Solve absolute value equation 2|x-3|-8=2

Answer:

To write the congruence statement, you need to line up the corresponding parts in the triangles: \begin{align*}\angle R \cong \angle F, \angle S \cong \angle E,\end{align*} and \begin{align*}\angle T \cong \angle D\end{align*}. Therefore, the triangles are \begin{align*}\triangle RST \cong \triangle FED\end{align*}.

Step-by-step explanation:

Answer:

$3.77

Step-by-step explanation:

First, add all of the numbers together:

$3.00+$3.45+$4.15+$4.60+$4.65+$2.80=22.65

Next, divide that number by the number of numbers:

22.65/6=3.77

<3

Answer:

see attached image

Step-by-step explanation:

Answer:

the answer is 260

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

Use the distance formula to determine the distance between two points.

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Work Shown:

The two given points are [tex](x_1,y_1) = (4,3)[/tex] and [tex](x_2,y_2) = (16,8)[/tex]

Use the distance formula

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(4-16)^2+(3-8)^2}\\\\d = \sqrt{(-12)^2+(-5)^2}\\\\d = \sqrt{144+25}\\\\d = \sqrt{169}\\\\d = 13\\\\[/tex]

[tex] {1000}^{ \frac{2}{3} } = {10}^{ {3}^{ \frac{2}{3} } } = {10}^{3 \times \frac{2}{3} } = {10}^{2} = 100 \\ [/tex]

Answer:

the input is the number or gallons aka b

the output is the balance in the account aka c

and the two points described are (5,442) and (13,226) aka c

Step-by-step explanation:

i did it on edge and got it right :)

Answer:

here the answer

Step-by-step explanation:

Step-by-step explanation:

x−7(x−2)=10x+9−x

Step 1: Simplify both sides of the equation.

x−7(x−2)=10x+9−x

x+(−7)(x)+(−7)(−2)=10x+9+−x(Distribute)

x+−7x+14=10x+9+−x

(x+−7x)+(14)=(10x+−x)+(9)(Combine Like Terms)

−6x+14=9x+9

−6x+14=9x+9

Step 2: Subtract 9x from both sides.

−6x+14−9x=9x+9−9x

−15x+14=9

Step 3: Subtract 14 from both sides.

−15x+14−14=9−14

−15x=−5

Step 4: Divide both sides by -15.

−15x−15=−5−15

x=13

Answer:

x=13

Answer:

-2

Step-by-step explanation:

Answer:

(see below)

Step-by-step explanation:

You can also solve this algebraically:

–5 – (–3)

–5 + 3

–2

Since it can't be negative units between two points on a number line, you can multiply it by –1 to make it a positive number:

–2 (–1)

2 units

Or, you can use a number line. I have screenshotted a number line attached below for you.

Hopefully this helps!

Answer:

Did you insert a picture because I cant see one

Answer:

The equations of the line are

y + 7 = [tex]\frac{9}{7}[/tex] (x + 4) ⇒ B

y - 2 = [tex]\frac{9}{7}[/tex] (x - 3) ⇒ E

Step-by-step explanation:

The point-slope form of the linear equation is

[tex]y-y1=m(x-x1)[/tex] , where

∵ The line passes through points (-4, -7) and (3, 2)

∴ x1 = -4 and y1 = -7

∴ x2 = 3 and y2 = 2

→ Use the rule of the slope above to find it

∵ [tex]m=\frac{2--7}{3--4}=\frac{2+7}{3+4}=\frac{9}{7}[/tex]

∴ The slope of the line is [tex]\frac{9}{7}[/tex]

→ Substitute the values of m and (x1, y1) in the form of the equation above

∵ y - -7 = [tex]\frac{9}{7}[/tex] (x - -4)

∴ y + 7 = [tex]\frac{9}{7}[/tex] (x + 4)

∴ The equation of the line is y + 7 = [tex]\frac{9}{7}[/tex] (x + 4)

→ Substitute the values of m and (x2, y2) in the form of the equation above

∵ y - 2 = [tex]\frac{9}{7}[/tex] (x - 3)

∴ The equation of the line is y - 2 = [tex]\frac{9}{7}[/tex] (x - 3)

→  Look at the answers to find the same equations

∴ Answers B and E have the same equations

Answer:

3 million or 3 x 10^6

Step-by-step explanation:

You would round this up to three million because the digit before it is 5 or larger. Then, using the three million number, you move the decimal over 6 places to get a digit less than ten so it would become 3 times 10 to the power of 6

Answer:

a) 98m

b) 2m/s

Step-by-step explanation:

a) 2+4+6+8+10(8) = 98m

b) a = change/time = 8m/4s = 2m/s

not completely sure about a) so pls double check that <//3

good luck and hope this helped a bit!

The correct answers for the given problem are: (a) The distance travelled on the cycle in the first 14 seconds is 96 m and (b)The acceleration in the first 4 seconds is 2 m/s².

The area under a graph can be found by dividing the graph into equal intervals of very small width and then find the area of the rectangle for each intervals. After summing all the areas of rectangles the area under the graph can be approximated.

The velocity time graph given in the problem can be used to find the distance travelled.

The distance travelled in first 14 seconds is equal to the area of the graph from t = 0 to t = 14.

This area consists of a triangle of height h = 8 and base b = 4 and a rectangle of length l = 8 and width b = (14 - 4) = 10.

Now, the total area is given as,

1/2 × b × h + l × b

= 1/2 × 4 × 8 + 8 × 10

= 16 + 80

= 96

(b) The acceleration is given as the rate change of velocity with respect to time.

The acceleration in first 4 seconds is given as,

a = (8 - 0)/4

   = 2

Hence, the distance travelled in first 14 seconds and acceleration in first 4 seconds is given as 96 m and 2 m/s² respectively.

To know more about area of a graph click on,

https://brainly.com/question/26315835

#SPJ2

Answer:

3/5 lmk if you need the work

Step-by-step explanation:

Answer:

p = 1/8

Step-by-step explanation:

Hi there !

⁸⁾-3p + 1/8 = ²⁾- 1/4

- 24p + 1 = - 2

- 24p = - 2 - 1

- 24p = - 3 | (-)

24p = 3

p = 3⁽³/24

p = 1/8

Good luck !

Answer:

Top left

Step-by-step explanation:

Answer:

A 1

Step-by-step explanation:

8x11=88

1x11=11

The value of the x should be more than or equal to 5.69. Then the correct option is A.

Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as we will as is used to compare two statements.

A school is planning a fundraiser with all profits going to charity.

Ticket Sales: 200x − 10x²

Event Cost: 500 + 20x

The amount of profit is found by subtracting the total cost from total ticket sales. A profit of $200 or more.

             Event cost − Total sales  ≥ Profit

         (500 + 20x) − (200x − 10x²) ≥ 200

− 200x + 10x² + 500 + 20x − 200 ≥ 0

                         10x² + 180x − 700 ≥ 0

                         10x² − 180x + 700 ≥ 0

                                  x² − 18x + 70 ≥ 0

On simplifying, we have

(x − 5.69) (x − 12.33) ≥ 0

                               x ≥ 5.69, 12.33

Thus, the value of the x should be more than or equal to 5.69. Then the correct option is A.

More about the inequality link is given below.

https://brainly.com/question/19491153

Answer:

Step-by-step explanation:

the 10,000's column

hope this helped :)

Answer:

[tex]the \: place \: of \: 5 \: is \: 50000 \: \\ i.e \: tent \: of \: thousand.[/tex]

Answer:

The point (1 | 6) is on the graph.

Step-by-step explanation:

Answer:

it is 1/6

Step-by-step explanation:

Answer:

y=[tex]\frac{1}{3}[/tex]x+8

Answer:

Step-by-step explanation:

P(y) = y³ + 2y² + 2y + 1  

P(-1) = (-1)³ + 2*(-1)² + 2*(-1) + 1

      = -1 + 2 - 2 + 1

      = 0

As, P(-1) = 0, (y + 1) is a factor.

  Use synthetic division or remainder theorem.

-1        1          2           2           1

           0        -1            -1         -1        

           1          1            1            0

quotient = y² + y + 1

y³ + 2y² + 2y + 1  = ( y + 1) (y² + y + 1)

Answer:

46 miles per hour. I think I've haven't had a problem as easy as this so I was overthinking a lot

Step-by-step explanation:

in the graph the line is passing through points (2,92) and the time is going by two's so you just divide to get the constant

Answer:

46 miles per hour

Step-by-step explanation:

2x46=92

92÷2=46

92-46=46

Answer:

[tex]\frac{d^2y}{dx^2} = \frac{-300y^2}{(4y^3-11)^3}[/tex]

Step-by-step explanation:

Given the expression  [tex]y^4+5x=11y[/tex], we are to find the second derivative [tex]\frac{d^2y}{dx^2}[/tex]

This differentiation will be implicit (indirect) as shown:

[tex]4y^3 \frac{dy}{dx} + 5 = 11\frac{dy}{dx} \\4y^3 \frac{dy}{dx} - 11 \frac{dy}{dx} = -5\\\frac{dy}{dx}(4y^3-11) = -5\\\frac{dy}{dx} = \frac{-5}{4y^3-11}[/tex]

Differentiating the second time using quotient rule:

[tex]\frac{d^2y}{dx^2} = \frac{4y^3-11 (0)- (-5)12y^2\frac{dy}{dx} }{(4y^3-11)^2} \\\\\frac{d^2y}{dx^2} = \frac{60y^2\frac{dy}{dx} }{(4y^3-11)^2} \\\\\frac{d^2y}{dx^2} = \frac{60y^2(\frac{-5}{4y^3-11} ) }{(4y^3-11)^2}\\\\\frac{d^2y}{dx^2} = \frac{-300y^2}{(4y^3-11)^3}[/tex]