Answer: [tex]\dfrac{d-0.5at^2}{t}=v_i[/tex]
Explanation:
[tex]d=v_it+0.5at^2\\\\\\\text{Subtract}\ 0.5at^2\ \text {from both sides:}\\d-0.5at^2=v_it\\\\\\\text{Divide both sides by t:}\\\dfrac{d-0.5at^2}{t}=v_i[/tex]
Question 1 of 10
Which situation is most likely to lead to improving a scientific theory?
O A. Development of new technologies
B. Relaxing government restrictions
C. Repeating an experiment to verify results
D. Increased funding for research
Answer:
The correct option is;
C. Repeating an experiment to verify results
Explanation:
A scientific theory is a statement explaining an observed natural phenomenon which can be simulated for verification ensuring that all protocols of the scientific method of investigation are observed.
By repeating the experiment under particular conditions such as through verification of data from direct observation such as in astronomy, a scientific theory can be improved by pointing out the natural behavior of the phenomenon to better clarify the assumptions made in the theory.
Answer:
Developing new technologies.
Explanation:
A car travels 30.0 km to the south and then turns around and travels 20.0 km to the north in 1.5 hours time. What is the car's total displacement? What is the car's average velocity?
Total displacement = ______ km S
Average velocity = ________ km/h S
Explanation:
Total displacement =30+20=50 Km
Average velocity =displacement /time
V=50/1.5=33.33km/hr
Answer:
Total Displacement: 10
Average velocity, closest option is 10.
Explanation:
30-20=10
how does an atom charge if all the electrons are removed
Answer: its does not have any charge but it still might have nuetrons.
Explanation:
Answer:
it will change to become a positively charged ion called a cation.
Explanation:
Ions are formed when an atom gains or loses electrons from its valence shell. This process causes an imbalance between the number of positively charged protons and negatively charged electrons, so the overall ion will carry a net positive or negative charge (I got this explanation from google)
Sort the length measurements in increasing order of magnitude from smallest to largest Drag each tile to the correct box Tiles Sequence micrometer Kilometer decimeter centimeter nanometer dekameter
Answer:
Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer
Explanation:
Given the following length measurement :
micrometer Kilometer decimeter centimeter nanometer dekameter.
Sorting in increasing order of magnitude from Smallest to Largest.
Expressing in terms of meters :
1 meter = 0.1 decameter
1 meter = 1 × 10^9 nanometer
1 meter = 1 × 10^2 centimeter
1 meter = 1 × 10^1 decimeter
1 meter = 0.001 kilometer
1 meter = 1 × 10^6 micrometers
Hence, arranging from Smallest to Largest :
Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer
88 L + 120 dL = _____________ L?
Answer:
100 L
Explanation:
10 dL = 1 L
A man dropped a dime in a wishing well, he heard it 10 sec later Find velocity on impact
Answer:
Vf = 98 m/s
Explanation:
The dime is in a free fall motion under the influence of gravity. For the final velocity of the dime, we use 1st equation of motion here:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (Since, the initially the dime was at rest)
g = acceleration due to gravity = 9.8 m/s²
t = time taken = 10 s
Therefore, using these values, we get:
Vf = 0 m/s + (9.8 m/s²)(10 s)
Vf = 98 m/s
How many weeks are in 309 seconds?
Not even a week. If you looking for a number it would be 0.00051091. Again not even a week.
Answer:
0.000510913 weeks...
Not even one week.
What is the formula for finding the perimeter of a space?
Answer:
What shape is it? the formula is different depending on the shaping
Explanation:
Square P=4s
Rectangle P=2L+2W
Triangle a+b+c
Circle P=C=2πr=πd
and so on
From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m/s. Calculate the initial recoil velocity of the rifle.
[tex]\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}[/tex]
Mass of rifle = 4kg
Mass of bullet = 50g = 0.05kg
Initial velocity of bullet = 35m/s
[tex]\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}[/tex]
Recoil velocity of rifle.
