Answer:x<-18
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
-1/2x+3>12
Step 2: Subtract 3 from both sides.
-1/2x+3-3>12-3
-1/2x>9
Step 3: Multiply both sides by 2/(-1).
(2/-1)*(-1/2x)>(2/-1x)*(-1/2x)
X<-18
:D
5+10/x=x+8 Solve the equation with steps
Answer:
2 and -5
Step-by-step explanation:
[tex]5+\dfrac{10}{x}=x+8 \\\\\\-3+\dfrac{10}{x}=x \\\\\\-3x+10=x^2 \\\\\\x^2+3x-10=0 \\\\\\(x+5)(x-2)=0 \\\\\\x=2,-5[/tex]
Hope this helps!
A quality control inspector has drawn a sample of 14 light bulbs from a recent production lot. If the number of defective bulbs is 1 or less, the lot passes inspection. Suppose 20% of the bulbs in the lot are defective. What is the probability that the lot will pass inspection
Answer:
0.1979 or 19.79%
Step-by-step explanation:
If 20% of all bulbs are defective, there is a 20% chance of each bulb being defective and an 80% chance of each bulb not being defective.
This is a binomial probability model with probability of success (bulb being defective) of p=0.20.
In order for the lot to pass inspection, it must contain either zero or one defective bulb, the probability of one of these scenarios occurring is:
[tex]Pass= P(d=0)+P(d=1)\\Pass= 0.80^{14}+14*0.20*0.80^{13}\\Pass=0.1979[/tex]
The probability that the lot will pass inspection is 0.1979 or 19.79%.
The image of ABC after a reflection across EG is ABC which statement is true about point F
Answer: First option.
Step-by-step explanation:
As the triangle is reflected over the line EG, this means that the distance between each common point of the triangles and the line must be the same for both triangles.
This means that the distance between B and E, is the same distance as the distance between B' and E.
Now, as you know, the midpoint of a segment is a point such that the distance between that point and each endpoint is the same.
So, in the linea AA', the points A and A' are the endpoints, and because F lies in the line of reflection, the distance between A and F is the same distance than in between A' and F.
So F is the midpoint in the line AA'
The correct option would be the first one, F is the midpoint of AA' because the line EG bisects AA', and F is colinear to E and G.
How many arrangements of the letters in the word olive can you make if each arrangement must use three letters
Answer:
60
Step-by-step explanation:
There are 5 letters that can be first.
There are 4 letters that can be second.
There are 3 letters that can be third.
The number of permutations is 5×4×3 = 60.
justify each step x/3-7=11 x/3=18 x=6
This is the steps for equation solving for the value of x,
x/3-7 = 11
now 7 goes to the other side of equation by changing the sign from - to +,
x/3 = 11 + 7
x/3 = 18
now when we multiply both sides of equation with 3 or 3 goes to the other side of equation and multiply with 18 leaving x alone here for finding the value of x,
and we get, x = 54
at the end of equation we get x = 54, if the equation was in the form 3x - 7 = 11, then we will get x = 6
The demand for the video games provided by Mid-Tech Video Games Inc. has exploded in the last several years. Hence, the owner needs to hire several new technical people to keep up with the demand. Mid-Tech gives each applicant a special test that Dr. McGraw, the designer of the test, believes is closely related to the ability to create video games. For the general population, the mean on this test is 100. Below are the scores on this first test for the applicants. 95 105 120 81 90 115 99 100 130 10 The owner is interested in the overall quality of the job applicants based on this test. Compute the mean and the median scores for the 10 applicants. What would you report to the owner
Answer:
Mean: 94.5.
Median: 99.5
Standard deviation: 33.1
We can tell the owner that the applicants don't have a score significantly below from 100.
Step-by-step explanation:
First, we analize the sample and calculate the statistics (mean, median and standard deviation).
