Select all examples that apply as a physical changes in properties (please help)

Select All Examples That Apply As A Physical Changes In Properties (please Help)

Answers

Answer 1
All except burning gasoline

Related Questions

A 400-gram sample of iron, initially at 21 0Cis heated to 65 0C. Determine the energy attained (in Joules) by the iron sample if the specific heat capacity of iron is 0.11 cal/g0C

Answers

Answer:

Q = 8100 J.

Explanation:

Hello there!

In this case, according to the given information, we can infer this is a question about calorimetry, and we can use the general heat equation to solve this one:

[tex]Q=mC(T_2-T_1)[/tex]

Thus, we plug in the given mass, specific heat and temperatures to obtain the energy involved in this heating process:

[tex]Q=400g*0.11\frac{cal}{g\°C} (65\°C-21\°C)\\\\Q=1936cal[/tex]

Which converted to Joules turns out to be:

[tex]Q=1936cal*\frac{4.184J}{1cal} \\\\Q=8100J[/tex]

Regards!

How are people responsible for marine debris

Answers

Answer:

Marine debris comes from many different sources and enters the ocean in many ways. Intentional littering and dumping are a big cause of marine debris. ... Those rivers and streams can eventually carry the trash to the ocean. Improper or careless waste disposal is another big cause.

hope this helps

have a good day :)

Explanation:

How many atoms of Neon are in 65.0 L of Neon gas?

Answers

Answer:

65.0 g NH3 x

mol NH3

17.04 g NH3

x  

6.02x1023 NH3 molecules

mol NH3

= 2.30x1024 NH3 molecules

(have uh good day)

Answer:

mole of Neon = 65L/22.4L

=2.901moles of Neon

1 mole of a substance contains 6.022x10^23atoms

So 2.901moles will contains

2.901 x 6.022x10^23atoms

=1.747 x 10^24atoms

Is this an alpha or beta decay?

Answers

Answer:

alpha  decay

Explanation:

alpha decay

uranium decays into a alpha decay

A dead tree is not an important part of an ecosystem. T or F

Answers

false. a dead tree is still important part of our ecosystem.

Balance this chemical equation

Ca(OH)2 + HCl ---> CaCl2 + H2O​

Answers

Answer:

The balance equation of Ca(OH)2 + HCl ---> CaCl2 + H2O​

is

Ca(OH)2(s) + 2HCl(aq) ---> CaCl2(aq) +2H2O​ (l) (balanced equation)

How do fossils evidence help you put the landmasses together

Answers

Explanation:

Alfred wegener collected pieces of evidence to support his theory having to do with geological "fit" and fossil evidence. This means that these extensive oceans between these land masses act as a type of barrier for fossil transfer.

3. Which model has properties most similar to chlorine?
Model A
Model B
Model C
Model D

Answers

Answer:

bnsjsbbakakaisbsbwnsjznss

Explanation:

cnsjzjsnsnsjs ssnsnsnzksmnznnzna

you can test carbon dioxide gas with​

Answers

A standard test for the presence of carbon dioxide is its reaction with limewater (a saturated water solution of calcium hydroxide) to form a milky-white precipitate of calcium hydroxide. Carbon dioxide occurs in nature both free and in combination (e.g., in carbonates).

Answer:

you can test carbon dioxide gas with calcium hydroxide

hope this is what you're looking for

stay safe and have a nice day

✌◕ ◡ ◕✌

What is the percent by volume of 12.5 mL of ethanol in 250 mL of water?
3%
5%
4%
6%

Answers

The answer for your question is 5%

The 500 cubic centimeter of 0.250 M Na2SO4 solution,
added to an aqueous solution of 15.00 grams of barium
chloride, resulted in the formation of a white precipitate of
barium sulfate. How many moles and how many grams of
barium sulfate are formed, respectively?

Answers

Answer:

0.072 moles, 16.776g.

Explanation:

The reaction of Na2SO4 and BaCl2 occurs as follows:

Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2NaCl(aq)

To solve this question we must find the moles of each reactant. As the reaction is 1:1, the reactant with the low number of moles is limiting reactant. The moles of limiting reactant = Moles BaSO4. The mass can be obtained with the molar mass of BaSO4 -233.38g/mol-

Moles Na2SO4:

500cm³ = 0.500L * (0.250mol / L) = 0.125 moles

Moles BaCl2 -Molar mass: 208.23g/mol-

15.00g * (1mol / 208.23g) = 0.072 moles

The moles of BaSO4 are 0.072 moles and its mass is:

0.072 moles * (233.38g / mol) = 16.8g ≈ 16.776g

EMERGENCY HELP ME OUT

Answers

Answer:

D, The volume will be multiplied by a factor of 4

Explanation:

First find the height

V = π(r^2)h

Plug in what we know

83 = π(3^2)h

83 = π(9)h

83  = (9π)h

9[tex]\pi[/tex] = 28.27

83/28.27 = (28.27)h/28.27

h = 2.94

Then find the volume of the new can by doubling the radius

3 x 2 = 6

r = 6

V = π(r^2)h

V = π(6^2)2.94

V = π(105.84)

V =332.51

For the first one, they rounded to the nearest whole #, so let's do the same.

V = 333

Then divide 333 by 83 to get 4

Therefore, the volume will be multiplied by a factor of 4

a cell was taken from dolly the sheep and used to make a geneticly identical copy of her the copy lived to be 6 years old what is that called?

Answers

Explanation:

dolly was cloned I guess

It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?

Answers

Answer:

5/8 M

Explanation:

NaOH + HCl ====> NaCl + H2O

in 25 mL of 0.5M acid, we have 1/80 Mol of HCl

it mean we must have 1/80 Mol of NaOH.

20 mL = 1/50 L

(1/80)Mol / (1/50)L = 5/8 M

10 points. Please help.


A balloon can hold 10 liters of a gas. If you blow up this balloon with 2 moles of oxygen gas at a pressure of 0.76 atmospheres, what is the temperature of the balloon? Pay attention to the unit of pressure used.

Answers

Answer:

The temperature of the balloon is 46.34 K.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

P= 0.76 atmV= 10 Ln= 2 molesR= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]T= ?

Replacing:

0.76 atm* 10 L= 2 moles* 0.082 [tex]\frac{atm*L}{mol*K}[/tex] *T

Solving:

[tex]T=\frac{0.76 atm* 10 L}{2 moles* 0.082\frac{atm*L}{mol*K}}[/tex]

T= 46.34 K

The temperature of the balloon is 46.34 K.

What is SnO2 compound name

Answers

Tin oxide if that helps by any chance

Need help ASAP ( will give 50 points)
Select the correct answer. Which galaxies have light smoothly spread across the
galaxy? A. spiral galaxy B. irregular galaxy C. lenticular galaxy D. elliptical galaxy

Answers

Answer:

Your answer would be D, Hope this helps.

in order to balance the reaction, what number needs to go in front of F(2)?​

Answers

Answer:

NA + F2 = NAF - Chemical Equation Balancer.

2 Na + F 2 → 2 NaF

Na is a reducing agent, F 2 is an oxidizing agent. ; Pale-yellow to greenish gas with a pungent, irritating odor.

based on the graph below, which statement

Answers

Answer:

4. Atmospheric pressure decreases as altitude increases.

Explanation:

hope this helps and is right. p.s i really need brainliest :)

What is the correct name for the chemical formula N408?

Answers

Answer:

molar mass (molar weight)

Explanation:

PLEASE ANSWER QUICKLY!! LOTS OF POINTS!❤

Phosphorous has two common isotopes, phosphorous - 30 and phosphorous - 31. Using the periodic table what can you infer about these two isotopes?​

Answers

Explanation:

The idea here is that you need to use the Periodic Table of elements to find the mass number of the most common isotope of phosphorus, P.

How many significant figures are in the measurement 1.3000 meters

Answers

Answer:

5

Explanation:

mark me brainliest!

When temperature drops, (for example from 20 degrees celsius to 10 degrees celsius)

a.) energy increases

b.) particles move slower

c.) particles collide more often

d.) pressure increases

Answers

When temperature drops the particles move slower because temperature effects the motion of atoms or molecules

6 a 100 sample of Au - 198 Au 198 be? Decays to 3.125 g in 13.5 days, what would the half-life of au198 be?

Answers

Answer:

Half-life = 2.7 days

Explanation:

The radioactive decay of an isotope follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] could be taken as the amount of A after t time, k is decay constant, [A]₀ initial amount of A.

Replacing to solve k:

Ln[3.125g] = -k*13.5days + ln[100g]

-3.465736 = -k*13.5days

k = 0.2567days⁻¹

Half-life is:

half-life = ln2 / k

Half-life = 2.7 days

The saturation point for a solution is 50.0 grams of solute per 500. grams of solvent. If you pour 70.0 grams of
solute into 800. grams of solvent, how many more grams of solute can you dissolve before reaching saturation?

Answers

Answer:

10.0g of solute before reaching saturation

Explanation:

A saturated solution is the solution that contains the maximum amount of solute that can be dissolved. In the problem, you can have

50.0g of solute / 500.0g Solvent

Now, in 800.0g solvent you can dissolve:

800.0g Solvent * (50.0g solute / 500.0g Solvent) = 80.0g of solute can be added

As you dissolve initially 70.0g of solute. You can add:

80.0g - 70.0g =

10.0g of solute before reaching saturation

Which half-reaction shows conservation of charge? * 5 points A) Cu + e– → Cu+ B) Cu2+ + 2e– → Cu C) Cu+ → Cu + e– D) Cu2+ → Cu + 2e–

Answers

Answer:

B) Cu2+ + 2e– → Cu.

Explanation:

Hello there!

In this case, in the regard of redox reactions, we must keep in mind that half-reactions show us how the flow of electrons when an element undergoes a change in its oxidation state, say increasing or decreasing. In such a way, if the element is oxidized, increase the oxidation state, we add electrons on the right side and the contrary if the element is reduced, decrease the oxidation state.

In such a way, we can see that the reaction B) Cu2+ + 2e– → Cu, shows how the Cu2+ cations are reduced by adding electrons to produce Cu and thus, conserve the charge.

Best regards!

How many moles of Chromium(III) nitrate (Cr(NO3)3) are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate (Pb(NO3)4) to produce chromium(III) nitrate (Cr(NO3)3) and lead? 4 Cr + 3 Pb(NO3)4 → 4 Cr(NO3)3 + 3 Pb

Answers

Answer:

[tex]0.64molCr(NO_3)_3[/tex]

Explanation:

Hello there!

In this case, according to the given chemical equation, it turns out possible for us to realize there is a 4:3 mole ratio of chromium(III) nitrate to lead(IV) nitrate, and therefore, we can calculate the moles of the former by applying the shown below stoichiometry setup:

[tex]0.85molPb(NO_3)_4*\frac{3molCr(NO_3)_3}{4molPb(NO_3)_4} \\\\0.64molCr(NO_3)_3[/tex]

Regards!

ANSWER THIS QUESTION FOR 29 POINTS
List several examples of what cells do all day?

I NEED HELP HELP ASAP

Answers

Answer:

Explanation:

cells process rna and trna

converting food into energy

the regrowth of cells that have died through out the day

the transcription of dna to rna

hope this helped :)

plz do it ..i am confused​

Answers

Answer:

..             ..

O : : C : : O

..             ..

Explanation:

Carbon

Atomic number = 6

Mass Number = 12

No. of protons = 6

No. of electrons = 6

No. of neutrons = 12 - 6 = 6

Electronic configuration - (K, L) = (2, 4)

Polar bears are adapted to stay warm by growing thick fur. These organisms most likely live in a what​

Answers

Answer:

They live in the open snow

Explanation:

Other Questions
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The standard costs associated with this level of production are as follows: Total Per Unit of ProductDirect materials $ 78,624 $ 20.16 Direct labor $ 12,870 3.30 Variable manufacturing overhead(based on direct labor-hours $ 2,340 0.60 $ 24.06 During April, the factory worked only 755 direct labor-hours and produced 4,000 robes. The following actual costs were recorded during the month: Total Per Unit of ProductDirect materials (14,000 yards) $ 84,000 $ 21.00 Direct labor $ 14,000 3.50 Variable manufacturing overhead $ 7,200 1.80 $ 26.30 At standard, each robe should require 3.2 yards of material. All of the materials purchased during the month were used in production.Required:1. Compute the materials price and quantity variances for April: (Input all amounts as positive values. Leave no cells blank - be certain to enter "0" wherever required. Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect (i.e., zero variance). 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