Solve 1/3(3.2×1.4)2.8

Simplify your answer​

Answer:

726

Step-by-step explanation:

Here p = k / q², and 24 = k / 121, or k = 2904

Then p = 2904 / q²

If q = 2, p = 2904 /4 = 726

Answer:

p = 12 × 11²

Step-by-step explanation:

By question,

=> p ∝ 1/q²

=> p = k/q²

=> 24 = k/11²

=> k = 24 * 11²

=> p = k/q²

=> p = 24*11²/2

=> p = 12 × 11²

Answer:

f(x) = 5*sin( (5/4)*x) + 2

Step-by-step explanation:

A general sine function can be written as:

f(x) = A*sin(w*x) + M

Where:

A is the amplitude

w is the frequency of the function

M is the midline

Here we know that we want to have:

An amplitude of 5. Then, A  = 5

A midline of 2, then M = 2

And a period of (8/5)*pi

For now, we can write our function as:

f(x) = 5*sin(w*x) + 2

Now, we know that for a function of period T, is always true that:

f(x) = f(x + T)

here, the period is T = (8/5)*pi

knowing that sin(0) = sin(2*pi)

Then we must have:

sin(0) = sin(w*0) = sin(w*( 0 +  (8/5)*pi)) = sin(2*pi)

Then the arguments of the third and fourt parts must be the same, thus:

w*(8/5)*pi = 2*pi

We can solve this for w now:

w*(8/5) = 2

w = 2*(5/8) = (5/4)

Then the function is:

f(x) = 5*sin( (5/4)*x) + 2

[tex]\red {incomplete \: question}[/tex]

Answer:

115°

Step-by-step explanation:

65 +65 = 130

360-130= 230

230÷2= 115

Answer: 124

Step-by-step explanation:  7^2=49; 13^2=169; 19^2=361. Only 124 cannot be expressed as a square of an integer.

Answer:

124

Step-by-step explanation:

Answer:

b, c , a

Step-by-step explanation:

I am guessing

Answer:

B, C, D

Step-by-step explanation:

Answer:

Hello! answer 9/1000

Step-by-step explanation:

All you have to do is multiply the probability of each then you will get your answer so...

6/20 × 4/20 × 3/20 = 9/1000 So thats your probability. Hope that helps!

Answer: The histogram is skewered to the right (right-skewered)

Step-by-step explanation:

The peak veers to the left and the tail is towards the right.

The histogram given is right-skewed.

A histogram is a representation of the distribution of data with intervals.

We have,

Right-skewed and left-skewed are terms used to describe the shape of a data distribution.

A right-skewed (or positively skewed) distribution is one in which the tail on the right-hand side of the graph is longer or fatter than the tail on the left-hand side.

A left-skewed (or negatively skewed) distribution is the opposite of a right-skewed distribution.

In this case, the tail on the left-hand side of the graph is longer or fatter than the tail on the right-hand side.

Now,

We see that the histogram given is right-skewed because the tail on the right-hand side of the graph is longer or fatter than the tail on the left-hand side.

Thus,

The histogram given is right-skewed.

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Using the equation, the time the object will hit the ground after it is launched is 3.4 seconds.

To model the path of a projectile launched from ground level (h = 0), we can set h = 0 in the equation for y:

[tex]y = (v_0sin \theta)t - 16t^2[/tex]

Therefore, the parametric equations for the path of the projectile are:

[tex]x = (v_0cos\theta)t \\y = (v_0sin \theta)t - 16t^2[/tex]

Substituting θ = 40∘ and v0 = 128 feet per second, we get:

[tex]x = (128 cos 40^o)t\\y = (128 sin 40^o)t - 16t^2[/tex]

To determine the maximum height, we need to find the vertex of the parabolic path, which is given by:

t = -b/2a

where a = -16, b = 128 sin 40∘, and c = 0 (since the projectile starts and ends at ground level). Substituting the values, we get:

t = -128 sin 40∘ / (2*(-16)) = 2.3 seconds (approx)

The maximum height can be found by substituting this value of t into the equation for y:

y = (128 sin 40∘)(2.3) - 16(2.3)^2 = 230.3 feet (approx)

Therefore, the maximum height is 230.3 feet and it is reached at 2.3 seconds.

