Answer: C = -5
Step-by-step explanation:
You have to add two on both sides and the remove 2/3 on both sides. Hope this helps
<!> Brainliest is appreciated! <!>
[tex]\text{Solve for c:}\\\\\frac{8}{3c-2}=\frac{2}{3c-12}\\\\\text{Cross multiply}\\\\8(3c-12)=2(3c-2)\\\\24c-96=6c-4\\\\\text{Subtract 6c from both sides}\\\\18c-96=-4\\\\\text{Add 96 to both sides}\\\\18c=92\\\\\text{Divide both sides by 18}\\\\c=\frac{92}{18}\\\\\text{Simplify}\\\\\boxed{c=\frac{46}{9}}[/tex]
A train travels 600 km in one hour .what is the trains Velocity in meters /seconds?
Answer:
166.6666 metres/second
Step-by-step explanation:
1 km/hr = 5m/18s
600*5/18
A translation moves A(2,3) onto A′(4,8). If B(4,6), what is the image of B under the same translation?
A. (6,11)
B. (12,18)
C. (6,8)
D. (8,12)
Need help on this math problem!!!
Answer:
[tex](fof^{-1})(x)=x[/tex]
Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]
Another function is the inverse of f(x),
[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]
Now composite function of these functions will be,
[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]
= [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]
= [tex][-\sqrt{x}+8-8]^2[/tex]
= [tex](-\sqrt{x})^2[/tex]
= x
Therefore, [tex](fof^{-1})(x)=x[/tex]
HELP IF YOU KNOW THIS PLEASEEEE
Answer:
63m
Step-by-step explanation:
In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. The article "Modeling of Simultaneously Continuous and Stochastic Construction Activities for Simulation" (J. of Construction Engr. and Mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value 8.46 min and standard deviation .913 min for the rv X 5 truck haul time.a. What is the probability that haul time will be at least 10 min? Will exceed 10 min?b. What is the probability that haul time will exceed 15 min?c. What is the probability that haul time will be between 8 and 10 min?d. What value c is such that 98% of all haul times are in the interval from 8.46 2 c to 8.46 1 c?e. If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
Answer:
a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455
b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460
d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)
c = 2.12
e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700
Step-by-step explanation:
This is a normal distribution problem with
Mean = μ = 8.46 min
Standard deviation = σ = 0.913 min
a) Probability that haul time will be at least 10 min = P(X ≥ 10)
We first normalize/standardize 10 minutes
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
To determine the required probability
P(X ≥ 10) = P(z ≥ 1.69)
We'll use data from the normal distribution table for these probabilities
P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)
= 1 - 0.95449 = 0.04551
The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455
b) Probability that haul time will exceed 15 min = P(X > 15)
We first normalize 15 minutes.
z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16
To determine the required probability
P(X > 15) = P(z > 7.16)
We'll use data from the normal distribution table for these probabilities
P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)
= 1 - 1.000 = 0.000
c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)
We normalize or standardize 8 and 10 minutes
For 8 minutes
z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50
For 10 minutes
z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69
The required probability
P(8 < X < 10) = P(-0.50 < z < 1.69)
We'll use data from the normal distribution table for these probabilities
P(8 < X < 10) = P(-0.50 < z < 1.69)
= P(z < 1.69) - P(z < -0.50)
= 0.95449 - 0.30854
= 0.64595 = 0.6460 to 4 d.p.
d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?
98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.
Let the lower limit be x'
Let the upper limit be x"
P(x' < X < x") = 0.98
P(X < x') = 0.01
P(X < x") = 0.99
Let the corresponding z-scores for the lower and upper limit be z' and z"
P(X < x') = P(z < z') = 0.01
P(X < x") = P(z < z") = 0.99
Using the normal distribution tables
z' = -2.326
z" = 2.326
z' = (x' - μ)/σ
-2.326 = (x' - 8.46)/0.913
x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34
z" = (x" - μ)/σ
2.326 = (x" - 8.46)/0.913
x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58
Therefore, P(6.34 < X < 10.58) = 98%
8.46 - c = 6.34
8.46 + c = 10.58
c = 2.12
e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?
This is a binomial distribution problem because:
- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)
- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)
- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)
Probability that at least one of them exceeds 10 mins = P(X ≥ 1)
= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
= 1 - P(X = 0)
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = 4 haul times are independently selected
x = Number of successes required = 0
p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455
q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545
P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044
P(X ≥ 1) = 1 - P(X = 0)
= 1 - 0.83004900044 = 0.16995099956 = 0.1700
Hope this Helps!!!
