Solve for x. Round to the nearest tenth, if necessary.

Answer:

The interquartile range is 30

Step-by-step explanation:

Here, we want to get the interquartile range

We start by arranging the numbers in order

10,20,30,40

The first quartile is;

(n + 1)/4 th term = (4+ 1)/4 = 5/4 = 1.25

This is approximately the first term = 10

Q3 is the third quartile

That is;

3(n + 1)/4 = 3(5)/4 = 15/4 =3.75

This is approximately the 4th term = 40

The interquartile range is the difference between the first and third quartile

Mathematically, we have that as;

40 - 10 = 30

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but I guess that you want to find the population of the cats in Year 1. This will be represented by x. Therefore,

x + (25% × x) = 60

x + (0.25 × x) = 60

x + 0.25x = 60

1.25x = 60

x = 60/1.25

x = 48

The population of cats in year 1 is 48

Answer:

16

Step-by-step explanation:

3x-8=2x

x=8

QR=2*8=16

Answer:

x = 7

Step-by-step explanation:

In order to get an unbiased sample of interest in soccer, the school survey should be conducted D. every fifth student entering the cafeteria.

Sampling methods are methods used to select a sample using specific methods. This includes various types of probability sampling and non probability sampling methods.

Given that,

Brookwood High School is considering adding co-ed soccer to the sports program for the fall season.

We need to get an unbiased sample of interest.

If the survey is conducted only among the members of the soccer team, the result will be biases because only the interest of someone in the team is known.

Similarly, in the case of students in freshman homerooms and girls in PE class.

If we select every fifth student entering the cafeteria, there is a chance for all the levels of students to be included which eliminates the possible bias.

Hence the option is D.

Learn more about Sampling Methods here :

https://brainly.com/question/12902833

#SPJ3

Answer:

[tex]\sqrt{61}[/tex]

Step-by-step explanation:

x = 6 units horizontally

y = 5 units vertically

Use the pythagorean theorem[tex]\sqrt{x^{2} + y^{2} } = L[/tex]

Plug x and y into the equation, and you will get [tex]\sqrt{61}[/tex] as the length.

Answer:

7.8 units (which is to the nearest tenth)

Step-by-step explanation:

We apply the Pythagorean Theorem here; the length of the line is the length of the hypotenuse of a triangle whose horizontal leg length is 6 and whose vertical leg length is 5 units.  This Theorem is expressed symbolically as

a^2 + b^2 = c^2.  In this particular case, a = 6, b = 5 and c is to be determined.  Performing the calculations, we get

6^2 + 5^2 = c^2, or:

36 + 25 = 61 = c^2

Taking the positive square root of both sides, we get c = √61 ) exactly,

which rounds off to 7.8 units (to the nearest tenth).

The length of the line is 7.8 units.

Answer: used the synthetic division method

y^2+9y-28+(62/y+2)

Step-by-step explanation:

Answer:

that's The truth

Step-by-step explanation:

that's more like a trade

Answer:

y = 21

Step-by-step explanation:

(3y-8) = 55 (corresponding angles are equal)

3y-8 = 55 (add 8 from both sides)

3y = 63 (divide 3 from both sides to isolate the y variable)

y = 21 (final answer)

Answer:

y = 21

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

This is because 21/7 is 3. So, you use the scale factor of 3 to divide 27/3 to get x which is 9.

Answer:

$13,400

Step-by-step explanation:

Simple Interest = principal × rate × time

principal= $9000

Rate= 12/100=0•12

Time=5years

Simple interest =PRT

= 9000× 0•12 × 5

= 5400

Total amount to be paid = 9000 + 5400

= $13400

Answer:

2.74 Seconds

Step-by-step explanation:

-16t²+120=0

-16t²=-120

t²=7.5

t=2.74

Answer:

B.24

Step-by-step explanation:

32 divided by 4

=8

8x3=24 paid cans

36-24=8 free cans

Answer:

y = -3/4x - 5

Slope: -3/4

y-intercept: -5

Answer:

The first derivative of [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex] is [tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex].

Step-by-step explanation:

Let [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex]. we can determine its first derivative by Rule for the Square Root Function, Rule for Power Function, Rule of Chain and Rule for the Addition of Functions, Rule for the Subtraction of Functions, Rule for the Division of Functions:

[tex]y' = \frac{1}{2\cdot \sqrt{\frac{1-x}{1+x} }}\cdot \frac{(-1)\cdot (1+x)-(1)\cdot (1-x)}{(1+x)^{2}}[/tex]

[tex]y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} }\cdot \left[\frac{-1-x-1+x}{(1+x)^{2}} \right][/tex]

[tex]y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} } \cdot \left[-\frac{2}{(1+x)^{2}} \right][/tex]

[tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex]

The first derivative of [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex] is [tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex].

