Solve and graph 4<-1/3n

Answer:

(2,9)

Step-by-step explanation:

Answer:

(2,9)

Step-by-step explanation:

because you move up by 6. which makes it (2,3)+6

Answer:

c = 17(83)-17(16)=1139

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

Step-by-step explanation:

Given :-

The length of the garden 8m greater than 2 times the width.

Area of the garden is 280 m²

Let us consider the length as x and width as y.

Sp, we can day length as :-

x = 8 + 2y ---(1)

Now, we know that:-

Area of Rectangle = Length × Breadth

280 = x * y

We can replace the value of x now,

280 = y × ( 8 + 2y)

280 = 8y + 2y²

2y² + 8y - 280 = 0

y² + 4y - 140 = 0

Factorise it.

(y -10)(y + 14)

Cancelling -ve value, we get the width as 10 metres.

Hope it helps :)

Answer:

Step-by-step explanation:

Width = w

Length = 2w + 8

Area of rectangular garden = 280 square meter

length * width = 280

(2w + 8 ) *w = 280

2w * w + 8*w = 280

2w² + 8w = 280

2w² + 8w - 280 = 0

Divide the whole equation by 2

w² + 4w - 140 = 0      

w² + 14w - 10w - 14 *10 = 0

w(w + 14) - 10(w + 14) = 0

(w + 14)(w - 10)= 0

w - 10 = 0       {Ignore w + 14, as measurements will not be -ve}

w = 10 m

l = 2*10 +8

= 20 +8

l  = 28 m

Answer:

A and D have whole grid squares that are the same size and aren't over lapping

C has overlapping grid squares making it hard to count

B can't be used to find area because some of the grid squares are different sizes

You still could use B because four of the smaller squares seems to be equivalent to one of the larger squares

Step-by-step explanation:

Answer:

the guy up there is right

Step-by-step explanation:

Answer:

5000

Step-by-step explanation:

i dont know this answer but i try that

Answer:

208m²

Step-by-step explanation:

Okay, so you can split this abomination into a rectangle, another rectangle, and a square, so we're going to start with the rectangle to the far left:

The formula for the area of a rectangle or square is length x width, so we just have to plug:

4 x 8 = 32

Now we do the next rectangle, but we have to figure out the length first, so:

4 + 4 = 8

Now we plug:

8 x 4 = 32 (I now realize that the rectangles are even and we could've just multiplied the first one by two, but it's always good to check)

Now we do the square:

12 x 12 = 144

Now we add it all together:

32 + 32 + 144 = 208

So the area of the figure is 208m²

if this is wrong, let me know so I can fix it

hope this helps:)

Answer:

1. Square, 10in x 8in, 160in^2

2. Each surface has an area of 80in^2

Step-by-step explanation:

1. Rectangle is the shape of each cut surface which is 10in by 8 in. Since the block was already painted with glitter, she needs to paint both sides of the cut surface only, 2*8in * 10in = 160in^2.

2. Each cut will have a surface area of 10in * 8in = 80in^2

Please leave a like if this is the answer you were looking for

Answer:

it Is a variable..............

Answer:

critical value = 5.29

Step-by-step explanation:

Given that they are divided into 4 groups and a sample of 5 test was selected

N = 5 * 4 = 20

k = 4

∝ = 0.01

Df for numerator ( SS group )= k - 1 = 3

Df for denominator ( SSE group )  = N - k = 20 - 4 = 16

DF ( degree of freedom )

Next we will use the F table to determine the critical value

Critical value =   [tex]F_{16,3,0.01}[/tex] = 5.29

Answer: c. . A matched-pairs t-test for a mean difference

Step-by-step explanation:

Based on the information given in the question and assuming all conditions for inference are met, the appropriate test for the investigation will be a matched-pairs t-test for a mean difference.

Since a matched-pairs t-test can be used to determine if a significant mean difference exist between two paired data, then this will be appropriate in this case since the safety officers at both schools want to know if there's an average difference in the number of cars parked per day in the student parking lots for the school year.

The appropriate test for the investigation of the given case is done by: Option C:  A matched-pairs t-test for a mean difference

When there has to be done comparison between means of two sets of paired data, then we use matched pair t test.

