Select the equation that represents the graph of the line.


A
y=x−1
B
y=12x−1
C
y=12x+2
D
y=x+2

NEED HELP !!!!!!

Answer:

g = 21/4


Decimal form:

g = 5.25


Mixed Number:

5 1/4

Answer:

Diana has 14 dimes and 12 nickels

Step-by-step explanation:

Create a system of equations, where d is the number of dimes and n is the number of nickels:

d + n = 26

0.1d + 0.05n = 2

Solve by elimination by multiplying the top equation by -0.1:

-0.1d - 0.1n = -2.6

0.1d + 0.05n = 2

Add these together, then solve for n:

-0.05n = -0.6

n = 12

So, she has 12 nickels. To find the number of dimes, subtract 12 from 26, since there were 26 coins in total and we found that she had 12 nickels.

26 - 12

= 14

So, Diana has 14 dimes and 12 nickels

Answer:

Is there any answer choices? If not I would think its 5$

                                                                                      5$

                                                                                      4$

Step-by-step explanation:

Answer:

Step-by-step explanation:

B/c they are similar triangles we can set the sides ratio's equal to each other again

7x + 6 / 56  = 78 /91

does it kind of makes sense why I'm able to set those two ratio's equal?

it's the tough part of these problems... understanding why that works

the rest is just algebra.. My calc II professor always told us our algebra sucks. :D he was funny,

anyway, use your mad algebra skilz on the above equation

7x + 6 = 56(78/91)

7x + 6 = 4368 / 91

7x + 6 = 48

7x = 48 - 6

7x = 42

x = 6

:)

Answer:

-6

Step-by-step explanation:

2 x -3 = -6

1 positive and a negative integer multiplied will get a negative answer

The answer is -6 ! Good luck!

Answer:

the answer is 13.72

Step-by-step explanation:

tell me if its right

Answer:

700

Step-by-step explanation:

We have, 14% × x = 98

or, 14

100 × x = 98

Multiplying both sides by 100 and dividing both sides by 14,

we have x = 98 ×

100

14

x = 700

If you are using a calculator, simply enter 98×100÷14, which will give you the answer.

9514 1404 393

Answer:

  a) line: y = x - 11

  b) k = -9

  c) AP = BP = √74

Step-by-step explanation:

There are four (4) formulas that are needed for solving this problem.

  m = (y2 -y1)/(x2 -x1) . . . . . . slope of a line between points (x1, y1) and (x2, y2)

  M = ((x1 +x2)/2, (y1 +y2)/2) . . . . midpoint of the segment between the points

  y -y1 = m(x -x1) . . . . . point-slope equation of a line given point and slope

  d = √((x2 -x1)² +(y2 -y1)²) . . . . distance between two points

In addition, you need to know that perpendicular lines have opposite reciprocal slopes.

__

The perpendicular bisector of a segment between two points will be a line with a slope that is the opposite reciprocal of the slope of the segment. That line will go through the midpoint of the segment.

a) The slope of the segment between A(7, -2) and B(9, -4) is ...

  m = (-4-(-2))/(9-7) = -2/2 = -1

The midpoint of AB is ...

  M = ((7+9)/2, (-2-4)/2) = (8, -3)

The opposite reciprocal of the slope of AB is ...

  m = -1/(-1) = 1

Then the point-slope equation of the perpendicular bisector is the line with slope 1 through the point (8, -3):

  y -(-3) = 1(x -8)

  y = x -11

__

b) Point P on the line has x-value of 2, so the y-value will be ...

  k = 2 -11 = -9

Point P has coordinates (2, -9).

__

c) The length of segment AP is given by the distance formula:

  d = √((2 -7)² +(-9-(-2))²) = √((-5)² +(-7)²) = √74

The length of segment BP is likewise given by the distance formula:

  d = √((2 -9)² +(-9 -(-4))²) = √((-7)² +(-5)²) = √74

AP = √74 = BP   ⇒   AP ≅ BP

Answer:

$81.95

Step-by-step explanation:

0.07 * 55 = 3.85

(3.85 * 7) + 55

26.95 + 55

81.95

Answer:

B(-6,4)

Step-by-step explanation:

Basically, it's the same as reflecting it over the origin, so you transform the sign to its opposite and keep the points.

9514 1404 393

Answer:

  2

Step-by-step explanation:

You need the smallest positive integer for which f(x) > 0.

  f(1) = 3 -4 -3 -1 = -5

  f(2) = ((3·2 -4)2 -3)2 -1 = (4 -3)2 -1 = 1

x = 2 is the smallest integer for which f(x) > 0.