Mean of the sample:
[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(95+105+120+81+90+115+99+100+130+10)\\\\\\M=\dfrac{945}{10}\\\\\\M=94.5\\\\\\[/tex]
The median, as the sample size is an even number, can be calculated as the average between the fifth and sixth value, sort by value:
[tex]\text{Median}=\dfrac{99+100}{2}=99.5[/tex]
The standard deviation is:
[tex]s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((95-94.5)^2+(105-94.5)^2+(120-94.5)^2+. . . +(10-94.5)^2)}\\\\\\s=\sqrt{\dfrac{9834.5}{9}}\\\\\\s=\sqrt{1092.7}=33.1\\\\\\[/tex]
To tell if this sample has a value significantly lower than the expected score of 100, we should make a hypothesis test.
The claim is that the mean score is significantly lower than 100.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=100\\\\H_a:\mu< 100[/tex]
The significance level is 0.05.
The sample has a size n=10.
The sample mean is M=94.5.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=33.1.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{33.1}{\sqrt{10}}=10.467[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{94.5-100}{10.467}=\dfrac{-5.5}{10.467}=-0.53[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=10-1=9[/tex]
This test is a left-tailed test, with 9 degrees of freedom and t=-0.53, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-0.53)=0.306[/tex]
As the P-value (0.306) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean score is significantly lower than 100.
You might need:
A circle is centered at J(3,3) and has a radius of 12.
Where does the point F(-6, -5) lie?
Choose 1 answer:
Answer:
Step-by-step explanation:
The equation of this circle is (x - 3)^2 + (y - 3)^2 = 12^2.
Let's substitute the coordinates of the given point and compare the results to the above equation: do they produce a correct statement?
(-6 - 3)^2 + (-5 - 3)^2 = ?
9^2 + 8^2 = 145
Because r = 12, the above result would need to be 144, not 145, if the given point were actually on the circle. We must conclude that (-6, -5) lies just outside the circle.
81 + 64 = 144
The weights of steers in a herd are distributed normally. The variance is 10,000 and the mean steer weight is 1400lbs. Find the probability that the weight of a randomly selected steer is between 1539 and 1580lbs. Round your answer to four decimal places.
Answer:
[tex]P(1539<X<1580)=P(\frac{1539-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{1580-\mu}{\sigma})=P(\frac{1539-1400}{100}<Z<\frac{1580-1400}{100})=P(1.39<z<1.8)[/tex]
And we can find this probability using the normal standard table with this difference:
[tex]P(1.39<z<1.80)=P(z<1.80)-P(z<1.39)= 0.9641-0.9177=0.0464[/tex]
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(1539,1580)[/tex]
Where [tex]\mu=1400[/tex] and [tex]\sigma=\sqrt{10000}= 100[/tex]
We are interested on this probability
[tex]P(1539<X<1580)[/tex]
And we can solve the problem using the z score formula given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Using this formula we got:
[tex]P(1539<X<1580)=P(\frac{1539-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{1580-\mu}{\sigma})=P(\frac{1539-1400}{100}<Z<\frac{1580-1400}{100})=P(1.39<z<1.8)[/tex]
And we can find this probability using the normal standard table with this difference:
[tex]P(1.39<z<1.80)=P(z<1.80)-P(z<1.39)= 0.9641-0.9177=0.0464[/tex]
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt-at?, to find a. In the formula, dis
displacement, vis final velocity, a Is acceleration, and t is time.
2(vt -d)=at^2
a=2(d – vt)/12
2(d-vt) = at^2
vt-d=1/2 at^2
d-vt = 1/2at^2
a=2(vt-d)/t^2
Options
[tex]2(vt -d)=at^2[/tex]
[tex]a=\frac{2(d - vt)}{t^2}[/tex]
[tex]2(d-vt) = at^2[/tex]
[tex]vt-d=\frac{1}{2} at^2[/tex]
[tex]d-vt = -\frac{1}{2}at^2[/tex]
[tex]a=\frac{2(vt-d)}{t^2}[/tex]
Answer:
See Explanation below
Step-by-step explanation:
Given
[tex]d = vt - \frac{1}{2}at^2[/tex]
Required
Steps to find a
To solve for a;
The step 1 is :
[tex]d-vt = -\frac{1}{2}at^2[/tex]
This is achieved by adding vt to both sides
The step 2 is:
[tex]vt-d=\frac{1}{2} at^2[/tex]
This is achieved by multiply both sides by -1
The step 3 is:
[tex]2(vt -d)=at^2[/tex]
This is achieved by multiplying both sides by 2
The step 4 is:
[tex]a=\frac{2(vt-d)}{t^2}[/tex]
This is achieved by dividing both sides by t²
Note that, not all steps in the option are used because they are either incorrect or not necessary
Answer:
for edmentum the answer is
Box 1: d-vt=1/2at^2
Box 2: vt-d=1/2at^2
Box 3: 2(vt-d)/t^2
Step-by-step explanation: Almost certain after scrounging Brainly.
Good luck!
A study conducted by Harvard Business School recorded the amount of time CEOs devoted to various activities during the workweek. Meetings were the single largest activity averaging 18 hours per week. Assume that the standard deviation for the time spent in meetings is 5.2 hours. To confirm these results, a random sample of 35 CEOs was selected. This sample averaged 16.8 hours per week in meetings. Which of the following statements is correct?
a. The interval that contains 95% of the sample means is 16.3 and 19.7 hours. Because the sample mean is between these two values, we have support for the results of the CEO study by the Harvard Business School.
b. The interval that contains 95% of the sample means is 17.1 and 18.9 hours. Because the sample mean is not between these two values, we do not have support for the results of the CEO study by the Harvard Business School.
c. The interval that contains 95% of the sample means is 15.7 and 20.3 hours. Because the sample mean is between these two values, we have support for the results of the CEO study by the Harvard Business School.
d. The interval that contains 95% of the sample means is 15.7 and 20.3 hours. Because the sample mean is between these two values, we do not have support for the results of the CEO study by the Harvard Business School
Answer:
a. The interval that contains 95% of the sample means is 16.3 and 19.7 hours. Because the sample mean is between these two values, we have support for the results of the CEO study by the Harvard Business School.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 18, \sigma = 5.2, n = 35, s = \frac{5.2}{\sqrt{35}} = 0.879[/tex]
95% of the sample means:
From the: 50 - (95/2) = 2.5th percentile.
To the: 50 + (95/2) = 97.5th percentile.
2.5th percentile:
X when Z has a pvalue of 0.025. So X when Z = -1.96.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]-1.96 = \frac{X - 18}{0.879}[/tex]
[tex]X - 18 = -1.96*0.879[/tex]
[tex]X = 16.3[/tex]
97.5th percentile:
X when Z has a pvalue of 0.975. So X when Z = 1.96.
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]1.96 = \frac{X - 18}{0.879}[/tex]
[tex]X - 18 = 1.96*0.879[/tex]
[tex]X = 19.7[/tex]
95% of the sample means are between 16.3 and 19.7 hours. This interval contains the sample mean of 16.8 hours, which supports the study.
So the correct answer is:
a. The interval that contains 95% of the sample means is 16.3 and 19.7 hours. Because the sample mean is between these two values, we have support for the results of the CEO study by the Harvard Business School.
5:36, 2:9, 3:18, 1:3 what is the largest ratio? please help me!
Answer:
[tex]1:3[/tex]
Step-by-step explanation:
[tex]5:36=5/36[/tex]
[tex]\approx 0.13888888888[/tex]
[tex]2:9=2/9[/tex]
[tex]\approx 0.22222222222[/tex]
[tex]3:18=1/6[/tex]
[tex]\approx 0.16666666666[/tex]
[tex]1:3=1/3[/tex]
[tex]\approx 0.33333333333[/tex]
Answer:
1:3
Step-by-step explanation:
GCF of 36, 9, 18, 3 is 36
5:36
2:9= 8:36
3:18= 6:36
1:3= 12:36
1:3 is the largest ratio.
Which is the better buy?. Store A $180 at 1/3 off Or Store B $110 at 10% off
Answer: Store B
Step-by-step explanation:
180 / 3 = 60. 180 - 60= $120. Store A cost is $120.