For the given case the investigation is to know whether there is an average difference in the number of cars parked per day in the student parking lots for the school year for both the schools in consideration.

So there are two data sets and comparison of their mean is to be done.

Thus, the appropriate test for the investigation of the given case is done by: Option C:  A matched pairs t-test for a mean difference.

Learn more about matched pair t-test here:

https://brainly.com/question/14690592

Answer:

The average value of g is:

[tex]\displaystyle g_{ave}=\frac{1}{6}e^6-\frac{49}{6}\approx 59.071[/tex]

Step-by-step explanation:

The average value of a function is given by the formula:

[tex]\displaystyle f_{ave}=\frac{1}{b-a}\int_a^b f(x)\, dx[/tex]

We want to find the average value of the function:

[tex]g(x)=e^{3x-3}-4x[/tex]

On the interval [1, 3].

So, the average value will be given by:

[tex]g_{ave}=\displaystyle \frac{1}{3-1}\int_1^3 e^{3x-3}-4x\, dx[/tex]

Simplify. We will also split the integral:

[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\int_1^3e^{3x-3}\, dx-\int _1^3 4x\, dx\right)[/tex]

We can use u-substitution for the first integral. Letting u = 3x - 3, we acquire:

[tex]\displaystyle u=3x-3\Rightarrow du = 3\, dx\Rightarrow \frac{1}{3} du=dx[/tex]

We will also change the limits of integration for our first integral. So:

[tex]u(1)=3(1)-3=0\text{ and } u(3)=3(3)-3=6[/tex]

Thus:

[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\int_0^6 e^{u}\, du-\int _1^3 4x\, dx\right)[/tex]

Integrate:

[tex]g_{ave}=\displaystyle \frac{1}{2}\left(\frac{1}{3}e^u\Big|_0^6-2x^2\Big|_1^3\right)[/tex]

Evaluate. So, the average value of g on the interval [1, 3] is:

[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\left[e^6-e^0\right]-\left[2(3)^2-2(1)^2\right]\right)[/tex]

Evaluate:

[tex]\displaystyle\begin{aligned} g_{ave}&=\frac{1}{2}\left(\frac{1}{3}(e^6-1)-16\right)\\&=\frac{1}{2}\left(\frac{1}{3}e^6-\frac{1}{3}-16\right)\\&=\frac{1}{6}e^6-\frac{49}{6}\approx59.071\end{aligned}[/tex]

Answer:

Subtotal 70.00

15% Tip 10.50

Total 80.50

Step-by-step explanation:

1% 0.70

2% 1.40

3% 2.10

4% 2.80

5% 3.50

6% 4.20

7% 4.90

8% 5.60

% Tip

9% 6.30

10% 7.00

11% 7.70

12% 8.40

13% 9.10

This dude above is trash and wrong, I got a 0 because of him

Answer:

send money and i gotchu

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

2-(-5)=7--one side

square (all sides are the same)

4 sides in total

7x4=28

Answer:

18057

Step-by-step explanation:

uh just 200 x 10 = 200 add that to the 6 to make 18057$ which is the price of the second van.

Answer:

B. [tex]\displaystyle -\frac{1}{3}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

The definition of a derivative is the slope of the tangent line

Basic Power Rule:

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \sqrt{x} + \sqrt{y} = 2[/tex]

[tex]\displaystyle (\frac{9}{4}, \frac{1}{4})[/tex]

Step 2: Differentiate

Implicit Differentiation

Step 3: Evaluate

Find slope of tangent line

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differentiation - Implicit Differentiation

Book: College Calculus 10e

Answer:

hi bro how are yuo join this meeting i will say you ans

Step-by-step explanation:

Answer:

Part A: 27.32

Part B: 4.92

Step-by-step explanation:

25.30*.08(or 8%) is equal to 2.024

25.30+2.024=27.324=27.32

32.24-27.32=4.92

Answer:

Step-by-step explanation:

A tariff is a tax imposed by a government of a country or of a supranational union on imports or exports of goods. Besides being a source of revenue for the government, import duties can also be a form of regulation of foreign trade and policy that taxes foreign products to encourage or safeguard domestic industry

Answer:

Step-by-step explanation:

c

Answer:

[tex](a)\ c = \frac{1}{15}[/tex]

[tex](b)\ 40\%[/tex]

[tex](c)\ 60\%[/tex]

Step-by-step explanation:

The given parameters can be represented as:

[tex]P_Y(y) \ge 0, y =1,2,3,4,5[/tex]

[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]

Solving (a): The value of c

To do this, we make use of the following rule;

[tex]\sum\limit^5_{y=1}P_Y(y_i) = 1[/tex]

Given that:

[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]

This is translated to:

[tex]c*1 + c * 2 + c * 3 + c * 4 + c * 5 = 1[/tex]

[tex]c + 2c + 3c + 4c + 5c = 1[/tex]

[tex]15c = 1[/tex]

Solve for c

[tex]c = \frac{1}{15}[/tex]

(b) The proportions of applications that requires at most 3 forms

This implies that: y = 1,2,3

So, we make use of:

[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]

Recall that:

[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]

Substitute [tex]c = \frac{1}{15}[/tex]

[tex]P_y(y) =\frac{1}{15}y[/tex]

So:

[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]

[tex]P(Y\le 3) = \frac{1}{15} * 1 +\frac{1}{15} * 2 +\frac{1}{15} * 3[/tex]

[tex]P(Y\le 3) = \frac{1}{15} +\frac{2}{15} +\frac{3}{15}[/tex]

Take LCM

[tex]P(Y\le 3) = \frac{1+2+3}{15}[/tex]

[tex]P(Y\le 3) = \frac{6}{15}[/tex]

[tex]P(Y\le 3) = 0.4[/tex]

Express as percentage

[tex]P(Y\le 3) = 0.4*100\%[/tex]

[tex]P(Y\le 3) = 40\%[/tex]

(c) The proportions of applications that requires between 2 and 4 forms (inclusive)

This implies that: y = 2,3,4

So, we make use of:

[tex]P(2 \le Y \le 4) = P(Y=2) + P(Y=3) + P(Y=4)[/tex]

[tex]P(2 \le Y \le 4) = 2 * \frac{1}{15} + 3 * \frac{1}{15} + 4 * \frac{1}{15}[/tex]

[tex]P(2 \le Y \le 4) = \frac{2}{15} + \frac{3}{15} + \frac{4}{15}[/tex]

Take LCM

[tex]P(2 \le Y \le 4) = \frac{2+3+4}{15}[/tex]

[tex]P(2 \le Y \le 4) = \frac{9}{15}[/tex]

[tex]P(2 \le Y \le 4) = 0.6[/tex]

Express as percentage

[tex]P(2 \le Y \le 4) = 0.6 * 100\%[/tex]

[tex]P(2 \le Y \le 4) = 60\%[/tex]

Answer:

I belive it;s 4/5

Step-by-step explanation:

Answer:

2?

Step-by-step explanation:

4 divided by 2 = 2

The scenario that will bring about a type II error will be when the true mean is 405 ppm and he uses a significance level of 0.15

It should be noted that a type II error simply describes the error that occurs when the individual fails to reject a null hypothesis.

From the complete question, type II error will be when the true mean is 405 ppm and he uses a significance level of 0.15. In this case, the null hyothesis was not rejected.

Learn more about type II error on:

https://brainly.com/question/16012410

Answer:

Step-by-step explanation:

Answer:

A,B,E or 1,2,5

if its letters or numbers.

Step-by-step explanat

The expressions that are the result of decreasing x by 80% will be (1 - 0.80)x, x - (80/100)x, and (20/100)x. Then the correct options are A, C, and E.

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.

The expressions that are the result of decreasing x by 80%.

We know that if something is decreased by a percentage p% then the percentage is written as (1 - p%). Then the expression is written as,

⇒ [(100 - 80) / 100]x

Then the expression can be written as,

⇒ [(100 - 80) / 100]x

⇒ x - (80/100)x

⇒ x - 0.80x

⇒ (1 - 0.80)x

⇒ 0.20x

⇒ (20/100)x

The expressions that are the result of decreasing x by 80% will be (1 - 0.80)x, x - (80/100)x, and (20/100)x. Then the correct options are A, C, and E.

More about the percentage link is given below.

https://brainly.com/question/8011401

#SPJ2

Answer:

45

Step-by-step explanation: