Sketch the graphs of the equations: y = −3 −x

Answer:

[tex]$\frac{3\pi }{2}$[/tex]

Step-by-step explanation:

Solve for the interval: [tex][0, 2\pi)[/tex]

[tex]4 \csc(\theta)+1=-3[/tex]

[tex]4 \csc(\theta)=-4[/tex]

[tex]\csc(\theta)=-1[/tex]

[tex]$\frac{1}{\sin(\theta)} =-1 \Rightarrow \sin(\theta)=-1$[/tex]

We have [tex]\sin(\theta)=-1[/tex] for coterminal angles [tex]$\frac{3\pi }{2}+2\pi n$[/tex]

Once we just want the interval [tex][0, 2\pi)[/tex]

The solution is [tex]$\frac{3\pi }{2}$[/tex]

Answer:

hope it helps

this is my best

please tell me if I'm wrong

[tex]\text{Molly used the addition property of equality}\\\\\text{In the equation shown in the question, you can see that Molly is trying}\\\text{to find the value of "d"}\\\\\text{In order to do this, she must get the "d" variable by itself}\\\\\text{To do this, she adds "3d" to both sides to get the "d" variable on one side}\\\\[/tex]

Answer:

HIG=28°

Step-by-step explanation:

HI is a diameter therefore it's measure is 180°

HI-IG=HG

180-128=HG

52°=HG

HIG=1/2HG

HIG=1/2(56°)

HIG=28°

Answer:

Step-by-step explanation:

Let the missing percent be 'x'

[tex] x \: \times \: \frac{1}{6} = \frac{2}{3} [/tex]

Use the commutative property to reorder the terms

[tex] \frac{1}{6} x = \frac{2}{3} [/tex]

Multiply both sides of the equation by 6

[tex] \frac{1}{6} x \times 6 = \frac{2}{3} \times 6[/tex]

Calculate

[tex]x = 4 \:[/tex] %

b. [tex]x \: \times 1 \frac{3}{5} = 0.2[/tex]

Convert the mixed number into improper fraction

[tex]x \times \frac{8}{5} = 0.2[/tex]

Use the commutative property to reorder the terms

[tex] \frac{8}{5} x = 0.2[/tex]

Multiply both sides of the equation by [tex] \frac{5}{8} [/tex]

[tex] \frac{8}{5} x \times \frac{5}{8} = 0.2 \times \frac{5}{8} [/tex]

Calculate

[tex]x = 0.125 \: [/tex] %

Hope this helps..

Best regards!!

Answer:

1)  2/3 is 400% of 1/6

2) 0.2 is 12.5% of 1 3/5

Step-by-step explanation:

1) First, let's switch these two fractions to a low common denominator. I used sixths, and got 4/6 and 1/6. then, noticing that 4/6 is 4x bigger than 1/6, and 100% means all of the 1/6, and 4/6 is 4x that, 4x 100% is 400%, that's the answer ;-)

2) First, let's convert these both to fractions, 1/5 and 1 3/5, which converts to 8/5. 8/5 is 8x as much as 1/5, which means that it is 12.5%

hope this helps and gives a clear answer!

Answer:

The value of a is e³ and b is e.

The steps are :

First, you have to integrate the expression shown in the first picture.

Next, you have to solve it as simultaneous equation shown in the second picture.

You have to apply :

[tex] ln(b) - ln(a) = ln( \frac{b}{a} ) [/tex]

[tex] ln(y) = x \: ⇒ \: {e}^{x} = y[/tex]

Answer:

b = (8)tan(30)

Step-by-step explanation:

Use mnuemonic device SOHCAHTOA

Answer:

According to the graph, f(−3)=3 and f(9)=-7

-7-3/9-(-3)= −10/12

Therefore the answer is -5/6

From Khan

The average rate of change over the interval [-3,9] will be 63 units per one unit change in y - value.

        [tex]b^x = \underbrace{b \times \dots \times b}_{x \text{ times}}[/tex]

        where : [m] → is slope of line and [c] → is the y - intercept

We have the following function -

f(x) = x³ - 9

The average rate of change would be -

r = {720 - (- 36)}/{9 - (- 3)}

r = 756/12

r = 63

Therefore, the average rate of change over the interval [-3,9] will be 63 units per one unit change in y - value.

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[ Complete question -

what is the average rate of change of f(x) = x³ - 9 over the interval [-3,9] ]

Answer:

Question

5) 0.81859

6) P(x<6.6) = 0.15866

7) 15.866 frogs would be longer than 8.2cm

Step-by-step explanation:

5. A biologist is measuring the lengths of frogs in a certain location. The lengths

of the frogs have a mean of 7.4 centimeters and a standard deviation of 0.8

centimeters. What is the probability that a randomly selected frog will measure

between 5.8 cm and 8.2 cm?

Using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

z1 = (x-μ)/σ

x is the raw score = 5.8cm

μ is the population mean = 7.4cm

σ is the population standard deviation. = 0.8cm

= 5.8 - 7.4/0.8

= -2

Using a z score table to find the probability of -2

P(z = -2) = 0.02275

z2 = (x-μ)/σ,

x is the raw score = 8.2cm

μ is the population mean = 7.4cm

σ is the population standard deviation. = 0.8cm

z = 8.2 - 7.4/0.8

z = 1

Using the Z-Table to find the probability

P(z = 1) = 0.84134

Hence, the probability that a randomly selected frog will measure between 5.8 cm and 8.2 cm is calculated as:

0.84134 - 0.02275 = 0.81859

6. Using the data from question #5, what is the probability that a randomly

selected frog will measure less than 6.6 cm?

Your answer

Using z score formula

z = (x-μ)/σ, where

x is the raw score = 6.6cm

μ is the population mean = 7.4cm

σ is the population standard deviation. = 0.8cm

z1 = (x-μ)/σ

= 6.6 - 7.4/0.8

= -1

Using the Z-Table to find the probability a randomly selected frog will measure less than 6.6 cm

P(x<6.6) = 0.15866

7. Using the data from #5, if 100 frogs are measured, how many of them would you predict to measure longer than 8.2 cm?

z = (x-μ)/σ,

x is the raw score = 8.2cm

μ is the population mean = 7.4cm

σ is the population standard deviation. = 0.8cm

z = 8.2 - 7.4/0.8

z = 1

Using the Z-Table to find the probability

P(x<8.2) = 0.84134

To find the probability of frogs that would be longer than 8.2cm

P(x>8.2) = 1 - P(x<8.2) = 0.15866

To calculate the number would be predicted to measure longer than 8.2 cm is :

0.15866 × 100 = 15.866% is longer than 8.2cm

Therefore,

15.866% × 100 frogs = 15.866 frogs.

Answer:

80

Step-by-step explanation:

The median is the middle line of the box plot

Answer:

def 80

Step-by-step explanation:

Answer:

a + b = 12

Step-by-step explanation:

Given

Quadrilateral;

Vertices of (0,1), (3,4) (4,3) and (3,0)

[tex]Perimeter = a\sqrt{2} + b\sqrt{10}[/tex]

Required

[tex]a + b[/tex]

Let the vertices be represented with A,B,C,D such as

A = (0,1); B = (3,4); C = (4,3) and D = (3,0)

To calculate the actual perimeter, we need to first calculate the distance between the points;

Such that:

AB represents distance between point A and B

BC represents distance between point B and C

CD represents distance between point C and D

DA represents distance between point D and A

Calculating AB

Here, we consider A = (0,1); B = (3,4);

Distance is calculated as;

[tex]Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex](x_1,y_1) = A(0,1)[/tex]

[tex](x_2,y_2) = B(3,4)[/tex]

Substitute these values in the formula above

[tex]Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex]AB = \sqrt{(0 - 3)^2 + (1 - 4)^2}[/tex]

[tex]AB = \sqrt{( - 3)^2 + (-3)^2}[/tex]

[tex]AB = \sqrt{9+ 9}[/tex]

[tex]AB = \sqrt{18}[/tex]

[tex]AB = \sqrt{9*2}[/tex]

[tex]AB = \sqrt{9}*\sqrt{2}[/tex]

[tex]AB = 3\sqrt{2}[/tex]

Calculating BC

Here, we consider B = (3,4); C = (4,3)

Here,

[tex](x_1,y_1) = B (3,4)[/tex]

[tex](x_2,y_2) = C(4,3)[/tex]

Substitute these values in the formula above

[tex]Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex]BC = \sqrt{(3 - 4)^2 + (4 - 3)^2}[/tex]

[tex]BC = \sqrt{(-1)^2 + (1)^2}[/tex]

[tex]BC = \sqrt{1 + 1}[/tex]

[tex]BC = \sqrt{2}[/tex]

Calculating CD

Here, we consider C = (4,3); D = (3,0)

Here,

[tex](x_1,y_1) = C(4,3)[/tex]

[tex](x_2,y_2) = D (3,0)[/tex]

Substitute these values in the formula above

[tex]Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex]CD = \sqrt{(4 - 3)^2 + (3 - 0)^2}[/tex]

[tex]CD = \sqrt{(1)^2 + (3)^2}[/tex]

[tex]CD = \sqrt{1 + 9}[/tex]

[tex]CD = \sqrt{10}[/tex]

Lastly;

Calculating DA

Here, we consider C = (4,3); D = (3,0)

Here,

[tex](x_1,y_1) = D (3,0)[/tex]

[tex](x_2,y_2) = A (0,1)[/tex]

Substitute these values in the formula above

[tex]Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex]DA = \sqrt{(3 - 0)^2 + (0 - 1)^2}[/tex]

[tex]DA = \sqrt{(3)^2 + (- 1)^2}[/tex]

[tex]DA = \sqrt{9 + 1}[/tex]

[tex]DA = \sqrt{10}[/tex]

The addition of the values of distances AB, BC, CD and DA gives the perimeter of the quadrilateral

[tex]Perimeter = 3\sqrt{2} + \sqrt{2} + \sqrt{10} + \sqrt{10}[/tex]

[tex]Perimeter = 4\sqrt{2} + 2\sqrt{10}[/tex]

Recall that

[tex]Perimeter = a\sqrt{2} + b\sqrt{10}[/tex]

This implies that

[tex]a\sqrt{2} + b\sqrt{10} = 4\sqrt{2} + 2\sqrt{10}[/tex]

By comparison

[tex]a\sqrt{2} = 4\sqrt{2}[/tex]

Divide both sides by [tex]\sqrt{2}[/tex]

[tex]a = 4[/tex]

By comparison

[tex]b\sqrt{10} = 2\sqrt{10}[/tex]

Divide both sides by [tex]\sqrt{10}[/tex]

[tex]b = 2[/tex]

Hence,

a + b = 2 + 10

a + b = 12

Answer:

a+b=6

Step-by-step explanation:

The tutor verified answer is mostly correct however, if you look under both by comperision sections you will see that it is:

[tex]4\sqrt{2}[/tex] and [tex]2\sqrt{10}[/tex] thus the answer is 4+2=6

Answer:

The awnser is 64

Step-by-step explanation:

It is 64 because you devide the perimiter (32) by 4, to get all sides, and then multiply 1 side by the other to get 64

THIS METHOD ONLY WORKS FOR A SQUARE

Answer:

c. (x-3) is not a factor.

Step-by-step explanation:

Answer:

y = 3x

Step-by-step explanation:

Assume a slope of 3

The y intercept is 0

The slope intercept form of the equation is

y= mx+b where m is the slope and b is the y intercept

y =3x+0

y = 3x

Answer:

62.5°

Hope this helps :)

Answer:

7 < (third side length) < 37

Step-by-step explanation:

Add these two side lengths together.  We get 37.  Unless the 3rd side is LESS than 37, we cannot form a triangle.  

Next, subtract 15 from 22, obtaining 7.  The 3rd side has to be GREATER than 7 in order for the sides 7+, 15 and 22 to form a triangle.

7 < (third side length) < 37

Answer:

26.63 ??

Step-by-step explanation:

I think you use pythagorean theorum to solve.

do 22^2 and 15^2 and get 709.1569

sqrt of that is 26.63

Answer:

A and C

Step-by-step explanation:

The roots of the quadratic function f(q) = q² - 125 are q = 5 and q = -5.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The quadratic function f(q) = q² - 125 can be factored as (q - 5)(q + 5).

Now,

To find the roots, we set the function equal to zero and solve for q:

So,

q² - 125 = 0

(q - 5)(q + 5) = 0

q - 5 = 0 or q + 5 = 0

q = 5 or q = -5

Therefore,

The roots of the quadratic function f(q) = q² - 125 are q = 5 and q = -5.

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Answer:

pen: $1.50 notebook: $2.00

Step-by-step explanation:

4×1.50 =6

5×2 = 10

6+10= 16

3×1.50= 4.50

8×2= 16

4.50 + 16 = 20.50

Answer:

3 dolla

Step-by-step explanation:

Answer:

8mins

Step-by-step explanation:

(2x60)/15=8 I hope this helps, hope it's right

Answer:

8 minutes

Step-by-step explanation:

You will multiply 60 times 2 and then divide by 15 leaving you with 8

Answer:

C. [tex](5-\frac{1}{2})^6[/tex]

Step-by-step explanation:

Given

[tex]15(5)^2(-\frac{1}{2})^4[/tex]

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

[tex]Sum = 2 + 4[/tex]

[tex]Sum = 6[/tex]

Each term of a binomial expansion are always of the form:

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

Where n = the sum above

[tex]n = 6[/tex]

Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion

[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

Substitute 6 for n

[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

By direct comparison of

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

and

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

We have;

[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]

Further comparison gives

[tex]^nC_r = 15[/tex]

[tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]b^r= (-\frac{1}{2})^4[/tex]

[Solving for a]

By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]a = 5[/tex]

[tex]n = 6[/tex]

[tex]r = 4[/tex]

[Solving for b]

By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]

[tex]r = 4[/tex]

[tex]b = \frac{-1}{2}[/tex]

Substitute values for a, b, n and r in

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

Solve for [tex]^6C_4[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]

Check the list of options for the expression on the left hand side

The correct answer is [tex](5-\frac{1}{2})^6[/tex]

Answer: D

Step-by-step explanation:

In every other solution, x gets canceled out, so it has no impact on the equation.  Thus, A, B, and C all have either infinite or no solution, because they have 6x on both sides of the equation.

Further proof:

6x-6=15x+15

Add(6)

6x=15x+21

Subtract(15x)

-9x=21

Divide(-9)

x = -2 3/9

Hope it helps <3

Answer:

d) 6x - 6 = 15x + 15

Step-by-step explanation:

Well let’s solve.

a)

6x - 15 = 6x + 15

Lets use the communicative property which is the moving of numbers.

We can start with -15, so we do +15,

6x = 6x + 30

Then we can do -6x

0 = 30

This is a false statement meaning there is no solution.

b)

6x - 6 = 6x + 15

We can start by doing +6

6x = 6x + 21

-6x

0 = 21

Again, this is a false statement meaning this has no solutions.

c)

6x + 15 = 6x + 15

So we do -15

6x = 6x

If this is the case then there is infinitely many solutions.

d)

6x - 6 = 15x + 15

So we can start by doing +5p6

6x = 15x + 21

Then we can do -15x

-9x = 21

then we can do 21 / -9 which is -2 1/3.

x = -2 1/3

So this has one solution.

Answer: B.

k=3

Step-by-step explanation:

g(x) is 3 units higher than f(x)

so k must be equal to 3

Answer:

it is b i think

k=3

Step-by-step explanation:

3x+4y=12 is Linear.

y-1/2x+6 is Linear.

y=4x^2 is nonlinear.

y+2=|4| is linear.

y+6=4x is linear.

In order to tell whether an equation is linear or not, you have to first see if there is any variable^2 or more than ^1. If that is the case, it isn't linear. For example the equation x^2=4 or y^5=100 isn't linear. It also isn't linear if the equation is divided by X or Y.For example the equation 1/x=1 isn't linear or 1/y^2=5 isn't linear.

A question is also linear if you can write it in the form y=mx+b , 'm' meaning the slope of the equation and 'b' meaning the y-intercept of the equation.

Answer:

Total mass of materials = 4.8kg

For gravel

55% of the materials are gravel

So we have

55/100 × 4.8 kg

= 2.64kg

For sand

30% of the materials are sand

We have

30/100 × 4.8

= 1.44kg

For cement

The remaining materials were cement so we add the masses of both the sand and gravel and subtract it from the total mass

That's

4.8 - (2.64 + 1.44)

4.8 - 4.08

= 0.72 kg

She earns £ 800 per week

She receives a raise of 7.5% which is

100 + 7.5 = 107.5%

So we have

107.5 / 100 × £ 800

= £ 860

She now earns £ 860 per week

Hope this helps you

Step-by-step explanation:

1)of 4.8kg concrete 55% is gravel,30% is sand and 15% is cement.

percent=Rate*Base

Pgravel=55%*4.8kg

Pgravel=2.64kg

Psand=30%*4.8kg

Psand=1.44kg

Pcement=15%*4.8kg

Pcement=0.72kg

2)percent=Rate*Base

percent=7.5%*£800

percent=60£

total earn=60£ + £800

total earn=£860

===========================================

Work Shown:

40 coins total

16 are dimes

40-16 = 24 coins are not dimes

Half of this is 24*(1/2) = 12 which are quarters. The other half (12) are pennies and nickels

n = number of nickels

p = number of pennies

This means n+p = 12 so that we have 12 pennies and nickels combined.

"There are 2 nickels for every penny", so we can write n = 2p. If p = 1, then n = 2. If p = 2, then n = 4, etc. Whatever p is, we double it to get n.

So,

n+p = 12

2p+p = 12

3p = 12

p = 12/3

p = 4, we have 4 pennies

n = 2p

n = 2*4

n = 8 and 8 nickels

-----------------------------------------

Here are all the coin counts

16+12+8+4 = 40 coins total

Answer:

Option (B) is correct, 4 pennies.

Answer:

Tina

Step-by-step explanation:

Since Amy owns the dog, she doesn't have the ferret and we know that Jewel doesn't have the ferret so the answer is Tina.

Answer:

3,5,7

Step-by-step explanation:

Answer:

7,8.15

Step-by-step explanation:

Answer \

c land on yellow 90 time

Answer:

all but B & D

Step-by-step explanation:

the sum of all data=314

314-120=194

164-44=150

I WAS WRONG THE ANSWERS WERE A AND D: DONT BELIEVE ME VIEW COMMENTS BELOW