110 * 0.9 = $99. Store B's cost is $99.
Answer:
Store B
Step-by-step explanation:
Store A the price would be about $120.60
Store B price would be about $99
To find store a price, you first find the discount, so
0.33 x 180 = 59.40
Then subtract this from the original price to know the total after the discount
180-59.40=120.60
Do the same thing with the other Store
110 x 0.10 = 11
110-11=99
Which are the possible side lengths of a triangle?
O 3 cm, 5 cm, 9 cm
O 4 cm, 8 cm, 10 cm
O 6 cm, 9 cm, 17 cm
O 8 cm, 10 cm, 18 cm
Answer:
4 cm, 8 cm, 10 cm
Step-by-step explanation:
For a triangle to exist, two sides added up must be greater than the third side. The only quantities that satisfy this relationship is the second option.
A student said that the y-intercept of the function y = 3 · 4x is 4. What is their mistake? What is the actual y-intercept?
Answer:
The y intercept is 0Step-by-step explanation:
the equation of a line is given as
[tex]y= mx+c[/tex]
where
m= is the slope
c= is the y intercept
their mistake is that they did not recall that if the "c" is not shown, it is assumed to be zero (0)
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is the temperature of the food. When the food is removed from the refrigerator, the temperature is given by T ( t ) = 8 t + 1.7 , where t is the time in hours. Find the composite function N ( T ( t ) ) : N ( T ( t ) ) = Find the time when the bacteria count reaches 8019. Time Needed = hours
Answer:
[tex]N(T(t)) = 1408t^2 - 385.6t - 105.52[/tex]
Time for bacteria count reaching 8019: t = 2.543 hours
Step-by-step explanation:
To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:
[tex]N(T(t)) = 22 * (8t + 1.7)^2 - 123 * (8t + 1.7) + 40[/tex]
[tex]N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40[/tex]
[tex]N(T(t)) = 1408t^2 + 598.4t + 63.58 - 984t - 169.1[/tex]
[tex]N(T(t)) = 1408t^2 - 385.6t - 105.52[/tex]
Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:
[tex]8019 = 1408t^2 - 385.6t - 105.52[/tex]
[tex]1408t^2 - 385.6t - 8124.52 = 0[/tex]
Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.
if segment ac and segment bc are tangent to circle o find the value of x
Answer:
x = 150°
Step-by-step explanation:
Start by cutting the shape into two triangles by bisecting the 30°
Now we have two triangles that have two angles 90° and 15°
Subtract 15° from 90°, you'll get 75°
Double 75° because x is split into 2
150° = x
Also, were given 3 angles, this is a quadrilateral.
90° + 90° + 30° = 210°
360° - 210° = 150°
Answer:
150°
Step-by-step explanation:
OA⊥AC and OB⊥BC
∠A+∠B+∠C+∠O=360°
90°×2+30°+x=360°
x=360°-210°=150°
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that the highest bid in excess of $10,100 will be accepted. Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,100 and $14,700. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)
Answer:
[tex] P(X<12000)[/tex]
And for this case we can use the cumulative distribution function given by:
[tex] P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b[/tex]
And using this formula we have this:
[tex] P(X<12000)= \frac{12000-10100}{14700-10100}= 0.41[/tex]
Then we can conclude that the probability that your bid will be accepted would be 0.41
Step-by-step explanation:
Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:
[tex] X \sim Unif( a= 10100, b =14700)[/tex]
If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:
[tex] P(X<12000)[/tex]
And for this case we can use the cumulative distribution function given by:
[tex] P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b[/tex]
And using this formula we have this:
[tex] P(X<12000)= \frac{12000-10100}{14700-10100}= 0.41[/tex]
Then we can conclude that the probability that your bid will be accepted would be 0.41
On August 1, 2021, a company accepts an $8,000, 9-month note receivable. For 2021, the company reports interest revenue of $200. What is the interest rate on the note?
Answer:
6%
Step-by-step explanation:
We have to calculate the interest rate in the note, we must follow the following steps, calculate the amount of time remaining from the year 2021, as follows:
interest is for 5 months i.e. from Aug 01 to Dec 31 for year 2021 , so it means it would be 5/12 months.