It has 2 solutions of a linear equation

Answer:

35/3x +200 = # of calories

Step-by-step explanation:

35/3 = calories burnt in 1 minute

x = minutes exercised for

add 200 to account for calories eaten

35/3x +200 = y

Answer:

C) 26π

Step-by-step explanation:

169π, radius = √169 = 13

diameter = 13 x 2 = 26

circumference = 26π

Answer:

[tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Chance of tales: [tex]\frac{1}{2}[/tex]

Chance of even number: [tex]\frac{3}{6}[/tex] or [tex]\frac{1}{2}[/tex]

Multiply: ([tex]\frac{1}{2}[/tex])([tex]\frac{1}{2}[/tex]) = [tex]\frac{1}{4}[/tex]

Answer:

Given:

Two trail maps:

Trail on the first map = 8 cm

Trail on the second map = 6 cm

Scale on first map = 1 cm : 2 km

A) What is the scale factor from the map to the actual trail?

For the first map, the scale factor is 1 cm: 2km. Therefore the actual trail is 8 centimeters * 2 kilometers = 16 km.

The scale factor of the second map is 16 km / 6 cm = 2.67 km : 1 cm

B) The length of the actual trail is 16 kilometers.

Step-by-step explanation:

In this exercise we have to use the knowledge of distance to calculate the value of the length, like this:

A) 1 cm

B) 16K

some of the information given in the statement was from:

Trail on the first map = 8 cmTrail on the second map = 6 cmScale on first map = 1 cm : 2 km

A) So to calculate the scale, you will need:

[tex]1 cm: 2km\\8 centimeters * 2 kilometers = 16 km\\16 km / 6 cm = 2.67 km : 1 cm[/tex]

B) So from the previous calculations we find the value of the length which is 16 kilometers.

See more about distance at brainly.com/question/989117

Answer:

Your question is in what base please?

Answer:

The amount of one-time payment should he make on his 40th birthday to pay off his pension plan is P32,880.77.

Step-by-step explanation:

Step 1: Calculation of present value on 3 months after his 60th birthday

The present value on 3 months after his 60th birthday can be calculated using the formula for calculating the present value of an ordinary annuity as follows:

PV60 = Q * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)

Where;

PV60 = present value on 3 months after his 60th birthday = ?

Q = quarterly claim = P10,000

r = quarterly interest rate = annual interest rate / 4 = 8% / 4 = 0.08 / 4 = 0.02

n = number of quarters = number of years * Number of quarters in a year = 5 * 4 = 20

Substitute the values into equation (1), we have:

PV60 =  P10,000 * ((1 - (1 / (1 + 0.02))^20) / 0.02)

PV60 = P10,000 * 16.3514333445971

PV60 = P163,514.33  

Step 2: Calculation of one-time payment on his 40th birthday

The one-time payment can be calculated using the formula the following formula:

PV = PV60 / (1 + r)^n ........................ (2)

Where;

PV = Present value or One-time payment = ?

PV60 = present value on 3 months after his 60th birthday = P163,514.33

r = quarterly interest rate = annual interest rate / 4 = 8% / 4 = 0.08 / 4 = 0.02

n = number of quarters from 40th to 3 months after his 60th birthday = (number of years * Number of quarters in a year) + One quarter = (20 * 4) + 1 = 81

Substitute the values into equation (2), we have:

PV = P163,514.33 / (1 + 0.02)^81 = P32,880.77

Therefore, the amount of one-time payment should he make on his 40th birthday to pay off his pension plan is P32,880.77.

Answer:

¹/25 mm²

Step-by-step explanation:

Area of a square = s²

Where s is the length of one side

using the diagram given,

s = ⅕ mm

Area = (⅕)²

Area of the square = ¹/25 mm²

Answer is a hope this helps

The system of equations will have no real solutions for c = -5, d = 4, i.e. option B.

What is system of equations?

System of equations is a finite set of equations for which common solutions are sought.

We have,

y = cx² + d     .....(i)

And,

2y = 10

⇒

y = 5     .....(ii)

So,

Now,

Comparing equation (i) and (ii),

We get,

cx² + d = 5

Now,

According to the question,

For,

c = -6, and d = 6

i.e.

cx² + d = 5

-6x² +6 = 5

We get,

-6x² = -1

i.e. [tex]x^2 = \frac{1}{6}[/tex]

That means equation have real solution.