[tex]\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}[/tex]
Recoil velocity of rifle is given by
[tex]\dag\:\boxed{\bf{\purple{V=-\dfrac{mv}{M}}}}[/tex]
M denotes mass of riflem denotes mass of bulletv denotes velocity of bullet[tex]:\implies\sf\:V=-\dfrac{mv}{M}[/tex]
[tex]:\implies\sf\:V=-\dfrac{0.05\times 35}{4}[/tex]
[tex]:\implies\sf\:V=-\dfrac{1.75}{4}[/tex]
[tex]:\implies\bf\:V=-0.437\:ms^{-1}[/tex]
[Note : -ve sign shows opposite direction]
Answer:
MgVg=MbVb.
4×Vg=0.05×35.
4Vg=1.75.
Vg=1.75/4
=0.4375 ~ 0.4m/s.
A train travels due north in a straight line with a constant speed of 100 m/s. Another train leaves a station 2,881 m away traveling on the same track, but traveling due south with a constant speed of 136 m/s. At what position will the trains collide? Round to the nearest whole number.
Answer:
The trains will collide at a distance 1660 m from the station
Explanation:
Let the train traveling due north with a constant speed of 100 m/s be Train A.
Let the train traveling due south with a constant speed of 136 m/s be Train B.
From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).
Hence, the two trains would have traveled a total distance of 2,881 m by the time they collide.
∴ If train A has covered a distance [tex]x[/tex] m by the time of collision, then train B would have traveled [tex](2881 - x)[/tex] m.
Also,
At the position where the trains will collide, the two trains must have traveled for equal time, t.
That is, At the point of collision,
[tex]t_{A} = t_{B}[/tex]
[tex]t_{A}[/tex] is the time spent by train A
[tex]t_{B}[/tex] is the time spent by train B
From,
[tex]Velocity = \frac{Distance }{Time }\\[/tex]
[tex]Time = \frac{Distance}{Velocity}[/tex]
Since the time spent by the two trains is equal,
Then,
[tex]\frac{Distance_{A} }{Velocity_{A} } = \frac{Distance_{B} }{Velocity_{B} }[/tex]
[tex]{Distance_{A} = x[/tex] m
[tex]{Distance_{B} = 2881 - x[/tex] m
[tex]{Velocity_{A} = 100[/tex] m/s
[tex]{Velocity_{B} = 136[/tex] m/s
Hence,
[tex]\frac{x}{100} = \frac{2881 - x}{136}[/tex]
[tex]136(x) = 100(2881 - x)\\136x = 288100 - 100x\\136x + 100x = 288100\\236x = 288100\\x = \frac{288100}{236} \\x = 1220.76m\\[/tex]
[tex]x[/tex]≅ 1,221 m
This is the distance covered by train A by the time of collision.
Hence, Train B would have covered (2881 - 1221)m = 1660 m
Train B would have covered 1660 m by the time of collision
Since it is train B that leaves a station,
∴ The trains will collide at a distance 1660 m from the station.
Dr. Sampson is studying the effects of caffeine on hunger. He hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. He then has the two groups journal their hunger pangs throughout the day and he compares the results. In this study, the experimental group consists of the participants who:
Answer:
The participants who were given the coffee
Explanation:
This is the group which the experiment is centered or focused around in order to achieve a result of derive informations regarding their exposure to some things.
Dr. Sampson is studying the effects of caffeine on hunger which means he hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. All this talks about The participants who were given the coffee being the experimental group
pls pls pls answer fast
Answer:
a) The maximum speed of the bus is 10 m/s
b) The bus was stationary for 3 seconds
c) The total distance travelled is about 126 m
d) The average velocity of the bus is approximately 5.04 m/s
Iron (II) hydroxide, whose chemical formula is shown here, is soluble in different solutions. In which solution would the Iron (III) hydroxide be LEAST soluble? A) OM (distilled water) B) 0.2M Fe3+ 0.5M Fe3- D) 1.0M Fe3-
Answer:
Explanation:
b 0.2m
Answer:
D. 1.0M Fe3+
Explanation:
I just took a took a test on this exact question.
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4
Answer:
3 Mg, 2 P, 14 O, 12 H
Explanation:
Se suelta una piedra cerca de la superficie lunar y cae libremente durante 7 segundos. La aceleración de la gravedad lunar es de 1,6 m/s² ¿qué velocidad alcanzará?
Answer:
v = 11.2 m/s
Explanation:
A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?
