Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a house in Midvale, UT for $ 172000 in 2004 in what year would the home be worth $ 249000 ?

Answer:

See explanation below

Step-by-step explanation:

Here a coin was tossed three times.

Let H = head &  T = tail

Find the following:

a) The sample space:

Since a coin is tossed thrice, all possible outcome would be:

S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}

b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.

A = {HTT, TTH, THT}

ii) B = at least two tails: Here 2 or more tails were recorded.

B = {HTT, TTT, TTH, THT}

iii) C = the last two tosses are heads:

C = { HHH, THH}

c) List the elements of the following events:

i) A. This means all outcomes in A

= {HTT, TTH, THT}

ii) A∪B. A union B, means all possible outcomes present in A or B or in both

= {HTT, TTH, THT, TTT}

iii) A∩B. This means all possible outcomes of A that are present in B.

= {HTT, TTH, THT}

iv) A∩C. All outcomes A that are present in B

= {∅}

Answer:

64

Step-by-step explanation:

There are only pink and yellow sections of the circle, so every spin will land on pink or yellow.

Answer: 64

Answer:

Brianliest!

Step-by-step explanation:

since there are only the colors pink and yellow and the prediction for the   number of times it will land on pink or yellow, it will have a 100% probability

64

Answer:

9

Step-by-step explanation:

5≤n≤12

List all the even integers

6,8,10,12

Then find the mean

(6+8+10+12) /4

36/4

9

The mean is 9

Answer:

B and E

Step-by-step explanation:

A: 3 + 6 < 4 + 3 and 6 > 4

9 < 7 is false so A is not the answer.

B: 1 + 5 < 4 + 3 and 5 > 4

6 < 7 and 5 > 4 are true so B is an answer.

C: 2 + (-1) < 4 + 3 and -1 > 4

-1 > 4 is false so C is not an answer.

D: 1 + 1 < 4 + 3 and 1 > 4

1 > 4 is false so D is not an answer.

E: 2 + 8 > 4 + 3 and 8 > 4

10 > 7 and 8 > 4 are both true so E is an answer.

F: -1 + 8 > 4 + 3 and 8 > 4

7 > 7 is false so F is not an answer.

Answer:

[tex]\frac{24}{89}[/tex] chance or ≈27% chance or 0.27

Step-by-step explanation:

P of getting a red golf ball: [tex]\frac{24}{23+24+18+24} =\frac{24}{89}[/tex]

Answer:

There is not enough evidence to support the claim that the chance of this cross to be blue-flowering is significantly smaller than 0.75 (P-value = 0.11).

Test statistic z=-1.225.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the chance to be blue-flowering is significantly smaller than 0.75.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.75\\\\H_a:\pi<0.75[/tex]

The significance level is 0.05.

The sample has a size n=200.

The sample proportion is p=0.71.

[tex]p=X/n=142/200=0.71[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.75*0.25}{200}}\\\\\\ \sigma_p=\sqrt{0.000938}=0.031[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.71-0.75+0.5/200}{0.031}=\dfrac{-0.038}{0.031}=-1.225[/tex]

This test is a left-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z<-1.225)=0.11[/tex]

As the P-value (0.11) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the chance to be blue-flowering is significantly smaller than 0.75.

Answer:

none of the choices are correct

Step-by-step explanation:

it's 4/3

20/15=4.3333333333333

4/3=4.333333333333333

8/6=4.33333333333

The scale factor of the two triangles is [tex]\frac{3}{4}[/tex].

When two triangles are similar, the reduced ratio of any corresponding sides is called  the scale factor of the similar triangles.

Similar triangles are triangles that have the same shape, but their sizes may vary.

According to the given question

We have two triangles NGK and ALH

In which

NG = 15, GK = 6, NK = 3

And, AL =  20, LH = 8 and AH = 4

Since, we have to find the scale factor of these two triangles so the two triangles must be similar.