Now,

For,

c = -5, and d = 4

i.e.

cx² + d = 5

-5x² + 4 = 5

We get,

-5x² = 1

i.e. [tex]x^2 = \frac{1}{-5}[/tex]

So, For these values of c and d, equation will not have any real solution, because square root can not be negative.

Hence, we can say that the system of equations will have no real solutions for c = -5, d = 4, i.e. option B.

To know more about system of equations click here

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Question:

Analyze the following budget, with an income of $600, to determine how much can be spent on food for the month.

Cell Phone $65

Food $___

Entertainment $95

College Savings $200

Car Expenses - Gas, Insurance $160

Answer:

[tex]Food = \$80[/tex]

Step-by-step explanation:

Given

[tex]Income = \$600[/tex]

Required

How much should be spent on food

This is calculated as:

[tex]Income = Food + Other\ budgets[/tex]

Where:

[tex]Other\ budgets = Phone + Ent + College + Car, Gas[/tex]

[tex]Other\ budgets = \$65 + \$95 + \$200 + \$160[/tex]

[tex]Other\ budgets = \$520[/tex]

So, we have:

[tex]\$600 = Food + \$520[/tex]

[tex]Food = \$600 - \$520[/tex]

[tex]Food = \$80[/tex]

Answer:

C $80 can be spent on food.

Answer:

D.324

Step-by-step explanation:

Answer:

D. 324 Sq in

Step-by-step explanation:

Painted area = area of rectangle + Area of square + Area of triangle

[tex] = 60 \times 4 + {8}^{2} + \frac{1}{2} \times 8 \times 5 \\ \\ = 240 + 64 + 20 \\ \\ = 324 \: {in}^{2} [/tex]

Answer: B. t=2

Step-by-step explanation:

If we implement t=2 into the function h=32(2)-16(2)^2 we get the height of 0 (Ground level).

Solve for h by simplifying both sides of the equation, then isolating the variable.

Hope this helps! :)

The object will hit the ground in 2 seconds.

What is height?

The vertical distance, either between the top and bottom of something or between a base and something above it, is considered as the height of an object.

Given that, An object is launched straight upward from ground level with an initial velocity of 32 feet per second. The formula h = 32t-16t² gives its height, h, in feet after t seconds.

When the object is hitting the ground, its height will be zero,

Therefore, put h = 0 in the equation,

0 = 32t-16t²

16t² = 32t

16t = 32

t = 2

Hence, the object will hit the ground in 2 seconds.

For more references on height, click;

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Answer:

The United States of America mostly and maybe Canada

Answer:

Step-by-step explanation:

[tex]\text{Given that:}[/tex]

[tex]y = 1+ sec(x) \ \ y =3[/tex]

[tex]\text{we draw the graph and the curves intersect at:}[/tex]

[tex]x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}[/tex]

[tex]\text{Applying washer method;}[/tex]

[tex]f(x) _{outer} - g(x) _{inner} --- (1)[/tex]

[tex]V= \int ^b_a A(x) \ dx --- (2)[/tex]

[tex]\text{outer radius = 3 - 1 = 2}[/tex]

[tex]\text{inner radius =}[/tex] [tex]( 1 + sec(x) ) - 1 = sec (x)[/tex]

[tex]A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)[/tex]

[tex]\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx[/tex]

[tex]V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx[/tex]

[tex]V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx[/tex]

[tex]V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx[/tex]

[tex]V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}[/tex]

[tex]V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )[/tex]

[tex]\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}[/tex]

Answer:

Quadratic and Trinomial

Step-by-step explanation:

It has a degree of 2, making it a quadratic. It has 3 terms, so it's a trinomial.

Answer:

3.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Does Daniela Works every day?

Do Daniela Work every day?

Does Daniela Work every day?

Did Daniela Work every day?

4.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Margarita don't brushes her car

Margarita doesn't brush her car

Margarita doesn't brushes her car

Margarita didn´t brush her car

5.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Do Camilo and Diana dances in the class?

Do Camilo and Diana dance in the class

Does Camilo and Diana dance in the class?

Do Camilo and Diana dance in the class?

6.LOOK AND CHOOSE THE CORRECT SENTENCES

(1 Punto)

You don't read a book

You don't reads a book

You doesn't read a book

7.LOOK AND CHOOSE THE CORRECT SENTENCES  

INTERROGATIVE  

____ he ___ better than you?

(1 Punto)

Does- plays

Does- play

Do- play

Do . plays

8.LOOK AND CHOOSE THE CORRECT SENTENCES  

NEGATIVE

It  ___ snow in summer.

