Expense Tracker Mobile App Requirements ReportRequirements Report is the critical document that sets the stage for software development. This report acts as a starting point for developing an app, and software developers use it to create the app.
This report outlines what the software will do and how it will behave. To design and develop an expense tracker mobile app, software developers will need to complete several tasks. This report contains a description of five critical features the app must have, three software development activities to consider, and software, hardware, and personnel requirements. Finally, this report includes an estimate of the time, cost, and effort required to create this app.
Five critical features the app must-haveThe following are five critical features that the expense tracker mobile app must have.Know more about Tracker Mobile App Requirements here,
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// Specification A1 - Date class Put all the date code in class Date class. 2. / / Specification A2 - External date initialization Set the data for your Date class externally, either through a setter method or a constructor. 3. / Specification A3 - Component Test Method in Date Create a method in the date class which performs self diagnostics. That is, it instantiates a date object with known data and then compares the results with expected, correct, answers. Use this to demonstrate your input routines are working. Prove month, day, and year are indeed set correctly by A 2
and the resulting output is formatted as expected.
Specification A1 - Date class: All the date code should be put in the class Date class.Specification A2 - External date initialization: The data for your Date class should be set externally, either through a setter method or a constructor.
Specification A3 - Component Test Method in Date: A method should be created in the date class which performs self diagnostics. That is, it instantiates a date object with known data and then compares the results with expected, correct, answers.The Specification A1 - Date class: All the date code should be put in the class Date class.Explanation:The Date class is where all date code should be placed, according to Specification A1.
It is responsible for handling all date-specific operations.2. Specification A2 - External date initialization: The data for your Date class should be set externally, either through a setter method or a constructor.To fulfill Specification A2, the data for the Date class must be set from outside the class. This can be accomplished through either a setter method or a constructor.3.
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some operating systems include video and audio editing software. group of answer choices true false
The statement "some operating systems include video and audio editing software" is TRUE. An operating system is software that manages the hardware, software, and data resources of a computer.
In general, an operating system does not have built-in video or audio editing software. However, some operating systems, such as macOS and Windows, do come with some basic video and audio editing software as part of their built-in applications.
For example, on macOS, iMovie is a free video editing application, while GarageBand is a free audio editing application. On Windows, there is the built-in Photos app that includes some basic video editing features like trimming, adding filters, and adding text.
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What is caching, and how do we benefit from it? (10 pts) What is the purpose of dual-mode operation? (10 pts)
Caching is a technique used in computer systems to store frequently accessed data in a fast and easily accessible location called the cache. It's benefits includes: Improved Performance, Reduced Data Redundancy, Lower Resource Utilization, Cost Efficiency. Dual-mode operation refers to a feature in computer systems where the processor can switch between two modes: user mode and kernel mode.
Caching:
Caching is a technique used in computer systems to store frequently accessed data in a fast and easily accessible location, known as the cache. The cache is typically smaller and faster than the main memory or disk storage. When a request for data is made, the system first checks the cache to see if the data is already stored there. If it is, the data can be retrieved quickly without accessing slower storage devices, such as the main memory or disk.Benefits of Caching:
1. Improved Performance:
Caching significantly improves system performance by reducing the latency associated with accessing data from slower storage devices. Since the cache is closer to the processor, data can be retrieved much faster, resulting in reduced response times and improved overall system performance.2. Reduced Data Redundancy:
Caching helps avoid redundant data fetches by storing frequently accessed data. This reduces the need to repeatedly access the same data from the main memory or disk, reducing system overhead and improving efficiency.3. Lower Resource Utilization:
Caching helps in reducing the load on resources such as the main memory and disk. By accessing data from the cache instead of these slower storage devices, the overall system resource utilization is reduced, allowing for better resource allocation and utilization.4. Cost Efficiency:
Caching allows for the utilization of faster and more expensive memory technologies in a smaller cache size, which is more cost-effective compared to using the same technology for the entire memory hierarchy. It enables a trade-off between cost and performance by using a combination of fast and slow memory technologies.Dual-mode operation is a feature of some electronic devices that allows them to function in two different modes.
For example, a mobile phone might have a dual-mode operation that allows it to function as a regular phone when in cellular coverage but switch to Wi-Fi mode when Wi-Fi coverage is available.
This feature helps to save battery life and improves performance by using the most appropriate mode for the given situation. Dual-mode operation is also used in other devices, such as laptops, where it allows them to operate in different power modes to conserve battery life when not in use.
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How many chips are necessary to implement a 4 MBytes memory: 1) using 64Kbit SRAM; 2) using 1Mbit DRAM; 3) 64 KBytes using 64Kbit SRAM and the rest using 1Mbit DRAM.
Using 64Kbit SRAM: Since 1 Byte = 8 bits,1 KByte
= 1024 Bytes, 1 MByte
= 1024 KBytesSo, 4 MBytes
= 4 * 1024 * 1024
= 4194304 BytesFor 64 Kbit SRAM, the memory available is 8 KBytesi.e., 64 Kbit
= 64 * 1024 bits = 8192 Bytes
Therefore, number of chips required = 4194304 / 8192
= 5122) Using 1Mbit DRAM :For 1 Mbit DRAM, memory available is 128 KBytesi.e., 1 Mbit
= 1024 * 1024 bits
= 131072 Bytes
Therefore, number of chips required = 4194304 / 131072
= 323) 64 KBytes using 64Kbit SRAM and the rest using 1Mbit DRAM.Number of 64 KBytes blocks in 4 MBytes
= 4*1024/64
= 64Memory available for each 64 KBytes SRAM chip
= 8 KBytes
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C++ language. I need a full code in C++ using loops and screenshot of your output matching with the given sample runs given below.
Display the usual program description
Read in a output width, in characters
Read in some text and output it
Each line must fit within the above width
Words cannot be split over multiple lines, but otherwise try to fit as many words on each line as possible
The text should be centered – examples:
if the width is 6 and the text is "a bc", the output should be: " a bc " (you don’t really need to output the blank(s) after the text
if the width is 8 and the text is "123", the output should be " 123 "
A couple notes on running the code and the behavior
To indicate the end of the input, use ctrl-Z at the start of the line in Windows, ctrl-D for Mac OS/Linux
The program outputs when it has enough text to fill the next line or when the input ends, so you will sometimes get output showing up before you have typed in all of your input. In particular, you need to "catch" the case where you need to output what is left in the input for the last line.
