Solve the inequality. Graph the solution

Answer:

B. (-1,7)

C. (0,5)

D. (2,3)

Step-by-step explanation:

We solve this question looking at the graphic.

A. (-7, 1)

When [tex]x = -7, y \rightarrow \infty[/tex], and thus (7,-1) is not solution of the equation.

B. (-1,7)

When [tex]x = -1, y = 7[/tex], and thus (-1,7) is a solution of the equation.

C. (0,5)

When [tex]x = 0, y = 5[/tex], and thus (0,5) is a solution of the equation.

D. (2,3)

When [tex]x = 2, y = 3[/tex], and thus (2,3) is a solution of the equation.

E. (3, 2)

When [tex]x = 3, y \neq 2[/tex], and thus (3,2) is not part of the solution

F. (5,0)

When [tex]x = 5, y \neq 0[/tex], and thus (5,0) is not part of the solution

Answer:

c

Step-by-step explanation:

because the coordinate of x is negative

Answer:

29 IS THE ANSWER PLEASE MARK AS BRAIN IST

Step-by-step explanation:

Answer:

[tex]r=3\\h=5\\\\8r+h\\= 8(3) + (5)\\= 24 + 5\\= 29[/tex]

Answer:

ur question is not complete.

Answer:

15m

Step-by-step explanation:

Answer:

x int. (-1,0) and (-2,0).   y-int,(0,10)

Step-by-step explanation:

y-int. it's 10 because the y-int is always the c value.

x-int.

x=-b±√b²-4ac/2a

x=-15±√15²-4(5)(10)/2(5)

x=-15±√225-200/10

x=-15±√25/10

x= -15+5/10.      x=-15-5/10

x=-10/10.           x=-20/10

x=-1.                  x=-2

Answer:

(x-8)² or (x-8)(x-8)

Step-by-step explanation:

x^2-16x+64

x^2 -8x -8x +64

x (x-8) - 8(x-8)

(x-8) (x-8)

(x-8)^2

Answer:

1 kg = 1000 grams

15,000 grams = 15kg

Answer:

4 yrs have passed since the account was opened

Step-by-step explanation:

With the quadratic equation in this form: [tex]ax^2+bx+c=0[/tex]

Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Example: 2x^2 + 7x + 3

ac is 2×3 = 6 and b is 7

So we want two numbers that multiply together to make 6, and add up to 7

In fact 6 and 1 do that (6×1=6, and 6+1=7)

How do we find 6 and 1?

It helps to list the factors of ac=6, and then try adding some to get b=7.

Factors of 6 include 1, 2, 3 and 6.

1 and 6 add to 7, and 6×1=6.

Step 2: Rewrite the middle with those numbers:

Rewrite 7x with 6x and 1x:

2x^2 + 6x + x + 3

Step 3: Factor the first two and last two terms separately:

The first two terms 2x^2 + 6x factor into 2x(x+3)

The last two terms x+3 don't actually change in this case

So we get:

2x(x+3) + (x+3)

Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.

In this case we can see that (x+3) is common to both terms, so we can go:

Start with: 2x(x+3) + (x+3)

Which is: 2x(x+3) + 1(x+3)

And so: (2x+1)(x+3)

Done!

Check: (2x+1)(x+3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 (Yes)

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Answer:

Option 4, BC = 12.689, m∠A = 58°, and m∠C = 32°

Hope this helps!

Answer:

x= -7

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

-19x+32=-24x-3

-19x+24x=-3-32

5x=-35

X=-35/5= -7

Answer: 37m

Step-by-step explanation:

Convert 300cm into m = 3m

6 + 6 + 3 + 3 + 3.5 + 3.5 + 12 = 37m

Answer:

(16, 24, 7)

Step-by-step explanation:

The Triangle Inequality states that the sum of lengths of any two sides should be greater than the length of the third side.

But 16 + 7 = 23 is not greater than 24.

Answer:

(a) Name: Multinomial distribution

Parameters: [tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]

(c) Name: Binomial distribution

Parameters: [tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

[tex](d)\ E(x) = 1[/tex]   [tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y) = 17[/tex]

Step-by-step explanation:

Given

[tex]p_1 = 5\%[/tex]

[tex]p_2 = 85\%[/tex]

[tex]p_3 = 10\%[/tex]

[tex]n = 20[/tex]

[tex]X \to[/tex] High Slabs

[tex]Y \to[/tex] Medium Slabs

[tex]Z \to[/tex] Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

[tex]X \to[/tex] Number of voids considered as high slabs

[tex]Y \to[/tex] Number of voids considered as medium slabs

[tex]Z \to[/tex] Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

[tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

And the mass function is:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

[tex]n = 20[/tex]

The number of voids (x, y and z) cannot be negative and they must be integers; So:

[tex]x + y + z = n[/tex]

[tex]x + y + z = 20[/tex]

Hence, the range is:

[tex]\{(x,y,z)| x + y + z=20\}[/tex]

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

[tex]E(x) = p_1* n[/tex]

[tex]E(x) = 5\% * 20[/tex]

[tex]E(x) = 1[/tex]

[tex]Var(x) = E(x) * (1 - p_1)[/tex]

[tex]Var(x) = 1 * (1 - 5\%)[/tex]

[tex]Var(x) = 1 * 0.95[/tex]

[tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]

In (b), we have: [tex]x + y + z = 20[/tex]

However, the given values of x in this question implies that:

[tex]x + y + z = 1 + 17 + 3[/tex]

[tex]x + y + z = 21[/tex]

Hence:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]

This question implies that:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]

Because

[tex]0, 1 \le 1[/tex] --- for x

In (e), we have:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

In (a), we have:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

So:

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]

Expand

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]

Using a calculator, we have:

[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1)[/tex]

This implies that:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

In (c), we established that X is a binomial distribution with the following parameters:

[tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

Such that:

[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]

So:

[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]

[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]

[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]

[tex]P(X=0) = 0.3585[/tex]

[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]

[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]

[tex]P(X=1) = 0.3774[/tex]

So:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]

[tex]P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y)[/tex]

Y has the following parameters

[tex]p_2 = 85\%[/tex]  and    [tex]n = 20[/tex]

[tex]E(Y) = p_2 * n[/tex]

[tex]E(Y) = 85\% * 20[/tex]

[tex]E(Y) = 17[/tex]

Answer:

H0: μ ≤ 1.30

H1: μ > 1.30

|Test statistic | > 1.833 ; Reject H0

Test statistic = 3.11

Yes

Pvalue = 0.006

Step-by-step explanation:

H0: μ ≤ 1.30

H1: μ > 1.30

Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54

Xbar = 14.84 / 10 = 1.484

Standard deviation, s = 0.187 (calculator)

Decison rule :

|Test statistic | > TCritical ; reject H0

df = n - 1 = 10 - 1 = 9

Tcritical(0.05; 9) = 1.833

|Test statistic | > 1.833 ; Reject H0

Test statistic :

(xbar - μ) ÷ (s/√(n))

(1.484 - 1.30) ÷ (0.187/√(10))

0.184 / 0.0591345

Test statistic = 3.11

Since ;

|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased

Pvalue estimate using the Pvalue calculator :

Pvalue = 0.006

Answer:

80

Step-by-step explanation:

20+80+x=180

100+x=180

x=180-100

x=80

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Answer:

parallelogram

Step-by-step explanation:

opposite sides are parallel and equal

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ([tex]S_{5}[/tex]) = 250

or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]

or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]

or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

Answer:

Step-by-step explanation:

Discussing interest starts with the principal, or amount your account starts with. This could be a starting investment, or the starting amount of a loan. Interest, in its most simple form, is calculated as a percent of the principal. For example, if you borrowed $100 from a friend and agree to repay it with 5% interest, then the amount of interest you would pay would just be 5% of 100: $100(0.05) = $5. The total amount you would repay would be $105, the original principal plus the interest.

