Solve the inequality. Graph the solution.

−16>x÷2

Answers

Answer 1

Answer:

-32>x

Step-by-step explanation:

-16>x÷2

-16×2>x

-32>x


Related Questions

The perimeter of the shape is

feet.

Answers

Answer:

This doens't realy make sense dude

What shape ??????????,

F r e e points for people that is low on points :)

Answers

Answer:

im not low on points but thank you <3.

Step-by-step explanation:

Answer:

:) :) :) :) :) :) :) :) :) :)

3
Johnny has been hired to draw a mural on the window of the pet store. The scale drawing he is using is shown below.
4.5 cm
6 cm
If 1 centimeter represents 10 inches on the mural, what is the actual height and width of the hamster that he will be drawing on the
mural?
OA.
66 in by 49.5 in
ОВ.
90 in by 120 in
Od
6 in by 4.5 in
OD. 60 in by 45 in

Answers

Answer:

OD 60 in by 45 in

Step-by-step explanation:

Need help please ……………………………..

Answers

Answer:

[tex]-2^{-2} = \frac{1}{-2^{2} } = \frac{1}{4} = 0.25[/tex]

[tex]-2^{-1} = \frac{1}{-2 } = -0.5[/tex]

[tex]-2^{0} = 1[/tex]

[tex]-2^{1} = -2[/tex]

[tex]-2^{2} = 4[/tex]

Step-by-step explanation:

WILL GIVE BRAINLIEST

Answers

Answer:

it is d

Step-by-step explanation:

A train leaves a point A at 5 pm and reach another point B at 11 pm. Another train leaves point B at 7 pm and reach point A at 10 pm. At what point will the two trains meet?

Answers

Answer: I think the two trains meet at 9pm

Explanation: A=train a B=train b

If A is traveling for 6 hours and B is traveling for 3 hours, then you minus 3 hours from A, so you are left with 3 hours. Convert that into time, and you are left with 9pm!

Hope this helps! :)

Step-by-step explanation:

let's think this through.

train a goes from A to B in 6 hours. that means with a speed of 1/6 / hour.

train b goes from B to A in 3 hours, so it is twice as fast as train a = 2/6 / hour.

when train b leaves B (at 7pm), train a was already traveling for 2 hours (1/3 of the whole trip) leaving it with 4 hours to go (2/3 if the distance).

that means that at that point now both trains are moving against each other with a relative speed of 3 times the

speed of a (the original speed of a plus the double speed of b).

this is the same as one train standing, and the other going the whole distance with 3 times the speed of a.

the whole distance is 2/3 of AB.

the speed is 3/6 / hour = 1/2 / hour.

so, a single train with that speed would cover the total distance AB in 2 hours. or half of the distance in 1 hour.

the question now, how long for 2/3 of AB.

the distances relate by a factor :

1/2 × f = 2/3

f = 2/3 / 1/2 = 2/3 × 2/1 = 4/3

now we need to multiply also the time in the distance/time speed ratio by this factor.

therefore, 2/3 of the total distance is done in 1×4/3 = 4/3 of an hour.

that means both trains meet after 4/3 of an hour after 7pm.

that is 7pm plus 1 hour and 20 minutes giving us 8:20pm.

help me with this question plz

Answers

Answer:

2

Step-by-step explanation:

you tell me true ya false

Divide 7 divided by 3/5

Express your answer in simplest form.

Answers

Answer:

35/5

Step-by-step explanation:

7/1 divded by 3/5. flip 3/5 to its reciprocal so it becomes 5/3, then times 7/1 by 5/3

35/5 hope this help!!

Compare the investment below to an investment of the same principal at the same rate compounded annually.

principal: $1,000, annual interest: 6%, interest periods: 6, number of years: 14 more than the investment compounded annually.

After 14 years, the investment compounded periodically will be worth $ ____(Round to two decimal places as needed.)​

Answers

After 14 years, the investment will be worth $ 2,306.72.

Given that an investment has a $ 1000 principal, 6% annual interest, 6 interest periods and 14 years of investment, to determine, after 14 years, how much the investment will be worth, the following calculation must be performed:

1000 x (1 + 0.06 / 6) ^ 14x6 = X 1000 x 1.01 ^ 84 = X 1000 x 2.3067 = X 2,306.72 = X

Therefore, after 14 years, the investment will be worth $ 2,306.72.

Learn more about maths in https://brainly.com/question/15603792

A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compare over the interval -2<= x <= 0?


The exponential function decays at one-half the rate of the quadratic function.
The exponential function decays at the same rate as the quadratic function.
The exponential function decays at two-thirds the rate of the quadratic function.
The exponential function decays at three-fourths the rate of the quadratic function.

Answers

Answer:

×e[-2,0}

Why;-2<x<0

Write the compound inequality in interval rotation

so the answer is;×e[-2,0}

brainliest me thanks for later

Answer:

D) The exponential function decays at three-fourths the rate of the quadratic function.

