2

Answer:

D.324

Step-by-step explanation:

Answer:

D. 324 Sq in

Step-by-step explanation:

Painted area = area of rectangle + Area of square + Area of triangle

[tex] = 60 \times 4 + {8}^{2} + \frac{1}{2} \times 8 \times 5 \\ \\ = 240 + 64 + 20 \\ \\ = 324 \: {in}^{2} [/tex]

Answer:

$81.95

Step-by-step explanation:

0.07 * 55 = 3.85

(3.85 * 7) + 55

26.95 + 55

81.95

Answer:

the answer is 13.72

Step-by-step explanation:

tell me if its right

Answer:

700

Step-by-step explanation:

We have, 14% × x = 98

or, 14

100 × x = 98

Multiplying both sides by 100 and dividing both sides by 14,

we have x = 98 ×

100

14

x = 700

If you are using a calculator, simply enter 98×100÷14, which will give you the answer.

Answer:

B(-6,4)

Step-by-step explanation:

Basically, it's the same as reflecting it over the origin, so you transform the sign to its opposite and keep the points.

Answer:

The United States of America mostly and maybe Canada

Answer:

Let's solve your equation step-by-step.

a=

4

3

−

7

−2

Step 1: Simplify both sides of the equation.

a=

4

3

−

7

−2

a=

4

3

+

7

2

a=(

4

3

+

7

2

)(Combine Like Terms)

a=

29

6

a=

29

6

Answer:

a=

29

6

Question:

Analyze the following budget, with an income of $600, to determine how much can be spent on food for the month.

Cell Phone $65

Food $___

Entertainment $95

College Savings $200

Car Expenses - Gas, Insurance $160

Answer:

[tex]Food = \$80[/tex]

Step-by-step explanation:

Given

[tex]Income = \$600[/tex]

Required

How much should be spent on food

This is calculated as:

[tex]Income = Food + Other\ budgets[/tex]

Where:

[tex]Other\ budgets = Phone + Ent + College + Car, Gas[/tex]

[tex]Other\ budgets = \$65 + \$95 + \$200 + \$160[/tex]

[tex]Other\ budgets = \$520[/tex]

So, we have:

[tex]\$600 = Food + \$520[/tex]

[tex]Food = \$600 - \$520[/tex]

[tex]Food = \$80[/tex]

Answer:

C $80 can be spent on food.

Answer:

number 1 and 2 r true

Step-by-step explanation:

Answer:

Diana has 14 dimes and 12 nickels

Step-by-step explanation:

Create a system of equations, where d is the number of dimes and n is the number of nickels:

d + n = 26

0.1d + 0.05n = 2

Solve by elimination by multiplying the top equation by -0.1:

-0.1d - 0.1n = -2.6

0.1d + 0.05n = 2

Add these together, then solve for n:

-0.05n = -0.6

n = 12

So, she has 12 nickels. To find the number of dimes, subtract 12 from 26, since there were 26 coins in total and we found that she had 12 nickels.

26 - 12

= 14

So, Diana has 14 dimes and 12 nickels

Answer:

g = 21/4


Decimal form:

g = 5.25


Mixed Number:

5 1/4

Answer:

Step-by-step explanation:

B/c they are similar triangles we can set the sides ratio's equal to each other again

7x + 6 / 56  = 78 /91

does it kind of makes sense why I'm able to set those two ratio's equal?

it's the tough part of these problems... understanding why that works

the rest is just algebra.. My calc II professor always told us our algebra sucks. :D he was funny,

anyway, use your mad algebra skilz on the above equation

7x + 6 = 56(78/91)

7x + 6 = 4368 / 91

7x + 6 = 48

7x = 48 - 6

7x = 42

x = 6

:)

Add them both up and divided by 2, 52+45=97. 97/2 =48.5

Step-by-step explanation:

Answer:

[tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Chance of tales: [tex]\frac{1}{2}[/tex]

Chance of even number: [tex]\frac{3}{6}[/tex] or [tex]\frac{1}{2}[/tex]

Multiply: ([tex]\frac{1}{2}[/tex])([tex]\frac{1}{2}[/tex]) = [tex]\frac{1}{4}[/tex]

Answer:

3.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Does Daniela Works every day?

Do Daniela Work every day?

Does Daniela Work every day?

Did Daniela Work every day?

4.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Margarita don't brushes her car

Margarita doesn't brush her car

Margarita doesn't brushes her car

Margarita didn´t brush her car

5.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Do Camilo and Diana dances in the class?

Do Camilo and Diana dance in the class

Does Camilo and Diana dance in the class?

Do Camilo and Diana dance in the class?

6.LOOK AND CHOOSE THE CORRECT SENTENCES

(1 Punto)

You don't read a book

You don't reads a book

You doesn't read a book

7.LOOK AND CHOOSE THE CORRECT SENTENCES  

INTERROGATIVE  

____ he ___ better than you?

(1 Punto)

Does- plays

Does- play

Do- play

Do . plays

8.LOOK AND CHOOSE THE CORRECT SENTENCES  

NEGATIVE

It  ___ snow in summer.

(1 Punto)

doesn't

don't

9.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

My cousin _____ English very well.

(1 Punto)

Speak

Speaking

Speaks

10.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

We _____  our bikes

(1 Punto)

Wash

Washes

Washing

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Step-by-step explanation:

Answer:

Is there any answer choices? If not I would think its 5$

                                                                                      5$

                                                                                      4$

Step-by-step explanation:

Answer:

Interest in a new downtown restaurant in Caldwell, Idaho:

(a) The sample in this survey is:

C. the 165 phone numbers chosen.

(b) The population of interest is:

C. all residents of Caldwell.

(c) The chance that all 165 phone numbers chosen are located in one particular neighborhood in Caldwell is:

E. None of the above.

Step-by-step explanation:

Population of interest = residents of Caldwell, Idaho

Sample of the population = 165

Number of willing participants/respondents = 60

Proportion of participants supporting a new downtown restaurant = 44/60 = 73%

Answer:

3a + 3b

Step-by-step explanation:

Answer:

5/4

Step-by-step explanation:

Answer:

slope = 1.25

Step-by-step explanation:

use the formula

m=rise/run or m=[tex]y_{2} - y_{1} / x_{2} - x_{1}[/tex]

-7-(-2)/(-3)-1

= 5/4 (or 1.25)

hope this helps :)

9514 1404 393

Answer:

  a) line: y = x - 11

  b) k = -9

  c) AP = BP = √74

Step-by-step explanation:

There are four (4) formulas that are needed for solving this problem.

  m = (y2 -y1)/(x2 -x1) . . . . . . slope of a line between points (x1, y1) and (x2, y2)

  M = ((x1 +x2)/2, (y1 +y2)/2) . . . . midpoint of the segment between the points

  y -y1 = m(x -x1) . . . . . point-slope equation of a line given point and slope

  d = √((x2 -x1)² +(y2 -y1)²) . . . . distance between two points

In addition, you need to know that perpendicular lines have opposite reciprocal slopes.

__

The perpendicular bisector of a segment between two points will be a line with a slope that is the opposite reciprocal of the slope of the segment. That line will go through the midpoint of the segment.

a) The slope of the segment between A(7, -2) and B(9, -4) is ...

  m = (-4-(-2))/(9-7) = -2/2 = -1

The midpoint of AB is ...

  M = ((7+9)/2, (-2-4)/2) = (8, -3)

The opposite reciprocal of the slope of AB is ...

  m = -1/(-1) = 1

Then the point-slope equation of the perpendicular bisector is the line with slope 1 through the point (8, -3):

  y -(-3) = 1(x -8)

  y = x -11

__

b) Point P on the line has x-value of 2, so the y-value will be ...

  k = 2 -11 = -9

Point P has coordinates (2, -9).

__

c) The length of segment AP is given by the distance formula:

  d = √((2 -7)² +(-9-(-2))²) = √((-5)² +(-7)²) = √74

The length of segment BP is likewise given by the distance formula:

  d = √((2 -9)² +(-9 -(-4))²) = √((-7)² +(-5)²) = √74

AP = √74 = BP   ⇒   AP ≅ BP

Answer:

¹/25 mm²

Step-by-step explanation:

Area of a square = s²

Where s is the length of one side

using the diagram given,

s = ⅕ mm

Area = (⅕)²

Area of the square = ¹/25 mm²

Answer:

[tex]\displaystyle f'(1) = \frac{3}{2}[/tex]

[tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra II

Exponential Rule [Rewrite]:                                                                            [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]:                                                                   [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Step-by-step explanation:

