Solve for the input that corresponds to the given output value. (Round answers to three decimal places when appropriate. Enter your answers as a comma-separated list. Note: Even though the question may be completed without the use of technology, the authors intend for you to complete the activity using the technology you will be using in the remainder of the course so that you become familiar with the basic functions of that technology.)
r(x) = 6 ln(1.8)(1.8x); r(x) = 9.3, r(x) = 25
r(x) = 9.3 x = ____
r(x) = 25 x = _____

Answers

Answer 1

Therefore, the value of x for r(x) = 9.3 is 4.1296 and for r(x) = 25 is 18.881 (rounded to three decimal places).

Given that the function

r(x) = 6 ln(1.8)(1.8x)

We need to solve for the input that corresponds to the given output value.

To find r(x) = 9.3, we have to substitute the given value in the given function and solve for x as follows:

6 ln(1.8)(1.8x)

= 9.3ln(1.8)(1.8x)

= 9.3 / 6

= 1.55(1.8x)

= e^(1.55)

x = e^(1.55) / 1.8

x = 4.1296

Thus, x = 4.1296

To find r(x) = 25, we have to substitute the given value in the given function and solve for x as follows:

6 ln(1.8)(1.8x)

= 25ln(1.8)(1.8x)

= 25 / 6

= 4.1667(1.8x)

= e^(4.1667)

x = e^(4.1667) / 1.8

x = 18.881

Thus, x = 18.881

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Related Questions

vertex at (4,3), axis of symmetry with equation y=3, length of latus rectums 4, and 4p>0

Answers

The given information describes a parabola with vertex at (4,3), axis of symmetry with equation y=3, and a latus rectum length of 4. The value of 4p is positive.

1. The axis of symmetry is a horizontal line passing through the vertex, so the equation y=3 represents the axis of symmetry.

2. Since the latus rectum length is 4, we know that the distance between the focus and the directrix is also 4.

3. The focus is located on the axis of symmetry and is equidistant from the vertex and directrix, so it has coordinates (4+2, 3) = (6,3).

4. The directrix is also a horizontal line and is located 4 units below the vertex, so it has the equation y = 3-4 = -1.

5. The distance between the vertex and focus is p, so we can use the distance formula to find that p = 2.

6. Since 4p>0, we know that p is positive and thus the parabola opens to the right.

7. Finally, the equation of the parabola in standard form is (y-3)^2 = 8(x-4).

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G is the centroid of equilateral Triangle ABC. D,E, and F are midpointsof the sides as shown. P,Q, and R are the midpoints of line AG,line BG and line CG, respectively. If AB= sqrt 3, what is the perimeter of DREPFQ?

Answers

The perimeter of DREPFQ is 1

How to determine the value

In an equilateral triangle, the intersection is the centroid

From the information given, we have that;

AB =√3

Then, we can say that;

AG = BG = CG = √3/3

Also, we have that D, E, and F are the midpoints of the sides of triangle Then, DE = EF = FD = √3/2.

AP = BP = CP = √3/6.

To find the perimeter of DREPFQ, we need to add up the lengths of the line segments DQ, QE, ER, RF, FP, and PD.

The perimeter of DREPFQ is √3/6 × √3/2)

Multiply the value, we get;

√3× √3/ 6 × 2

Then, we get;

3/18

divide the values, we have;

= 0.167

Multiply this by six sides;

= 1

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The complete question:

G is the centroid of equilateral Triangle ABC. D,E, and F are midpointsof the sides as shown. P,Q, and R are the midpoints of line AG,line BG and line CG, respectively. If AB= sqrt 3, what is the perimeter of DREPFQ

2. (14 points) Find a function F(n) with the property that the graph of y- F(x) is the
result of applying the following transformations to the graph of
v=1²+2r. First, stretch the graph horizontally by a factor of 4, then shift the resulting graph 7 units down and 3 units to the left. Leave your answer unsimplified. You don't have to sketch the graph,

Answers

Given that, the graph of y - F(x) is the result of applying the following transformations to the graph of v = 1² + 2r.Therefore, the function F(n) can be determined by applying the inverse of these transformations.

The correct option is (C)

The graph of v = 1² + 2r is a parabola.

To stretch it horizontally by a factor of 4, replace r with r/4: v = 1² + 2r/4²

or v = 1 + r/8.

Now, shifting the graph down by 7 units means replacing v with (v - 7): v - 7 = 1 + r/8

or v = r/8 + 8.

Finally, shifting the graph 3 units to the left means replacing r with (r + 3): v = (r + 3)/8 + 8

or v = (r + 24)/8.

The function F(n) is given by F(n) = (n + 24)/8.

We know that the graph of v = 1² + 2r is a parabola. Then the transformations of the graph are as follows: To stretch the graph horizontally by a factor of 4, we replace r with r/4: v = 1² + 2r/4²

or v = 1 + r/8.

Now, shift the resulting graph 7 units down by replacing v with (v - 7): v - 7 = 1 + r/8

or v = r/8 + 8.

Finally, shift the resulting graph 3 units to the left by replacing r with (r + 3): v = (r + 3)/8 + 8

or v = (r + 24)/8.

Thus, the function F(n) is given by F(n) = (n + 24)/8. To determine the function F(n) with the given graph, we need to apply the inverse transformations of the graph. First, we stretch the graph horizontally by a factor of 4. This can be done by replacing r with r/4, which gives v = 1² + 2r/4²

or v = 1 + r/8.

Next, we shift the resulting graph down 7 units by replacing v with (v - 7), which gives v - 7 = 1 + r/8

or v = r/8 + 8.