Step-by-step explanation:

nth term = 1 - 5n

6th term = 1 - 5(6)

= 1 - 30

= - 29

Answer:

y = 1/2x + 3

Step-by-step explanation:

Rise/Run and since y = 3 when x = 0, then the b part in y = mx + b is 3.

Answer:

14in approx

Step-by-step explanation:

Given data

number of rotations= 10

Distance travelled=  879.2 inches

Hence if in 10 rotations the distance covered is  879.2 inches

               in 1 rotation the distance covered will be x inches

cross multiply

10x= 879.2

x=  879.2/10

x=  87.92 inches

This means that the circumference of the  tire is 87.92 in

From

C= 2πr

Let us solve for r

87.92=2*3.142*r

87.92=6.284r

r= 87.92/6.284

r= 13.9

Hence the radius is 14in approx

Answer:

Step-by-step explanation:

What is the question?

g(x) = -0.5x² + 4x - 2 is a down-opening parabola. Do you need to know how to put it in vertex form?

vertex (4,6)

focus (4,5.5)

Answer:

answer the solution is 3

Answer:

YZ = 14

Step-by-step explanation:

We are told that;

WZ = 23 and XZ = 18

Now, ∠X in △XWZ which is a right angle triangle can be gotten using trigonometric ratio.

Thus;

WZ/XZ = tan θ

23/18 = tan θ

tan θ = 1.2778

θ = tan^(-1) 1.2778

θ = 51.95°

Now, the ∠X is 90° in △XWY.

Thus, in △XZY, ∠X = 90 - 51.95 = 38.05°

Again, using trigonometric ratio, we can find YZ.

Thus;

YZ/XZ = tan 38.05°

YZ = XZ tan 38.05°

YZ = 18 × 0.7827

YZ = 14.0886

Approximating to a whole number gives: YZ = 14

Answer:

A bird drops a stick to the ground from a height of 80 feet. The equation 0=−16x2+64x+80 gives the number of seconds that have passed when it hits the ground. After about how many seconds did the stick hit the ground?

Step-by-step explanation:

h = -16t^2 + 80   Stick hits the ground when h = 0:

0 = -16t^2 + 80    

16t^2 = 80

t^2 = 80/16 = 5

t = POSITIVE root 5 (due to the real world nature of the problem)

t approximately 2.236 seconds.

========================================

Graph is a downward opening parabola with h-intercept of 80, t-intercept(s) of sqrt(5), - sqrt(5)

Symmetric about h-axis, though I would only graph on the right side of the h-axis since  

that is where t >= 0.

Answer:

(2,114)

Step-by-step explanation:

g(x)= -16x² + 64x + 80

Plug 2 in to check if it's correct.

g(2)= -16(2)² + 64(2) + 80

-16(4)+128+80

-64+128+80

= 144

Answer:

144

Step-by-step explanation:

Answer:

[tex]x->-2^{-}, p(x)->-\infty[/tex] and as [tex]x->-2^{+}, p(x)->-\infty[/tex]

Step-by-step explanation:

Given

[tex]p(x) = \frac{x^2-2x-3}{x+2}[/tex] -- Missing from the question

Required

The behavior of the function around its vertical asymptote at [tex]x = -2[/tex]

[tex]p(x) = \frac{x^2-2x-3}{x+2}[/tex]

Expand the numerator

[tex]p(x) = \frac{x^2 + x -3x - 3}{x+2}[/tex]

Factorize

[tex]p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}[/tex]

Factor out x + 1

[tex]p(x) = \frac{(x -3)(x + 1)}{x+2}[/tex]

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

[tex]x -> -2^{-}[/tex] Say x = -3

[tex]p(x) = \frac{(x -3)(x + 1)}{x+2}[/tex]

[tex]p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12[/tex]

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

[tex]x->-2^{-}, p(x)->-\infty[/tex]

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: [tex]x>-2[/tex]

Say x = -2.1

[tex]p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1[/tex]

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

[tex]x->-2^{+}, p(x)->-\infty[/tex]

So, the behavior is:

[tex]x->-2^{-}, p(x)->-\infty[/tex] and as [tex]x->-2^{+}, p(x)->-\infty[/tex]