(1 Punto)

doesn't

don't

9.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

My cousin _____ English very well.

(1 Punto)

Speak

Speaking

Speaks

10.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

We _____  our bikes

(1 Punto)

Wash

Washes

Washing

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Step-by-step explanation:

Answer:

340.34

Step-by-step explanation:

Answer:

(3.14) (rxr) (h) dived by 3

3.14 x 5x5 x 13

3.14 x 25 x 13

= 1,020.5 divided by 3

= 340.16

Answer:

[tex]\displaystyle f'(1) = \frac{3}{2}[/tex]

[tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra II

Exponential Rule [Rewrite]:                                                                            [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]:                                                                   [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Step-by-step explanation:

Step 1: Define

f(x) = x√x

f'(1) is x = 1 for 1st derivative

f''(1) is x = 1 for 2nd derivative

Step 2: Differentiate

[1st Derivative] Product Rule:                                                                       [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[\sqrt{x}][/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[x^{\frac{1}{2}}][/tex][1st Derivative] Basic Power Rule:                                                                 [tex]\displaystyle f'(x) = (1 \cdot x^{1 - 1})\sqrt{x} + x(\frac{1}{2}x^{\frac{1}{2}-1})[/tex][1st Derivative] Simply Exponents:                                                               [tex]\displaystyle f'(x) = (1 \cdot x^0)\sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Simplify:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Rewrite [Exponential Rule - Rewrite]:                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2x^{\frac{1}{2}}})[/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2\sqrt{x}})[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + \frac{x}{2\sqrt{x}}[/tex][2nd Derivative] Rewrite [Exponential Rule - Root Rewrite]:                     [tex]\displaystyle f'(x) = x^{\frac{1}{2}} + \frac{x}{2x^{\frac{1}{2}}}[/tex][2nd Derivative] Basic Power Rule/Quotient Rule [Derivative Property]: [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{(2x^{\frac{1}{2}})^2}[/tex][2nd Derivative] Simplify/Evaluate Exponents:                                           [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{-1}{2}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Basic Power Rule:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^{1 - 1})(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{1}{2} - 1})}{4x}[/tex][2nd Derivative] Simply Exponents:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^0)(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{x^{\frac{1}{2}}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - \frac{x}{x^{\frac{1}{2}}}}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{x^{\frac{1}{2}}}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule  - Root Rewrite]:                     [tex]\displaystyle f''(x) = \frac{1}{2\sqrt{x}} + \frac{\sqrt{x}}{4x}[/tex]

Step 3: Evaluate

[1st Derivative] Substitute in x:                                                                     [tex]\displaystyle f'(1) = \sqrt{1} + \frac{1}{2\sqrt{1}}[/tex][1st Derivative] Evaluate Roots:                                                                     [tex]\displaystyle f'(1) = 1 + \frac{1}{2(1)}[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(1) = 1 + \frac{1}{2}[/tex][1st Derivative] Add:                                                                                       [tex]\displaystyle f'(1) = \frac{3}{2}[/tex][2nd Derivative] Substitute in x:                                                                   [tex]\displaystyle f''(1) = \frac{1}{2\sqrt{1}} + \frac{\sqrt{1}}{4(1)}[/tex][2nd Derivative] Evaluate Roots:                                                                 [tex]\displaystyle f''(1) = \frac{1}{2(1)} + \frac{1}{4(1)}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(1) = \frac{1}{2} + \frac{1}{4}[/tex][2nd Derivative] Add:                                                                                     [tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

Answer:

(3x+4b)(a-2y)

Step-by-step explanation:

(3ax-6xy)+(8by-4ab)

3x(a-2y) -4b(-2y+a)

(3x+4b) (a-2y)

Answer:

(a−2y)(3x−4b)

Step-by-step explanation:

3ax−6xy+8by−4ab

⇒3ax−4ab−6xy+8by

⇒a(3x−4b)−2y(3x−4b)

⇒(a−2y)(3x−4b)

Hope it is helpful...

Answer: printer cost > Keyboard cost ($40)

Step-by-step explanation:

Answer:

k = p - 40

Step-by-step explanation:

the word "is" is the same as equal so k =.... $40 less than p which could be written as p - 40 therefore k = p - 40