Finally, we shift the resulting graph 3 units to the left by replacing r with (r + 3), which gives v = (r + 3)/8 + 8

or v = (r + 24)/8.

Therefore, the function F(n) is given by F(n) = (n + 24)/8.

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What is the equation of the following line? Be sure to scroll down first to see all answer options. (-2,-8) ( 0,0)

Answers

Answer:

y = -4x

Step-by-step explanation:

We can find the equation of the line in slope-intercept form, whose general equation is given by:

y = mx + b, where

m is the slope,and b is the y-intercept.

Finding the slope (m):

We can find the slope (m) using the slope formula, which is given by:

m = (y2 - y1) / (x2 - x1), where

(x1, y1) is one point on the line,and (x2, y2) is another point on the line.

Thus, we can plug in (0, 0) for (x1, y1) and (2, -8) for (x2, y2) to find m, the slope of the line:

m = (-8 - 0) / (2 - 0)

m = -8/2

m = -4

Thus, the slope of the line is-4.

Finding the y-intercept (b):

We see that the point (0, 0) lies on the line so the y-intercept is 0 since the line intersects the y-axis at (0, 0).When the y-intercept is 0, we don't write it in the equation.

Thus, the equation of the line is y = -4x.

Given f(x)=−6+x2, calculate the average rate of change on each of the given intervals. (a) The average rate of change of f(x) over the interval [−4,−3.9] is (b) The average rate of change of f(x) over the interval [−4,−3.99] is (c) The average rate of change of f(x) over the interval [−4,−3.999] is (d) Using (a) through (c) to estimate the instantaneous rate of change of f(x) at x=−4, we have

Answers

The average rate of change on each of the given intervals and the estimate of the instantaneous rate of change of f(x) at x = -4 is calculated and the answer is found to be -∞.

Given f(x)=−6+x², we have to calculate the average rate of change on each of the given intervals.

Using the formula, The average rate of change of f(x) over the interval [a,b] is given by:  f(b) - f(a) / b - a

(a) The average rate of change of f(x) over the interval [-4, -3.9] is given by: f(-3.9) - f(-4) / -3.9 - (-4)f(-3.9) = -6 + (-3.9)² = -6 + 15.21 = 9.21f(-4) = -6 + (-4)² = -6 + 16 = 10

The average rate of change = 9.21 - 10 / -3.9 + 4 = -0.79 / 0.1 = -7.9

(b) The average rate of change of f(x) over the interval [-4, -3.99] is given by: f(-3.99) - f(-4) / -3.99 - (-4)f(-3.99) = -6 + (-3.99)² = -6 + 15.9601 = 9.9601

The average rate of change = 9.9601 - 10 / -3.99 + 4 = -0.0399 / 0.01 = -3.99

(c) The average rate of change of f(x) over the interval [-4, -3.999] is given by:f(-3.999) - f(-4) / -3.999 - (-4)f(-3.999) = -6 + (-3.999)² = -6 + 15.996001 = 9.996001

The average rate of change = 9.996001 - 10 / -3.999 + 4 = -0.003999 / 0.001 = -3.999

(d) Using (a) through (c) to estimate the instantaneous rate of change of f(x) at x = -4, we have

f'(-4) = lim h → 0 [f(-4 + h) - f(-4)] / h= lim h → 0 [(-6 + (-4 + h)²) - (-6 + 16)] / h= lim h → 0 [-6 + 16 - 8h - 6] / h= lim h → 0 [4 - 8h] / h= lim h → 0 4 / h - 8= -∞.

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Fill in the blank: When finding the difference between 74 and 112, a student might say, and then I added 2 more tens onto "First, I added 6 onto 74 to get a ______80 to get to 100 because that's another______

Answers

When finding the difference between 74 and 112, a student might say, "First, I added 6 onto 74 to get a number that ends in 0, specifically 80, to get to 100 because that's another ten."

To find the difference between 74 and 112, the student is using a strategy of breaking down the numbers into smaller parts and manipulating them to simplify the subtraction process. In this case, the student starts by adding 6 onto 74, resulting in 80. By doing so, the student is aiming to create a number that ends in 0, which is closer to 100 and represents another ten. This approach allows for an easier mental calculation when subtracting 80 from 112 since it involves subtracting whole tens instead of dealing with more complex digit-by-digit subtraction.

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Averie rows a boat downstream for 135 miles. The return trip upstream took 12 hours longer. If the current flows at 2 mph, how fast does Averie row in still water?

Answers

Averie's speed in still water = (speed downstream + speed upstream) / 2, and by substituting the known values, we can calculate Averie's speed in still wat

To solve this problem, let's denote Averie's speed in still water as "r" (in mph).

We know that the current flows at a rate of 2 mph.

When Averie rows downstream, her effective speed is increased by the speed of the current.

Therefore, her speed downstream is (r + 2) mph.

The distance traveled downstream is 135 miles.

We can use the formula:

Time = Distance / Speed.

So, the time taken downstream is 135 / (r + 2) hours.

On the return trip upstream, Averie's effective speed is decreased by the speed of the current.

Therefore, her speed upstream is (r - 2) mph.

The distance traveled upstream is also 135 miles.

The time taken upstream is given as 12 hours longer than the downstream time, so we can express it as:

Time upstream = Time downstream + 12

135 / (r - 2) = 135 / (r + 2) + 12

Now, we can solve this equation to find the value of "r," which represents Averie's speed in still water.

Multiplying both sides of the equation by (r - 2)(r + 2), we get:

135(r - 2) = 135(r + 2) + 12(r - 2)(r + 2)

Simplifying and solving the equation will give us the value of "r," which represents Averie's speed in still water.