To find the horizontal distance at this point, we can substitute the value of t into the equation for x:

x = (128 cos 40∘)(2.3) = 172.8 feet (approx)

Therefore, the approximate horizontal distance the object is at this point is 172.8 feet.

To determine the time the object will hit the ground after it is launched, we need to find the time when y = 0:

[tex]0 = (128 sin 40)t - 16t^2[/tex]

Solving for t using the quadratic formula, we get:

t = 0 or t = 8 sin 40∘ / 2 = 3.4 seconds (approx)

Therefore, the time the object will hit the ground after it is launched is 3.4 seconds.

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Answer:

16.

Step-by-step explanation:

Is there a picture?

Answer:

true

Step-by-step explanation:

[tex]\frac{x}{2} <20[/tex]

* substitute 30 for x *

[tex]\frac{30}{2} <20\\\frac{30}{2} =15\\[/tex]

we're left with 15 < 20 which is true

Answer:

Greatest would be Chlorine Krypton Argon Fluorine and least Hydrogen

Answer:

J, I, G, K, H.

Step-by-step explanation:

The elements go from least to greatest, and since they are negatives, we sort them from the highest negative to the lowest negative.

Answer: The answer is B. Because 3 multiplied by x and add it by 3 equates to y. example: (x=2) 3x2+3= y. y=9 .

The answer is not b

Step-by-step explanation:

75 as a fraction of 125 would be 75/125

Now Lets simplify

75/25=3

125/25=5

We get 3/5

We can not reduce 3/5 anymore, so the answer is 3/5

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25. 75 is 3/5 fraction of 125.

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

Let 75 be x fraction of 125. Therefore, we can write the statement as,

x × 125 = 75

x = 75/125

x = 3 /5

Hence, 75 is 3/5 fraction of 125.

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Answer: [tex]-\frac{5}{12}[/tex]

Steps:

[tex]1\frac{1}{4}\times \left(-1\right)\frac{1}{3}[/tex]

Convert mixed numbers to improper fractions: [tex]1\frac{1}{4}[/tex][tex]=\frac{5}{4}[/tex]

[tex]=\frac{5}{4}\times \left(-1\right)\frac{1}{3}[/tex]

[tex]\mathrm{Apply\:the\:rule}:\quad \:a\left(-b\right)=-ab[/tex]

[tex]\frac{5}{4}\left(-1\right)=-\frac{5}{4}\times \:1[/tex]

[tex]=-\frac{5}{4}\times \:1\times \frac{1}{3}[/tex]

[tex]\mathrm{Apply\:rule}\:a\times 1=a[/tex]

[tex]=-\frac{5}{4}\times \frac{1}{3}[/tex]

[tex]\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}[/tex]

[tex]\frac{5}{4}\times \frac{1}{3}=\frac{5\times \:1}{4\times \:3}[/tex]

[tex]=-\frac{5\times \:1}{4\times \:3}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:5\times \:1=5[/tex]

[tex]=-\frac{5}{4\times \:3}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:4\times \:3=12[/tex]

[tex]=-\frac{5}{12}[/tex]

Hope This Helps!

22cm^3

Step-by-step explanation:

My education system is different so I dont know what nearest tenth would mean in this .

But going mathematically:

Its diameter is 7 centimetres.

So to find its volume we can use the formula pi/d or pi/r^2

Now, 22/7÷7 would be 22cm³.

The combined area of the circular bases of the cylinder is of 25.12 squared inches.

The area of a circle of radius r is given by:

[tex]A = \pi r^2[/tex]

In this problem, there are two bases, and each base is a circle of r = 2 in, hence the combined area in inches squared of the two bases is given by:

[tex]A_c = 2 \times \pi \times 2^2 = 8\pi = 25.12[/tex]

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Answer:

25.12 squared inches.

Hope this helps!

Answer:

The p-value of the test is 0.0014 < 0.01, meaning that the data indicates that the true average unrestrained compressive strength is less than the design value of 3200.

Step-by-step explanation:

We want to determine whether the data indicate that the true average unrestrained compressive strength is less than the design value of 3200.

At the null hypothesis, we test if the mean is at the design value of 3200, so:

[tex]H_0: \mu = 3200[/tex]

At the alternate hypothesis, we test if it is less than the design value of 3200, so:

[tex]H_a: \mu < 3200[/tex]

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

3200 is tested at the null hypothesis:

This means that [tex]\mu = 3200[/tex]

The sample average unrestrained compressive strength for 50 specimens of a particular type of brick was computed to be 3120 psi, and the sample standard deviation was 180.

This means that [tex]n = 50, X = 3120, s = 180[/tex]

Test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{3120 - 3200}{\frac{180}{\sqrt{50}}}[/tex]

[tex]t = -3.14[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean below 3120, which is the p-value of t = -3.14, using a one-tailed test, with 50 - 1 = 49 degrees of freedom.

With the help of a calculator, the p-value of the test is 0.0014

The p-value of the test is 0.0014 < 0.01, meaning that the data indicates that the true average unrestrained compressive strength is less than the design value of 3200.

Answer:

B

Step-by-step explanation:

Answer:

Radio es 8.799974535 cm

Diametro es 17.59994907 cm

Explicación paso a paso:

Como tienes la medida en cm, me indica que es el perimetro del circulo

C=πd

55.292=3.1416 d

\frac{55.292}{3.1416} =d

3.1416

55.292

=d

17.59994907=d

Para sacar radio hay que dividir entre 2

r=8.799974535

By solving for x you get x=6

Answer:

x = 6

Step-by-step explanation:

12x = 72

72/12 = 6

x = 6

I honestly don't know the answer. Hope this helps..

Answer:

We determined that the 10th figure will have 45 shaded squares. That means 100 – 45 = 55 squares will be unshaded

Step-by-step explanation:

hope this helps

Answer: [tex]x=9,\:x=-9[/tex]

Steps:

[tex]x^2-55=26[/tex]

[tex]\mathrm{Add\:}55\mathrm{\:to\:both\:sides}[/tex]

[tex]x^2-55+55=26+55[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]x^2=81[/tex]

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{81},\:x=-\sqrt{81}[/tex]

[tex]\sqrt{81}[/tex]= 9

[tex]-\sqrt{81}=-9[/tex]

So That Equals:

[tex]x=9,\:x=-9[/tex]

#[tex]Hardnessed To Perfection[/tex]

Answer:

it would only be 8, unless you need to go down to the decimal point then it would be 8.25

Step-by-step explanation:

it would be 8 because if you need to find how many bananas you have, to do this you would divide 15 by 2 and get 7.5 then you multiply those by 5 to get the number of bananas which would be 37.5, and then if 8 mangos = 30 bananas you only have 8 mangos.

(sorry if this is very jumbled and hard to understand, also getting brainliest would help, thank you)

Answer:

0-6 de correct answer okay.

At x→ -3 the value of the limit of function g(x) does not exist because the left-hand limit and right-hand limit are not equal an option second is correct.

A limit is a value at which a function approaches the output for the given values in mathematics. Limits are used to determine integrals, derivatives, and continuity in calculus and mathematics.

We have a graph of function g(x)

[tex]\rm \lim_{x \to a}g(x)[/tex]

Let's check at x = -3

Finding the left-hand limit and right-hand limit.

[tex]\rm \lim_{x \to -3^{-1}}g(x) = -2[/tex]

[tex]\rm \lim_{x \to -3^{+1}}g(x) = -4[/tex]

Since the left-hand limit and right-hand limit are not equal then at x = -3 the limit does not exist.

Thus, at x→ -3 the value of the limit of function g(x) does not exist because the left-hand limit and right-hand limit are not equal an option second is correct.

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Answer:

Step-by-step explanation: