Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule to determine the following. ​(a) What percentage of people has an IQ score between 66 and 134​? ​(b) What percentage of people has an IQ score less than 83 or greater than 117​? ​(c) What percentage of people has an IQ score greater than 117​? ​(a) 95​% ​(Type an integer or a​ decimal.) ​(b) (Type an integer or a​ decimal.)

Answers

Answer 1

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117​.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = scores of an IQ test

SO, X ~ Normal([tex]\mu=100, \sigma^{2} = 17^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                      Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

Now, the empirical rule states that;

68% of the data values lie within 1 standard deviation from the mean.95% of the data values lie within 2 standard deviations from the mean.99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

     z score for 66 =  [tex]\frac{X-\mu}{\sigma}[/tex]  =  [tex]\frac{66-100}{17}[/tex]  = -2

     z score for 134 =  [tex]\frac{X-\mu}{\sigma}[/tex]  =  [tex]\frac{134-100}{17}[/tex]  = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

     z score for 83 =  [tex]\frac{X-\mu}{\sigma}[/tex]  =  [tex]\frac{83-100}{17}[/tex]  = -1

     z score for 117 =  [tex]\frac{X-\mu}{\sigma}[/tex]  =  [tex]\frac{117-100}{17}[/tex]  = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117​ = [tex]\frac{32\%}{2}[/tex] = 16%.


Related Questions

Suppose you were given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). What is the value of a?

Answers

Answer:

Hope it helps..........

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). Hence, the value of x is 7.5.

What is a function?

Function is a type of relation, or rule, that maps one input to specific single output.

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2).

here x = 2

Substitute in the function;

F(x)=x^4-2x^3+3x^2 - ax+3

F(2) = 2^4-2(2)^3+3(2)^2 - a(2) +3

F(2) = 16 - 16 + 12 - 2a +3

F(2) = 15 - 2a

15 - 2a = 0

15 = 2a

a = 7.5

Hence, the value of x is 7.5

Learn more about function here:

https://brainly.com/question/2253924

#SPJ2

Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!

Answers

Step-by-step explanation:

(-3x-2/x) multiply by (-15x+12/x)

find the circumference of a circle with a diameter of 6 cm

Answers

Circumference = πd

~substitute (π)(6 cm)

~simplify → 6π cm.

So the circumference of the circle shown here is 6π cm.

Answer:

18.85 cm

Step-by-step explanation:

The circumference of a circle has a formula.

Circumference = π × diameter

The diameter is 6 centimeters.

Circumference = π × 6

Circumference ≈ 18.85

The circumference of the circle is 18.85 centimeters.

In a study of the accuracy of fast food​ drive-through orders, one restaurant had 40 orders that were not accurate among 307 orders observed. Use a 0.05 significance level to test the claim that the rate of inaccurate orders is greater than ​10%. State the test result in terms of the claim. Identify the null and alternative hypotheses for this test The test statistic for this hypothesis test is? The​ P-value for this hypothesis test is? Identify the conclusion for this hypothesis test. State the test result in terms of the claim.

Answers

Answer:

We conclude that the rate of inaccurate orders is greater than ​10%.

Step-by-step explanation:

We are given that in a study of the accuracy of fast food​ drive-through orders, one restaurant had 40 orders that were not accurate among 307 orders observed.

Let p = population proportion rate of inaccurate orders

So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\leq[/tex] 10%     {means that the rate of inaccurate orders is less than or equal to ​10%}

Alternate Hypothesis, [tex]H_A[/tex] : p > 10%      {means that the rate of inaccurate orders is greater than ​10%}

The test statistics that will be used here is One-sample z-test for proportions;

                          T.S.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of inaccurate orders = [tex]\frac{40}{307}[/tex] = 0.13

           n = sample of orders = 307

So, the test statistics =  [tex]\frac{0.13-0.10}{\sqrt{\frac{0.10(1-0.10)}{307} } }[/tex]  

                                    =  1.75

The value of z-test statistics is 1.75.

Also, the P-value of the test statistics is given by;

            P-value = P(Z > 1.75) = 1 - P(Z [tex]\leq[/tex] 1.75)

                          = 1 - 0.95994 = 0.04006

Now, at 0.05 level of significance, the z table gives a critical value of 1.645  for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 1.75 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the rate of inaccurate orders is greater than ​10%.

Jess is cutting bows of ribbon which will be used to wrap gifts. If jess needs 1 7/11 feet of ribbon to make a bow and she has 36 feet of ribbon, then how many bows can jess make?

Answers

Answer:

22

Step-by-step explanation:

You need to divide 36 ft by 1 7/11 ft, and then round down if you don't get a whole number.

[tex]\dfrac{36~ft}{1 \frac{7}{11}~ft} =[/tex]

[tex]= \dfrac{36}{\frac{18}{11}}[/tex]

[tex] = \dfrac{36}{1} \times \dfrac{11}{18} [/tex]

[tex] = \dfrac{36 \times 11}{1 \times 18} [/tex]

[tex] = 22 [/tex]

Answer: 22

a) Al usar un microscopio el microscopio se amplía una célula 400 veces. Escribe el factor de ampliación como cociente o como escala.
b) La imagen de una célula usando dicho microscopio mide 1,5 mm ¿ Cuánto mide la célula en la realidad?

Answers

Answer:

x = 0,00375 mm

Step-by-step explanation:

a) El factor de ampliación es 400/1   es decir el tamaño real se verá ampliado 400 veces mediante el uso del microscopio

b) De acuerdo a lo establecido en la respuesta a la pregunta referida en a (anterior) podemos establecer una regla de tres, según:

Si al microscopio el tamaño de la célula es 1,5 mm, cual será el tamaño verdadero ( que es reducido 400 en relación al que veo en el microscopio)

Es decir     1,5 mm      ⇒    400

                    x (mm)    ⇒       1 (tamaño real de la célula)

Entonces

x  =  1,5 /400

x = 0,00375 mm

The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown. f(x) = 4(x2 + 12x) + 10 (twelve-halves) squared = 36 What is the function written in vertex form?

Answers

Answer:

[tex]f(x)=4(x+6)^2-134[/tex]

Step-by-step explanation:

We are required to write the function[tex]f(x) = 4x^2 + 48x + 10[/tex] in vertex form.

First, bring the constant to the left-hand side.

[tex]f(x) -10= 4x^2 + 48x[/tex]

Factorize the right hand side.

[tex]f(x) -10= 4(x^2 + 12x)[/tex]

Take note of the factored term(4) and write it in the form below.

[tex]f(x) -10+4\Box= 4(x^2 + 12x+\Box)[/tex]

[tex]\Box = (\frac{\text{Coefficient of x}}{2} )^2\\\\\text{Coefficient of x}=12\\\\\Box = (\frac{12}{2} )^2 =6^2=36[/tex]

Substitute 36 for the boxes.

[tex]f(x) -10+4\boxed{36}= 4(x^2 + 12x+\boxed{36})[/tex]

[tex]f(x) -10+144= 4(x^2 + 12x+6^2)[/tex]

[tex]f(x) +134= 4(x+6)^2\\f(x)=4(x+6)^2-134[/tex]

The function written in vertex form is [tex]f(x)=4(x+6)^2-134[/tex]

Answer:

C

Step-by-step explanation:

I just finished the unit test on Edge. and got a 100% and I selected "c" as my answer.

Which of the following best describes the algebraic expression 5(x + 2) - 3 ?
bre

Answers

Answer:

D

Step-by-step explanation:

Silver Lake has a population of 114,000. The population is decreasing at a rate of 1.5% each year. Which of the following choices is the correct function? a p(s) = 114000• 0.985x b p(s) = 114000x c p(s) = 114000x + 0.985 d None of these choices are correct.

Answers

Answer: D

Step-by-step explanation:

According to the question, Silver Lake has a population of 114,000. The population is decreasing at a rate of 1.5% each year

The initial population Po = 114000

Rate = 1.5% = 0.015

The declining population formula will be:

P = Po( 1 - R%)x^2

The decay formula

Since the population is decreasing, take away 0.015 from 1

1 - 0.015 = 0.985

Substitutes all the parameters into the formula

P(s) = 114000(0.985)x^2

P(s) = 114000× 0985x^2

The correct answer is written above.

Since option A does not have square of x, we can therefore conclude that the answer is D - non of the choices is correct.

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Three hundred feet of fencing is used

dimensions of the playground that maximize the total enclosed area. What is the maximum area?

The smaller dimension is

feet

Answers

Answer:

50 ft by 75 ft3750 square feet

Step-by-step explanation:

Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...

  y = (300 -2x)/3

And the enclosed area is ...