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Fill in the blanks with the correct values: The five number summary for a particular quantitative variable is

Min = 9; Q1 = 20; Median = 30; Q3 = 34; Max = 40

The middle 50% of observations are between BLANK and BLANK


50% of observations are less than BLANK
.

The largest 25% of observations are greater than BLANK

Answers

The middle 50% of observations are between 20 and 34. 50% of observations are less than 30. The largest 25% of observations are greater than 34.

The given five number summary for a particular quantitative variable is:

Min = 9

Q1 = 20

Median = 30

Q3 = 34

Max = 40

The middle 50% of observations are between the first quartile, Q1, and the third quartile, Q3. Hence, the middle 50% of observations lie between 20 and 34. The median (which is also the second quartile) is equal to 30, so 50% of the observations are less than 30.Finally, Q3 is the 75th percentile. Hence, 25% of the observations are greater than Q3. Since Q3 is equal to 34, the largest 25% of observations are greater than 34.

The middle 50% of observations are between 20 and 34. 50% of observations are less than 30. The largest 25% of observations are greater than 34.

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Which of the following is the appropriate substitution for the Bernoulli differential equation xyy ′−2xy=4xy 2? Letz= y ∧−1 y ∧−3 y ∧ −4 (D) y∧ −2

Answers

To solve the Bernoulli differential equation xyy' - 2xy = 4xy^2, we can make the substitution z = y^(1-2) = y^(-1).  The appropriate substitution is z = y^(-2), not one of the options listed. This substitution simplifies the equation and transforms it into a separable first-order differential equation. By Differentiating both sides of the equation with respect to x, we get: dz/dx = d(y^(-1))/dx

Using the chain rule, we have:

dz/dx = (-1)(y^(-2))(dy/dx)

dz/dx = -y^(-2)dy/dx

Substituting this into the original differential equation, we have:

xy(-y^(-2)dy/dx) - 2xy = 4xy^2

Simplifying, we get:

-y(dy/dx) - 2 = 4y^2

Now, we have a separable first-order differential equation. By rearranging terms, we get:

dy/dx = -(4y^2 + 2)/y

To further simplify the equation, we can substitute z = y^(-2), giving us:

dy/dx = -(-4z + 2)

Therefore, the appropriate substitution for the Bernoulli differential equation is z = y^(-2), not one of the options listed.

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(a) Find the closed area determined by the graphs of \( x=2-y^{2} \) and \( y=x \) by following the \( y \) axis when integrating. (b) Express the same area in terms of integral(s) on the \( x \)-axis

Answers

(a) To find the area determined by the graphs of ( x=2-y^{2} ) and ( y=x ), we first need to determine the limits of integration. Since the two curves intersect at ( (1,1) ) and ( (-3,-3) ), we can integrate with respect to ( y ) from ( y=-3 ) to ( y=1 ).

The equation of the line ( y=x ) can be written as ( x-y=0 ). The equation of the parabola ( x=2-y^2 ) can be rewritten as ( y^2+x-2=0 ). At the points of intersection, these two equations must hold simultaneously, so we have:

[y^2+x-2=0]

[x-y=0]

Substituting ( x=y ) into the first equation, we get:

[y^2+y-2=0]

This equation factors as:

[(y-1)(y+2)=0]

So the two points of intersection are ( (1,1) ) and ( (-2,-2) ). Therefore, the area of the region enclosed by the two curves is given by:

[\int_{-3}^{1} [(2-y^2)-y] dy]

Simplifying this expression, we get:

[\int_{-3}^{1} (2-y^2-y) dy = \int_{-3}^{1} (1-y^2-y) dy = [y-\frac{1}{3}y^3 - \frac{1}{2}y^2]_{-3}^{1}]

Evaluating this expression, we get:

[(1-\frac{1}{3}-\frac{1}{2}) - (-3+9-\frac{27}{2}) = \frac{23}{6}]

Therefore, the area enclosed by the two curves is ( \frac{23}{6} ).

(b) To express the same area in terms of an integral on the ( x )-axis, we need to solve for ( y ) in terms of ( x ) for each equation. For ( y=x ), we have ( y=x ). For ( x=2-y^2 ), we have:

[y^2+(-x+2)=0]

Solving for ( y ), we get:

[y=\pm\sqrt{x-2}]

Note that we only want the positive square root since we are looking at the region above the ( x )-axis. Therefore, the area enclosed by the two curves is given by:

[\int_{-2}^{2} [x-\sqrt{x-2}] dx]

We integrate from ( x=-2 ) to ( x=2 ) since these are the values where the two curves intersect. Simplifying this expression, we get:

[\int_{-2}^{2} (x-\sqrt{x-2}) dx = [\frac{1}{2}x^2-\frac{2}{3}(x-2)^{\frac{3}{2}}]_{-2}^{2}]

Evaluating this expression, we get:

[(2-\frac{8}{3}) - (-2-\frac{8}{3}) = \frac{16}{3}]

Therefore, the area enclosed by the two curves is ( \frac{16}{3} ) when integrating with respect to the ( x )-axis.

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Suppose that we will take a random sample of size n from a population having mean µ and standard deviation σ. For each of the following situations, find the mean, variance, and standard deviation of the sampling distribution of the sample mean :
:
(a) µ = 12, σ = 5, n = 28 (Round your answers of "σ " and "σ 2" to 4 decimal places.)
(b) µ = 539, σ = .4, n = 96 (Round your answers of "σ " and "σ 2" to 4 decimal places.)
(c) µ = 7, σ = 1.0, n = 7 (Round your answers of "σ " and "σ 2" to 4 decimal places.)
(d) µ = 118, σ = 4, n = 1,530 (Round your answers of "σ " and "σ 2" to 4 decimal places.)

Answers

Mean, µx = µ = 118, Variance, σ2x = σ2/n = 4^2/1530 = 0.0001044 and Standard Deviation, σx = σ/√n = 4/√1530 = 0.1038

Sampling Distribution of the Sample Mean:

Suppose that we will take a random sample of size n from a population having mean µ and standard deviation σ.

The sampling distribution of the sample mean is a probability distribution of all possible sample means.

Statistics for each question:

(a) µ = 12, σ = 5, n = 28

(b) µ = 539, σ = .4, n = 96

(c) µ = 7, σ = 1.0, n = 7

(d) µ = 118, σ = 4, n = 1,530

(a) Mean, µx = µ = 12, Variance, σ2x = σ2/n = 5^2/28 = 0.8929 and Standard Deviation, σx = σ/√n = 5/√28 = 0.9439

(b) Mean, µx = µ = 539, Variance, σ2x = σ2/n = 0.4^2/96 = 0.0001667 and Standard Deviation, σx = σ/√n = 0.4/√96 = 0.0408

(c) Mean, µx = µ = 7, Variance, σ2x = σ2/n = 1^2/7 = 0.1429 and Standard Deviation, σx = σ/√n = 1/√7 = 0.3770

(d) Mean, µx = µ = 118, Variance, σ2x = σ2/n = 4^2/1530 = 0.0001044 and Standard Deviation, σx = σ/√n = 4/√1530 = 0.1038

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Find all polynomial solutions p(t, x) of the wave equation utt=uzz with (a) deg p ≤ 2, (b) deg p = 3.

Answers

The polynomial solution for deg p = 3 is p(t, x) = At³ + Bx³ + Ct² + Dx² - 3At² - 2Ct - 3Bx² - 2Dx, where A, B, C, and D are constants.

(a) Case: deg p ≤ 2

Let's assume p(t, x) = At² + Bx² + Ct + Dx + E, where A, B, C, D, and E are constants.

Substituting p(t, x) into the wave equation, we have:

(p_tt) = 2A,

(p_zz) = 2B,

(p_t) = 2At + C,

(p_z) = 2Bx + D.

Therefore, the wave equation becomes:

2A = 2B.

This implies that A = B.

Next, we consider the terms involving t and x:

2At + C = 0,

2Bx + D = 0.

From the first equation, we get C = -2At. Substituting this into the second equation, we have D = -4Bx.

Finally, we have the constant term:

E = 0.

So, the polynomial solution for deg p ≤ 2 is p(t, x) = At² + Bx² - 2At - 4Bx, where A and B are constants.

(b) Case: deg p = 3

Let's assume p(t, x) = At³ + Bx³ + Ct² + Dx² + Et + Fx + G, where A, B, C, D, E, F, and G are constants.

Substituting p(t, x) into the wave equation, we have:

(p_tt) = 6At,

(p_zz) = 6Bx,

(p_t) = 3At² + 2Ct + E,

(p_z) = 3Bx² + 2Dx + F.

Therefore, the wave equation becomes:

6At = 6Bx.

This implies that A = Bx.

Next, we consider the terms involving t and x:

3At² + 2Ct + E = 0,

3Bx² + 2Dx + F = 0.

From the first equation, we get E = -3At² - 2Ct. Substituting this into the second equation, we have F = -3Bx² - 2Dx.

Finally, we have the constant term:

G = 0.

So, the polynomial solution for deg p = 3 is p(t, x) = At³ + Bx³ + Ct² + Dx² - 3At² - 2Ct - 3Bx² - 2Dx, where A, B, C, and D are constants.

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Which set of values could be the side lengths of a 30-60-90 triangle?
OA. (5, 5√2, 10}
B. (5, 10, 10 √√3)
C. (5, 10, 102)
OD. (5, 53, 10)

Answers

A 30-60-90 triangle is a special type of right triangle where the angles are 30 degrees, 60 degrees, and 90 degrees. The sides of a 30-60-90 triangle always have the same ratio, which is 1 : √3 : 2.

This means that if the shortest side (opposite the 30-degree angle) has length 'a', then:

- The side opposite the 60-degree angle (the longer leg) will be 'a√3'.

- The side opposite the 90-degree angle (the hypotenuse) will be '2a'.

Let's check each of the options:

A. (5, 5√2, 10): This does not follow the 1 : √3 : 2 ratio.

B. (5, 10, 10√3): This follows the 1 : 2 : 2√3 ratio, which is not the correct ratio for a 30-60-90 triangle.

C. (5, 10, 10^2): This does not follow the 1 : √3 : 2 ratio.

D. (5, 5√3, 10): This follows the 1 : √3 : 2 ratio, so it could be the side lengths of a 30-60-90 triangle.

So, the correct answer is option D. (5, 5√3, 10).

if the information 7/15 was shown on a pie chart what would be the angle

Answers

If the information 7/15 was shown on a pie chart, the angle would be approximately 168 degrees.

To find the angle, you can use the formula:

(angle) = (fraction of total) x 360 degrees

In this case, the fraction of the total represented by 7/15 is:

7/15 = 0.4667

Multiplying this by 360 degrees gives:

0.4667 x 360 = 168 degrees

Therefore, the angle on the pie chart representing 7/15 would be approximately 168 degrees.
Final answer:

The question asks about converting a fraction into an angle for a pie chart. You multiply the fraction (7/15) by the total degrees in a circle (360 degrees) which gives you approximately 168 degrees.

Explanation:

The subject is tied to the understanding of how data is represented in pie charts, specifically how fractions or percentages can be expressed in terms of angles in a pie chart. This question pertains to the interpretation of pie charts in mathematics, more specifically to fundamental aspects of geometry and data representation.

First, we must understand that a pie chart is a circular chart divided into sectors or 'pies', where the arc length of each sector (and consequently its central angle and area), is proportional to the quantity it represents. So the total measurement for a pie chart is 360 degrees - the same as a full circle. When you have a fraction like 7/15, it represents a portion of the whole. To convert this fraction into an angle for the pie chart, we need to multiply it by the total degrees in a circle.

So, the calculation would be (7/15) * 360. When you do the math, you get around 168 degrees. So if the information 7/15 was shown on a pie chart, it would open up an angle of approximately 168 degrees.

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This test: 100 point (s) possible This question: 2 point (s) possible Find an equation for the line with the given properties. Express your answer using either the general form or the slope -intercept

Answers

The slope-intercept form of a linear equation is [tex]y = mx + b[/tex], where m is the slope of the line and b is the y-intercept.

A linear equation is of the form [tex]y = mx + b[/tex]. The slope-intercept form of a linear equation is [tex]y = mx + b[/tex], where m is the slope of the line and b is the y-intercept. The slope is the change in the y-coordinates divided by the change in the x-coordinates. For example, if the slope of the line is 2, then for every one unit that x increases, y increases by two units.

The general form of a linear equation is [tex]Ax + By = C[/tex], where A, B, and C are constants.

To convert the slope-intercept form to the general form, rearrange the equation to get [tex]-mx + y = b[/tex].

Multiply each term of the equation by -1 to get [tex]mx - y = -b[/tex].

Finally, rearrange the equation to get [tex]Ax + By = C[/tex], where [tex]A = m[/tex], [tex]B = -1[/tex], and[tex]C = -b[/tex].

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For a large sporting event the broadcasters sold 68 ad slots for a total revenue of $152 million. What was the mean price per ad slot? The mean price per ad slot was $2.2 million. (Round to one decimal place as needed.)

Answers

The broadcasters sold 68 ad slots for $152 million, resulting in a total revenue of $152 million. To find the mean price per ad slot, divide the total revenue by the number of ad slots sold. The formula is μ = Total Revenue / Number of Ad Slots sold, resulting in a mean price of $2.2 million.

For a large sporting event, the broadcasters sold 68 ad slots for a total revenue of $152 million. The task is to find the mean price per ad slot. The mean price per ad slot was $2.2 million. (Round to one decimal place as needed.)The formula for the mean of a sample is given below:

μ = (Σ xi) / n

Where,μ represents the mean of the sample.Σ xi represents the summation of values from i = 1 to i = n.n represents the total number of values in the sample.

The mean price per ad slot can be found by dividing the total revenue by the number of ad slots sold. We are given that the number of ad slots sold is 68 and the total revenue is $152 million.

Let's put these values in the formula.

μ = Total Revenue / Number of Ad Slots sold

μ = $152 million / 68= $2.23529411764

The mean price per ad slot is $2.2 million. (Round to one decimal place as needed.)

Therefore, the mean price per ad slot is $2.2 million.

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When is a z-score considered to be highly unusual?
a z-score over 1.96 is considered highly unusual

a z-score over 2 is considered highly unusual

a z-score over 3 is considered highly unusual

Answers

A z-score over 2 is considered highly unusual.

A z-score is a measure of how many standard deviations a particular data point is away from the mean in a standard normal distribution. A z-score of 2 means that the data point is 2 standard deviations away from the mean. In a standard normal distribution, approximately 95% of the data falls within 2 standard deviations of the mean. This means that only about 5% of the data falls beyond 2 standard deviations from the mean.

Therefore, if a z-score is over 2, it indicates that the corresponding data point is in the tail of the distribution and is relatively far from the mean. This is considered highly unusual because it suggests that the data point is an extreme outlier compared to the majority of the data. In other words, it is highly unlikely to observe such a data point in a normal distribution, and it indicates a significant deviation from the expected pattern.

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(ii) At any party, the number of people who have shaken the hand of an odd number of people is even. [30Que 5. Give examples of the following: (i) a connected simple graph with 6 vertices such that each vertex has degree 3 (ii) a graph with 3 components and 4 loops. 6. Prove the following: if a graph has a closed walk of odd length, then it has a cycle of odd length. How many edges does the complete bipartite graph K m,n
​ have? Justify your answer.

Answers

Let G be a graph with a closed walk of odd length, say v_0, v_1, ..., v_{2k+1}, v_0. We want to show that G has a cycle of odd length.

Let W = {v_i : 0 ≤ i ≤ 2k+1} be the set of vertices in the closed walk. Since the walk is closed, the first and last vertices are the same, so we can write:

w_0 = w_{2k+1}

Let C be the subgraph of G induced by the vertices in W. That is, the vertices of C are the vertices in W and the edges of C are the edges of G that have both endpoints in W.

Since W is a closed walk, every vertex in W has even degree in C (because it has two incident edges). Therefore, the sum of degrees of vertices in C is even.

However, since C is a subgraph of G, the sum of degrees of vertices in C is also equal to twice the number of edges in C. Therefore, the number of edges in C is even.

Now consider the subgraph H of G obtained by removing all edges in C. This graph has no edges between vertices in W, because those edges were removed. Therefore, each connected component of H either contains a single vertex from W, or is a path whose endpoints are in W.

Since G has a closed walk of odd length, there must be some vertex in W that appears an odd number of times in the walk (because the number of vertices in the walk is odd). Let v be such a vertex.

If v appears only once in the walk, then it is a connected component of H and we are done, because a single vertex is a cycle of odd length.

Otherwise, let v = w_i for some even i. Then w_{i+1}, w_{i+2}, ..., w_{i-1} also appear in the walk, and they form a path in H. Since this path has odd length (because i is even), it is a cycle of odd length in G.

Therefore, we have shown that if G has a closed walk of odd length, then it has a cycle of odd length.

The complete bipartite graph K_m,n has m+n vertices, with m vertices on one side and n on the other side. Each vertex on one side is connected to every vertex on the other side, so the degree of each vertex on the first side is n and the degree of each vertex on the second side is m. Therefore, the total number of edges in K_m,n is mn, since there are mn possible pairs of vertices from the two sides that can be connected by an edge.

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The weekly demand for Math Wars - Attack of the Limits video games is given by p=420/(x−6)+4000 where x is the number thousands of video games produced and sold, and p is in dollars. Using the Marginal Revenue function, R ′(x), approximate the marginal revenue when 12,000 video games have been produced and sold.
_____dollars

Answers

The marginal revenue when 12,000 video games have been produced and sold is 105 dollars.

Given function, p=420/(x-6)+4000

To find the marginal revenue function, R′(x)

As we know, Revenue, R = price x quantity

R = p * x (price, p and quantity, x are given in the function)

R = (420/(x-6) + 4000) x

Revenue function, R(x) = (420/(x-6) + 4000) x

Differentiating R(x) w.r.t x,

R′(x) = d(R(x))/dx

R′(x) = [d/dx] [(420/(x-6) + 4000) x]

On expanding and simplifying,

R′(x) = 420/(x-6)²

Now, to approximate the marginal revenue when 12,000 video games have been produced and sold, we need to put the value of x = 12

R′(12) = 420/(12-6)²

R′(12) = 105 dollars

Therefore, the marginal revenue when 12,000 video games have been produced and sold is 105 dollars.

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Question 13 of 25
The graph of a certain quadratic function has no x-intercepts. Which of the
following are possible values for the discriminant? Check all that apply.
A. -18
B. 0
C. 3
D. -1
SUBMIT

Answers

Answer:

Since the graph of a certain quadratic function has no x-intercepts, the discriminant has to be negative, so A and D are possible values for the discriminant.

According to a company's websife, the top 10% of the candidates who take the entrance test will be called for an interview. The reported mean and standard deviation of the test scores are 63 and 9 , respectively. If test scores are normolly distributed, what is the minimum score required for an interview? (You may find it useful to reference the Z table. Round your final answer to 2 decimal places.)

Answers

The minimum score required for an interview is approximately 74.52 (rounded to 2 decimal places). To find the minimum score required for an interview, we need to determine the score that corresponds to the top 10% of the distribution.

Since the test scores are normally distributed, we can use the Z-table to find the Z-score that corresponds to the top 10% of the distribution.

The Z-score represents the number of standard deviations a particular score is away from the mean. In this case, we want to find the Z-score that corresponds to the cumulative probability of 0.90 (since we are interested in the top 10%).

Using the Z-table, we find that the Z-score corresponding to a cumulative probability of 0.90 is approximately 1.28.

Once we have the Z-score, we can use the formula:

Z = (X - μ) / σ

where X is the test score, μ is the mean, and σ is the standard deviation.

Rearranging the formula, we can solve for X:

X = Z * σ + μ

Substituting the values, we have:

X = 1.28 * 9 + 63

Calculating this expression, we find:

X ≈ 74.52

Therefore, the minimum score required for an interview is approximately 74.52 (rounded to 2 decimal places).

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A race car driver must average 270k(m)/(h)r for 5 laps to qualify for a race. Because of engine trouble, the car averages only 220k(m)/(h)r over the first 3 laps. What minimum average speed must be ma

Answers

The race car driver must maintain a minimum average speed of 330 km/h for the remaining 2 laps to qualify for the race.

To find the minimum average speed needed for the remaining 2 laps, we need to determine the total distance covered in the first 3 laps and the remaining distance to be covered in the next 2 laps.

Given:

Average speed for the first 3 laps = 220 km/h

Total number of laps = 5

Target average speed for 5 laps = 270 km/h

Let's calculate the distance covered in the first 3 laps:

Distance = Average speed × Time

Distance = 220 km/h × 3 h = 660 km

Now, we can calculate the remaining distance to be covered:

Total distance for 5 laps = Target average speed × Time

Total distance for 5 laps = 270 km/h × 5 h = 1350 km

Remaining distance = Total distance for 5 laps - Distance covered in the first 3 laps

Remaining distance = 1350 km - 660 km = 690 km

To find the minimum average speed for the remaining 2 laps, we divide the remaining distance by the time:

Minimum average speed = Remaining distance / Time

Minimum average speed = 690 km / 2 h = 345 km/h

The race car driver must maintain a minimum average speed of 330 km/h for the remaining 2 laps to qualify for the race.

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The average number of misprints per page in a magazine is whixch follows a Poisson's Probability distribution. What is the probability that the number of misprints on a particular page of that magazine is 2?

Answers

The probability that a particular book is free from misprints is 0.2231. option D is correct.

The average number of misprints per page (λ) is given as 1.5.

The probability of having no misprints (k = 0) can be calculated using the Poisson probability mass function:

[tex]P(X = 0) = (e^{-\lambda}\times \lambda^k) / k![/tex]

Substituting the values:

P(X = 0) = [tex](e^{-1.5} \times 1.5^0) / 0![/tex]

Since 0! (zero factorial) is equal to 1, we have:

P(X = 0) = [tex]e^{-1.5}[/tex]

Calculating this value, we find:

P(X = 0) = 0.2231

Therefore, the probability that a particular book is free from misprints is approximately 0.2231.

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Question 13: The average number of misprints per page of a book is 1.5.Assuming the distribution of number of misprints to be Poisson. The probability that a particular book is free from misprints,is B. 0.435 D. 0.2231 A. 0.329 C. 0.549​

An organization drills 3 wells to provide access to clean drinking water. The cost (in dollars ) to drill and maintain the wells for n years is represented by 34,500+540n . Write and interpret an expr

Answers

This means that the total cost for drilling and maintaining the wells for 5 years would be $37,500.

The expression representing the cost (in dollars) to drill and maintain the wells for n years is given by:

34,500 + 540n

In the given expression, the constant term 34,500 represents the initial cost of drilling the wells, which includes expenses such as equipment, labor, and permits. The term 540n represents the cost of maintaining the wells for n years, with 540 being the annual maintenance cost per well.

Interpreting the expression:

The expression allows us to calculate the total cost of drilling and maintaining the wells for a given number of years, n. As the value of n increases, the cost will increase proportionally, reflecting the additional expenses incurred for maintenance over time.

For example, if we plug in n = 5 into the expression, we can calculate the cost of drilling and maintaining the wells for 5 years:

[tex]\(34,500 + 540 \times 5 = 37,500\).[/tex]

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Solve and graph -3 x-10>5

Answers

Answer:  x < -5

The graph has an open hole at -5 and shading to the left

The graph is below.

=====================================================

Work Shown:

-3x - 10 > 5

-3x > 5+10

-3x > 15

x < 15/(-3) ... inequality sign flips

x < -5

The inequality sign flips whenever we divide both sides by a negative number.

The graph has an open hole at -5 with shading to the left.

The open hole means "exclude this endpoint from the solution set".

2. A store is having a 12-hour sale. The rate at which shoppers enter the store, measured in shoppers per hour, is [tex]S(t)=2 t^3-48 t^2+288 t[/tex] for [tex]0 \leq t \leq 12[/tex]. The rate at which shoppers leave the store, measured in shoppers per hour, is [tex]L(t)=-80+\frac{4400}{t^2-14 t+55}[/tex] for [tex]0 \leq t \leq 12[/tex]. At [tex]t=0[/tex], when the sale begins, there are 10 shoppers in the store.

a) How many shoppers entered the store during the first six hours of the sale?

Answers

The number of customers entered the store during the first six hours is 432 .

Given,

S(t) = 2t³ - 48t² + 288t

0≤ t≤ 12

L(t) = -80 + 4400/t² -14t + 55

0≤ t≤ 12

Now,

Shoppers entered in the store during first six hours.

Time variable is 6.

Thus substitute t = 6 ,

S(t) = 2t³ - 48t² + 288t

S(6) = 2(6)³ - 48(6)² + 288(6)

Simplifying further by cubing and squaring the terms ,

S(6) = 216*2 - 48 * 36 +1728

S(6) = 432 - 1728 + 1728

S(6) = 432.

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tanning parlor located in a major located in a major shopping center near a large new england city has the following history of customers over the last four years (data are in hundreds of customers) year feb may aug nov yearly totals 2012 3.5 2.9 2.0 3.2 11.6 2013 4.1 3.4 2.9 3.6 14 2014 5.2 4.5 3.1 4.5 17.3 2015 6.1 5.0 4.4 6.0 21.5

Answers

The Cycle Factor Forecast is 0.13,0.13,0.13,0.13 and the Overall Forecast is 6.3,5.4,4.9,6.3.

Time series forecasting differs from supervised learning in their goal. One of the main variables in forecasting is the history of the very metric we are trying to predict. Supervised learning on the other hand usually seeks to predict using primarily exogenous variables.

A and B. The table is shown below with attached python code at the very end. To get this values simply use stats model as they have all the functions needed. Seasonal index is also in the table.

C and D: To forecast either of these, we will use tbats with a frequency of 4 which has proven to be better than an auto arima on average. Again code, is attached at end. Forecasts are below. It seems tabs though a naïve forecast was best for the cycle factor.

Cycle Factor Forecast: 0.13,0.13,0.13,0.13

Overall Forecast: 6.3,5.4,4.9,6.3

E:0.324

Again I simply created a function in python to calculate the RMSE of any two time series.

F.

CODE:

import pandas as pd

from statsmodels.tsa.seasonal import seasonal_decompose

import numpy as np

import matplotlib.pyplot as plt

data=3.5,2.9,2.0,3.2,4.1,3.4,2.9,2.6,5.2,4.5,3.1,4.5,6.1,5,4.4,6,6.8,5.1,4.7,6.5

df=pd.DataFrame()

df"actual"=data

df.index=pd.date_range(start='1/1/2004', periods=20, freq='3M')

df"mv_avg"=df"actual".rolling(4).mean()

df"trend"=seasonal_decompose(df"actual",two_sided=False).trend

df"seasonal"=seasonal_decompose(df"actual",two_sided=False).seasonal

df"cycle"=seasonal_decompose(df"actual",two_sided=False).resid

def rmse(predictions, targets):

return np.sqrt(((predictions - targets) ** 2).mean())

rmse_values=rmse(np.array(6.3,5.4,4.9,6.3),np.array(6.8,5.1,4.7,6.5))

plt.style.use("bmh")

plot_df=df.ilocNo InterWiki reference defined in properties for Wiki called ""!

plt.plot(plot_df.index,plot_df"actual")

plt.plot(plot_df.index,plot_df"mv_avg")

plt.plot(plot_df.index,plot_df"trend")

plt.plot(df.ilocNo InterWiki reference defined in properties for Wiki called "-4"!.index,6.3,5.4,4.9,6.3)

plt.legend("actual","mv_avg","trend","predictions")

Therefore, the Cycle Factor Forecast is 0.13,0.13,0.13,0.13 and the Overall Forecast is 6.3,5.4,4.9,6.3.

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"Your question is incomplete, probably the complete question/missing part is:"

A tanning parlor located in a major shopping center near a large New England city has the following history of customers over the last four years (data are in hundreds of customers):

a. Construct a table in which you show the actual data (given in the table), the centered moving average, the centered moving-average trend, the seasonal factors, and the cycle factors for every quarter for which they can be calculated in years 1 through 4.

b. Determine the seasonal index for each quarter.

c. Project the cycle factor through 2008.

d. Make a forecast for each quarter of 2008.

e. The actual numbers of customers served per quarter in 2008 were 6.8, 5.1, 4.7 and 6.5 for quarters 1 through 4, respectively (numbers are in hundreds). Calculate the RMSE for 2008.

f. Prepare a time-series plot of the actual data, the centered moving averages, the long-term trend, and the values predicted by your model for 2004 through 2008 (where data are available).


70% of all Americans are home owners. if 47 Americans are
randomly selected,
find the probability that exactly 32 of them are home owners

Answers

Given that 70% of all Americans are homeowners. If 47 Americans are randomly selected, we need to find the probability that exactly 32 of them are homeowners.

The probability distribution is binomial distribution, and the formula to find the probability of an event happening is:

P (x) = nCx * px * q(n - x)Where, n is the number of trialsx is the number of successesp is the probability of successq is the probability of failure, and

q = 1 - pHere, n = 47 (47 Americans are randomly selected)

Probability of success (p) = 70/100

= 0.7Probability of failure

(q) = 1 - p

= 1 - 0.7

= 0.3To find P(32), the probability that exactly 32 of them are homeowners,

we plug in the values:nCx = 47C32

= 47!/(32!(47-32)!)

= 47!/(32! × 15!)

= 1,087,119,700

px = (0.7)32q(n - x)

= (0.3)15Using the formula

,P (x) = nCx * px * q(n - x)P (32)

= 47C32 * (0.7)32 * (0.3)15

= 0.1874

Hence, the probability that exactly 32 of them are homowner are 0.1874

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Classification using Nearest Neighbour and Bayes theorem As output from an imaging system we get a measurement that depends on what we are seeing. For three different classes of objects we get the following measurements. Class 1 : 0.4003,0.3985,0.3998,0.3997,0.4015,0.3995,0.3991 Class 2: 0.2554,0.3139,0.2627,0.3802,0.3247,0.3360,0.2974 Class 3: 0.5632,0.7687,0.0524,0.7586,0.4443,0.5505,0.6469 3.1 Nearest Neighbours Use nearest neighbour classification. Assume that the first four measurements in each class are used for training and the last three for testing. How many measurements will be correctly classified?

Answers

Nearest Neighbor (NN) technique is a straightforward and robust classification algorithm that requires no training data and is useful for determining which class a new sample belongs to.

The classification rule of this algorithm is to assign the class label of the nearest training instance to a new observation, which is determined by the Euclidean distance between the new point and the training samples.To determine how many measurements will be correctly classified, let's go step by step:Let's use the first four measurements in each class for training, and the last three measurements for testing.```


Class 1: train = (0.4003,0.3985,0.3998,0.3997) test = (0.4015,0.3995,0.3991)
Class 2: train = (0.2554,0.3139,0.2627,0.3802) test = (0.3247,0.3360,0.2974)
Class 3: train = (0.5632,0.7687,0.0524,0.7586) test = (0.4443,0.5505,0.6469)```

We need to determine the class label of each test instance using the nearest neighbor rule by calculating its Euclidean distance to each training instance, then assigning it to the class of the closest instance.To do so, we need to calculate the distances between the test instances and each training instance:```
Class 1:
0.4015: 0.0028, 0.0020, 0.0017, 0.0018
0.3995: 0.0008, 0.0010, 0.0004, 0.0003
0.3991: 0.0004, 0.0006, 0.0007, 0.0006

Class 2:
0.3247: 0.0694, 0.0110, 0.0620, 0.0555
0.3360: 0.0477, 0.0238, 0.0733, 0.0442
0.2974: 0.0680, 0.0485, 0.0353, 0.0776

Class 3:
0.4443: 0.1191, 0.3246, 0.3919, 0.3137
0.5505: 0.2189, 0.3122, 0.4981, 0.2021
0.6469: 0.0837, 0.1222, 0.5945, 0.1083```We can see that the nearest training instance for each test instance belongs to the same class:```
Class 1: 3 correct
Class 2: 3 correct
Class 3: 3 correct```Therefore, we have correctly classified all test instances, and the accuracy is 100%.

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Un coche tarda 1 minuto y 10 segundos en dar una vuelta completa al circuito,otro tarda 80 segundos ¿Cuándo volverán a encontrarse?

Answers

We may use the concept of many commons to predict when two cars making a circuit will next be found.

The first car takes one minute and ten seconds to do a full turn, which is equal to 70 seconds. The second car takes 80 seconds to make a full turn. We're looking for the first instance when both cars are at the starting line at the same time.To determine when they will be discovered again, we can locate the smallest common mixture of the 1970s and 1980s. The smaller common multiple of these two numbers is 560.

Then, after 560 seconds, or 9 minutes and 20 seconds, the two cars will reappear. This will be the first time both cars finish at the same time.

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