Simplify (4x)². Rewrite the expression in the form k ⋅ xⁿ

Answer:

viscosity is the state of being thick, sticky, and semifluid in consistency, due to internal friction.

"cooling the fluid raises its viscosity"

a quantity expressing the magnitude of internal friction, as measured by the force per unit area resisting a flow in which parallel layers unit distance apart have unit speed relative to one another.

plural noun: viscosities

"silicone oils can be obtained with different viscosities"

Step-by-step explanation:

The viscosity of a fluid is a measure of its resistance to deformation at a given rate. For liquids, it corresponds to the informal concept of "thickness": for example, syrup has a higher viscosity than water. hope this helps you :)

Answer:

O An oil's resistance to flow at different temperatures

Step-by-step explanation:

Internal friction of a moving fluid .

Step-by-step explanation:

The formulae to find them are:

and mode= number of greatest frequency.

(note; f is frequency, N is number of data and x is x is the raw data)

hope it helps..

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean [tex]\bar x[/tex] =  371.08

standard deviation [tex]\sigma[/tex] = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = [tex]\dfrac{\sigma }{\sqrt{n}}[/tex]

Standard Error S.E = [tex]\dfrac{24.45 }{\sqrt{26}}[/tex]

Standard Error S.E = [tex]\dfrac{24.45 }{4.898979486}[/tex]

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  [tex]\approx[/tex] 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = [tex]\sigma \times \sqrt{1+ \dfrac{1}{n}}[/tex]

The standard error of the mean = [tex]24.45 \times \sqrt{1+ \dfrac{1}{26}}[/tex]

The standard error of the mean = [tex]24.45 \times \sqrt{1+0.03846153846}[/tex]

The standard error of the mean = [tex]24.45 \times \sqrt{1.03846153846}[/tex]

The standard error of the mean = [tex]24.45 \times 1.019049331[/tex]

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

[tex]\approx[/tex] 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

Answer:

15%

Step-by-step explanation:

To calculate the margin of error, we can adopt this formula

Margin of error = critical value* (standard deviation/sqrt of sample size)

Where critical value is 2.33, sd is 0.78 and sample size is150.

Thus, we have:

Margin of error = 2.33*(0.78/√150)

Margin of error = 2.33*(0.78/12.2474)

Margin of error =2.33*0.06369

Margin of error = 0.1484 which is a 15% margin of error

Answer:

50

Step-by-step explanation:

50 because of the 100 of 79 to 7

Answer:

B Kim rode 3 more miles per week than Eric rode.

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

[tex]p \propto \dfrac{1}{d}[/tex]

Introducing the constant of proportionality

[tex]p = \dfrac{k}{d}[/tex]

If 150 pounds is required for a distance of 10 inches from the object

[tex]150 = \dfrac{k}{10}\\\\k=1500[/tex]

Therefore, the relationship between p and d is:

[tex]p = \dfrac{1500}{d}[/tex]

When d=3 Inches

[tex]p = \dfrac{1500}{3}\\\implies p=500$ pounds[/tex]

The pressure applied when the distance is 3 inches is 500 pounds.

Answer

Step-by-step explanation:

Given,

r = 10

Let's create an equation,

[tex]3r = 10 + 5s[/tex]

plugging the value of r

[tex]3 \times 10 = 10 + 5s[/tex]

Multiply the numbers

[tex]30 = 10 + 5s[/tex]

Move 5s to L.H.S and change its sign

Similarly, Move 30 to R.H.S and change its sign.

[tex] - 5s = 10 - 30[/tex]

Calculate

[tex] - 5s = - 20[/tex]

The difference sign ( - ) should be cancelled on both sides

[tex]5s = 20[/tex]

Divide both sides of the equation by 5

[tex] \frac{5s}{2} = \frac{20}{5} [/tex]

Calculate

[tex]s = 4[/tex]

The value of s is 4.

Hope this helps..

Best regards!!

Answer:

A. 4 (on edgenuity)

Step-by-step explanation:

Answer:

Number:3.75

Equation:7 x-9=3(x+2)

Step-by-step explanation:

Let the number be x.

According to the question,

7 x-9=3(x+2)

7 x-9= 3 x+ 6

7 x- 3 x= 9+6

4 x= 15

x=15/4

x=3.75

If you verify the answer you will get,

11.25=11.25

Thank you!

Answer:

x=2 y=4

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

A tessellation refest to a shape that is repeated over and over again covering a plane without any gaps or overlaps. The statement is false given that regular tessellations use only one polygon. Semi-regular tessellations are created with more than one type of regular polygon.

Answer:

Step-by-step explanation:

Hello!

For the rectangle ABCD

AB= DC= 11

BC= AD= 2

Point E lies halfway between AB and CD

The shaded are forms two triangles, I'll refer to the upper triangle as "Triangle one" and the lower triangle will be "triangle 2"

The area of a triangle is calculated as

[tex]a= \frac{bh}{2}[/tex]

b= base

h= height

Triangle 1

b₁= AB= 11

[tex]h_1= \frac{BC}{2}= \frac{2}{2}= 1[/tex]

[tex]a_1= \frac{b_1h_1}{2}= \frac{11*1}{2}= 5.5[/tex]

Triangle 2

b₂= DC= 11

[tex]h_2= \frac{BC}{2}= \frac{2}{2} = 1[/tex]

[tex]a_2= \frac{b_2h_2}{2}= \frac{11*1}{2}= 5.5[/tex]

Now you add the areas of both triangles to get the area of the shaded region:

a₁ + a₂= 5.5 + 5.5= 11

Since point E is halfway to all sides of the rectangle, even tough it doesn't see so, the shaded area is equal to half the area of the rectangle:

area= bh= DC*AD= 11*2= 22

area/2= 22/12= 11

I hope this helps!

Answer:

[tex]\boxed{x = 15}[/tex]

Step-by-step explanation:

Let the number be x

Condition:

[tex]2x - \frac{2}{3} x = 20[/tex]

Multiplying 3 to both sides

=> 3(2x) - 2x = 3(20)

=> 6x - 2x = 60

=> 4x = 60

Dividing both sides by 4

=> x = 15

Answer:

15

Step-by-step explanation:

Let x be that number.

2/3 of x subtracted from twice of x is 20.

2x - 2/3x = 20

Solve for x.

Combine like terms.

4/3x = 20

Multiply both sides by 3/4

x = 60/4

x = 15

The number is 15.

Answer:

Largest possible length is 21 inches.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = [tex]l[/tex] inches and

Width = [tex]w[/tex] inches

As per given condition:

[tex]l = 2w+3[/tex] ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

[tex]P = 2 \times (Width + Length)[/tex]

Putting the given values and conditions as per equation (1):

[tex]60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch[/tex]

Putting in equation (1):

[tex]l = 2\times 9+3\\\Rightarrow l = 21\ inch[/tex]

So, the answer is:

Largest possible length is 21 inches.

Step-by-step explanation:

In the fourth quadrant, the equation of the unit circle is:

y = -√(1 − x²), 0 ≤ x ≤ 1

The x and y coordinates of the centroid are:

cₓ = (∫ x dA) / A = (∫ xy dx) / A

cᵧ = (∫ y dA) / A = (∫ ½ y² dx) / A

For a quarter circle in the fourth quadrant, A = -π/4.

Solving each integral:

∫₀¹ xy dx

= ∫₀¹ -x √(1 − x²) dx

= ½ ∫₀¹ -2x √(1 − x²) dx

If u = 1 − x², then du = -2x dx.

When x = 0, u = 1.  When x = 1, u = 0.