  A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)

This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.

The maximum area is enclosed when the dimensions are ...

  50 ft by 75 ft

That maximum area is 3750 square feet.

_____

Comment on the solution

The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).

A triangular plot of land has one side along a straight road measuring 147147 feet. A second side makes a 2323degrees° angle with the​ road, and the third side makes a 2222degrees° angle with the road. How long are the other two​ sides?

Answers

Answer:

81.23 ft and 77.88 ft long

Step-by-step explanation:

The sum of the internal angles of a triangle is 180 degrees, the missing angle is:

[tex]a+b+c=180\\a+23+22=180\\a=135^o[/tex]

According to the Law of Sines:

[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}= \frac{C}{sin(c)}[/tex]

Let A be the side that is 147 feet long, the length of the other two sides are:

[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}\\B=\frac{sin(23)*147}{sin(135)}\\B=81.23\ ft\\\\\frac{A}{sin(a)}= \frac{C}{sin(c)}\\C=\frac{sin(22)*147}{sin(135)}\\C=77.88\ ft[/tex]

The other two sides are 81.23 ft and 77.88 ft long

A tank contains 3,000 L of brine with 16 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. (a) How much salt is in the tank after t minutes

Answers

Answer:

The amount of salt in the tank after t minutes is

y= 16e^(t/100)kg

Step- by-step Explanation

The tank contain 3000L of the brine

The rate is 30L/ min

The solution is mixed thoroughly, therefore, the rate in= rate out

dy/dt= rate in to the tank= rate out of the tank

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

An instructor asks students to rate their anxiety level on a scale of 1 to 100 (1 being low anxiety and 100 being high anxiety) just before the students take their final exam. The responses are shown below. Construct a relative frequency table for the instructor using five classes. Use the minimum value from the data set as the lower class limit for the first row, and use the lowest possible whole-number class width that will allow the table to account for all of the responses. Use integers or decimals for all answers.
48,50,71,58,56,55,53,70,63,74,64,33,34,39,49,60,65,84,54,58
Provide your answer below:
Lower Class Limit Upper Class Limit Relative Frequency

Answers

Answer:

The frequency table is shown below.

Step-by-step explanation:

The data set arranged ascending order is:

S = {33 , 34 , 39 , 48 , 49 , 50 , 53 , 54 , 55 , 56 , 58 , 58,  60 , 63 , 64 , 65 , 70 , 71 , 74 , 84}

It is asked to use the minimum value from the data set as the lower class limit for the first row.

So, the lower class limit for the first class interval is 33.

To determine the class width compute the range as follows:

[tex]\text{Range}=\text{Maximum}-\text{Minimum}[/tex]

          [tex]=84-33\\=51[/tex]

The number of classes requires is 5.

The class width is:

[tex]\text{Class width}=\frac{Range}{5}=\frac{51}{2}=10.2\approx 10[/tex]

So, the class width is 10.

The classes are:

33 - 42

43 - 52

53 - 62

63 - 72

73 - 82

83 - 92

Compute the frequencies of each class as follows:

Class Interval                  Values                        Frequency

   33 - 42                      33 , 34 , 39                             3

   43 - 52                      48 , 49 , 50                            3

   53 - 62          53 , 54 , 55 , 56 , 58 , 58,  60              7

   63 - 72                 63 , 64 , 65 , 70 , 71                      5

   73 - 82                              74                                  1

   83 - 92                             84                                   1

   TOTAL                                                                   20

Compute the relative frequencies as follows:

Class Interval          Frequency        Relative Frequency

   33 - 42                        3                   [tex]\frac{3}{20}\times 100\%=15\%[/tex]

   43 - 52                        3                   [tex]\frac{3}{20}\times 100\%=15\%[/tex]

   53 - 62                        7                   [tex]\frac{7}{20}\times 100\%=35\%[/tex]

   63 - 72                        5                   [tex]\frac{5}{20}\times 100\%=25\%[/tex]

   73 - 82                         1                   [tex]\frac{1}{20}\times 100\%=5\%[/tex]

   83 - 92                         1                   [tex]\frac{1}{20}\times 100\%=5\%[/tex]

   TOTAL                        20                          100%

What is the standard form for 80000 + 200+ 2

Answers

Answer:

80202

Step-by-step explanation:

Simply add according to number value:

200 - 2 goes into hundreds place

2 - 2 goes into ones place

80000 - 8 goes into ten-thousands place

Consider the statement, "Confidence intervals are underutilized" and explain what the implications might be of using or not using confidence intervals.

Answers

Answer:

Step-by-step explanation:

Confidence intervals have been underutilized prior to this time.

The implications of not using confidence intervals include:

- The under-representation or over-representation of research results that amounts from the use of a single figure to represent a statistic.

- In Market Research analysis, neglecting the use of confidence intervals will increase the risk of your portfolio.

Implications/Importance of using confidence intervals include:

- Calculation of confidence interval gives additional information about the likely values of the statistic you are estimating.

- In the presentation and comprehension of results, confidence intervals give more accuracy from the data or metrics captured.

- Given a sample mean, confidence intervals show the likely range of values of the population mean.

the ellipse is centered at the origin, has axes of lengths 8 and 4, its major axis is horizontal. how do you write an equation for this ellipse?​

Answers

Answer:

The equation for this ellipse is [tex]\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1[/tex].

Step-by-step explanation:

The standard equation of the ellipse is described by the following expression:

[tex]\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}} = 1[/tex]

Where [tex]a[/tex] and [tex]b[/tex] are the horizontal and vertical semi-axes, respectively. Given that major semi-axis is horizontal, [tex]a > b[/tex]. Then, the equation for this ellipse is written in this way: (a = 8, b = 4)

[tex]\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1[/tex]

The equation for this ellipse is [tex]\frac{x^{2}}{64} + \frac{y^{2}}{16} = 1[/tex].

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a that makes the following probability statements true.

a. P(X <= a) =0.95
b. P(X < a)= 0.49
c. P(X >= a)= 0.85
d. P(X >a )= 0.89
e. P(1.83 <= x <=a)= 0.31

Answers

Answer:

(a) The value of a is 53.35.

(b) The value of a is 38.17.

(c) The value of a is 26.95.

(d) The value of a is 25.63.

(e) The value of a is 12.06.

Step-by-step explanation:

The probability density function of X is:

[tex]f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}[/tex]

Here, 22 < X < 55.

(a)

Compute the value of a as follows:

[tex]P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35[/tex]

Thus, the value of a is 53.35.

(b)

Compute the value of a as follows:

[tex]P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17[/tex]

Thus, the value of a is 38.17.

(c)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95[/tex]

Thus, the value of a is 26.95.

(d)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63[/tex]

Thus, the value of a is 25.63.

(e)

Compute the value of a as follows:

[tex]P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06[/tex]

Thus, the value of a is 12.06.

A contractor is setting up new accounts for the local cable company. She earns $75 for each customer account she sets up. Which expression models this situation, and how much will she profit if she sets up 8 customers? (The variable c represents the number of customers.) Question 4 options: A) c – 75; $9.78 B) 75c; $600 C) c + 75; $600 D) 75/c; $9.78

Answers

Answer:

B

Step-by-step explanation:

The contractor gets $75 for every single customer she sets up. Okay, so if she sets up 1 customer, she gets $75, if she sets up 2, she gets $150 and so on.

This is a multiplication expression since multiplication is just repeated addition, which is what is happening in this case, where the contractor gets $75 added to her account every time she sets another person up.

At this point you can just eliminate the other answer options except for B, so it is B.

But to double check... if you multiply 75 by 8, you would get $600, which is B.

Answer:

d

Step-by-step explanation:

75/c; $9.78

Simplify the expression (5j+5) – (5j+5)

Answers

Answer:

0

Step-by-step explanation:

multiply the negative thru the right part of the equation so, 5j+5-5j-5. The 5j and the 5 than cancel out with each other. Hope this helps!

Answer:

0

Explanation:

step 1 - remove the parenthesis from the expression

(5j + 5) - (5j + 5)

5j + 5 - 5j - 5

step 2 - combine like terms

5j + 5 - 5j - 5

5j - 5j + 5 - 5

0 + 0

0

therefore, the simplified form of the given expression is 0.

50 pts If You Get IT RIGHT!!!
Kellianne lined up the interior angles of the triangle along line p below. Triangle A B C. Angle A, B, and C are on line p. Which statements are true for line p? Check all that apply.

Answers

Answer:

angles a and b are lined up

CAN SOMEONEHELP PLS ASAP

Answers

Answer:

a ≈ 2.2

Step-by-step explanation:

Using the Cosine rule in Δ ABC

a² = b² + c² - 2bc cos A

Here b = 3, c = 4 and A = 32° , thus

a² = 3² + 4² - (2 × 3 × 4 × cos32° )

    = 9 + 16 - 24cos32°

    = 25 - 24cos32° ( take the square root of both sides )

a = [tex]\sqrt{25-24cos32}[/tex] ≈ 2.2

At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men nor teachers. Find the number of women teachers attending the lecture

Answers

Answer:

20 teachers

Step-by-step explanation:

Because if you take 100 and minus it by 29, 23, 4 and 24 you get 20.

solve the proportion for y 11/8=y/13

Answers

Answer:

We can use the cross products property.

11/8 = y / 13

8y = 11 * 13

y = 11 * 13 / 8 = 17.875

Answer:

y=17.875

Step-by-step explanation:

[tex]\frac{11}{8} = \frac{y}{13}[/tex]

11(13)=8y

143=8y

y=17.875

A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66degreesF.Construct a 99​%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body​ temperature?

Answers

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 104 - 1 = 103

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.624

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.

The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

A half marathon is 13.1 miles long. Leah is running a half marathon and has completed 7.75 miles. How many miles to
the finish line?

Answers

Answer:

5.35 more miles

Answer:

5.35 miles to the finish line

Step-by-step explanation:

Step one

13.1-7.75=

5.35

Can Someone help me!!! I need this ASAP! What number? Increased by 130% is 69? FYI: the answer is less than 69

Answers

Answer:

Hey there!

There are a few ways you could solve this problem, but the easiest would to be writing an equation.

You could say-

2.3x=69

Divide by 2.3

x=30

Hope this helps :)

Answer:

30

Step-by-step explanation:

the answer is 30 bc increasing something by 130% is multiplying it by 2.3 so technically you have to divide 69 by 2.3 which equals to 30

Which proportion would convert 18 ounces into pounds?

Answers

Answer:

16 ounces = 1 pound

Step-by-step explanation:

You would just do 18/16 = 1.125 pounds. There are always 16 ounces in a pound, so it always works like this

16 ounces to 1 pound

A 37 bag sample had a mean of 421 grams. Assume the population standard deviation is known to be 29. A level of significance of 0.05 will be used. State the null and alternative hypothesis.

Answers

Answer:  [tex]H_0:\mu=421[/tex]

[tex]H_a : \mu\neq421[/tex]

Step-by-step explanation:

A null hypothesis is a type of hypothesis that is used in statistics that assumes there is no difference between particular characteristics of a population wheres the alternative hypothesis shows that there is a difference.

Given: A 37 bag sample had a mean of 421 grams.

Let [tex]\mu[/tex] be the population mean.

Then, the null hypothesis would be:

[tex]H_0:\mu=421[/tex]

whereas the alternative hypothesis would be:

[tex]H_a : \mu\neq421[/tex]

which of the following equations is equal to 2x^2+8 A. (2x-4i)(x-2i) B. (2x+4i)(x+2i) C. (2x-2i)(x+6i) D. (2x-4i)(x+2i)

Answers

Answer:

(2x-4i) (x+2i)

Step-by-step explanation:

2x^2+8

Factor out 2

2 ( x^2+4)

Writing as the difference of squares  a^2 -b^2 = (a-b) (a+b)

2 ( x^2 -(2i)^2)

2 ( x-2i) (x+2i)

Multiplying the 2 into the first term

(2x-4i) (x+2i)

Which of the following relations is a function?
A{(3,-1), (2, 3), (3, 4), (1,7)}

B{(1, 2), (2, 3), (3, 4), (4, 5)}.

C{(3, 0), (4, -3), (6, 7), (4,4)}

D{(1, 2), (1, 3), (2, 8), (3, 9)}​

Answers

Answer:

B

Step-by-step explanation:

A is not a function because the same x value is repeated twice with different y values. The same goes for C and D so the answer is C.

Answer:

B.

Step-by-step explanation:

Well a relation is a set of points and a function is a relation where every x value corresponds to only 1 y value.

So lets see which x values in these relations have only 1 y value.

A. Well a isn’t a function because the number 3 which is a x value had two y values which are -1 and 4.

B. This relation is a function because there are no similar x values.

C. This is not a function because the x value 4 has two y values which are 4 and -3.

D. This is not a function because the number 1 has 2 and 3 as y values.

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