Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =

Answer:

AB = 10

CW = 8

angle BAD = 50

angle CDB = 65

angle DWA = 90

angle WCD = 25

Step-by-step explanation:

use the known facts that a rhombus = 360 degrees, pythagorean theorem, etc. if you want a full explanation lmk and i can edit my response

Answer:

a) The expected value is 75, the standard deviation is 3 and the shape is approximately normal.

b) 0.9387 = 93.87% probability that the average aptitude test in the sample will be between 70.14 and 82.14.

c) 0.0052 = 0.52% probability that the average aptitude test in the sample will be greater than 82.68.

d) 0.8907 = 89.07% probability that the average aptitude test in the sample will be less than 78.69.

e) C = 81.51.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

The scores on the test are normally distributed with a mean of 75 and a standard deviation of 15.

This means that [tex]\mu = 75, \sigma = 15[/tex]

a. What are the expected value, the standard deviation, and the shape of the sampling distribution of?

By the Central Limit Theorem, it will be approximately normal, with expected value [tex]\mu = 75[/tex] and standard deviation [tex]s = \frac{15}{\sqrt{25}} = 3[/tex].

b. What is the probability that the average aptitude test in the sample will be between 70.14 and 82.14?

This is the pvalue of Z when X = 82.14 subtracted by the pvalue of Z when X = 70.14.

X = 82.14

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{82.14 - 75}{3}[/tex]

[tex]Z = 2.38[/tex]

[tex]Z = 2.38[/tex] has a pvalue of 0.9913.

X = 70.14

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{70.14 - 75}{3}[/tex]

[tex]Z = -1.62[/tex]

[tex]Z = -1.62[/tex] has a pvalue of 0.0526

0.9913 - 0.0526 = 0.9387

0.9387 = 93.87% probability that the average aptitude test in the sample will be between 70.14 and 82.14.

c. What is the probability that the average aptitude test in the sample will be greater than 82.68?

This is 1 subtracted by the pvalue of Z when X = 82.68. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{82.68 - 75}{3}[/tex]

[tex]Z = 2.56[/tex]

[tex]Z = 2.56[/tex] has a pvalue of 0.9948.

1 - 0.9948 = 0.0052

0.0052 = 0.52% probability that the average aptitude test in the sample will be greater than 82.68.

d. What is the probability that the average aptitude test in the sample will be less than 78.69?

This is the pvalue of Z when X = 78.69. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{78.69 - 75}{3}[/tex]

[tex]Z = 1.23[/tex]

[tex]Z = 1.23[/tex] has a pvalue of 0.8907.

0.8907 = 89.07% probability that the average aptitude test in the sample will be less than 78.69.

e. Find a value, C, such that P(( x>C) = .015.

This is X when Z has a pvalue of 1 - 0.015 = 0.985. So X when Z = 2.17.

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]2.17 = \frac{X - 75}{3}[/tex]

[tex]X - 75 = 3*2.17[/tex]

[tex]X = 81.51[/tex]

So C = 81.51.

Answer:

x/3 + 6 = 14

Step-by-step explanation:

Answer:

if the period is a multiplication sign then its 135

Step-by-step explanation:

Answer:

135

Step-by-step explanation:

following the PEMDAS rule, of course

Answer:

by point slope form

(y-5)/(x-2)=-2

Answer:

3x+y=16

x−y+4=8

4x−5+y=0

Answer:

Option B. y – 3 = –1/7(x – 3)

Step-by-step explanation:

From the question given above, the following data were obtained:

Slope (m) = –1/7

Coordinate = (3, 3)

x₁ coordinate = 3

y₁ coordinate = 3

The equation of the line can be written as follow

y – y₁ = m(x – x₁)

y – 3 = –1/7(x – 3)

Answer:

7

Step-by-step explanation:

Answer: 84, 35

Step-by-step explanation:

12*7=84

5*7=35

84-35=49

The two numbers are 35 and 84

Let the two numbers be x and y

If the ratio are in 12: 5, hence:

x/y = 12/5

5x = 12y

x = 12y/5

If their difference is 49, then;

x - y = 49 .................. 2

12y/5 - y = 49

7y/5 = 39

7y = 49 * 5

y = 7 * 5

y = 35

Recall that x - y = 49

x = 49 + y

x = 49 + 35

x = 84

Hence the two numbers are 35 and 84

Learn more on equations here: https://brainly.com/question/14323743

Answer:

1152

Step-by-step explanation:

When finding the area to something we must multiply.