Given that,
The acceleration due to the gravity of lunar gravity is 1.6 m/s²
A stone is dropped near the lunar surface and falls freely for 7 seconds.
We need to find the speed with which it reach.
The initial velocity of the stone will be 0 as it was at rest.
Using equation of kinematics v=u+at
[tex]v=1.6\times 7\\\\v=11.2\ m/s[/tex]
So, the stone will reach with a speed of 11.2 m/s
The slowest moving animal is a crab found in the Red Sea. It travels with an average speed of 5.7 Km/year How long will it take this animal to travel 100 km?
Time = distance / speed
Time = (100 km) / (5.7 km/yr)
Time = 17.5 years
If this is true, then it's not likely that any member of the species has ever traveled 100 km in its lifetime. Weird !
An athlete participating in cross-country spends the afternoon practicing, and at the end is completely exhausted from all the hard word, even though their average velocity during the practice was 0 m/s. Explain how this situation is possible.
Answer: please find the answer in the explanation
Explanation:
Velocity is the distance covered in a specific direction per time taken.
And in velocity, we have final velocity V and initial velocity U.
The definition of average velocity is:
Average velocity = (V + U)/2
Since velocity involves direction, if the initial velocity U is of the same magnitude as the final velocity V and both are of opposite direction. Then,
Average velocity = (-U + V)/2
Since they are of the same magnitude,
V = U.
Therefore,
Average velocity = (-U + U)/2 = 0
could you guys help me with homework it's due tommorow
Answer:
d students show that stress can make people sick
Referring to the image below (based on vectors physics), how does he get F2X = F2Cosθ. I don't understand how he got the equation so that he knows there are equal. I circled it in orange.
Answer:
Please see explanation below
Explanation:
Recall that trigonometric functions like cosine (cos) and sine (sin) of an angle are defined based on the relationships between the sides and hypotenuse of a right angle triangle:
[tex]sin(\theta)=\frac{opposite}{hypotenuse} \\cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]
where the terms "opposite" and "adjacent" refer to the sides opposite and adjacent to the angle in question.
Based on such, one can solve for example for the "adjacent" side (the horizontal component of the 200 N vector you need to find) to the known angle ([tex]\theta[/tex]) in the following way:
[tex]cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(30^o)=\frac{adjacent}{200}\\adjacent=200\,\,cos(30^o)[/tex]
Car A is travelling with a constant speed of 30 m/s and Car B is travelling with a constant speed of 110 km/h. Which car is travelling at a faster speed?
Answer:
Car B is travelling at a faster speed
Explanation:
We are given;
Speed of car A; V_a = 30 m/s
Speed of car B; V_b = 110 km/h
Now, V_a is already in m/s, so let's convert V_b to m/s too.
From conversions, 36 km/h = 10 m/s, therefore, 110 km/h would give;
(110 × 10)/36 = 30.56 m/s
Thus, V_b = 30.56 m/s
Comparing both speeds in m/s, we can see that 30.56 m/s > 30 m/s.
Thus, Car B is travelling at a faster speed.
1/2mv^2+Fd=mgh solve for F
Answer:
[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]
Explanation:
Step 1: Write out equation
[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]
Step 2: Subtract FD on both sides
[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]
Step 3: Subtract mgh on both sides
[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]
Step 4: Divide both sides by -d
[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]
Step 5: Rewrite
[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]
During a baseball game, a batter hits a pop-up to a fielder 93 m away.The acceleration of gravity is 9.8 m/s2.If the ball remains in the air for 5.4 s, howhigh does it rise?Answer in units of m
Explanation:
It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m
The ball remains in the air for 5.4 s, the time of flight is 5.4 s
Time of flight : [tex]T=\dfrac{2v\sin\theta}{g}[/tex]
[tex]5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46[/tex]
Maximum height of the projectile : [tex]H=\dfrac{v^2\sin^2\theta}{2g}[/tex]
We need to find H.
So,
[tex]H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m[/tex]
So, it will rise to a height of 35.72 m.
Where is the Oort cloud located?
