Answer:
d. The slope of the relationship between firstfloorsquarefootage and price is moresteep for homes near the beach than elsewhere in Tampa.
Step-by-step explanation:
In this regression model, we have a positive slope. This positive slope is indicative of an increase. So to interpret this slope, we would say that the slope of the relationship that exists between the two variables (price and firstfloorsquarefootage) is steeper for the homes that are closer to the beach compared to the ones that are elsewhere. Therefore option D is our answer.
how to solve 46 divide by 6 and change it to a multiplication equation
Answer:
46/6 is approximately 7.667.
To change it to a multiplication problem, I can do 46 = 6*7.667. The answer is not exact, just an estimated approximation.
You can also try to divide yourself.
A park has a triangular sandbox. Todd wants to create a smaller sandbox at his backyard having the same angles as the park sandbox.
What is the perimeter in feet of Todd’s sandbox?
Please answer ASAP this is due tomorrow
Answer:
227.08in^2
You want to find the surface area for this problem. SA=2lw+2lh+2hw
Step-by-step explanation:
L=2.5
W=7.4
H=9.6
SA=2lw+2lh+2hw
SA=2(2.5x7.4)+2(2.5x9.6)+2(9.6x7.4)
SA=37+142.08+48
SA=227.08in^2
What is the slope of the graph shown?
I need help on the griding for (1/2,2). Please explain. :(
What is the value of the digit 2 in the number 425,611?
Answer:
20,000 or 10,000
Step-by-step explanation:
The 2 is in the ten thousandth place, but the value is 20,000
Which of the following trigonometric ratios are correct?
9514 1404 393
Answer:
D, F
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with this. It reminds you ...
Sin = Opposite/Hypotenus
sin(40°) = x/b . . . . matches D
Cos = Adjacent/Hypotenuse
cos(40°) = a/b . . . . no match
Tan = Opposite/Adjacent
tan(40°) = x/a . . . . matches F
The question that is asked
Answer:
THE ANSWER IS B BECAUSE I AM BIG BRAIN
Step-by-step explanation:
Which of the following choices lists the values of the side longths of a triangle with 45-45-90 degree angles and a hypotonuso - 247? Need help
Answer:
D 12rad2 12rad2 24
Step-by-step explanation:
I will give 40 points to the person who has the awnser and work solved to all 5 questions
Answer:
4w+6h-h
4w+5h
7y+4y
11y
6x+3y+5x
11x+3y
5x+12d-2x+4d
3x+16d
3x^2+6y+5x^2+2x
8x^2+6y+2x
Let me know if this helps!
Answer:
A, D,and E
Step-by-step explanation:
During science class, groups measure out different volumes of vinegar. The line plot below shows the amount of vinegar used by 12 groups, rounded to the nearest 1/2 ml.
Answer: it should be 22 1/2 :)
On a later day, he asked the same group of 10 friends to throw a ball again and collected another set of data. The median of the second data set is 49 feet, and the IQR is 6 feet.
a. Did the 10 friends, as a group, perform better (or throw farther) in the second round compared to the first round?
(Worse or better)
b. Were the distances in the second data set more variable or less variable compared to those in the first round?
(More variable or less variable)
Answer:
a
Step-by-step explanation:
9. square
A =
s= 15 ft
Answer:
225 square feet
Step-by-step explanation:
If one side = 15 ft, and it's a square, you do 15 x 15 = 225 square feet
Hope that helps!
Which expression is equivalent to -2(9y-3)
a) -18y + 6 c) -18y -3
b) -18y - 6 d) 18y + 6
Answer:
A) - 18y + 6
Step-by-step explanation:
Distribute -2 to all terms within the parenthesis.
Note that:
When you multiply/divide:
Two positive terms, the result will be positive.
One negative and one positive term, the result will be negative.
Two negative terms, the result will be negative.
First, multiply -2 with 9y:
-2 * 9y = -18y
Next, multiply -2 with -3:
-2 * -3 = 6
-18y + 6, or A) is your answer.
~
An element with
mass 510 grams decays by 26.3% per minute. How much of the
element is remaining after 7 minutes, to the nearest 10th of a gram?
Answer:
60.2 grams is remaining after 7 minutes.
Step-by-step explanation:
Exponential equation for amount of substance:
The exponential equation for the amount of a substance is given by:
[tex]A(t) = A(0)(1-r)^t[/tex]
In which A(0) is the initial amount and r is the decay rate, as a decimal, and t is the time measure.
An element with mass 510 grams decays by 26.3% per minute.
This means that [tex]A(0) = 510, r = 0.263[/tex]
So
[tex]A(t) = A(0)(1-r)^t[/tex]
[tex]A(t) = 510(1-0.263)^t[/tex]
[tex]A(t) = 510(0.737)^t[/tex]
How much of the element is remaining after 7 minutes?
This is A(7). So
[tex]A(7) = 510(0.737)^7 = 60.2[/tex]
60.2 grams is remaining after 7 minutes.
<5 is a complement of <6 and m<5 = 59 degrees. Find m<6.
A pair of complementary angles, when added, equal 90. So if <5 is 59 degrees, what do you do to find <6? You subtract 59 with 90.
90-59=31
So <6 is 31 degrees.
---
hope it helps
Write an exponential function in the form y=ab^xy=ab
x
that goes through points (0, 18)(0,18) and (2, 1152)(2,1152).
Answer:
Step-by-step explanation:
let y=ab^x
x=0,y=18
18=ab^0=a
a=18
y=18b^x
when x=2,y=1152
[tex]1152=18b^{2}\\b^{2}=\frac{1152}{18}=64=8^2\\b=8\\so~y=18(8)^x[/tex]
Quadrilateral KLMN is dilated by a scale factor of 2/3 to form quadrilateral K'L'M'N'. What is the measure of side NK?
Answer:
NK = 42
Step-by-step explanation:
Scale factor of dilating KLMN to form K'L'M'N' = ⅔. This fraction implies there was a reduction of the original shape to form the new image/shape.
NK corresponds to N'K'
N'K' = 28
To get the NK, divide 28 by the scale factor.
28 ÷ ⅔ = 28*³/2 = 42
NK = 42
3.1 Simplify the following ratios:
3.1.1 500g: 3 kg
- 15
Answer:
1g:6g-15
Step-by-step explanation:
OMG PLEASE HELP PLEASE OMG HELP ME HELP PLZ!!!!!!!!!! HELPPPPPPPPPPPPp
17.5 mark brainlist plssssssssssssss
please help me understand and solve this
Step-by-step explanation:
just multiple them and you'll get the results and the results you got add them together
4 1/6 divided by 1 1/8
Answer:
3.7037037037
Step-by-step explanation:
Answer:
5 35/48
Step-by-step explanation:
25/6x11/8=275/48=5 35/48
A plane flies 545 kilometers with a bearing of 316° from Naples to Elgin (see figure). The plane then flies 680 kilometers from Elgin to Canton (Canton is due west of Naples). Find the bearing of the flight from Elgin to Canton. (Round to the nearest whole number.)
Answer:
235°Step-by-step explanation:
Use of low of sinesConsider triangle CENBearing of angle counted from zero to the vector of flightWe have
∠CNE = complementary with 44° ⇒ m∠CNE = 90° - 44° = 46°NE = b = 545 kmEC = a = 680 km∠ECN = xFind the measure of angle x:
sin 46° / a = sin x / bsin 46° / 680 = sin x / 545sin x = 545 sin 46 deg / 680x = arcsin (545 sin 46 deg / 680)x = 35° (rounded)Bearing of the flight from Elgin to Canton is:
270° - 35° = 235° as the vector is in the third quadrantAnswer:
235°
Step-by-step explanation:
Bearing: The angle (in degrees) measured clockwise from north.
The given scenario can be modeled as a triangle.
Given sides of the triangle:
a = 680 kmb = 545 kmAs due north is at a right angle to due west, the angle in the right corner of the triangle is:
⇒ 90° - 44° = 46°
Use the Sine Rule to find angle y marked on the attached diagram (the angle opposite side b).
Sine Rule
[tex]\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}[/tex]
(where A, B and C are the angles and a, b and c are the sides opposite the angles)
[tex]\implies \sf \dfrac{\sin 46^{\circ}}{680}=\dfrac{\sin y}{545}[/tex]
[tex]\implies \sf \sin y= \dfrac{545\sin 46^{\circ}}{680}[/tex]
[tex]\implies \sf y= \sin^{-1} \left(\dfrac{545\sin 46^{\circ}}{680}\right)[/tex]
[tex]\implies \sf y=35.20682806...^{\circ}[/tex]
Interior angles of a triangle sum to 180°
⇒ x° + y° + 46° = 180°
⇒ x° + 35.2068...° + 46° = 180°
⇒ x° = 98.79317194...°
Consecutive Interior Angles Theorem
When a straight line intersects two parallel straight lines, the consecutive interior angles formed sum to 180°. Therefore the angle between due north and side a of the triangle is:
⇒ 180° - 44° = 136°
To find the bearing of the flight from Elgin to Canton, find the angle labelled green on the attached diagram:
[tex]\implies \sf Bearing =136^{\circ}+ 98.79317194...^{\circ}[/tex]
[tex]\implies \sf Bearing = 234.7931719...^{\circ}[/tex]
[tex]\implies \sf Bearing = 235^{\circ}[/tex]
As bearings are usually given as a three-figure bearings, the bearing of the flight from Elgin to Canton is 235°.
Learn more about bearings here:
https://brainly.com/question/27928951
I don't understand this, please help
Answer:
∠2 = 150°, it is a supplementary angle to 30°
∠3 = 30°, it is an alternate angle to 30°
∠4 = 150°, it is a supplementary angle to 30°
∠5 = 30°, it is an alternate angle to 30°
∠6 = 150°, it is a supplementary angle to 30°
∠7 = 30°, it is an alternate angle to 30°
∠8 = 150°, it is a supplementary angle to 30°
You purchase a car for $20,000. It depreciates 30% each year. Which formula calculates how much your car will be worth in 10 years?
Answer:6722.8(sorry if i'm wrong)
Step-by-step explanation:
A survey is targeted at 12-year-old children. Whoch question are appropriate for the population? Select two options. 38 points. A. What year did you graduate from high school. B. What color was your first car. C. Where is your favorite vacation spot. D. What is the last book you read. E. Should taxes be increased to fund a new park?
Answer:
C & D
Step-by-step explanation:
please send pic of these i can give answer i think answer is b andc
Find the volume of this triangular pyramid
Answer:
63,616 ft³
Step-by-step explanation:
Volume of triangular pyramid = ⅓(base area * height of pyramid)
Base area = ½*b*h
b = 71 ft
h = 84 ft
Base area = ½*71*84 = 2,982 ft²
Height of pyramid = 64 ft
Plug in the values
Volume of triangular pyramid = ⅓(2,982*64)
= 63,616 ft³
What is 3000 times 0.22
Answer:
66
Step-by-step explanation:
Condense the log equation: 4 log x + log y - 5 log z
Answer:
The condensed log equation is: [tex]\log{\frac{x^4y}{z^5}}[/tex]
Step-by-step explanation:
We use these following logarithm properties to solve this question:
[tex]a\log{x} = \log{x^a}[/tex]
[tex]\log{a} + \log{b} = \log{ab}[/tex]
[tex]\log{a} - \log{b} = \log{\frac{a}{b}}[/tex]
In this question:
[tex]4\log{x} = \log{x^4}[/tex]
[tex]5\log{5} = \log{z^5}[/tex]
So
[tex]4\log{x} + \log{y} - 5\log{z}[/tex]
Becomes:
[tex]\log{x^4} + \log{y} - \log{z^5}[/tex]
Now applying the addition and subtraction properties, we have:
[tex]\log{\frac{x^4y}{z^5}}[/tex]
The condensed log equation is: [tex]\log{\frac{x^4y}{z^5}}[/tex]
Determine whether the following functions with their specified domain and range is injective, surjective, and bijective. If you determine that a given function with its specified domain and range is injective, surjective, or bijective, you do not need to prove it. On the other hand, if you determine that a given function with its specified domain and range fails to be injective, surjective, or bijective, you MUST provide a counter example.
a. f: R → R defined by f(x) = x^4 + 1.
b. f: R (1,0) defined by f(x) = x^4 + 1
c. f: R + R defined by f(x) = 2^x.
d. f: R (1,0) defined by f(x) = 2^x + 1.
Answer:
Step-by-step explanation:
[tex]\text{Given that:}[/tex]
[tex]f: \mathbb{R} \to \mathbb{R}[/tex] [tex]\text{which is de-fined by : } f(x) = x^4 + 1[/tex]
[tex]\mathbf{f \ is \ not \ injective}[/tex]
[tex]\mathtt{counterexample:}[/tex]
[tex]Assume \ x =1, y = -1 \\ \\ f(x) = 1^4 + 1= 2 \\ \\ f(y) = (-1)^4 + 1 = 2[/tex]
[tex]Hence \ f(x) = f(y) , but \ x \ne y[/tex]
[tex]Also;[/tex] [tex]f[/tex] [tex]\text{ is not surjective.}[/tex]
[tex]Take (y )= -10 \ \varepsilon \ \mathbb{R}[/tex]
[tex]\text{But there is no pre-image x such that}[/tex] [tex]f(x) = y[/tex]
[tex](b)[/tex]
[tex]f: \mathbb{R} \to (1, \infty) \ \ \text{which is de-fined as} \ f(x) = x^4 + 1 \\ \\ \text{f is injective and surjective and; thus bijective}[/tex]
[tex](c) \\ \\ f : \mathbb{R} \to \ \mathbb{R} \text{which can be de-fined as} \ f(x) = 2^x \\ \\ \text{f is injective and f is no surjective} \\ \\ \mathtt{counterexample:} \\ \\ Assume \ 2 \ \varepsilon \ \mathbb{R} \\ \\ whereas; 2^x = -2 \\ \text{which implies that }: \implies x = \dfrac{log_x(-2)}{log 2} = not \ de'fined[/tex]
[tex](d) f : \mathbb{R} \to (1 , \infty) , \ \text{which is de'fined by} \ \ f(x) = 2^x+1 \\ \\ \text{Thus; f is injective, surjective, and bijective}[/tex]