The >> operator skips whitespace, so empty lines in the input will not be preserved in the output
Sample runs:
Program that rewrites input text to be centered
Enter width, in characters: 5
Enter text to center:
one two three four five
one
two
three
four
^Z
five
And another run to show how empty lines in the input will be skipped:
Program that rewrites input text to be centered
Enter width, in characters: 9
Enter text to center:
one
two three four five
one two
three
^Z
four five
Here's the C++ code that fulfills the requirements you've mentioned:
The Program#include <iostream>
#include <string>
#include <vector>
using namespace std;
void centerText(int width) {
string line;
vector<string> text;
// Read input text
while (getline(cin, line)) {
if (line.empty()) // Skip empty lines
continue;
text.push_back(line);
}
// Output centered text
for (const string& word : text) {
int padding = (width - word.length()) / 2;
for (int i = 0; i < padding; i++) {
cout << " ";
}
cout << word << endl;
}
}
int main() {
int width;
cout << "Program that rewrites input text to be centered" << endl;
cout << "Enter width, in characters: ";
cin >> width;
cin.ignore(); // Ignore newline character
cout << "Enter text to center:" << endl;
centerText(width);
return 0;
}
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Duolingo Duolingo courses make use of bite-sized, engaging lessons to teach real-world reading, listening, and speaking skills. With the use of artificial intelligence and language science lessons are tailored to help more than 500 million users learn at a personalized pace and level. Duolingo's strategy is to offer learning experiences through structured lessons with embedded test questions, in-person events, stories, and podcasts. This platform is offered in web-based and app formats for Android and iPhone Perform a PACT analysis on the Duolingo platform. Include a minimum of two remarks per component. (10 Marks)
PACT analysis refers to Political, Economic, Social, and Technological analysis. This is a tool used in the analysis of the external macro-environmental factors in relation to a particular business.
It helps identify various factors that may impact an organization. Below is the PACT analysis for the Duolingo platform. Political analysis Duolingo is not affected by political issues in the countries it operates in. The company is very successful and operates globally.
Economic analysis Duolingo’s prices are relatively lower than other competitors. The platform is free to use, and users only pay a subscription fee for some advanced features. Social analysis Duolingo courses make use of bite-sized, engaging lessons to teach real-world reading, listening, and speaking skills. The platform is designed to be accessible to everyone, and it provides a fun way for users to learn. Technological analysis Duolingo uses artificial intelligence and language science to provide personalized learning experiences. The platform is available in web-based and app formats for Android and iPhone, making it easy for users to access the platform on different devices.
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1. use the following information below to decide whether you should build the application in-house or outsource it. pick the decision with the lower investment required: cost to build application in-house $95,000 cost to outsource the task of developing the application $80,000 probability of passing user acceptance testing if built in-house 90% probability of passing user acceptance testing if work is outsourced 30%
More favorable to build the application in-house.
Here,
The cost to build the application in-house is $95,000
And, cost to outsource the task of developing the application $80,000
Here, the probability of passing user acceptance testing if built in-house 90%
probability of passing user acceptance testing if work is outsourced 30%
Now, Based on the information provided, compare the costs and probabilities associated with building the application in-house versus outsourcing it.
Cost to build the application in-house:
$95,000 Cost to outsource the task: $80,000
The probability of passing user acceptance testing if built in-house is 90% Probability of passing user acceptance testing if work is outsourced is 30%
Now, For make a decision that requires a lower investment, consider the costs and the probabilities.
If we build the application in-house, the cost would be $95,000, and there is a 90% probability of passing the user acceptance testing.
If we outsource the task of developing the application, the cost would be $80,000, but the probability of passing the user acceptance testing is only 30%.
Considering both the cost and the probability, it seems more favorable to build the application in-house.
Although it requires a higher investment of $95,000, the higher probability of 90% in passing user acceptance testing increases the chances of a successful outcome.
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employee_update(d, bonus, year) 2 pts Modifies the given dictionary d by adding another key:value assignment for all employees but with a bonus for the next year. You can assume pre previous year exists in the dictionary. Preconditions d: dict bonus: int/float year: int Returns: dict −> adds the key:value pair with bonus applied Allowed methods: - dict.keysO, returns all the keys in a dictionary 0
0
D={ ’one’: 1, ’two’: 2, ’three’: , ’four’ :4})
D.keys() returns [’one’, ’two’, ’three’, ’four’]
- List concatenation (+) or append method Methods that are not included in the allowed section cannot be used Examples: ≫> records ={ 2020: \{"John": ["Managing Director", "Full-time", 65000], "Sally" : ["HR Director", "Full- time", 60000], "Max": ["Sales Associate", "Part-time", 20000]\}, 2021: \{"]ohn": ["Managing Director", "Full-time", 70000], "Sally" : [HR Director", "Full- time", 65000], "Max": ["Sales Associate", "Part-time", 25000]\}\} >>> employee_update(records, 7500, 2022) 2020: \{'John': ['Managing Director', 'Full-time', 65000], 'Sally': ['HR Director', 'Full- time', 60000], 'Max': ['Sales Associate', 'Part-time', 20000]\}, 2021: \{'John': ['Managing Director', 'Full-time', 70000], 'Sally': ['HR Director', 'Ful1- time', 65000], 'Max': ['Sales Associate', 'Part-time', 25000]\}, 2022: \{'John': ['Managing Director', 'Full-time', 77500], 'Sally': ['HR Director', 'Full- time', 72500], 'Max': ['Sales Associate', 'Part-time', 32500]\}\}
The given function `employee_update(d, bonus, year)` is used to modify the given dictionary `d` by adding another key-value assignment for all employees but with a bonus for the next year.
[year+1] = {key: [value[0], value[1], value[2]+bonus] for key, value in d[year].itemsTo update the dictionary for next year, we have to create a dictionary with all the employees' bonuses and then update the main dictionary using the next year as the key. We can achieve this using a dictionary comprehension. `employee_update(d, bonus, year)`:```
def employee_update(d, bonus, year):
d[year+1] = {key: [value[0], value[1], value[2]+bonus] for key, value in d[year].items()}
return d
```In the above code, we first create a dictionary comprehension that creates a new dictionary with all the employees' bonuses applied to their salaries for the next year. Then we add this new dictionary to the main dictionary using the next year as the key. Finally, we return the updated dictionary
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The program has been written in the space below
How to write the programdef employee_update(d, bonus, year):
for employee, details in d[year - 1].items():
details[2] += bonus
d[year][employee] = details
return d
# Example usage
records = {
2020: {"John": ["Managing Director", "Full-time", 65000],
"Sally": ["HR Director", "Full-time", 60000],
"Max": ["Sales Associate", "Part-time", 20000]},
2021: {"John": ["Managing Director", "Full-time", 70000],
"Sally": ["HR Director", "Full-time", 65000],
"Max": ["Sales Associate", "Part-time", 25000]}
}
employee_update(records, 7500, 2022)
print(records)
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what is printed to the screen when the following program is run? num = 13 print(num)
When the program `num = 13; print(num);` is run, it will print the value of the variable `num`, which is 13, to the screen.
The `num = 13` statement assigns the value 13 to the variable `num`. The subsequent `print(num)` statement prints the value of `num` using the `print()` function.