Which relationship in the triangle must be true?
A
c
b
C
B
а
sin(B) = sin(A)
sin(B) = cos(90 - B)
COS(B) = sin(180 - B)
cos(B) = (A)
Answer:
sin(B) = cos(90 - B).
Step-by-step explanation:
To answer this question, you must understand SOH CAH TOA.
SOH = Sine; Opposite divided by Hypotenuse
CAH = Cosine; Adjacent divided by Hypotenuse
TOA = Tangent; Opposite divided by Adjacent
I roughly drew a triangle for reference. Let's say we have a 3-4-5 triangle.
As you can see, sin(b) does not equal sin(a). To get the sine of an angle, you would do opposite over hypotenuse. For angle B, that would be 3/5, while for angle A, that would be 4/5.
As stated above, sin(B) is 3/5. Now, if you did cos(90 - B), it would be the same thing as cos(A). This is because the triangle is a right triangle. Since a triangle has 180 degrees, and one angle is a right triangle, the other two angles will add up to be 90 degrees. So, 90 - B = A. cos(A) is the same thing as adjacent over hypotenuse, which is 3/5. So, sin(B) = cos(90 - B) must be true.
Let's just check the others to make sure they are false.
cos(B) = 4/5.
sin(180 - B) is basically the same thing as sin(A + C), which is definitely NOT 4/5.
cos(B) = 4/5, which is NOT the same as A.
So, your answer is sin(B) = cos(90 - B).
Hope this helps!
Can someone please help me I really need help
Answer:
choice c
Step-by-step explanation:
y axis shows value of computer
v-intercept; x axis = 0
show initial value of the computer
Estimate. 6.13/3 Choose 1 answer: a 2 b20 c200 d2000
Answer:
The answer is option A.
2.Hope this helps you
PLEASE HELP, I WILL MARK YOU BRANIEST, PLEASE EXPLAIN AND GIVE AN ACCURATE ANSWER 1) Each letter of the word "MATHEMATICS" is written on a separate slip of paper and placed in a hat. A letter is chosen at random from the hat. What is the probability of choosing "M" on your first try? 2) Suppose you choose an “M” on your first try. You keep the slip of paper (do not replace it in the hat) and go for another letter. What is the probability of getting another “M”?
Step-by-step explanation:
Total letters = 11
Probability of letter M = 2/11
Probability of second M = 1/10
please help !! what’s the answer? i don’t understand !!
Answer:
992
Step-by-step explanation:
You must convert the meter the kilometer by miltiplying by 1000
and when you do it you must multiply 0.992 by 1000 since it is a fraction .
or you can work it this way :
0.992⇒1m x(the new rate) ⇒1000m x= 0.992*1000= 992a group of girls bought 72 rainbow hairbands ,144 brown and black hairbands and 216 bright colored hairbands .what is the largest possible number of girls in the group
Answer:
72
Step-by-step explanation:
We are assuming that all girls in the group bought the same number of items.
Therefore, we need to find the highest common factor of 72, 144 and 216.
HCF
72 = 2 * 2 * 2 * 3 * 3
144 = 2 * 2 * 2 * 2 * 3 * 3
216 = 2 * 2 * 2 * 3 * 3 * 3
The product of the emboldened numbers is the highest common factor.
That is:
2 * 2 * 2 * 3 * 3 = 72
Therefore, the largest possible number of girls in the group is 72.
Help!!!!! please!!!!!
Hey there! :)
Answer:
B. The volume of Cylinder B is larger.
Step-by-step explanation:
Find the volumes of each cylinder using the formula V = πr²h:
Cylinder A:
V = π3² · 5
V = 9π · 5
V = 45π units³
Cylinder B:
V = π5²· 3
V = 25π · 3
V = 75π units³
75π u³ > 45π u³, so the volume of Cylinder B is larger.
What is the slope of the line that contains the points (-1, 2) and (3, 3)?
O A. 4
O B. 4
ОС.
4
OD.
4
Answer:
the answer shoudl be OB 4
Which of the following is the best definition of slope?
O A. The point where a line crosses the y-axis
B. The measure of the steepness of a line
O C. The value of a dependent variable
O D. The value of an independent variable
Answer: B
Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.
Based on a recent poll, there is a 50-50 chance that randomly selected adut has pierced ears, Express the indicated degree of likelihood as a proabability value between 0 and 1.