Answer: A, C, D

Step-by-step explanation:

A is correct because Audrey reads 40 pages a day, and David reads 20. When you divide 40 by 20, you get 2. This means that 2 times 20 would be 40, and anything multiplied by 2 is "twice".

40 ÷ 20 = 2

2 × 20 = 40

B is not correct because after 6 days, Audrey reads 240 pages, and David reads only 120. We can figure this out by multiplying the pages read by 6.

Audrey: 40 × 6 = 240

David: 20 × 6 = 120

C is correct because when you subtract 20 from 40, you get 20. Since Audrey reads 40 pages a day and David reads 20, you can use this equation: 40-20 to figure the answer out. Audrey reads 20 more pages every day.

[tex]40-20=20[/tex]

D is correct because after 2 days, Audrey will have read 80 pages, and David will have read 40 pages. When you subtract 40 from 80, you get 40 pages.

40 × 2 = 80

20 × 2 = 40

80 - 40 = 40

E is not correct because, after 3 days, Audrey will have read 120 pages, and David will have read 60 pages. One-third of 120 is 40, not 60. Three times 60 would be 180, not 120. So, This answer is incorrect.

Answer:

D. Yes, because it passes the vertical line test

Step-by-step explanation:

Answer:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

Step-by-step explanation:

Given

[tex]y = 4x[/tex]

[tex](x_1,x_2) = (x,x+1)[/tex]

Required

Show that the y values increases by 4 for [tex]x_2 - x_1 = 1[/tex]

We have:

[tex]y = 4x[/tex]

For [tex]x_1 = x[/tex]

[tex]y_1 = 4x_1[/tex]

Substitute [tex]x_1 = x[/tex]

[tex]y_1 = 4x[/tex]

For [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4x_2[/tex]

Substitute [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4(x+1)[/tex]

[tex]y_2 = 4x+4[/tex]

So, we have:

[tex]y_2 = 4x+4[/tex]

[tex]y_1 = 4x[/tex]

Subtract [tex]y_1[/tex] from [tex]y_2[/tex]

[tex]y_2 - y_1 = 4x + 4 - 4x[/tex]

Collect like terms

[tex]y_2 - y_1 = 4x - 4x+ 4[/tex]

[tex]y_2 - y_1 = 4[/tex]

Hence:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

i.e. an increment of 4

Answer:

Last Option; 84 cu. mm

Step-by-step explanation:

We know that;

Volume = 1/3(Bh)

And that this is figure has a square base, therefore B that represents the area of the base will be: 6 * 6 = 36

And height = 7mm

Therefore we can say;

Volume = (1/3)*(6 x 6)*(7)

Volume = (1/3)*(36)*(7)

Volume = (12)*(7)

Volume = 84

Hope this helps!

Answer:

c

Step-by-step explanation:

Infinite solutions. A system of linear equations has infinite solutions when the graphs are the exact same line.

So C would be the most accurate statement

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9514 1404 393

Answer:

  392 ft

Step-by-step explanation:

As in the attached figure, you seem to have sides b and c of the triangle, along with angle C. You want to find side 'a'. The law of sines can be used to find angle B, then angle A can be found from the sum of angles. Knowing angle A, we can find side 'a'.

  sin(B)/b = sin(C)/c

  sin(B) = (b/c)sin(C) = 400/550·sin(88°)

  B = arcsin(8/11·sin(88°)) ≈ 46.621°

Then angle A = ...

  A = 180° - B - C = 180° -46.621° -88° = 45.379°

Now, we can find side 'a' from ...

  a/sin(A) = c/sin(C)

  a = c·sin(A)/sin(C) ≈ 550·sin(45.379°)/sin(88°) ≈ 391.710 . . . feet

The unknown side of the triangle is about 392 feet.