As, ΔNGK is similar to ΔALH

⇒ [tex]\frac{NG}{AL} = \frac{GK}{LH} = \frac{NK}{AH}[/tex]

⇒ [tex]\frac{15}{20} = \frac{6}{8} =\frac{3}{4}[/tex]

⇒ [tex]\frac{3}{4} = \frac{3}{4} =\frac{3}{4}[/tex]

Hence, the scale factor of the two triangles is [tex]\frac{3}{4}[/tex].

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Answer:

a) 0.202 = 20.2% probability that a customer has to wait more than 4 minutes.

b) 0.33 = 33% probability that a customer is served within the first minute.

c) 11.5 minutes.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

In this question:

[tex]m = 2.5, \mu = \frac{1}{2.5} = 0.4[/tex]

(a) Find the probability that a customer has to wait more than 4 minutes.

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

[tex]P(X > 4) = e^{-0.4*4} = 0.202[/tex]

0.202 = 20.2% probability that a customer has to wait more than 4 minutes.

(b) Find the probability that a customer is served within the first minute.

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

[tex]P(X \leq 1) = 1 - e^{-0.4*1} = 0.33[/tex]

0.33 = 33% probability that a customer is served within the first minute.

(c) The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she doesn't want to give away free hamburgers to more than 1% of her customers. What number of minutes should the advertisement use

We have to find x for which:

[tex]P(X > x) = 0.01[/tex]

So

[tex]P(X > x) = e^{-0.4x}[/tex]

Then

[tex]e^{-0.4x} = 0.01[/tex]

[tex]\ln{e^{-0.4x}} = \ln{0.01}[/tex]

[tex]-0.4x = \ln{0.01}[/tex]

[tex]x = -\frac{\ln{0.01}}{0.4}[/tex]

[tex]x = 11.5[/tex]

So 11.5 minutes.

The length of wire used for the square in order to minimize the total area is 9.42m.

We are given that;

Length of wire= 30m

Now

Let the length of the wire used for the square x. The length of the wire used for the circle is 30-x.

The perimeter of the square is 4x and the perimeter of the circle is 2πr=2π(30-x)/(2π)=15-x/π.

The area of the square is [tex]x^2/16[/tex] and

the area of the circle is π(15-x/π)2/4π=225/π-(15x)/π2+[tex]x^2[/tex]/4π.

The total area is A=x2/16+225/π-(15x)/π2+[tex]x^2[/tex]/4π.

To maximize A, we take its derivative with respect to x and set it equal to zero: d[tex]A/dx=x/8-15/π^2+1/(4π)(x)=0[/tex]

Solving for x, we get x=120/(8+4π).

Therefore, 30-x=120/(8+4π)(3-π).

To minimize A, we take its derivative with respect to x and set it equal to zero:

[tex]dA/dx=x/8-15/π^2+1/(4π)(x)=0[/tex]

Solving for x, we get x=120/(8+4π)(3+π).

So, 30-x=120/(8+4π)(3-π).

Therefore, by area the answer will be approximately 9.42 m.

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Answer:

All the possible numbers she could represent using the counters are:

0.6  |  1.5  |  2.4  |  3.3  |  4.2  |  5.1  |  6

Step-by-step explanation:

Please refer to the attached diagram for this question.

We are asked to list all the possible numbers she could represent using the counters.

The possible numbers are:

When there is 0 counter in the "ones" place and 6 counters in the "tenths" place.

0.6

When there is 1 counter in the "ones" place and 5 counters in the "tenths" place.

1.5

When there are 2 counters in the "ones" place and 4 counters in the "tenths" place.

2.4

When there are 3 counters in the "ones" place and 3 counters in the "tenths" place.

3.3

When there are 4 counters in the "ones" place and 2 counters in the "tenths" place.

4.2

When there are 5 counters in the "ones" place and 1 counter in the "tenths" place.

5.1

When there are 6 counters in the "ones" place and 0 counter in the "tenths" place.

6

Therefore, all the possible numbers she could represent using the counters are:

0.6  |  1.5  |  2.4  |  3.3  |  4.2  |  5.1  |  6

Answer:

60°

Step-by-step explanation:

∠ABC-∠CBD=∠1

[tex]135-75[/tex]

[tex]=60[/tex]

Answer:

Brainliest goes to me!

Step-by-step explanation:

angle abc = 135 degrees

part of it is angle 1 and the other part is angle cbd

<abc (135) = cbd (75) + <1

angle 1 = 60 degrees

Answer:

(g o h)(5) = 4

Step-by-step explanation:

h(x) = x - 7

g(x) = x^2

(g o h)(5) = ?

(g o h)(x) = g(h(x)) = (x - 7)^2

(g o h)(5) = (5 - 7)^2 = (-2)^2 = 4

Answer:

g°h(5)=4

Step-by-step explanation:

g°h(5)=g( h(5))

h(5)=5-7=-2

g(-2)=(-2)^2=2^2=4

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 4% of respondents did not provide a response, 26% said that their experience fell short of expectations, 65% of the respondents said that their experience met expectations (Clarkson Magazine, Summer, 2001). If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations? If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?

Solution:

Probability = number of favorable outcomes/number of total outcomes

From the information given,

The probability that respondents did not provide a response, P(A) is 4/100 = 0.04

The probability that a respondent said that their experience fell short of expectations, P(B) is 26/100 = 0.26

The probability that a respondent said that their experience met expectations, P(C) is 65/100 = 0.65

A) Adding all the probabilities, it becomes 0.04 + 0.26 + 0.65 = 0.95

Therefore, the probability,P(D) that a respondent said that their experience surpassed expectations is 1 - 0.95 = 0.05

B) The event of a randomly chosen respondent saying that their experience met expectations and that their experience surpassed expectations are mutually exclusive because they cannot occur together. It means that P(C) × P(D) = 0

Therefore, the probability of P(C) or P(D) is 0.65 + 0.05 = 0.7

Answer:

correct option: 2 -> It would decrease.

Step-by-step explanation:

If the amount of gas is the same, the following relation needs to be constant:

[tex]Pressure * Volume / Temperature[/tex]

So, If the pressure is constant, the volume and the temperature are directly proportional (if one increases, the other also increases).

Then, an decrease of 3 times in the volume would cause an decrease of 3 times in the temperature.

So the correct option is 2.: It would decrease.

Answer:

A. Tomas is correct; AC is opposite ∠B and BC is adjacent to ∠B.

Step-by-step explanation:

edge2021

The description of Thomas is correct. AC is opposite ∠B and BC is adjacent to ∠B.

Right angled triangle are those triangle for which one of the angle is 90 degrees.

Hypotenuse of a right angled triangle is the longest side.

Opposite side with respect to an angle is the side opposite to that angle.

Adjacent side with respect to an angle is the side which is adjacent to the angle.

Given is a triangle ABC.

Here C is the right angle.

Then the side opposite to the right angle is the hypotenuse.

So AB is the hypotenuse.

Now we are describing the sides in relation to the ∠B.

Side opposite to ∠B is AC, which is the opposite side.

Side adjacent to ∠B is BC, which is the adjacent side.

This is the description of Thomas.

Hence Thomas is correct about describing the sides in relation to ∠B.

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The complete question is as follows :

Two students describe the sides of right triangle ABC in relation to ∠B. Triangle A B C is shown. Angle A C B is a right angle. Tomas : AB is the hypotenuse. AC is the opposite side. BC is the adjacent side. Iliana : AB is the hypotenuse. BC is the opposite side. AC is the adjacent side. Who is correct? Explain. Tomas is correct; AC is opposite ∠B and BC is adjacent to ∠B. Iliana is correct; BC is opposite ∠B and AC is adjacent to ∠B. Both are correct because both AC and BC are opposite ∠B. Neither is correct because neither AC nor BC is opposite ∠B.