We can do so by using the formula l * w* h * b (Length, Width, Height, Base)

2* 3= 6

6* 16= 96

96* 12= 1152

Answer:

-5/3

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( -3 -7)/(6-0)

   = -10 / 6

   = -5/3

Answer:

math          way  can help

Step-by-step explanation:

Answer:

George is a good friend :)

Step-by-step explanation:

Answer:

x = 54

Step-by-step explanation:

Since both triangles are similar, therefore,

[tex] \frac{UV}{PQ} = \frac{VW}{QR} [/tex]

[tex] \frac{77}{66} = \frac{63}{x} [/tex]

[tex] \frac{7}{6} = \frac{63}{x} [/tex]

Cross multiply

[tex] 7*x = 63*6 [/tex]

[tex] 7x = 378 [/tex]

Divide both sides by 7

x = 54

Answer:

1. jim is 18, dog is 9 2. surface area

Step-by-step explanation:

1.

ryo=13

jawad=13x2=26 --> (ryo x 2)

jim=26-8=18 --> (jawad-8)

dog=18/2=9 --> (jim/2)

2.

you need to know the surface area of the accent wall and then you can calculate how many quarts you need

Answer:

Step-by-step explanation:

Answer:

I think 1/4

Step-by-step explanation:

1000% ÷ 4 =250%

Step-by-step explanation:

(250÷50)/(100÷50) = 5/2 when reduced to the simplest form.

Answer:

4) 7k² + 9k

= k(7k + 9)

5) x² - 25

= (x)² - (5)².

(a² - b²) = (a+b)(a-b)

= (x - 5)(x + 5)

B True because both graphs approaches x=0 but never touches it

E True if you just graph it out you can see that graph of g is going down and the graph of x is going up

A false because neither of the equations have a y intercept they have asymptote of x=0

C false because it is also a reflection across the x axis

D incorrect is because they both have domain {0<x<♾}

Hope this helped!

Answer:

its 8 seconds :)

Answer:

b and d

Step-by-step explanation:

Width of the enlarged photograph = 14 cm

Length of a small photograph = 6 cm

Width of a small photograph = 4 cm

Length of the photograph when enlarged = 21 cm

Let the width of the photograph when enlarged be x.

Which means :

[tex] = \tt 4 : 6 : : x : 21[/tex]

[tex] =\tt \frac{4}{6} = \frac{x}{21} [/tex]

[tex] =\tt 4 \times 21 = 6 \times x[/tex]

[tex] =\tt 84 = 6x[/tex]

[tex] =\tt x = \frac{84}{6} [/tex]

[tex] =\tt x = 14[/tex]

Thus, the value of x = 14

Therefore, the width of the enlarged photograph = 14 cm

Answer:

The third one.

Step-by-step explanation:

8x(5+2) is also 7x8 so you'd get 56. The 8x5 is 40 then you can do 40+(8x2) which is 40+16 which is = to 56. So the third one is equivalent to each other.

Answer:

$2,874.19

Step-by-step explanation:

Hope this helps

Answer:

C

Step-by-step explanation:

I got the answer C because if the estimated value of the tank is 50 and it gets drained it will only have 18 gallon in it

5%

3.36m inutos

2.24mi nutos

Answer:

16.1 + 6.1=22

that is not equal because it will give you 22.2

as the answer hope this helps

have a good day :)

Step-by-step explanation:

Answer:

See attachment for graph

Step-by-step explanation:

Given

[tex]y = 2^x[/tex]

Required

Plot the graph

First, we list out possible values of x and y

When [tex]x = 0[/tex]:

[tex]y = 2^0 = 1[/tex]

When [tex]x= 1[/tex]:

[tex]y = 2^1 = 2[/tex]

When [tex]x =2[/tex]:

[tex]y = 2^2 = 4[/tex]

When [tex]x = 5[/tex]

[tex]y = 2^5 = 32[/tex]

So, we plot the graph by connecting the points of the above values.

See attachment for graph

Answer:

1/12 hope this help :)