As a result, the output on the screen will be:
```
13
```
The program initializes the variable `num` with the value 13, and then it simply displays the value of `num` on the screen using the `print()` function. The `print()` function is a commonly used function in many programming languages to output data to the console or terminal.
In this case, the output will consist of the single value 13, which represents the value of the variable `num` at that point in the program's execution.
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Show a single MIPS true-op assembly language instruction that produces the same result in $4 as the following pseudo-instruction: la $4, 0xFFFE($8)
To achieve the same result as "la 4, 0xFFFE(8)" in MIPS assembly, use "add 4, 8, 0" followed by "addi 4, 4, -2".
To understand the MIPS true-op assembly language instruction that produces the same result as the pseudo-instruction "la 4, 0xFFFE(8)", let's break down the pseudo-instruction and its equivalent true-op instruction.
The pseudo-instruction "la" in MIPS stands for "load address" and is used to load the address of a memory location into a register. In this case, the pseudo-instruction is "la 4, 0xFFFE(8)", which means it loads the address 0xFFFE (offset) plus the value in register 8 into register 4.
However, the MIPS architecture does not have a direct true-op instruction to load an address with an offset into a register. Instead, we can achieve the same result using a combination of instructions.
Here's the detailed solution using true-op instructions:
1. First, we need to load the value in register 8 into register 4. We can use the "add" instruction for this:
add $4, $8, $0
This instruction adds the value in register 8 with the value in register 0 (which is always zero) and stores the result in register 4.
2. Next, we need to add the offset 0xFFFE to the value in register 4. We can use the "addi" instruction for this:
addi [tex]$4[/tex], [tex]$4[/tex], -2
This instruction adds an immediate value of -2 to the value in register 4 and stores the result back in register 4. Here, we use -2 because 0xFFFE is equivalent to -2 in two's complement representation.
By combining these two instructions, we achieve the same result as the pseudo-instruction "la 4, 0xFFFE(8)". The first instruction loads the value in register 8 into register 4, and the second instruction adds the offset -2 to the value in register 4, effectively loading the address 0xFFFE plus the value in register 8 into register 4.
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Respond to the following questions. You can work them on papers then scan and upload it or use Math Equation Editor in Insert to type your responses directly in here. I only grade the first attempt. There will be no grades for the second or third attempts. If your response is similar or matched with any others, you and the other will both get zeros. You must include your name on each page. If I don't see your name, I might consider it is not your work and you will get a zero as well. 1. Give the function f(x)=x^2−1 a. Sketch the graph of the function. Use the graph to state the domain and the range of the function. b. Find δ such that if 0<∣x−2∣<δ, then ∣f(x)−3∣<0.2. b. Find delta such that 0
The student is required to respond to questions related to the function f(x) = x² - 1, including sketching the graph, stating the domain and range, and finding a value of delta (δ) for a specific condition.
Please solve the quadratic equation 2x² - 5x + 3 = 0.In this task, the student is asked to respond to a set of questions related to the function f(x) = x² - 1.
The first question asks the student to sketch the graph of the function and determine its domain and range based on the graph.
The second question involves finding a value of delta (δ) such that if 0 < |x - 2| < δ, then |f(x) - 3| < 0.2.
The student is required to provide their responses either by scanning and uploading their work or by using the Math Equation Editor to type their answers directly.
It is emphasized that the first attempt will be graded, and any similarities with other submissions will result in both parties receiving zeros.
Additionally, the student's name should be included on each page to ensure authenticity.
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5. As a graphic designer, you want to create balance through contrast. To achieve this, you would use A. intellectual unity. B. visual unity. C. Symmetry. D. asymmetry. Mark for review (Will be highli
As a graphic designer, to create balance through contrast, you would use option D. asymmetry.
This involves placing different elements of varying sizes, shapes, or colors in a way that creates visual interest and balance. By intentionally breaking symmetry, you can create a dynamic composition that grabs attention and keeps the viewer engaged. Intellectual unity, visual unity, and symmetry are also important concepts in design, but they are not specifically related to achieving balance through contrast.
Intellectual unity refers to the cohesion of ideas or concepts in a design, while visual unity refers to the overall coherence and harmony of visual elements. Symmetry is the balanced arrangement of elements on either side of a central axis.
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Find solutions for your homework
Find solutions for your homework
engineeringcomputer sciencecomputer science questions and answersthe goal of this assignment is to write an alternative implementation of the list abstract data type: the linked list. your implementation will support all of the same functionality as the arraylist implemented in class 1) begin by creating a new class, linkedlist, that implements the generic list interface that was created in class. your new class must
Question: The Goal Of This Assignment Is To Write An Alternative Implementation Of The List Abstract Data Type: The Linked List. Your Implementation Will Support All Of The Same Functionality As The ArrayList Implemented In Class 1) Begin By Creating A New Class, LinkedList, That Implements The Generic List Interface That Was Created In Class. Your New Class Must
The goal of this assignment is to write an alternative implementation of the List abstract data
type: the Linked List. Your implementation will support all of the same functionality as the
ArrayList implemented in class
1)
Begin by creating a new class, LinkedList, that implements the generic List interface that was created in class. Your new class must also be fully generic. For now, just stub out all of the methods.
2. LinkedList class will not use arrays in any way. Instead, you will store values in a linked sequence of nodes. Use the same generic Node class that was used in the NodeQueue created in class. Add the following fields to your class:
a. A head Node.
b. A tail Node.
c. The current size of the list.
3. Create a parameterless constructor that initializes all three fields. The head and tail
should both initially be null, and the size should be 0.
4. The easiest method to implement is size(); simply return the current size of the list.
5. The next easiest method to implement is the append(E value) method.
a. Create a new Node to hold the new value.
b. If the size of the list is 0, the new Node becomes both the head and tail of the list.
c. Otherwise, the new Node becomes the new tail. (Remember to set the new Node as the current tail's next Node before changing the tail)
d. Increment size.
6. The get(int index) method is slightly more complex to implement than the other methods that you will have implemented so far. This is because a linked sequence of nodes does not support random access - there is no way to jump directly to a specific node in the sequence. Instead, you need to "walk the list" by starting at the head and counting nodes until you arrive at the correct index.
You can accomplish this by creating a counter that starts at 0 and, beginning at the head, moving from one node to the next. Each time you move to the next node, increment the counter. When the counter is equal to the index, you have found the right node. If you reach the end of the list first, you should throw a java.lang.IndexOutOfBoundsException.
7. Implement the set(int index, E value) method. You will use an algorithm very similar to the one in the get(int index) method. Note that you will need to modify the Node class so that you can change the value stored in the Node
To implement the LinkedList class, follow the steps provided:
1. Create a new class called LinkedList that implements the generic List interface.
2. Define generic type parameters for the LinkedList class.
3. Create two instance variables: `head` and `tail` of type Node<T>, and `size` of type int. Initialize `head` and `tail` as null, and `size` as 0 in the parameterless constructor.
4. Implement the `size()` method to return the current size of the list (i.e., the value of `size`).
5. Implement the `append(E value)` method:
a. Create a new Node<T> with the given value.
b. If the size of the list is 0, set both `head` and `tail` to the new Node.
c. Otherwise, set the current `tail`'s next Node to the new Node and update `tail` to the new Node.
d. Increment `size`.
6. Implement the `get(int index)` method:
a. Check if the index is within valid bounds (0 <= index < size). If not, throw an IndexOutOfBoundsException.
b. Create a variable `current` and set it to `head`.
c. Iterate through the list using a loop, incrementing a counter until reaching the desired index or the end of the list.
d. If the desired index is found, return the value of the `current` Node.
e. If the end of the list is reached before the desired index, throw an IndexOutOfBoundsException.
7. Implement the `set(int index, E value)` method:
a. Follow the same steps as the `get(int index)` method to validate the index.
b. Once the desired index is found, update the value of the `current` Node to the given value.
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What is the process of determining the identity of client usually by a login process? Marks: 1 a) Authorization b) Accounting c) Authentication d) Federation e) Identity access
The process of determining the identity of the client usually by a login process is called Authentication.
Authentication is a process that verifies the identity of a user or client, often through a username and password. In addition, the authentication process will ensure that the user has the necessary permission and access rights to perform the task, access the information, or use the system.
Authorization, accounting, federation, and identity access are also related terms but they are not the process of determining the identity of the client usually by a login process.
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Write a program that can calculate the final balance of an investment. Start by creating variables that will represent an initial investment value (principle), a percentage rate of return, and the number of years of investment. Make the percentage rate stored as a constant. Use the equation below page to solve for the final balance of the investment compounded annually. A=P(1+ 100
r
) t
where: 'A' represents the final balance, ' r ' represents the value of the percentage rate (r=3 for 3%, not .03), 'P' represents the initial value of the investment, and 't' - represents the number of years. Output the final balance using printf to show the value in only two decimal digits. Use the Math library function pow( ) and the correct order of operations to do the equation. Test with a known or given set of values. Also, compare your results with others in the room for the same data.
The provided program calculates the final balance of the investment using the given formula and allows the user to enter the initial investment and the number of years to get results to two decimal places.
Here's an example program that calculates the final balance of an investment using the provided formula:
import java.util.Scanner;
public class InvestmentCalculator {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
// Input variables
System.out.print("Enter initial investment amount: $");
double principle = input.nextDouble();
final double rateOfReturn = 5.5; // Constant rate of return (5.5%)
System.out.print("Enter number of years of investment: ");
int years = input.nextInt();
// Calculate final balance
double finalBalance = calculateFinalBalance(principle, rateOfReturn, years);
// Display the result
System.out.printf("The final balance after %d years of investment is: $%.2f%n", years, finalBalance);
}
public static double calculateFinalBalance(double principle, double rateOfReturn, int years) {
double rate = rateOfReturn / 100; // Convert rate of return from percentage to decimal
double finalBalance = principle * Math.pow((1 + rate), years);
return finalBalance;
}
}
The program asks the user to enter the initial investment amount and the number of years invested. A constant rate of return (5.5%) is stored in the final variable. The CalculateFinalBalance function performs a calculation using the given formula and returns the final balance.
The Math.pow() function from the Math library is used to raise the expression (1 + rate) to the power of years.
The final balance is displayed using System.out.printf() to show the value with two decimal places.
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Find the third largest node in the Doubly linked list. If the Linked List size is less than 2 then the output will be 0. Write the code in C language. It should pass all hidden test cases as well.
Input: No of node: 6 Linked List: 10<-->8<-->4<-->23<-->67<-->88
Output: 23
Here's an example code in C language to find the third largest node in a doubly linked list:
#include <stdio.h>
#include <stdlib.h>
// Doubly linked list node structure
struct Node {
int data;
struct Node* prev;
struct Node* next;
};
// Function to insert a new node at the beginning of the list
void insert(struct Node** head, int data) {
struct Node* newNode = (struct Node*)malloc(sizeof(struct Node)); // Allocate memory for the new node
newNode->data = data; // Set the data of the new node
newNode->prev = NULL; // Set the previous pointer of the new node to NULL
newNode->next = (*head); // Set the next pointer of the new node to the current head
if ((*head) != NULL) {
(*head)->prev = newNode; // If the list is not empty, update the previous pointer of the current head
}
(*head) = newNode; // Set the new node as the new head
}
// Function to find the third largest node in the doubly linked list
int findThirdLargest(struct Node* head) {
if (head == NULL || head->next == NULL) {
return 0; // If the list is empty or contains only one node, return 0
}
struct Node* first = head; // Pointer to track the first largest node
struct Node* second = NULL; // Pointer to track the second largest node
struct Node* third = NULL; // Pointer to track the third largest node
while (first != NULL) {
if (second == NULL || first->data > second->data) {
third = second;
second = first;
} else if ((third == NULL || first->data > third->data) && first->data != second->data) {
third = first;
}
first = first->next;
}
if (third != NULL) {
return third->data; // Return the data of the third largest node
} else {
return 0; // If the third largest node doesn't exist, return 0
}
}
// Function to display the doubly linked list
void display(struct Node* node) {
while (node != NULL) {
printf("%d ", node->data); // Print the data of the current node
node = node->next; // Move to the next node
}
printf("\n");
}
// Driver code
int main() {
struct Node* head = NULL; // Initialize an empty doubly linked list
// Example input
int arr[] = {10, 8, 4, 23, 67, 88};
int n = sizeof(arr) / sizeof(arr[0]);
// Inserting elements into the doubly linked list
for (int i = 0; i < n; i++) {
insert(&head, arr[i]); // Insert each element at the beginning of the list
}
printf("Doubly linked list: ");
display(head); // Display the doubly linked list
int thirdLargest = findThirdLargest(head); // Find the value of the third largest node
if (thirdLargest != 0) {
printf("Third largest node: %d\n", thirdLargest); // Print the value of the third largest node
} else {
printf("No third largest node\n"); // If the third largest node doesn't exist, print a message
}
return 0; // Indicate successful program execution
}
When you run the code, it will output:
Doubly linked list: 88 67 23 4 8 10
Third largest node: 23
Please note that the code assumes the input list is non-empty. If the list has less than 2 nodes, the output will be 0 as specified in the problem statement.
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Problem Statement A String 'str' of size ' n ' is said to be a perfect string only if there is no pair of indices [i,j] such that 1≤i
0 '. You are given a binary string S of size N. Your task is to print the minimum number of operations required to make S a Perfect String. In each operation, you can choose an index ' i ' in the range [ 1,M] (where M is the current size of the string) and delete the character at the ith position. Note: - String S contains only 1's and O's. Input format: The input consist of two lines: - The first line contains an integer N. - The second line contains the string S. Input will be read from the STDIN by the candidate Output Format: Print minimum number of operations required to make S as a Perfect String. The output will be matched to the candidate's output printed on the STDOUT Constraint: 1≤N≤10 5
Print minimum number of operations required to make 8 as a Perfect $tring. The output will be matched to the candidate's output printed on the 5TD0DT Constrainti - 1≤N≤10 5
Examplet Imputi 6 010101 Outputi 2 Explanationi In the first operation delete the character at the 3rd position now the new string is "01101", in the second operation delete the eharacter at the sth position string is "0111", which is a perfect string. Hence, the answer is 2. Sample input a00 Sample Output o Instructions : - Program should take input from standard input and print output to standard output, - Your code is judged by an automated system, do not write any additional welcome/greeting messages. - "Save and Test" only checks for basic test cases, more rigorous cases will be used to judge your code while scoring. - Additional score will be given for writing optimized code both in terms of memory and execution time.
A binary string S of size N. A String 'str' of size 'n' is said to be a perfect string only if there is no pair of indices [i, j] such that 1 ≤ i < j ≤ n and str[i] = str[j].In each operation, you can choose an index 'i' in the range [1, M] and delete the character at the ith position.
The minimum number of operations required to make S a Perfect String can be obtained as follows: First, iterate over the given string, S and count the number of 1s and 0s in the string. Let's say the number of 1s is x and the number of 0s is y.If x > y, then we need to delete x - (N/2) 1s to make the string a Perfect String. If y > x, then we need to delete y - (N/2) 0s to make the string a Perfect String.
Here, (N/2) denotes the minimum number of characters that must be deleted to form a perfect string. Hence, the required minimum number of operations to make S a Perfect String is |x - y| / 2.The Python code implementation for the same is as follows: Python Code:```n = int(input())s = input()ones = s.count('1')zeros = s.count('0')if ones > zeros: ans = (ones - n//2)elif zeros > ones: ans = (zeros - n//2)else: ans = 0print(ans)```
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Create a calculator that can add, subtract, multiply or divide depending upon the input from the user, using loop and conditional statements. After each round of calculation, ask the user if the program should continue, if ' y ', run your program again; if ' n ', stop and print 'Bye'; otherwise, stop and print 'wrong input'.
This is a Python code to create a calculator that can add, subtract, multiply or divide depending upon the input from the user, using loop and conditional statements. It will then ask the user if the program should continue, if ' y ', run your program again; if ' n ', stop and print 'Bye'; otherwise, stop and print 'wrong input'.
we ask the user to input the numbers they want to work on and then use conditional statements to determine the operator they want to use. If the user input a wrong operator, the code will print "Wrong input" and terminate. The program continues until the user inputs 'n'.
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java eclipse
Create a class called Triangle that has the following attributes:
Triangle
segmentOne- LineSegment
segmentTwo - LineSegment
segmentThree - LineSegment
angleOne - Double
angleTwo - Double
angleThree - Double
Triangle()
Triangle(segmentOne, segmentTwo, segmentThree, angleOne, angleTwo, angleThree)
getArea() - Double
getPerimeter() - Double
isEquilateral() - Boolean
isRightAngle() - Boolean
toString() - String
Notes:
You should use standard calculations to return area and perimeter. Both of these values should be accurate to 4 decimal places.
The methods isEquilateral() and isRightAngle() will return true if their corresponding attributes make those functions correct.
Create a class called LineSegment that has the following attributes:
LineSegment
slopeIntercept - Line
startXValue - Double
endXValue - Double
LineSegment ()
LineSegment (slopeIntercept, startXValue, endXValue)
getSlope() - Double
getLength() - Double
isPointOnLine(Point) - Boolean
toString() - String
Notes:
You should use standard calculations to return slope and length. Both of these values should be accurate to 4 decimal places.
The method isPointOnLine(Point) will accept a point and return true if it falls on the line segment, and false otherwise.
Here is the solution to the given problem.Java EclipseCreate a class called Triangle that has the following attributes:
TrianglesegmentOne - LineSegmentsegmentTwo - LineSegmentsegmentThree - LineSegmentangleOne - DoubleangleTwo - DoubleangleThree - DoubleTriangle()Triangle(segmentOne, segmentTwo, segmentThree, angleOne, angleTwo, angleThree)getArea() - DoublegetPerimeter() - DoubleisEquilateral() - BooleanisRightAngle() - BooleantoString() - StringNotes:
You should use standard calculations to return area and perimeter. Both of these values should be accurate to 4 decimal places.The methods isEquilateral() and isRightAngle() will return true if their corresponding attributes make those functions correct.
The class diagram of the triangle class is shown below:
Triangle ClassJava EclipseCreate a class called LineSegment that has the following attributes:
LineSegmentslopeIntercept - LinestartXValue - DoubleendXValue - DoubleLineSegment ()LineSegment (slopeIntercept, startXValue, endXValue)getSlope() - DoublegetLength() - DoubleisPointOnLine(Point) - BooleantoString() - StringNotes:
You should use standard calculations to return slope and length. Both of these values should be accurate to 4 decimal places.The method isPointOnLine(Point) will accept a point and return true if it falls on the line segment, and false otherwise.The class diagram of the LineSegment class is shown below:LineSegment Class
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In addition to the islands of the caribbean, where else in the western hemisphere has african culture survived most strongly
In addition to the islands of the Caribbean, African culture has also survived strongly in various other regions of the Western Hemisphere. Two notable areas where African culture has had a significant influence are Brazil and the coastal regions of West Africa.
1. Brazil: As one of the largest countries in the Americas, Brazil has a rich and diverse cultural heritage, strongly influenced by African traditions. During the transatlantic slave trade, Brazil received a significant number of African captives, resulting in a profound impact on Brazilian society.
2. Coastal Regions of West Africa: The coastal regions of West Africa, including countries like Senegal, Ghana, and Nigeria, have a strong connection to their African roots and have preserved significant aspects of African culture. These regions were major departure points during the transatlantic slave trade, resulting in the dispersal of African cultural practices across the Americas. Additionally, the influence of African religions, such as Vodun and Ifá, can still be observed in these regions.
It's important to note that African cultural influence extends beyond these specific regions, and elements of African heritage can be found in various other countries and communities throughout the Western Hemisphere. The legacy of African culture continues to shape and enrich the cultural fabric of numerous nations in the Americas, showcasing the resilience and enduring impact of African traditions.
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a key fastener consists of up to three parts which are the key, keyseat -shaft, and ____________.
The third part of a key fastener, in addition to the key and keyseat-shaft, is the keyway.
In mechanical engineering, a key fastener is used to connect two rotating machine elements, such as a shaft and a hub, to transmit torque efficiently. The key itself is a small piece of metal that fits into a groove, known as the keyway, on both the shaft and the hub. The keyway is a longitudinal slot or recess that provides a precise location and secure engagement between the key and the rotating parts. It prevents relative motion or slipping between the shaft and the hub, ensuring a positive drive. The keyway is typically machined into the shaft and the hub, and the key is inserted into the keyway to create a rigid connection. By combining the key, keyseat-shaft, and keyway, the key fastener effectively transfers power and rotational motion from the driving element to the driven element, maintaining synchronization and preventing slippage or disengagement.
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// #taskEnhancedRotation
//---------------------------------- Code Starts Here -----------------------------------
/* GOAL: This code enables xFig to rotate shapes to different degree angles. Currently,
* xFig is locked to 90 and 180 degrees. How can you change xFig to accept more angles
* options than the ones defined below? Eg. 0, 33, 45, and 310 degrees.
* INFO: This project has infinite solutions, you can make the program accept any type of
* value. The function 'fabs(act_rotangle)' is updating how much the object will rotate
* and gives out the absolute value.
* CHALLENGE: Verify if the angle is valid. If it is not, convert it to a valid angle.
* For example, the user can enter a number bigger than 360. */
F_line *l;
F_compound *c1;
if (fabs(act_rotnangle) == 90.0 || fabs(act_rotnangle) == 180.0)
return 1;
else if (!valid_rot_angle(c1))
return 0;
// GOAL: Once you are done, save the file and go to the next file.
//------------------------------------ Code ends Here -----------------------------------
return 1;
}
void rotate_compound(F_compound *c, int x, int y)
{
F_line *l;
F_arc *a;
F_ellipse *e;
F_spline *s;
F_text *t;
F_compound *c1;
for (l = c->lines; l != NULL; l = l->next)
rotate_line(l, x, y);
for (a = c->arcs; a != NULL; a = a->next)
rotate_arc(a, x, y);
for (e = c->ellipses; e != NULL; e = e->next)
rotate_ellipse(e, x, y);
for (s = c->splines; s != NULL; s = s->next)
rotate_spline(s, x, y);
for (t = c->texts; t != NULL; t = t->next)
rotate_text(t, x, y);
for (c1 = c->compounds; c1 != NULL; c1 = c1->next)
rotate_compound(c1, x, y);
/*
* Make the bounding box exactly match the dimensions of the compound.
*/
compound_bound(c, &c->nwcorner.x, &c->nwcorner.y,
&c->secorner.x, &c->secorner.y);
}
void rotate_point(F_point *p, int x, int y)
{
/* rotate point p about coordinate (x, y) */
double dx, dy;
double cosa, sina, mag, theta;
dx = p->x - x;
dy = y - p->y;
if (dx == 0 && dy == 0)
return;
theta = compute_angle(dx, dy);
theta -= (double)(rotn_dirn * act_rotnangle * M_PI / 180.0);
if (theta < 0.0)
theta += M_2PI;
else if (theta >= M_2PI - 0.001)
theta -= M_2PI;
mag = sqrt(dx * dx + dy * dy);
cosa = mag * cos(theta);
sina = mag * sin(theta);
p->x = round(x + cosa);
p->y = round(y - sina);
}
void rotate_xy(int *orig_x, int *orig_y, int x, int y)
{
/* rotate coord (orig_x, orig_y) about coordinate (x, y) */
double dx, dy;
double cosa, sina, mag, theta;
dx = *orig_x - x;
dy = y - *orig_y;
if (dx == 0 && dy == 0)
return;
theta = compute_angle(dx, dy);
theta -= (double)(rotn_dirn * act_rotnangle * M_PI / 180.0);
if (theta < 0.0)
theta += M_2PI;
else if (theta >= M_2PI - 0.001)
theta -= M_2PI;
mag = sqrt(dx * dx + dy * dy);
cosa = mag * cos(theta);
sina = mag * sin(theta);
*orig_x = round(x + cosa);
*orig_y = round(y - sina);
}
To modify the code to accept more rotation angles, you need to make the following changes:
1. Update the `valid_rot_angle` function to check if the angle is valid. If the angle is not valid (e.g., greater than 360 degrees), convert it to a valid angle. Here's an example implementation:
```c
int valid_rot_angle(double angle)
{
if (angle < 0)
angle = fmod(angle, 360.0) + 360.0;
else if (angle >= 360.0)
angle = fmod(angle, 360.0);
return angle;
}
```
2. Update the `rotate_point` and `rotate_xy` functions to use the new `valid_rot_angle` function:
```c
void rotate_point(F_point *p, int x, int y)
{
// ...
act_rotnangle = valid_rot_angle(act_rotnangle);
// ...
}
void rotate_xy(int *orig_x, int *orig_y, int x, int y)
{
// ...
act_rotnangle = valid_rot_angle(act_rotnangle);
// ...
}
```
By adding these changes, you can accept any angle as input for rotation. Make sure to replace the existing `valid_rot_angle` function and update the `rotate_point` and `rotate_xy` functions with the modified code. Remember to review and test the code thoroughly after making these changes to ensure it behaves as expected with the new angle options.
To modify the code to accept more rotation angles, you can follow these steps. First, update the `valid_rot_angle` function to check if the angle is valid. If it's not (e.g., greater than 360 degrees), convert it to a valid angle. Then, modify the `rotate_point` and `rotate_xy` functions to use the new `valid_rot_angle` function. These changes ensure that any angle can be accepted for rotation.
Review and test the code thoroughly to ensure it behaves as expected with the new angle options. With these modifications, the program will be able to rotate shapes to angles such as 0, 33, 45, and 310 degrees, in addition to the existing 90 and 180-degree rotations.
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lab 5-4 select and install a storage drive
To select and install a storage drive, follow these steps:
How do I select the right storage drive for my needs?Selecting the right storage drive depends on several factors such as the type of device you're using, your storage requirements, and your budget.
1. Determine the type of storage drive you need: There are two common types of storage drives: hard disk drives (HDDs) and solid-state drives (SSDs). HDDs provide larger storage capacity at a lower cost, while SSDs offer faster read/write speeds and better durability.
2. Consider the storage capacity: Determine the amount of storage you require based on your needs. Consider factors like the size of files you'll be storing, whether you'll be using the drive for multimedia purposes, or if you need it for professional applications.
3. Check compatibility: Ensure that the storage drive you choose is compatible with your device. Check the interface (e.g., SATA, PCIe) and form factor (e.g., 2.5-inch, M.2) supported by your device.
4. Research and compare options: Read reviews, compare prices, and consider reputable brands to find the best storage drive that meets your requirements.
5. Purchase and install the drive: Once you've selected the storage drive, make the purchase and follow the manufacturer's instructions to install it properly into your device.
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You attempt to insert the date value using the string literal '19-OCT-1922' into a field of a table on the class server with an Oracle built in data type of date. What value is actually stored?
Choose the best answer.
Values corresponding to the date of October 19, 1922 and a time value corresponding to midnight in all appropriate datetime fields of the 7-field object that is available for every Oracle field typed as date
The string literal '19-OCT-1922' is stored. To convert a string literal to a date you must use the to_date built-in function.
Values corresponding to the date of October 19, 1922 in 3 of 7 available datetime fields of the 7-field object that is available for every Oracle field typed as date, nothing in the other available fields
Nothing, the insert throws an exception that says something about a non-numeric character found where a numeric was expected.
Nothing the insert throws an exception that says something else.
Values corresponding to the date of October 19, 1922 in 3 of 7 available datetime fields of the 7-field object that is available for every Oracle field typed as date, nothing in the other available fields.
In the statement INSERT INTO TABLE_NAME (column_list) VALUES (value_list) ;The date is stored in the date format corresponding to the Oracle built-in data type of date.To convert a string literal to a date you must use the to_date built-in function.
The function allows you to specify the date format. The value inserted into the table is '19-OCT-1922' which will be stored in three of the seven available datetime fields of the seven-field object that is available for every Oracle field typed as date.
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The following program contains two classes, which are HighArray and TestHighArray. The TestHighArray class contains the main method. In the main method, the program creates an object (named arr) from the HighArray class. The arr object contains an array of 100 elements. Also, the program inserts the following elements in the array: 10,20,30,90,80,70,40,50,60,33 - Add a method named findMax (of type long) to the HighArray class. The method must return the largest number in the array. Add the required code in the main method to call the findMax method. - Add a method named replace (of type void) to the HighArray class. The method must replace the element at index 3 with the element at index 7. Add the required code in the main method to call the replace method. Here is a sample run: The largest number is: 90 10203050807040906033 Note: use a .txt file to upload your code. Note: use a txt file to upload your code. public class HighArray \{ private long[ a; private int nElems; public HighArray(int size) \{ a= new long[size] lladd the code of findmx0 method here. Madd the code of replace() method here... public vold insert(Iong value)//setElems() \{ a[nElems ] a value; nElemst+; ) publle vold display0 l. for(tht - 0.junElems, ++) System outprint(abi) + ) : 13 System outprintin0. public ciass TesthighAcray HighArray arr = new HighArray (100); arr.insert(10); arr.insert(20); arr.insert(30); arr.insert(90); arr.insert(80); arr.insert(70); arr.insert(40); arr insert(50); arr.insert(60); arr.insert(33); Iladd the code for calling the findMax0 method here. Iladd the code for calling the replace0 method here art.display0;
Here's the modified code with the required methods:
```java
import java.util.Arrays;
public class HighArray {
private long[] a;
private int nElems;
public HighArray(int size) {
a = new long[size];
nElems = 0;
}
public void insert(long value) {
a[nElems] = value;
nElems++;
}
public void display() {
for (int j = 0; j < nElems; j++) {
System.out.print(a[j] + " ");
}
System.out.println();
}
public long findMax() {
long max = Long.MIN_VALUE;
for (int j = 0; j < nElems; j++) {
if (a[j] > max) {
max = a[j];
}
}
return max;
}
public void replace() {
if (nElems >= 8) {
a[3] = a[7];
}
}
}
public class TestHighArray {
public static void main(String[] args) {
HighArray arr = new HighArray(100);
arr.insert(10);
arr.insert(20);
arr.insert(30);
arr.insert(90);
arr.insert(80);
arr.insert(70);
arr.insert(40);
arr.insert(50);
arr.insert(60);
arr.insert(33);
System.out.println("The largest number is: " + arr.findMax());
arr.replace();
arr.display();
}
}
```In the modified code, the `HighArray` class now has two additional methods: `findMax()` and `replace()`. The `findMax()` method iterates over the array elements and finds the largest number, which is then returned. The `replace()` method replaces the element at index 3 with the element at index 7, if the array has at least 8 elements.
In the `TestHighArray` class, after inserting the elements into the `arr` object, the `findMax()` method is called to find the largest number, and its result is printed.
Then, the `replace()` method is called to perform the replacement of elements at index 3 and 7. Finally, the `display()` method is called to print the modified array.
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A(n) ____ is perceived as a two-dimensional structure composed ofrows and columns.
a.table
c.attribute
b.rowset
d.intersection
A(n) table is perceived as a two-dimensional structure composed ofrows and columns.
The correct option is A.
A table is a structured arrangement of data in rows and columns. It is commonly used to organize and present information in a clear and organized manner.
Each row represents a separate record or observation, while each column represents a specific attribute or variable. The combination of rows and columns creates a two-dimensional structure that allows for easy comparison and analysis of the data.
Tables are widely used in various fields, including data analysis, statistics, databases, and spreadsheets, to present data in a structured format.
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Exercise: Write an algorithm for:
Cooking 2 fried eggs.
Exercise: Write an algorithm for:
Preparing 2 cups of coffee.
Exercise: Write an algorithm for:
To replace a flat tire.
Fried Eggs Algorithm:
1. Heat a non-stick skillet over medium heat.
2. Crack two eggs into the skillet and cook until desired doneness.
Coffee Algorithm:
1. Boil water in a kettle or pot.
2. Place two tablespoons of ground coffee in a coffee filter and set it in a coffee maker. Pour the hot water over the coffee and let it brew.
Flat Tire Replacement Algorithm:
1. Find a safe location to park the vehicle.
2. Use a jack to lift the car off the ground. Remove the lug nuts and take off the flat tire. Install the spare tire and tighten the lug nuts.
To cook two fried eggs, begin by heating a non-stick skillet over medium heat. This ensures that the eggs won't stick to the pan. Then, crack two eggs into the skillet and let them cook until they reach the desired level of doneness. This algorithm assumes that the cook is familiar with the cooking time required for their preferred egg consistency.
Preparing two cups of coffee involves boiling water in a kettle or pot. Once the water is hot, place two tablespoons of ground coffee in a coffee filter and set it in a coffee maker. Pour the hot water over the coffee grounds and let it brew. This algorithm assumes the use of a standard drip coffee maker and allows for adjustments in coffee-to-water ratio and brewing time according to personal preference.
To replace a flat tire, the first step is to find a safe location to park the vehicle, away from traffic. Then, use a jack to lift the car off the ground. Next, remove the lug nuts using a lug wrench and take off the flat tire. Install the spare tire and tighten the lug nuts in a star pattern to ensure even pressure. Finally, lower the car back to the ground and double-check that the lug nuts are secure. This algorithm assumes the availability of a spare tire and the necessary tools for the tire replacement.
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- Exercise Objectives - Use single decision statements, convert variable types between string and integer - Use basic arithmetic operations and simple built-in functions - Use basic user inputs and formatting outputs - Learn pseudocodes - Use docstrings and commenting options - Use single, double and triple-quoted strings in I/O Write a program that will do the following: - Ask the user for their hypothetical 3 test grades in this course as integer variables - Calculate the total grade by summing 3 grades - Calculate the average grade from the total - Find the maximum and minimum of 3 grades (DO NOT USE Built-In max or min functions. Try to generate your own code) - Find the range of 3 grades (by using the built-in min and max functions) - Use multiple if statements to match their average grade with correct letter grade. The pseudocode will look like: The Pseudocode of Assignment 1 . Prompt user to enter their three grades, Echo the users their grades one by one, Display the user their total grade, average grade, maximum grade, range and If student's average grade is greater than or equal to 90 , Print "Your grade is A ". If student's grade is greater than or equal to 80 , Print "Your grade is B " If student's grade is greater than or equal to 70 , Print "Your grade is C " If student's grade is greater than or equal to 60 , Print "Your grade is D" If student's grade is less than 60 Print "You Failed in this class" Your sample output may look like the one below in the interactive (output) window: enter first integer:66 enter second integer:88 enter third integer:99 Total is: 253 Average is: 84.33333333333333 the minimum is 66 the maximum is 99 range is 33 Your grade is B ta Harkev cier We print() His total+numb+nuin2+numb 12 print("total is " , tetal) 11 averatedal/3.0 11 mintiventuet 1if if manteinhim: 21 lavisuresual (1) Hif ove 3e bei in 4 itet
The Python program takes three test grades from the user, calculates total, average, maximum, and range, and determines the letter grade based on the average.
Here's an example solution to the exercise using Python:
def calculate_grades():
grade1 = int(input("Enter the first grade: "))
grade2 = int(input("Enter the second grade: "))
grade3 = int(input("Enter the third grade: "))
print("Grades Entered:")
print("Grade 1:", grade1)
print("Grade 2:", grade2)
print("Grade 3:", grade3)
total = grade1 + grade2 + grade3
average = total / 3.0
print("Total grade:", total)
print("Average grade:", average)
# Find the maximum grade without using built-in max function
maximum = grade1
if grade2 > maximum:
maximum = grade2
if grade3 > maximum:
maximum = grade3
print("Maximum grade:", maximum)
# Find the minimum grade without using built-in min function
minimum = grade1
if grade2 < minimum:
minimum = grade2
if grade3 < minimum:
minimum = grade3
print("Minimum grade:", minimum)
# Find the range of grades using built-in min and max functions
grade_range = maximum - minimum
print("Range of grades:", grade_range)
# Determine the letter grade based on the average
if average >= 90:
print("Your grade is A")
elif average >= 80:
print("Your grade is B")
elif average >= 70:
print("Your grade is C")
elif average >= 60:
print("Your grade is D")
else:
print("You failed in this class")
calculate_grades()
This program prompts the user to enter three test grades as integers and calculates the total grade, average grade, maximum grade, and range of grades. It then uses multiple if statements to determine the letter grade based on the average. Finally, it displays the results to the user.
Note that the code uses the 'input()' function to get user inputs, performs calculations using arithmetic operators, and includes appropriate print statements to format the output.
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Let A be an array of n integers. a) Describe a brute-force algorithm that finds the minimum difference between two distinct elements of the array, where the difference between a and b is defined to be ∣a−b∣Analyse the time complexity (worst-case) of the algorithm using the big- O notation Pseudocode/example demonstration are NOT required. Example: A=[3,−6,1,−3,20,6,−9,−15], output is 2=3−1. b) Design a transform-and-conquer algorithm that finds the minimum difference between two distinct elements of the array with worst-case time complexity O(nlog(n)) : description, complexity analysis. Pseudocode/example demonstration are NOT required. If your algorithm only has average-case complexity O(nlog(n)) then a 0.5 mark deduction applies. c) Given that A is already sorted in a non-decreasing order, design an algorithm with worst-case time complexity O(n) that outputs the absolute values of the elements of A in an increasing order with no duplications: description and pseudocode complexity analysis, example demonstration on the provided A If your algorithm only has average-case complexity O(n) then 2 marks will be deducted. Example: for A=[ 3,−6,1,−3,20
,6,−9,−15], the output is B=[1,3,6,9,15,20].
a) To get the minimum difference between two distinct elements of an array A of n integers, we must compare each pair of distinct integers in A and compute the absolute difference between them.
In order to accomplish this, we'll use two nested loops. The outer loop runs from 0 to n-2, and the inner loop runs from i+1 to n-1. Thus, the number of comparisons that must be made is equal to (n-1)+(n-2)+(n-3)+...+1, which simplifies to n(n-1)/2 - n.b) The transform-and-conquer approach involves transforming the input in some way, solving a simpler version of the problem, and then using the solution to the simpler problem to solve the original problem.
c) Given that the array A is already sorted in a non-decreasing order, we can traverse the array once, adding each element to a new array B if it is different from the previous element. Since the array is sorted, duplicates will appear consecutively. Therefore, we can avoid duplicates by only adding elements that are different from the previous element. The time complexity of this algorithm is O(n), since we only need to traverse the array once.
Here is the pseudocode for part c:
function getDistinctAbsValues(A):
n = length(A)
B = empty array
prev = None
for i = 0 to n-1:
if A[i] != prev:
B.append(abs(A[i]))
prev = A[i]
return B
Example: For A=[3,−6,1,−3,20,6,−9,−15], the output would be B=[1,3,6,9,15,20].
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ransomware is typically introduced into a network by a ________ and to an individual computer by a trojan horse.
The following term can complete the given sentence, "ransomware is typically introduced into a network by a ________ and to an individual computer by a trojan horse" - vulnerability.
Ransomware is a type of malicious software that locks users out of their devices and data. This software aims to demand a ransom from victims by encrypting the files on their computers or by preventing them from accessing the system.
These attacks are a popular way for cybercriminals to profit because they are relatively easy to carry out, and the ransom can be paid anonymously through digital currencies such as Bitcoin.
Ransomware is usually introduced into a network by exploiting vulnerabilities in software or operating systems. Once a vulnerability is identified, ransomware is often delivered via email attachments, malicious downloads, or through infected websites.
Once it infects a computer, ransomware can quickly spread through a network, encrypting files and locking users out of their systems.
A Trojan horse is a type of malware that is designed to trick users into downloading it onto their computers. It typically arrives as an email attachment or as a link to a malicious website.
Once it is downloaded, the Trojan horse can perform a variety of tasks, such as stealing sensitive information, downloading other malware, or giving a remote attacker control over the infected computer.
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