Answer:
1/2 or 0.5
Step-by-step explanation:
Saying that there is a 50-50 chance of an event happening is equivalent to saying there is a 1 in 2 chance. Therefore, expressing that degree of likelihood as a value between 0 and 1:
[tex]\frac{1}{2}=0.50[/tex]
There is a 1/2 or 0.5 chance that a randomly selected adult has pierced ears.
Answer:
1/2 or 0.5
Step-by-step explanation:
50-50 chance between 0-1 means half of 0-1 which is 1/2 or 0.5
1/2 or 0.5!
solve this, please prove it with steps in detail
Answer:
2
Step-by-step explanation:
-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3
-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)
-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3
2
I am looking to decrease my bill by 25%. Can you look at my current plan and tell me what I can remove to achieve this reduction in cost? My current bill is $140.00 per month
Answer: $35
Step-by-step explanation:
From the question, we are informed that the current bill of the person is $140.00 per month and that the person wants to decrease the bill by 25%.
To know the amount that the person needs to deduct, we have to calculate 25% of $140.00. This will be:
= 25% of $140
= 25/100 × $140
= 1/4 × $140
= 0.25 × $140
= $35
The person will need to remove $35. The person will now pay ($140 - $35) = $105 monthly.
The amount that could be removed to achieve the specified reduction is $35.00
From the question,
We are to determine what should be removed from the current bill to decrease it by 25%
From the given information,
The current bill = $140.00 per month
Now, we will determine 25% of $140.00
That is,
[tex]\frac{25}{100}\times \$140.00[/tex]
= 25 × $1.40
= $35.00
Hence, the amount that could be removed to achieve the specified reduction is $35.00
Learn more here: https://brainly.com/question/10610667
A certain quantity decays exponentially over time. The initial quantity at t = 0 is 1,000. The quantity
decays at a rate of 2%. What is the quantity at t = 4?
A. 0.00016
B. 1.6000
C. 903.9208
D. 922.3682
Answer:
D: 922.3682
Step-by-step explanation:
First you take 1000 and subtract 20 from it.( 2% of 1000 = 1000x0.02x2=20).
You could do this on a calculator by entering 1000 and then subtracting 2% by clicking minus then, 2 then percent, then equals. you get 980. do the same to 980. (click minus, then 2, then percent, then equals). you get 960.4. do the same to 960.4. you get 941.192. do the same one more time since it says t=4 and you get 922.36816 which rounded to the nearest ten-thousandths is 922.3682.
hope this helped!
Consider the following quadratic equation. -4x^2+bx-11=0 Determine a possible value of b so that the quadratic has two complex solutions.
Answer:
Step-by-step explanation:
hello,
for [tex]ax^2+bx+c=0[/tex]
[tex]\Delta = b^2-4ac[/tex]
so here
[tex]\Delta = b^2-4*(-4)*(-11)=b^2-176[/tex]
to have two complex solutions we need [tex]\Delta < 0\\[/tex]
so [tex]b^2<176[/tex]
[tex]<=> b < \sqrt{176}=13.266...[/tex]
for instance we can take b = 0
hope this helps
Answer:
The correct answer is 12.
Step-by-step explanation:
i got it correct on my test, thanks to comment on the question above.
which is the domain of the function in this table ?
Answer: 1,2,3,4
Step-by-step explanation:
The domain consists of every x value
Please help! *grade 9 algebra work* :)
Answer:
9x-3 or 3(3x-1)
Step-by-step explanation:
A triangle has three sides. To find the perimeter, add those side lengths together.
3x-3+(4x-1)+(2x+1)
Add your common terms (xs and constants) together.
3x+4x+2x=9x
-1+-3+1=-3
9x-3
If you want to, you can factor the expression.
3(3x-1)
Answer:
9x - 3
Step-by-step explanation:
The perimeter is all the sides added together.
4x - 1 + 2x + 1 + 3x - 3
Rearrange.
4x + 2x + 3x - 1 + 1 - 3
Combine like terms.
9x - 3
Nash's Trading Post, LLC took a physical inventory on December 31 and determined that goods costing $208,000 were on hand. Not included in the physical count were $30,000 of goods purchased from Swifty Corporation, FOB, shipping point, and $23,500 of goods sold to Marigold Corp. For $30,000, FOB destination. Both the Swifty purchase and the Marigold sale were in transit at year-end.
Answer:
$261,500
Step-by-step explanation:
What amount should Nash report as its December 31 inventory?
Item Amount
Goods on hand as per physical count $208,000
(+) Goods purchased from Swifty $30,000
Corporation FOB shipping point
(+) Goods sold to Marigold Corp $23,500
FOB destination (at cost value)
Ending inventory $261,500
Notes:
1) In case of FOB shipping point, the ownership of goods is transferred to the buyer when the goods are shipped and hence in the case of purchases from Swifty corporation, the goods should be included in the inventory of Nash's Trading Post as the goods are shipped and are in transit.
2) In case of FOB destination, the ownership of goods is transferred to the buyer when the goods reaches to the buyer, hence in the case of sales made to Marigold Corp, the goods are still in transit and the ownership is not transferred to Marigold Corp, hence Nash's Trading Post should included that goods in its inventory.
Two teaching methods, A and B, are implemented for learning Spanish. There is a 70% chance of successfully learning Spanish if method A is used, and a 85% chance of success if methodB is used. However, method B is substantially more 3. time consuming and is therefore used only 20% of the time (method A is used the other 80% of the time). The following notations are suggested:
A-Method A is used.
B-Method B is used.
L-Spanish was learned successfully Interpret each of the probabilities given in the original problem in probability
a) notation with their respective values (four of these).
b) Draw a Probability Tree representing each of the probabilities mentioned above.
c) What is the likelihood a person does not learn Spanish?
d) A student learned the spanish successfully. What is the probability that they were taught by method B?
Answer:
(a) Shown below.
(b) Shown below.
(c) The probability that a person does not learn Spanish is 0.18.
(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.
Step-by-step explanation:
(a)
Consider the provided data.
[tex]P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85[/tex]
Then the probability of not learning Spanish using the respective methods are:
[tex]P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15[/tex]
(b)
The Probability Tree representing each of the probabilities mentioned above is attached below.
(c)
Compute the probability that a person does not learn Spanish as follows:
[tex]P(L')=P(L'|A)P(A)+P(L'|B)P(B)[/tex]
[tex]=(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18[/tex]
Thus, the probability that a person does not learn Spanish is 0.18.
(d)
Compute the probability that method B was used given that a student learned the Spanish successfully as follows:
[tex]P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}[/tex]
[tex]=\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83[/tex]
Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.
You have a prepaid bus pass that has $10 on it. Every time you ride the bus it costs you 50 cents. Assume that you cannot put anymore money on the card after it is used. Create an equation for the situation above.
Answer:
y = 10 - 0.5x for 0 ≤ x ≤ 20
Step-by-step explanation:
Initial value = (0,10)
final value = (20,0)
Cost per trip = debit of 0.50 = slope
equation : y = 10 - 0.5x for 0 <= x <= 20
The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (rounded to 2 DP) of these 13 people's big finger?
Answer:
The mean length of the 13 people's big finger is 15.45 cm
Step-by-step explanation:
Given;
mean length of 4 childrens' big finger, x' = 14cm
mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm
Let the total length of the 4 childrens' big finger = t
[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]
Let the total length of the 9 adults' big finger = T
[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]
The total length of the 13 people's big finger = t + T
= 56 + 144.9
=200.9 cm
The mean length of these 13 people's big finger;
x''' = (200.9) / 13
x''' = 15.4539 cm
x''' = 15.45 cm (2 DP)
Therefore, the mean length of the 13 people's big finger is 15.45 cm
Does the following table show a proportional relationship between the variables , g and h?
9
3
6
9
h
9
36
81
Choose 1 answer:
А
Yes
No
Report a problem
Answer:
no
Step-by-step explanation:
Answer:
No is the answer you are welcome
. Write an example problem that includes a compound event. b. List all of the outcomes of the sample space of the compound event.
Answer:
living organism
Step-by-step explanation:
soil particals and decad crops living organism
Helppp!!!! please!!!
Answer:
A. 336 ft²
Step-by-step explanation:
Add the sides: 6*8 + 6*12 + 12*8 + 10*12 = 336
One little trick: the area of the triangle sides is base times half height, i.e., 6*8/2, but since we have two of them you can just use 6*8!
Please answer i will give thanks and 5 star
Answer:
A, B, and E are all less than 1/8
Here is a Venn diagram. One of the numbers in the Venn diagram is picked at random. Find the probability that this number is in set C'
Answer:
5/6
Step-by-step explanation:
hello
in total there are 12 numbers
C has two items
so C' has 10 items
so the probability that this number is in set C' is 10/12=5/6
hope this helps