O between the orbit of Mars and the orbit of Jupiter
O in the different orbits between the sun and Neptune
O beyond the Kuiper belt, at the farthest end of the solar system
O all over the solar system and between the orbits of the planets
Answer: C
Explanation: just did it
Answer:
C
Explanation:
edg 2021 AP Physc
4. If a person runs at 4 m/s for 2 minutes, how far will they run?
Answer:
48 metresExplanation:
[tex]Speed = 4m/s\\Time = 2m = 120 secods\\\\Distance = ?\\Distance = Speed \times time \\\\Distance = 4 \times 12\\= 48\: meters[/tex]
The distance covered by the person is 480 meters.
We have a a person who runs at 4 m/s for 2 minutes.
We have to determine how far he had run.
What is the formula to calculate the distance travelled by the moving body?The distance travelled by the body can be given by -
d = v x t
where -
v - velocity of body
t - time for which the body travelled
According to question, we have -
v = 4 m/s
t = 2 minutes = 120 seconds
Therefore, the distance travelled will be -
d = v x t
d = 4 x 120
d = 480 meters
Hence, the distance covered by the person is 480 meters.
To solve more questions on Kinematics, visit the link below -
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A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 5.00 m/s, and her takeoff point is 1.30 m above the pool.
Required:
a. How long are her feet in the air?
b. What is her highest point above the board?
c. What is her velocity when her feet hit the water?
Answer:
a
t = 1.235 s
b
[tex]h_{max} = 2.55 \ m[/tex]
c
[tex]v = -7.10 m/s[/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]u = 5.0 \ m/s[/tex]
The take of height is [tex]h = -1.30 \ m[/tex]
The negative sign show that the height is on the negative y-axis when the take off point is consider as the origin
Generally from the kinematic equation we have that
[tex]s = ut + \frac{1}{2}at^2[/tex]
=> [tex]-1.30 = 5.0 t + \frac{1}{2} (-9.8)t^2[/tex]
Here g is negative given that the swimmers jump motion is against gravity
[tex]4.9t^2 - 5t - 1.30[/tex]
solving using quadratic formula we obtain that
t = 1.235 s
Generally the highest point is mathematically evaluated as
[tex]h_{max} = \frac{v^2 - u^2 }{2 * (-g) }[/tex]
Here v = 0 m/s since the velocity at the highest point is 0
[tex]h_{max} = \frac{0^2 - 5^2 }{2 * (-9.8) }[/tex]
[tex]h_{max} = 2.55 \ m[/tex]
Generally her velocity when the feet hits the water is mathematically evaluated from kinematic equation as
[tex]v = \pm \sqrt{ u^2 + 2 (-g) * (-h)}[/tex]
[tex]v = -7.10 m/s[/tex]
The negative value of the velocity is selected because the velocity is on the negative y-axis
If the 20-mm-diameter rod is made of A-36 steel and the stiffness of the spring is k = 61 MN/m , determine the displacement of end A when the 60-kN force is applied. Take E = 200 GPa.
Answer:
σ = 1.09 mm
Explanation:
Step 1: Identify the given parameters
rod diameter = 20 mm
stiffness constant (k) = 55 MN/m = 55X10⁶N/m
applied force (f) = 60 KN = 60 X 10³N
young modulus (E) = 200 Gpa = 200 X 10⁹pa
Step 2: calculate length of the rod, L
K = \frac{A*E}{L}K=
L
A∗E
L = \frac{A*E}{K}L=
K
A∗E
A=\frac{\pi d^{2}}{4}A=
4
πd
2
d = 20-mm = 0.02 m
A=\frac{\pi (0.02)^{2}}{4}A=
4
π(0.02)
2
A = 0.0003 m²
L = \frac{A*E}{K}L=
K
A∗E
L = \frac{(0.0003142)*(200X10^9)}{55X10^6}L=
55X10
6
(0.0003142)∗(200X10
9
)
L = 1.14 m
Step 3: calculate the displacement of the rod, σ
\sigma = \frac{F*L}{A*E}σ=
A∗E
F∗L
\sigma = \frac{(60X10^3)*(1.14)}{(0.0003142)*(200X10^9)}σ=
(0.0003142)∗(200X10
9
)
(60X10
3
)∗(1.14)
σ = 0.00109 m
σ = 1.09 mm
Therefore, the displacement at the end of A is 1.09 mm
Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially atx1 = 14.7 mm.In this configuration, q1 exerts a repulsive force of 2.62 µN on q2. Particle q2 is then moved tox2 = 18.0 mm.What is the force (magnitude and direction) that q2 exerts on q1 at this new location? (Give the magnitude in µN.)