= ½ ∫₁⁰ √u du

= ½ ∫₁⁰ u^½ du

= ½ (⅔ u^³/₂) |₁⁰

= (⅓ u√u) |₁⁰

= 0 − ⅓

= -⅓

∫₀¹ ½ y² dx

= ½ ∫₀¹ (1 − x²) dx

= ½ (x − ⅓ x³) |₀¹

= ½ [(1 − ⅓) − (0 − 0)]

= ⅓

Therefore, the x and y coordinates of the centroid are:

cₓ = (-⅓) / (-π/4) = 4/(3π)

cᵧ = (⅓) / (-π/4) = -4/(3π)

Answer:

23+15i

Step-by-step explanation:

(-3+2i) (-3-7i)

multiply -3 w (-3+2i) and multiply -7i w (-3+2i)

9-6i+21i-14i^2

combine like terms

9+15i-14i^2

i squared is equal to -1 so

9+15i-(14x-1)

9+14+15i

23+15i

hope this helps :)

Answer:

15 pt

Step-by-step explanation:

to convert qt to pt you multiply by 2 so 7 and 1/2 times 2 is 15

Answer:

a. [tex] \frac{- 42,500}{(v + 60)(v - 40)} [/tex]

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

[tex] t = \frac{d}{r} [/tex]

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

[tex] t = \frac{d}{r} [/tex]

[tex] t = \frac{425}{v + 60} [/tex]

=>Flight time of the return flight:

[tex] t = \frac{425}{v - 40} [/tex]

=>Difference in flight times:

[tex] \frac{425}{v + 60} - \frac{425}{v - 40} [/tex]

[tex] \frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)} [/tex]

[tex] \frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)} [/tex]

[tex] \frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)} [/tex]

[tex] \frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)} [/tex]

[tex] \frac{- 42,500}{(v + 60)(v - 40)} [/tex]

The answer is 3,240

Explanation:

To calculate the total income tax, it is necessary to calculate what is the 15% of 8000, and 17% for the remaining money, which is 12.000 (20,000 - 8,000= 12,000). Considering the statement specifies the 15% is paid for the first 8,000 and from this, the 17% is paid. Now to know the percentages you can use a simple rule of three, by considering 8000 and 12000 as the 100%. The process is shown below:

1. Write the values

[tex]8000 = 100[/tex]

[tex]x = 15[/tex] (the percentage you want to know)

2. Use cross multiplication

[tex]x =\frac{8000 x 15 }{100}[/tex]

[tex]x = 1200[/tex]

This means for the first 8000 the money Rafael needs to pay is 1,200

Now, let's repeat the process for the remaining money (12,000)

[tex]12000 = 100\\\\[/tex]

[tex]x = 17[/tex]

[tex]x = \frac{12000 x 17}{100}[/tex]

[tex]x = 2040[/tex]

Finally, add the two values [tex]1200 + 2040 = 3240[/tex]

Answer:

The probability is  [tex]P(\= X > x ) = 0.78814[/tex]

Step-by-step explanation:

From the question we are given that

     The population  mean is  [tex]\mu = 149[/tex]

     The standard deviation is  [tex]\sigma = 14[/tex]

     The random number    [tex]x = 147.81[/tex]

      The sample  size is  [tex]n = 88[/tex]

The probability that  the sample mean would be greater than [tex]P(\= X > x ) = P( \frac{ \= x - \mu }{\sigma_{\= x} } > \frac{ x - \mu }{\sigma_{\= x} } )[/tex]

Generally the z- score of this normal distribution is mathematically represented as

       [tex]Z = \frac{ \= x - \mu }{\sigma_{\= x} }[/tex]

Now

        [tex]\sigma_{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]\sigma_{\= x } = \frac{14 }{\sqrt{88} }[/tex]

         [tex]\sigma_{\= x } = 1.492[/tex]

Which implies that

         [tex]P(\= X > x ) = P( Z > \frac{ 147.81 - 149 }{ 1.492} )[/tex]

        [tex]P(\= X > x ) = P( Z > -0.80 )[/tex]

Now from the z-table  the  probability is  found to be

        [tex]P(\= X > x ) = 0.78814[/tex]

13 since  i think it's when a single didget number has a 1 at the beginning. i might be wrong thoough

Answer:

y + 4 = 4/3(x - 6).