Step 1: Define

f(x) = x√x

f'(1) is x = 1 for 1st derivative

f''(1) is x = 1 for 2nd derivative

Step 2: Differentiate

[1st Derivative] Product Rule:                                                                       [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[\sqrt{x}][/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[x^{\frac{1}{2}}][/tex][1st Derivative] Basic Power Rule:                                                                 [tex]\displaystyle f'(x) = (1 \cdot x^{1 - 1})\sqrt{x} + x(\frac{1}{2}x^{\frac{1}{2}-1})[/tex][1st Derivative] Simply Exponents:                                                               [tex]\displaystyle f'(x) = (1 \cdot x^0)\sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Simplify:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Rewrite [Exponential Rule - Rewrite]:                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2x^{\frac{1}{2}}})[/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2\sqrt{x}})[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + \frac{x}{2\sqrt{x}}[/tex][2nd Derivative] Rewrite [Exponential Rule - Root Rewrite]:                     [tex]\displaystyle f'(x) = x^{\frac{1}{2}} + \frac{x}{2x^{\frac{1}{2}}}[/tex][2nd Derivative] Basic Power Rule/Quotient Rule [Derivative Property]: [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{(2x^{\frac{1}{2}})^2}[/tex][2nd Derivative] Simplify/Evaluate Exponents:                                           [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{-1}{2}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Basic Power Rule:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^{1 - 1})(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{1}{2} - 1})}{4x}[/tex][2nd Derivative] Simply Exponents:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^0)(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{x^{\frac{1}{2}}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - \frac{x}{x^{\frac{1}{2}}}}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{x^{\frac{1}{2}}}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule  - Root Rewrite]:                     [tex]\displaystyle f''(x) = \frac{1}{2\sqrt{x}} + \frac{\sqrt{x}}{4x}[/tex]

Step 3: Evaluate

[1st Derivative] Substitute in x:                                                                     [tex]\displaystyle f'(1) = \sqrt{1} + \frac{1}{2\sqrt{1}}[/tex][1st Derivative] Evaluate Roots:                                                                     [tex]\displaystyle f'(1) = 1 + \frac{1}{2(1)}[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(1) = 1 + \frac{1}{2}[/tex][1st Derivative] Add:                                                                                       [tex]\displaystyle f'(1) = \frac{3}{2}[/tex][2nd Derivative] Substitute in x:                                                                   [tex]\displaystyle f''(1) = \frac{1}{2\sqrt{1}} + \frac{\sqrt{1}}{4(1)}[/tex][2nd Derivative] Evaluate Roots:                                                                 [tex]\displaystyle f''(1) = \frac{1}{2(1)} + \frac{1}{4(1)}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(1) = \frac{1}{2} + \frac{1}{4}[/tex][2nd Derivative] Add:                                                                                     [tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

Answer: 7 degrees of freedom.

Step-by-step explanation:

Answer:

Your question is in what base please?

9514 1404 393

Answer:

  2

Step-by-step explanation:

You need the smallest positive integer for which f(x) > 0.

  f(1) = 3 -4 -3 -1 = -5

  f(2) = ((3·2 -4)2 -3)2 -1 = (4 -3)2 -1 = 1

x = 2 is the smallest integer for which f(x) > 0.

Answer:

(3x+4b)(a-2y)

Step-by-step explanation:

(3ax-6xy)+(8by-4ab)

3x(a-2y) -4b(-2y+a)

(3x+4b) (a-2y)

Answer:

(a−2y)(3x−4b)

Step-by-step explanation:

3ax−6xy+8by−4ab

⇒3ax−4ab−6xy+8by

⇒a(3x−4b)−2y(3x−4b)

⇒(a−2y)(3x−4b)

Hope it is helpful...

Answer:

Quadratic and Trinomial

Step-by-step explanation:

It has a degree of 2, making it a quadratic. It has 3 terms, so it's a trinomial.

Answer:B

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\text{Given that:}[/tex]

[tex]y = 1+ sec(x) \ \ y =3[/tex]

[tex]\text{we draw the graph and the curves intersect at:}[/tex]

[tex]x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}[/tex]

[tex]\text{Applying washer method;}[/tex]

[tex]f(x) _{outer} - g(x) _{inner} --- (1)[/tex]

[tex]V= \int ^b_a A(x) \ dx --- (2)[/tex]

[tex]\text{outer radius = 3 - 1 = 2}[/tex]

[tex]\text{inner radius =}[/tex] [tex]( 1 + sec(x) ) - 1 = sec (x)[/tex]

[tex]A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)[/tex]

[tex]\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx[/tex]

[tex]V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx[/tex]

[tex]V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx[/tex]

[tex]V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx[/tex]

[tex]V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}[/tex]

[tex]V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )[/tex]

[tex]\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}[/tex]

So... where the graph

Answer:

-6

Step-by-step explanation:

2 x -3 = -6

1 positive and a negative integer multiplied will get a negative answer

The answer is -6 ! Good luck!