Answer:
The force magnitude is 1.75 μN acting outward from the origin towards x₂
Explanation:
The given parameters, are;
The location of q₁ = The origin
The location of q₂ = 14.7 mm from q₁
The repulsive force exerted on q₂ by q₁ = 2.62 μN
The location the particle q₂ is located to = 18.0 mm from q₁
By Coulomb's law, we have;
[tex]F = k\dfrac{q_1 \times q_2 }{r^2}[/tex]
Where;
k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)
r = The distance between the particles
F = The force acting between the particles
When r = 14.7 mm F = 2.62 μN
∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸
q₂ × q₁ = 1.48 × 10⁻¹⁸ C²
When the distance is increased to 18.0 mm, we have;
F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N
∴ F = 1.75 μN.
Therefore;
The force magnitude is 1.75 μN outward from the origin towards x₂.
To magnitude of the force that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location is 1.75 µN.
Given the following data:
Initial distance of [tex]q_2[/tex] = 14.7 mm to m = 0.0147 meter.Repulsive force = 2.62 µNFinal distance of [tex]q_2[/tex] = 18.0 mm to m = 0.018 meter.Scientific data:
Coulomb's constant = [tex]8.99 \times 10^9\; Nm^2/C^2[/tex]To calculate the force (magnitude and direction) that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location, we would apply Coulomb's law:
The force in an electric field.Mathematically, the force in an electric field is given by this formula:
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
Where:
k is Coulomb's constant.q is the charge.r is the distance.[tex]q_1q_2 =\frac{F}{k} \times r^2\\\\q_1q_2 =\frac{2.62 \times 10^{-6}}{8.99 \times 10^9} \times 0.0147^2\\\\q_1q_2 = 2.914 \times 10^{-16} \times 0.00021609\\\\q_1q_2 = 6.30 \times 10^{-20}\;C^2[/tex]
For the force, when r = 0.018:
[tex]F =\frac{8.99 \times 10^9 \times 6.30 \times 10^{-20}}{0.018^2} \\\\F =\frac{5.66 \times 10^{-10}}{0.000324} \\\\F = 1.75 \times 10^{-6}[/tex]
Note: 1 µN = [tex]1 \times 10^{-6}\;N[/tex]
Force, F = 1.75 µN.
In conclusion, the direction of the force at the new location is outward from the origin along [tex]X_2[/tex].
Read more on electric field here: https://brainly.com/question/14372859
Select the correct images.
Identity the electromagnets with poles that are reversed from the electromagnet shown above.
Answer:
I think it is the third one
Explanation:
Everything about it is flipped
The electromagnets with poles that are reversed from the electromagnet is according to image C.
What is magnet?A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.
A bar is a magnet which can attract the particle which are charged. It has two poles North and South.
The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.
An electromagnet is a soft metal core made into a magnet by the passage of electric current through a coil surrounding it.
When the poles are reversed, then the direction of current flow is also reversed.
Thus, the correct option is C.
Learn more about magnet.
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A car travels a distance of 98 meters in 10.0 seconds. What is the average speed of the car during this 10.0 second interval?
Answer:
9.8 m/s
Explanation:
Distance Traveled = 98 m
Total Time = 10 s
Average Speed = Total Distance/Total Time
= 98/10
= 9.8 m/s
Hope this helped...
A bus is mobing with aspped of 72km/hr .convert this speed in m/s.
Answer
ANSWER WITH FULL EXPLANATION
If a speed is given km/h, then the formula to convert the speed from km/h to m/s is
km/h = m/s
In other words, if you want to convert the given speed from km/h to m/s, then multiply the given number by and put "m/s" after it.
The speed of a car is 72 km/h.
Converting the speed into m/s
72 km/h = m/s = 20 m/s
∴ The speed of the car (expressed in m/s) is 20 m/s.
SHORT ANSWER
1km/h=5/18m/s
72km/h=72×5/18m/s
=4×5m/s
=20m/s.
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