Step-by-step explanation:

1985 x 99 I already know the answer: 196515

Answers

Answer:

196515

Step-by-step explanation:

Answer:

196515

Step-by-step explanation:

need this soon please

Answers

Answer: pretty sure -7

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

(-80) - (-10) is -79

-70 / (+10) = -7

PLS HELP HELLLLLOPPPPPP PLEASSSS BRO IM LITERALLY GONNA CRY

Answers

Answer:

F The last option

{ n = 7 h - 2}

{ n = 4 h - 2}

Step-by-step explanation: I HOPE THIS HELPS

Answer:

it's

n=2h+4

n=2h+7

(and vice versa)

The given represent 7 necklace and 4 necklace,that means add it to the no.of necklace they can make every hour and that is 2. So the correct equation is in the above answers.

Step-by-step explanation:

I hope it helps you a lot dude lovelots

#LEARN WITH BRAINLY

Find the missing side in the similar figures below

Answers

Answer:

e

Step-by-step explanation:

24*5/3=40

The answer would be E. Trust me on this one

Find the side of a rhombus if its diagonals are 14 and 48
(Use Pythagorean theorem)

Answers

Answer:

25

Step-by-step explanation:

Let,

Rhombus = ABCD

Diagonal = AC and BD

Mark its centre as O

Now,

AC = 2AO

AO = AC/2

AO = 48/2

AO = 24 cm

Also,

BD = 2BO

BO = BD/2

BO = 14/2

BO = 7 cm²

Now,

In ∆AOB

AB² = AO² + BO²

Here, AB is the side

AB² = (24)² + (7)²

AB² = 576 + 49

AB² = 625

AB = √(625)

AB = 25

The
is the distance across a circle, going through the center.
circumference
diameter
radius
area

Answers

The distance across a circle, going through the center is called Diameter.

Suppose a 5-digit number is formed using the digits from 1 to 9 (without replacement). What is the probability that it will be an even number?​

Answers

Answer:

First take 5 empty. Digits.The no of digits are 9 (1-9).The last no must be even so . The total no of even no’s . Are 4 (2,4,6,8)The probability of last digit is 4There are remaing 8 digits so. Place them where. U required. The probability are. 8, 7,6,5(no reputations)The final answer is 4*8*7*6*5=6720 ways

Answer:

0.444    (44.4%)

Step-by-step explanation:

All possible ending: 1,2,3,4,5,6,7,8,9        ... 9

ending with 2,4 6,8 to make even number: 4

                                                  ___   ___  ___  ___  ___

even number :                              8   *   7   *   6  *   5  *   4

All 5 digit without repeating:        8   *   7   *   6  *   5  *   9

possibility = (8*7*6*5*4) / (8*7*6*5*9)

                = 4/9

                = 0.444    (44.4%)

_______________________________________________

(4 * ₈P₄) / (9 * ₈P₄) = 4/9

ChallengE
See attachment and answer :)​

Answers

QuestionSimplify:

[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

Answer :

[tex]\displaystyle{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}[/tex]

Step-by-step-explanation:

We have given an expression.

We have to simplify the expression.

The given expression is

[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\sqrt{16\:\times\:3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

We know that,

[tex]\displaystyle{\boxed{\pink{\sf\:\sqrt{a\:\times\:b}\:=\:\sqrt{a}\:\times\:\sqrt{b}\:}}\:\cdots\sf\:a\:,\:b\:\geq\:0}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\sqrt{16}\:\times\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\times\:4\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

We know that,

[tex]\displaystyle{\boxed{\blue{\sf\:\sqrt{\dfrac{a}{b}}\:=\:\dfrac{\sqrt{a}}{\sqrt{b}}\:}}\:\cdots\sf\:b\: > \:0}[/tex]

[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{\sqrt{1}}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{1}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{16\:\sqrt{3}\:\times\:2\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{16\:\times\:2\:\sqrt{3}\:\times\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}} \\ \\\displaystyle{\implies\sf\:\dfrac{32\:\times\:3\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{8\:\times\:4\:\times\:3\:-\:5\:+\:(\:6\:\sqrt{3}\:\times\:2\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:6\:\times\:2\:\times\:\sqrt{3}\:\times\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:12\:\times\:3\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:12\:\times\:3}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:+\:12\:\times\:3\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:(\:8\:+\:3\:)\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:\times\:11\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{132\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}\:\times\:\dfrac{\sqrt{3}}{\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{2\:\times\:3}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{6}} \\ \\ \\ \displaystyle{\therefore\:\underline{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}}[/tex]

What is the value of x + y when x is the additive identity and y = 5?
O 5
O There is not enough information to determine the value.
O - 5
O 0

Answers

Answer:

-5.

Step-by-step explanation:

5 + -5 = 0, so i's -5.

what is the equation of the line that passes through the point (4,0) and has a slope of 5/4?

Answers

Answer:

y=5/4x-5

Step-by-step explanation:

y-y1=m(x-x1)

y-0=5/4(x-4)

y=5/4(x-4)

y=5/4x-20/4

y=5/4x-5

Please help ASAP
Solve for X.