We have to calculate the interest as follows:
I = P * R * T
We replace:
200 = 8000 * R * 5/12
we solve for R
200 * 12/5 = 8000 * R
R * 8000 = 480
R = 480/8000
R = 0.06
Which means that the interest rate on the note is 6%
Find the vertex of the graphed function.
f(x) = |x-4| +3
AY
00
6
4
2
Y
4
The vertex is at
Answer:
The x-coordinate is the solution to x - 4 = 0, which is x = 4 and the y-coordinate is 3 so the answer is (4, 3).
The FDA regulates that fresh Albacore tuna fish that is consumed is allowed to contain 0.82 ppm of mercury or less. A laboratory is estimating the amount of mercury in tuna fish for a new company and needs to have a margin of error within 0.023 ppm of mercury with 97% confidence. Assume the population standard deviation is 0.143 ppm of mercury. What sample size is needed? Round up to the nearest integer, do not include any decimals. Answer:
Answer:
[tex]n=(\frac{2.17(0.143)}{0.023})^2 =182.03 \approx 183[/tex]
So the answer for this case would be n=183 rounded up to the nearest integer
Step-by-step explanation:
Information provided
[tex]\bar X[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
[tex]\sigma = 0.143[/tex] represent the population standard deviation
n represent the sample size
[tex] ME = 0.023[/tex] the margin of error desired
Solution to the problem
The margin of error is given by this formula:
[tex] ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (a)
And on this case we have that ME =0.023 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex] (b)
The confidence level is 97% or 0.97 and the significance would be [tex]\alpha=1-0.97=0.03[/tex] and [tex]\alpha/2 = 0.015[/tex] then the critical value would be: [tex]z_{\alpha/2}=2.17[/tex], replacing into formula (5) we got:
[tex]n=(\frac{2.17(0.143)}{0.023})^2 =182.03 \approx 183[/tex]
So the answer for this case would be n=183 rounded up to the nearest integer
please help, me find the area of Letter E.
Answer:
7.005 m^2.
Step-by-step explanation:
We can split this into one vertical rectangle 3.45 * 0.9 m^2
2 rectangles 2 * 0.75 = 1.5 m^2
1 rectangle 1.2 * 0.75 m^2
= 3.105 + 2 * 1.5 + 0.9
= 7.005 m^2.
Please show work for number 3 and 4!
Answer:
Three: x = 400
Four : 9
Step-by-step explanation:
Three
a = 10*√2
2a = √(2x) Square both sides.
4a^2 = 2x Divide both sides by 2
2a^2 = x Put a = 10√2 into a^2
2(10√2)^2 = x Square a
2(100*2) = x Multiply the result by 2.
2(200) = x
x = 400
Four
x^(a^2) / x ^(b^2) = x^36
Substitute a + b = 4 in for b.
x^(a^2) / x^(4 - a)^2 = x^36
Subtract powers
x^(a^2 - (4 - a)^2 = x^36
x^(a^2 - (16 - 8a + a^2) = x^36
Gather like terms
x^(8a - 16) = x^36
The powers are now equal
8a - 16 = 36
Add 16 to both sides
8a = 36 + 16
8a = 52
Divide by 8
a = 6.5
Solve for b
a + b = 4
6.5 + b = 4
b = 4 - 6.5
b = - 2.5
a - b = 6.5 - (- 2.5) = 9
If sin(18+x)=cos58 find value of x
Answer:
14
Step-by-step explanation:
Since sine and cosine are cofunctions of each other:
[tex]\sin (\theta)= \cos (90-\theta)[/tex]
and vice versa. Therefore:
[tex]18+x=90-58 \\\\18+x=32 \\\\x=32-18=14[/tex]
Hope this helps!
If AYWZ - AYXW, what is true about ZXWZ?
O ZXWZ is an obtuse angle.
ZXWZ is a right angle,
ZXWZ is congruent to ZWXY.
ZXWZ is congruent to ZXZW.
Answer:
<XWZ is a right angle
Step-by-step explanation:
Since <YWZ and <XWY both equal 45 degrees, So, <XWZ is a right angle.
Given that ΔYWZ and ΔYXW are similar triangles, the statement that is true about ΔYXW is: B. XWZ is a right angle,
Similar TrianglesTriangles that are similar possess equal corresponding angles.
We are given that:
ΔYWZ ~ ΔYXW
Therefore:∠YWZ = ∠XWY = 45 degrees
Thus:∠YWZ + ∠XWY = ∠XWZ
45 + 45 = ∠XWZ
∠XWZ = 90 degrees (right angle).
Therefore, given that ΔYWZ and ΔYXW are similar triangles, the statement that is true about ΔYXW is: B. XWZ is a right angle,
Learn more about similar triangles on:
https://brainly.com/question/2644832
Pleasssseeee hheeelllppp
Answer:
No
Step-by-step explanation:
They are not congruent or similar because the figures themselves indicate no similar or congruent parts. Although they may seem congruent or similar, without telling us one thing, we cannot assume that they are similar or congruent.
In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that the average price of the rooms in the sample was $108.50 with a standard deviation of $16.
a) Formulate the null and alternative hypotheses to determine whether or not the average room price is significantly different from $112.
b) Compute the test statistic.
c) Using the p-value approach, what is your conclusion? Let alpha = .05.
d) Using the critival value approach, what is your conclusion? Let alpha = .05.
e) Write a concluding statement based on your answers above.
Answer:
C
Step-by-step explanation:
5.27 + 3.5
Find the value of
7.9 - 4.36
Give your answer as a decimal.
Write down all the figures on your
calculator display.
Answer:
The value of 7.9-4.36 is 3.54
The value of 5.27 + 3.5 is 8.77
Step-by-step explanation:
6 identical toys weigh 1.8kg how much would 4 weigh
Answer:
1.2kg
Step-by-step explanation:
6 identical toys weigh 1.8kg.
1 toy would weigh:
1.8/6 = 0.3
0.3 kg.
Multiply 0.3 with 4 to find how much 4 identical toys would weigh.
0.3 × 4 = 1.2
4 identical toys would weigh 1.2kg
Answer:
[tex]1.2kg[/tex]
Step-by-step explanation:
6 identical toys weigh = 1.8kg
Let's find the weight of 1 toy ,
[tex]1.8 \div 6 = 0.3[/tex]
Now, lets find the weigh of 6 toys,
[tex]0.3 \times 4 = 1.2kg[/tex]
PLEASEEEE HELLLPPPP COMPARING EXPONENTIAL FUNCTIONS ...an online retailer developed two exponential functions to model the weekly usage of two coupon codes where x os the number of weeks since the start of the year.
Answer:
A. The weekly usage of both coupons is decreasing and approaching a horizontal asymptote as x gets larger.
Step-by-step explanation:
You can see that f(x) is a decreasing exponential function because the base is 0.75, a value less than 1. The horizontal asymptote is 10, the constant added to the exponential term.
Obviously, g(x) is decreasing. If we assume it is an exponential function, we know there is a horizontal asymptote. (Every exponential function has a horizontal asymptote.)
__
If you use your graphing calculator's exponential regression function, you can find a good model for g(x) is ...
g(x) = 950·0.7^x +12
That is, it is an exponential function that decays faster than f(x), but has a higher horizontal asymptote.
_____
Both functions are decreasing and approaching horizontal asymptotes.
Keisha, a scheduler at Mangel-Wurzel Transport, gets a call from a regular customer needing to move 70.3 m^3 of rock and soil, which Keisha knows from previous experience has an average density of 880 kg/m^3. Keisha has available a dump truck with a capacity of 9 m^3 and a maximum safe load of 5300. kg. Calculate the number of trips the dump truck will have to make to haul the customer's load away.
Answer:
Step-by-step explanation:
You take 70.3m^3 multiple with 880kg /m^3 divide with 5300.kg will give you the answer cause I tried it and it worked 100% true.
I hope tis helps .