Select the correct answer.
Which theory was first proposed by Albert Einstein?
OA. the theory of special relativity
O B. the theory of universal gravitation
c. the theory of inertia
OD. the theory of radioactivity

If you drag a bag across floor, you are experiencing a friction force

if you throw a paper or feather up, it floats side ways slowly. It is called air Resistance.

if you push or pull a Door, it is Normal force.

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Answer:

mars, reason why is because they both are diff from the size

Explanation:

Answer:

You could try finding a familiar peer to join the activity with your child. Or ask your child who their friends are at school, or what they look for in a friend at school.

Answer:

Let the parents their Children to play outside

Explanation:

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Answer: B. Mechanical energy

Explanation: "Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position)."

"Potential and kinetic energy of an object as it is stored and moved. Examples of MECHANICAL ENERGY- roller coasters, hydraulic lift, bow and arrow, and helicopters. Helicopters, cars, roller coasters, all moving objects that are being acted on by a force."

Incorrect options: A. Thermal energy and B. Electromagnetic energy. (explanation on both below)

"Thermal energy (also called heat energy) is produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. The energy that comes from the temperature of the heated substance is called thermal energy."

"Electromagnetic radiation, in classical physics, the flow of energy at the universal speed of light through free space or through a material medium in the form of the electric and magnetic fields that make up electromagnetic waves such as radio waves, visible light, and gamma rays."

Answer:

Electromanetic

Explanation:ESPERO TE AYUDE

Answer:

Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt.

Explanation:

Solution :

Let [tex]$m_1=m_2=4$[/tex] kg

[tex]$u_1 = 5$[/tex] m/s

Let [tex]$v_1$[/tex] and [tex]$v_2$[/tex] are the speeds of the disk [tex]$m_1$[/tex] and [tex]$m_2$[/tex]  after the collision.

So applying conservation of momentum in the y-direction,

[tex]$0=m_1 .v_1_y -m_2 .v_2_y $[/tex]

[tex]$v_1_y = v_2_y$[/tex]

[tex]$v_1 . \sin 60=v_2. \sin 30$[/tex]

[tex]$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$[/tex]

[tex]$v_2=1.732 \times v_1$[/tex]

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

[tex]$m_1.u_1=m_1.v_1_x+m_2.v_2_x$[/tex]

[tex]$u_1=v_1_x+v_2_x$[/tex]

[tex]$5=v_1. \cos 60 + v_2 . \cos 30$[/tex]

[tex]$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$[/tex]

[tex]$v_1 = 2.50$[/tex] m/s

So, [tex]$v_2 = 1.732 \times 2.5$[/tex]

          = 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

It's value in ft/s² is g = 32.174 ft/s²

Thus;

Weight of car = 1120 × 32.174

Weight of car = 36034.88 lb.ft/s²

Answer:

The right approach is "1479°C".

Explanation:

The given values are:

Mass of iron piece,

[tex]m_p=42 \ kg[/tex]

Mass of iron bucket,

[tex]m_I=5 \ kg[/tex]

Mass of water,

[tex]m_w=10 \ kg[/tex]

Iron's specific heat,

[tex]C_I=470 \ J/Kg^{\circ}C[/tex]

Water's specific heat,

[tex]C_w=4186 \ J/Kg^{\circ}C[/tex]

Initial temperature,

[tex]t_I=23^{\circ}C[/tex]

Final equilibrium temperature,

[tex]T=150^{\circ}C[/tex]

Latent heat,

[tex]L_v=2260\times 10^3 \ J/Kg[/tex]

As we know,

The heat lost by the glowing piece of iron will be equal to the heat gain by the iron bucket as well as water, then

⇒ [tex]m_IC_I \Delta T=m_wC_w(100-23)+m_wL_v+m_bC_I(150-23)[/tex]

On substituting the given values, we get

⇒ [tex]42\times 420\times \Delta T=10\times 4186(100-23)+10(2260\times 10^3)+5\times 420(150-23)[/tex]

⇒ [tex]17640 \Delta T=3.22\times 10^6+2.26\times 10^7+2.667\times 10^5[/tex]

⇒          [tex]\Delta T=\frac{2.60867\times 10^7}{17640}[/tex]

⇒          [tex]\Delta T=1479^{\circ}C[/tex]

Answer:

E₀ = 2.0*10⁻¹¹ J = 0.2 pJ

Ef = 3.0*10⁻¹¹ J = 0.3 pJ

Explanation:

      [tex]E = \frac{1}{2} * C * V^{2} (1)[/tex]

       [tex]C = \frac{\epsilon_{o}*A}{d} (2)[/tex]

       [tex]E_{o} = \frac{1}{2} * C_{o} * V_{o} ^{2} = \frac{1}{2} * 1.77*10^{-13}F*(1.5V)^{2} = 0.2 pJ (6)[/tex]

       [tex]E_{f} = \frac{1}{2} * C_{f} * V_{f} ^{2} = \frac{1}{2} * 1.18*10^{-13}F*(2.25V)^{2} = 0.3 pJ (9)[/tex]

Answer:

1) Linear motion

2) Rotational motion

3) Rotational Motion

4) Random Motion ( The ball can be rolling in any direction)

5) Linear motion

The types of motion in each activity include the following:

This involves an object or a body changing position over time. There are

different types of motion with different examples as can be seen above in

this scenario.

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Answer:

trur

Explanation:

gvidttcyhjddgdhjfjdjsjs

Answer:

I'm not sure but I think it's 4.5 v

Answer:

the nephew

Explanation:

because we need to First find the trails that is on top of all the others in order to find who was the last to leave, since the person that was last to leave would most likely step on another person's trail that has been theirs before them.

by looking at this picture I noticed that the butler's footprint was the latest one but the dogs footprint steps over it therefore making it the last to leave, and the person who owns a dog is her nephew so therefore the nephew is the one that stole the butterfly trophy.

The breeze/wind moves from the land to the sea. This statement is NOT correct about sea breezes.

Local wind patterns known as sea breezes flow from the sea to land during the day. When there is no strong large-scale wind system and it is very hot or very cold during the day or at night, sea breezes and land breezes alternate along the coasts of large lakes or oceans.

Because the sea breeze's surface flow ends over land, an area of low-level air convergence is created. Locally, this convergence frequently causes air to rise, which promotes the formation of clouds. Showers over land in the afternoon may result from such clouds.

Hence, the sea  breeze/wind moves from the land to the sea. This statement is NOT correct about sea breezes.

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Answer:

Explanation:

a) See the attached file for diagram . The two triangles are ABC and DEC .

b )

Angle of incidence = i

Tan i = ( 309 - 227 ) / 105

= 82 / 105 = .78

i = 38°

c )

Sin i / sinr = 1 / μ where μ is refractive index of water .

Sin i / sinr = 1 / μ = 1 / 1.33

sin 38 / sinr = .7518

.6156 / sinr = .7518

sinr = .6156 / .7518

.819

r = 55°

d )

angle  the refracted beam makes with the horizontal = 90 - 55 = 35°

e )

h / 227 = Tan 35

h = 227 x Tan 35

= 159 m

Height required = 159 m .

Answer:

Volume of water displaced = 450 - 375 = 75 ml

Vr = volume of rock = 75 ml

Wr = 9.22 - 7.60 = 1.62 N  weight of 75 ml of rock

Density of rock = 1.62 N / 75 ml = .0216 N / ml

Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml

Density of rock / density of water = .0216 / .0098 = 2.20

The specific gravity of the rock in the given water volume is 0.2.

The given parameters;

The specific gravity of the rock is calculated as follows;

[tex]S.G = \frac{weight \ in \ air}{Weight \ in \ water} \\\\S.G = \frac{450 - 375}{375} \\\\S.G = 0.2[/tex]

Thus, the specific gravity of the rock in the given water volume is 0.2.

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Answer:

is that youuuuuuu? fine.

Answer:

when water hits a metal surface it alongside oxygen have a chemical reaction making Hydrogenated Iron Oxide

Explanation:

what i remember from 7th grade

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2[/tex]

Let d be the breaking distance. It can be calculated using third equation of motion as :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m[/tex]

So, the required distance covered by the car is 44.64 m.

Answer:

The answer is option D. +f

Option D represents a concave lens. There are two types of lenses, one is a concave lens while the other is the convex lens.

A concave lens deviates a direct beam from the source into a reduced form.  At minimum, one interior face of concave lenses is curved.

Because it is curved round inwards at the center and bulges outwards through the edges, causing the light to diverge, a concave lens is also known as a diverging lens.

It forms an upright , virtual picture both real and virtual pictures are formed from the concave lens.

The image formed from the positive side of the focus of the lens.+f shows the positive side of the focus of the lens.f is the focal length.