Answer:

1

Step-by-step explanation:

4^3 × 4^-3

Apply the law of exponents.

4^(3+-3)

4^(0)

Any base with the exponent of 0 is equal to 1.

= 1

Answer:

1

Step-by-step explanation:

the exponents cancel out to 0, and an exponent of 0 is always 1

[tex]solution \\ {2x}^{2} - x + ( - x - {2x}^{2} - 2) \\ = {2x}^{2} - x - x - {2x}^{2} - 2 \\ = {2x}^{2} - {2x}^{2} - x - x - 2 \\ = - 2x - 2[/tex]

Hope it helps

Good luck on your assignment

Answer:

[tex] - 2x - 2[/tex]

Step-by-step explanation:

[tex]2 {x}^{2} - x + ( - x - 2 {x}^{2} - 2) \\ 2 {x}^{2} - x - x - 2 {x}^{2} - 2 \\ 2 {x}^{2} - 2 {x}^{2} - x - x - 2 \\ - 2x - 2[/tex]

hope this helps you.

brainliest appreciated

good luck!

have a nice day!

Answer:

£29.37

Step-by-step explanation:

→ First step is to find the amount of hours it takes for 5 builders

[tex]\frac{3*\frac{11}{2} }{5} =\frac{33}{2} /5=\frac{33}{2} *\frac{1}{5} =\frac{33}{10} =3\frac{3}{10}[/tex]

→ Now we know how long 5 builder takes we need to multiply the hourly rate by their time worked

[tex]3\frac{3}{10} *8.90=\frac{33}{10} *8.90=3.3*8.90 = 29.37[/tex]

Answer:

Step-by-step explanation:

When the number of builders is increased, the hours worked will be reduced.

So, this is inverse proportion.

Number of hours worked by  5 builders = [tex]\frac{3*\frac{11}{2}}{5}\\\\[/tex]

                                                                  [tex]=3*\frac{11}{2}*\frac{1}{5}\\\\=\frac{33}{10}\\\\=3\frac{1}{10}[/tex]

Amount received by each builder= 33/10 * 8.90

                                                       =    £ 29.37                                                    

Answer:

46

Step-by-step explanation:

Azman=35+amin

Aziz=3×amin

therefore;35+amin+2amin+amin/3=73

219=35+4amin

219-35=4amin

184=4amin

Amin's mark=184÷4

=46

Cos(angle) = adjacent/hypotenuse

Cos(angle) = 1.5/10

Angle = arccos(1.5/10)

Angle = 81.37 degrees

Although the angle is close, it is over the 80 degrees, so the inspector should be concerned.

Answer:

The 99% confidence interval for the mean germination time is (12.3, 19.3).

Step-by-step explanation:

The question is incomplete:

Recorded here are the germination times (in days) for ten randomly  chosen seeds of a new type of bean: 18, 12, 20, 17, 14, 15, 13, 11, 21, 17. Assume that the population germination time is normally distributed. Find the 99% confidence interval for the mean germination time.

We start calculating the sample mean M and standard deviation s:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(18+12+20+17+14+15+13+11+21+17)\\\\\\M=\dfrac{158}{10}\\\\\\M=15.8\\\\\\[/tex]

[tex]s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((18-15.8)^2+(12-15.8)^2+(20-15.8)^2+. . . +(17-15.8)^2)}\\\\\\s=\sqrt{\dfrac{101.6}{9}}\\\\\\s=\sqrt{11.3}=3.4\\\\\\[/tex]

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=15.8.

The sample size is N=10.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{10}}=\dfrac{3.4}{3.162}=1.075[/tex]

The degrees of freedom for this sample size are:

df=n-1=10-1=9

The t-value for a 99% confidence interval and 9 degrees of freedom is t=3.25.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=3.25 \cdot 1.075=3.49[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 15.8-3.49=12.3\\\\UL=M+t \cdot s_M = 15.8+3.49=19.3[/tex]

The 99% confidence interval for the mean germination time is (12.3, 19.3).