Answers

Answer:

86

Step-by-step explanation:

So the angle your trying to find has another angle 4 the triangle is a right triangle so 90-4=86

Hopes This Helps :)

a parking garage charges $4 for the first hour and $1.50 for each additional hour. sydney has 13$ in her purse

Answers

Answer:

7 hours

Step-by-step explanation:

Answer:

she could park there for 7 hours

Step-by-step explanation:

13-4=9 9/1.50=6

been trying for an hour, need help

Answers

By using tangents u can get the answer

Sin45degre = x divided by root 5

Answer:

[tex]\sqrt{\frac{5}{2} }[/tex]

Step-by-step explanation:

We know that this is a 45-45 triangle. Where there are two angles that are 45 degrees and the other angle is a right angle (90 degrees).

The sides are a, b (which equals a) and, c (which equals a*square root of 2).

In this triangle we are given c, and tasked at finding a. Since c= [tex]a*\sqrt{2}[/tex], then we know that, [tex]\sqrt{5}= a*\sqrt{2}[/tex].  Divide the equation by square root of 2 to find a. Which equals [tex]\sqrt{\frac{5}{2} }[/tex]

Mark which expressions represent the distance between 46 and-15

Answers

|-15-46|
...........

The area of any rectangular shape is given by the product of its width and length. If the area of a particular
rectangular garden is given by A = 15x°-35x and its width is given by 5x, then find an expression for the
garden's length.

Answers

The expression that can be used to find the

garden's length is l = 5x(x - 7) / 5x where l = (x - 7)

Given:

Area of a rectangle = 15x² - 35x

Width of the rectangle = 5x

Length of the rectangle = l

Area of the rectangle = length × width

15x² - 35x = l * 5x

Factor out the left hand side

5x(x - 7) = l * 5x

Divide both sides by 5x

5x(x - 7) / 5x = l

x - 7 = l

Therefore, the expression that can be used to find the garden's length is l = 5x(x - 7) / 5x

Learn more about area of a rectangle:

https://brainly.com/question/14137384

According to the website www.olx.uz, monthly rent for a two-bedroom apartment has a mean of
$250 and a standard deviation of $100 in the city of Andijan. The distribution of the monthly rent does not
follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample
of 40 two-bedroom apartments and finding the mean to be at least $275 per month?

Answers

Using the normal distribution and the central limit theorem, it is found that there is a 0.0571 = 5.71% probability of selecting a sample  of 40 two-bedroom apartments and finding the mean to be at least $275 per month.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

It measures how many standard deviations the measure is from the mean.  After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $250, hence [tex]\mu = 250[/tex].The standard deviation is of $100, hence [tex]\sigma = 100[/tex].The sample is of 40 apartments, hence [tex]n = 40, s = \frac{100}{\sqrt{40}}[/tex].

The probability of selecting a sample  of 40 two-bedroom apartments and finding the mean to be at least $275 per month is the p-value of Z when X = 275, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{275 - 250}{\frac{100}{\sqrt{40}}}[/tex]

[tex]Z = 1.58[/tex]

[tex]Z = 1.58[/tex] has a p-value of 0.9429.

1 - 0.9429 = 0.0571

0.0571 = 5.71% probability of selecting a sample  of 40 two-bedroom apartments and finding the mean to be at least $275 per month.

You can learn more about the normal distribution and the central limit theorem at https://brainly.com/question/24663213

At the beginning of a basketball season, the Panthers won 20 games out of 80 games. At this rate, how many games will they win in a normal 100-game season?

games

Answers

They will win 25 games in 100 game season at that rate.Since they win 5 games out of every 20.

The answer is 25

If f(1) = 9 and f(n) = -4f(n-1) + 4 then find the value of f(3).

Answers

Answer:

132

Step-by-step explanation:

f(1) = 9

f(n) = -4f(n-1) + 4

Let n = 2

f(2) = -4f(2-1) + 4 = -4 f(1) +4 = -4(9) +4 = -36+4 = -32

Let n = 3

f(3) = -4f(2-1) + 4 =-4f(2)+4 =  -4 (-32) +4 = 128+4=132

The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This distribution has a mean of 47 and a standard deviation of 7. Using the empirical rule, what is the approximate percentage of 1-mile long roadways with potholes numbering between 40 and 68?

Answers

Answer:   83.85%

This value is approximate.

==========================================================

Explanation:

Let's compute the z score for x = 40

z = (x-mu)/sigma

z = (40-47)/7

z = -1

We're exactly one standard deviation below the mean.

Repeat these steps for x = 68

z = (x-mu)/sigma

z = (68-47)/7

z = 3

This score is exactly three standard deviations above the mean.

Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.

34+34+13.5+2.35 = 83.85

Roughly 83.85% of the one-mile roadways have between 40 and 68 potholes.

please help me with the question please ☹️

Answers

Answer:

the last one

Step-by-step explanation:

because those are oppiste poles

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