Hence, option D represents a concave lens

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Considering both boxes as one body, it would have a total mass of 4.0 kg. By Newton's second law, the 32 N force applies an acceleration a such that

∑ F = 32 N = (4.0 kg) a   →   a = 8.0 m/s²

and both boxes share this acceleration. (There is no friction, so the given force is the only one involved in the direction of the boxes' motion.)

Now consider just the smaller box. It is feeling the effect of the 32 N push in one direction and, as it comes into contact with the larger box, a normal force that points in the opposite direction. Let n be the magnitude of this normal force; this is what you want to find. By Newton's second law,

∑ F = 32 N - n = (1.0 kg) (8.0 m/s²)

n = 32 N - 8.0 N

n = 24 N

Just to make sure that this is consistent: by Newton's third law, the larger box feels the same force but pointing in the opposite direction. On the smaller box, n opposes the pushing force, so points backward. So from the larger box's perspective, n acts on it in the forward direction. This is the only force acting on the larger box, so Newton's second law gives

∑ F = 24 N = (3.0 kg) (8.0 m/s²)

Answer:

3333.3 ohm

Explanation:

V=IR so R =V/I (in Ampere) so convert 3.6 mA to 3.6*10^-3 A

so R =12/3.6*10^-3 =3333.3

Answer:

The recipe for a hurricane is a combination of warm, humid wind over tropical waters. The temperature of tropical waters must be at least 80 degrees F for up to 165 feet below the ocean’s surface. As this warm water meets the wind that blows west from Africa across the ocean, it causes the water to vaporize. The water vapor then rises into the atmosphere, where it cools and liquefies.

Explanation:

I hope this helps

Answer:d

Explanation:

Given

Initially, the ice cube is floating over the water

When the cube is pressed to touch the bottom, it is submerged fully

Therefore more buoyant force is acting on it

At first, a part of the volume is submerged in the water, so the buoyant force is less, but as the entire cube is immersed in the water, the buoyant force increases.

Answer:

vavg = 0.37 m/s

Explanation:

       [tex]v_{avg} = \frac{\Delta x}{\Delta t} (1)[/tex]

       [tex]t_{1} =\frac{x_{1}}{v_{1} } = \frac{3.0m}{0.24m/s} = 12.5 s (2)[/tex]

       [tex]\Delta t = t_{1} + \frac{t_{1} }{2} = 12.5 s + 6.25 s = 18.75 s (3)[/tex]

       [tex]v_{avg} = \frac{\Delta x}{\Delta t} = \frac{7.0m}{18.75m} = 0.37 m/s (4)[/tex]

Answer:

True.  it is restricted to the orbits of certain radii around the nucleus.

The position can change, but it must be in one of these orbits

Explanation:

In this exercise some affirmations are given and you must select which ones are correct, for this we review the Bohr atomic model that has the following postulates:

* the orbits are circular

* Only certain orbits are stable, stationary state

* the radiation emitted is the difference in energy between two stable orbits

* the size of the orbit is given by the quantization of the angular momentum

             L = n [tex]\hbar[/tex]

When reviewing the different statements, the correct one is:

* it is restricted to the orbits of certain radii around the nucleus.

The position can change, but it must be in one of these orbits

Answer: [tex]0.985\times 10^{-4}\ T[/tex]

Explanation:

Given

Electron is accelerated 3.5 kV potential difference

Distance between plates d=29 mm

The potential difference between plates is V=100 V

here, the kinetic energy of an electron is acquired through a potential difference of 3.5 kV

[tex]\Rightarrow \dfrac{1}{2}m_ev^2=e\times 3.5\times 10^3\\\\\Rightarrow v=\sqrt{\dfrac{2\times 3.5\times 10^3e}{m_e}}=\sqrt{\dfrac{7\times 10^3\times 1.6\times 10^{-19}}{9.1\times 10^{-31}}}\\\\\Rightarrow v=\sqrt{1.23\times 10^{15}}=3.5\times 10^7\ m/s[/tex]

To move in a straight line Force due to magnetic field must be balanced by force due to charge

[tex]\Rightarrow F_B=F_q\\\\\Rightarrow evB=eE\\\\\Rightarrow B=\dfrac{E}{v}\\\\\Rightarrow B=\dfrac{\frac{V}{d}}{3.5\times 10^7}=\dfrac{\frac{100}{0.029}}{3.5\times 10^7}\\\\\Rightarrow B=\dfrac{3.448\times 10^3}{3.5\times 10^7}=0.985\times 10^{-4}\ T[/tex]