Solve for x and find NM

Answer:

The student is incorrect because I I or absolute value would make the -9 to positive 9.  

Step-by-step explanation:

-9<4

on a numberline

-9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4

but the absolute value of -9 (or) |–9|

is actually positive 9

9>4

on a number line

4 5 6 7 8 9

explanation:

There isn't an exact way to answer this problem. Is there more to the question? If not, I am unable to answer it for you.

Answer:

y-intercept = (0, 8)

axis of symmetry= -b/2a

Step-by-step explanation:

Also when you want something to be squared use this symbol ^

Answer:

The 95% confidence interval is   [tex]0.6428 < \sigma < 1.0954[/tex]

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 29

    The sample standard deviation is [tex]s = 0.81[/tex]

  Generally the 95% confidence interval to estimate the true standard deviation  is mathematically represented as  

                      [tex]\sqrt{\frac{(n- 1)s^2 }{ X^2_( \frac{\alpha }{2 } , n-1)} } < \sigma < \sqrt{\frac{(n- 1)s^2 }{ X^2_(1- \frac{\alpha }{2 } , n-1)} }[/tex]

Generally from the  chi -distribution table  the critical value of [tex]\frac{\alpha }{2}[/tex] at a degree of freedom of  [tex]df = 29 - 1 = 28[/tex]  is  

            [tex]X^2 _{\frac{\alpha }{2} , 28 } =44.46079184[/tex]

Generally from the  chi -distribution table  the critical value of [tex]1 - \frac{\alpha }{2}[/tex] at a degree of freedom of  [tex]df = 29 - 1 = 28[/tex]  is  

             [tex]X^2 _{(1 - \frac{\alpha }{2}) , 28 } = 15.30786055[/tex]

So

                 [tex]\sqrt{\frac{(29- 1)0.81^2 }{ 44.46079184 } } < \sigma < \sqrt{\frac{(29- 1)0.81^2 }{15.315.307860551 }[/tex]

=>              [tex]0.6428 < \sigma < 1.0954[/tex]

Answer:

A. 36

Step-by-step explanation:

[tex]9^{3*12} =9^{36}[/tex]

You multiply the the exponent

Step-by-step explanation:

(1 point)

No, there isn't a more efficient way to solve this system.

Yes, a more efficient way is to multiply the first equation by 4, add to eliminate y, then solve for x.

Yes, a more efficient way is to multiply the first equation by −4, add to eliminate y, then solve for x.

Yes, a more efficient way is to multiply the first equation by −4, add to eliminate x, then solve for y.

Answer:

im pretty sure its the first

Step-by-step explanation:

Answer:

down there

Step-by-step explanation:

1. Adam 57 seconds, Cameron 60 seconds, Cody 60 seconds, Kevin 58 seconds, Joao 59 seconds

2.Just line the bars to the times

Answer:

unlikely

Step-by-step explanation:

60/122

60 ÷122=0.49

0.49 × 100 =49

49% chance

answer is unlikely

Answer:

x = 8,25%

Step-by-step explanation:

46,87 - 43 = 3,87

$46,87 -----  100%

$3,87   ------  x

46,87x = 100 . 3,87

         x = 387 / 46,87

         x = 8,25%

Answer:

yudsghbndnshegdm

Step-by-step explanation:send ur location come thruuuuuuuuuuuuuuuuuuuuuuuuuuu

Answer:

Its B

Step-by-step explanation:

Got it right on the test

Answer:

The answer is B

Step-by-step explanation:

Edge 2021

Answer:

15) The ratio of hours to miles is 1 hour to 75 miles; 1/75

16) They will have traveled 900 miles.

17) It will take them around 9 hours.

Step-by-step explanation:

15) Finding the unit rate of the trend (which in this case I considered to be line) can be done by finding the slope and simplifying it. There is a constant linear slope in this graph so it was evident that as the x-values increased by 1, the y-values increased by 75. All you had to do was convert the values into ratio form which would be 1/75. The 1 should remain "numerator" and the 75 as denominator because it is the hour-to-mile ratio (the units were listed in thw instructions in the chronological order in which they were to be answered in ratio form; 1 hour to 75 miles).

16) You can set up an equivalent-ratios equation. Because we know that the unit ratio is 1 hour to 75 miles, and we were given the value of 12 hours, we can set up the equation like this: 1/75=12/x. I would then multiply the 75 miles by 12 so that the ratios will be proportionate. This gives me 900 miles. Now I know, based on the ratio 12 hours to 900 miles (12/900), that if the family travels for 12 hours, they will have traveled 900 miles.

17) We can do the same thing as we did in number 16. We just have to switch the value we use in the second ratio. This means that the equivalent-ratios equation will look like 1/75=x/700, because 700 miles is our given value as opposed to a value with a unit of hours, and miles are the denominators in these ratios. Now we have to see how many times 75 goes into 700 to figure out what to multiply the 1 by to get our proportionate ratios. We have to divide 700 by 75 which is roughly 9 (rounded down from 9.3). The ratio now reads: 1/75=9/700. This means that it will take the family around 9 hours to drive 700 miles (9 hours to 700 miles was the ratio).

Answer:

The values of p = 0 < p ≤ 2/3

Step-by-step explanation:

First we write the probability of 6V flashlight working representing it as a binomial mass function of a binomial random variable

P ( 6v flashlight working  ) = P ( at least one 6V battery works )

                                           = P ( 1 6v battery work )  + P ( 2  6v battery work )

                                           = b( 2; 2, p ) + b( 1; 2, p )

write out a formula of  b( 2; 2, p ) + b( 1; 2, p )

P ( 6v flashlight working  )  = p^2 + 2p( 1 - p )

Next we write the probability of D flashlight working representing it as a binomial mass function of a binomial random variable

P ( D flashlight works ) = p ( at least two D batteries works )

                                     = b( 4; 4, p ) + b(3;4, p ) + b(2; 4, p )

write out a formula of  b( 4; 4, p ) + b(3;4, p ) + b(2; 4, p )

P ( D flashlight works ) = [tex]P^4 + 4p^3 ( 1- p ) + 6p^2 ( 1- p)^2[/tex]

attached below is the remaining solution

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

[tex]\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}[/tex]

We can write this as:

[tex]\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}[/tex]

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

[tex]\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}[/tex]

Then we have the inequality

[tex]1 > (x - 2)/3[/tex]

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

Answer:

It's the last one

I hoped that helped