Step-by-step explanation:

The point-slope formula is shown below. We just need to find the slope.

(-4 - (-8)) / (6 - 3) = (-4 + 8) / 3 = 4 / 3

m = 4/3, y1 = -4, and x1 = 6.

y - (-4) = 4/3(x - 6)

y + 4 = 4/3(x - 6).

Hope this helps!

Answer: B

Step-by-step explanation:

Answer:B

Step-by-step explanation: I took the edge quiz and it was right.

Answer:

The answer is

Step-by-step explanation:

x² + 2x - 3 - 2x² + x + 4

Group like terms

That's

x² - 2x² + 2x + x - 3 + 4

Simplify

- x² + 3x + 1

when x = 3

We have

(-3)² + 3(3) + 1

9 + 9 + 1

18 + 1

19

Hope this helps you

Answer:

5/12

Step-by-step explanation:

Total number of marbles in the bag

6red+ 4blue + 14 yellow = 24 marbles

Not yellow marbles = 10 marbles

P ( not yellow ) = number of not yellow marbles / total marbles

                          =10/24

                          = 5/12

Answer:

5/12

Step-by-step explanation:

6 red marbles

4 blue marbles

14 yellow marbles

total marbles = 6 + 4 + 14 = 24 marbles

24 - 14 = 10 marbles

10 marbles are not yellow.

P(not yellow) = 10/24 = 5/12

Answer:

f^-1(x) = x + 5

Step-by-step explanation:

f(x) = x-5

y = x-5

Exchange x and y

x = y-5

Solve for y

x+5 = y-5+5

x+5 =y

The inverse is x+5

Answer:

Hey there!

Pythagorean Theorem:

[tex]a^2+b^2=c^2\\[/tex]

Let 6 be a, and 11 be b.

[tex]6^2+11^2=c^2\\[/tex]

[tex]36+121=c^2\\[/tex]

[tex]157=c^2[/tex]

[tex]\sqrt{157} =c[/tex]

Hope this helps :)

Answer:

[tex]12.529[/tex]

Step-by-step explanation:

[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {6}^{2} + {11}^{2} = {c}^{2} \\ 36 + 121 = {c}^{2} \\ 157 = {c}^{2} \\ \sqrt{157} = {c}^{2} \\ c = 12.529[/tex]

[tex]hope \: it \: helps \: < 3[/tex]

Answer:

26

Step-by-step explanation:

Given that:

At time, t=0, Billy puts 625 into an account paying 6% simple interest

At the end of year 2, George puts 400 into an account paying interest at a force of interest, 1/(6+t), for all t ≥ 2.

If both accounts continue to earn interest indefinitely at the levels given above, the amounts in both accounts will be equal at the end of year n. Calculate n.

In order to calculate n;

Let K constant to be the value of time for both accounts

At  time, t=0, the value of time K when Billy puts 625 into an account paying 6% simple interest is:

[tex]K = 625 \times (1+ 0.06 K)[/tex]

[tex]K = 625 +37.5 K[/tex]

At year end 2; George  amount of 400 will grow at a force interest, then the value of  [tex]K = 400 \times e^{\int\limits^2_k {\dfrac{1}{6+t}} \, dx }[/tex]

[tex]K =400 \times \dfrac{6+K}{6+2}[/tex]

[tex]K =400 \times \dfrac{6+K}{8}[/tex]

[tex]K =50 \times ({6+K})[/tex]

[tex]K =300+50K[/tex]

Therefore:

If K = K

Then:

625 + 37.5 = 300 +50 K

625-300 = 50 K - 37.5 K

325 = 12.5K

K = 325/12.5

K = 26

the amounts in both accounts  at the end of year n = K = 26

Answer:

20.8 hours

Step-by-step explanation:

2 3/5 = 2.6.The painter will take (2.6 × 8) = 20.8 hours to paint a wall.

Hope this helps and pls mark as brianliest :)

Answer:

20.8, 20 4/5, and 104/5