Answer:

Step-by-step explanation:

let s estimate the following

[tex](secA-tanA)(secA+tanA)=sec^2A-tan^2A=\dfrac{1}{cos^2A}-\dfrac{sin^2A}{cos^2A}=\dfrac{1-sin^2A}{cos^2A}=\dfrac{cos^2A}{cos^2A}=1[/tex]

as [tex]cos^2A+sin^2A=1[/tex]

it means that

[tex]\dfrac{1}{secA-tanA}=secA+tanA[/tex]

hope this helps

An account with a $250 balance accrues 2% annually. If no deposits or withdrawals are made so, to take the balance to $282 requires 6.4 years and this can be determined by using the simple interest formula.

Given :

SImple interest formula can be used to determine the total number of years will it take for the balance to be $282.

The formula of simple interest is given by:

[tex]\rm A = P(1+rt)[/tex]

where A is the final amount, P is the initial principal balance, r is the annual interest rate and t is the time in years.

Now, put the known values in equation (1).

[tex]\rm 282 = 250(1+0.02t)[/tex]

[tex]\rm 282=250+5t[/tex]

32 = 5t

t = 6.4 years

So, 6.4 years will it take for the balance to be $282.

So, the graph correct graph is shown by option D).

For more information, refer to the link given below:

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Answer:

D

Step-by-step explanation:

Answer:

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Step-by-step explanation:

Given that:

the number of units demanded [tex]q = pe^{-3p}[/tex]

Taking differentiations ; we have,

[tex]\dfrac{dq}{dp}=e^{-3p}+p(-3e^{-3p})[/tex]

[tex]\dfrac{dq}{dp}=(1-3)e^{-3p}[/tex]

Now; the price elasticity of demand using the differentials definition of elasticity  is:

[tex]E(p) = \dfrac{dq}{dp}*\dfrac{p}{q}[/tex]

[tex]E(p) =[(1-3)e^{-3p}]*[\dfrac{p}{pe^{-3p}}][/tex]

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

(b)   Use your answer from part (a) to estimate the percent change in q when the price is raised from $2.00 to $2.10.

The estimate of the percentage change in price is :

[tex]=\dfrac{2.10-2.00}{2.00}*100 \%[/tex]

= 5%

From (a)

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

Now at p = $2.00

E(2) = 1 - 3 (2.00)

E(2) = 1 - 6

E(2) = -5

The percentage change in q = -5 × 5%

The percentage change in q = -25%

Thus; we can conclude that the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Answer:

1/100

Step-by-step explanation:

Since the numerators are all the same, the lowest value will depend on the denominators. The greater the denominator, the lower the value. Thus, the answer is 1/100

Answer:

Answer choice 1

Step-by-step explanation:

[tex]5^2\cdot 5^9= \\\\5^{2+9}= \\\\5^{11}[/tex]

Therefore, the correct answer choice is choice 1. Hope this helps!

Answer:

False.

Step-by-step explanation:

This statement is false, for any value of F because the power function with an even exponent is always positive or 0.

[tex]\frac{2}{3}=\frac{boys}{18}[/tex]

3*boys=2*18

3*boys=36

boys=12

12+18=30

total number of students: 30

Answer:

30 students

Step-by-step explanation:

2:3 = x:18

X = number of boys

[tex]\frac{2}{3} = \frac{x}{18}[/tex]

multiply 18 by both sides

18 × [tex]\frac{2}{3} = X[/tex]

X = 18 × [tex]\frac{2}{3} = 12[/tex]

18 + 12 = 30

Answer:

Midpoint Of AB = ( 1+1/2 , -2-1/2)

= (2/2 , -3/2)

= ( 1 , -1.5)

Hope this helps

Please mark Branliest.

Answer:

-2,0

Step-by-step explanation: