Sixteen stations, numbered 1 through 16, are contending for the use of a shared channel by using the adaptive tree walk protocol. If all the stations whose addresses are prime numbers suddenly become ready at once, how many bit slots are needed to resolve the contention

Answer:

11 bit slot will be needed

Explanation:

The number of prime numbers between 1 through 16

= 2, 3 , 5, 7, 11 and 13

hence we can say 6 stations are to use the shared channel

Given that all the stations are ready simultaneously

The number of bit slots that will be needed to handle the contention will be 11 bits :

slot 1 : 2, 3, 5 , 7, 11 , 13

slot 2 : 2,3, 5, 7

slot 3 : 2, 3

slot 4 : 2 .   slot 5 : 3 .  slot 6 : 5,7.   slot 7 : 5 .   slot 8 : 7.  slot 9: 11,13.  

slot 10 : 11.   slot 11 : 13

b) Set of strings of 0s and 1s whose 5th symbol from left is 1.

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The animation steps will play backward.
The animation steps will play forward, then backward.
The animation steps will play forward.
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A network consists of 75 workstations and three servers. The workstations are currently connected to the network with 100 Mbps switches, and the servers have 1000 Mbps connections. Describe two network problems that can be solved by replacing the workstations' 100 Mbps switches and NICs with 1000 Mbps switches and NICs. What potential problems can this upgrade cause

hello! can someone write a c++ program for this problem

Problema 2018.3.2 - Cheated dice
Costica is on vacation and his parents sent him to the country. There he gets terribly bored and looking through his grandfather's closet, he came across a bag full of dice. Having no one to play dice with, but it seemed to him that some of the dice were heavier than the others, Costica chose a dice and started to test it by throwing it with him and noting how many times each face fell. He then tries to figure out whether the dice are rolled or not, considering that the difference between the maximum number of appearances of one face and the minimum number of occurrences (of any other face) should not exceed 10% of the total number of throws.
Requirement
Given a number N of dice rolls and then N natural numbers in the range [1: 6] representing the numbers obtained on the rolls, determine whether the dice is tricked according to the above condition.
Input data
From the input (stdin stream) on the first line reads the natural number N, representing the number of rolls. On the following N lines there is a natural number in the range [1: 6] representing the numbers obtained on throws.
Output data
At the output (stdout stream) a single number will be displayed, 0 or 1, 0 if the dice are normal, and 1 if it is cheated.
ATTENTION to the requirement of the problem: the results must be displayed EXACTLY in the way indicated! In other words, nothing will be displayed on the standard output stream in addition to the problem requirement; as a result of the automatic evaluation, any additional character displayed, or a display different from the one indicated, will lead to an erroneous result and therefore to the qualification "Rejected".
Restrictions and clarifications
1. 10 ≤ N ≤ 100
2. Caution: Depending on the programming language chosen, the file containing the code must have one of the extensions .c, .cpp, .java, or .m. The web editor will not automatically add these extensions and their absence makes it impossible to compile the program!
3. Attention: The source file must be named by the candidate as: . where name is the last name of the candidate and the extension (ext) is the one chosen according to the previous point. Beware of Java language restrictions on class name and file name!
Input data

10
6
6
6
6
6
6
6
6
6
6
Output data
1

Roll the dice 10 times, all 10 rolls produce the number 6. Because the difference between the maximum number of rolls (10) and the minimum number of rolls (0) is strictly greater than 10% of the total number of rolls (10% of 10 is 1), we conclude that the dice are oiled.

Input data
10
1
4
2
5
4
6
2
1
3
3
Output data
0

Throw the dice 10 times and get: 1 twice, 2 twice, 3 twice, 4 twice, 5 and 6 at a time. Because the difference between the maximum number of appearances (two) and the minimum number of occurrences (one) is less than or equal to 10% of the total number of throws (10% of 10 is 1), we conclude that the dice are not deceived.

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