Scientists discover remains of wooden structures near a Celtic runes site. What kind of testing will indicate when the stones were moved into place by the Celts?

Carbon dating

Radioactive dating

Answers

Answer 1

Answer:

Carbon

Explanation:

Bc i got this question on my test

Answer 2

Answer:

A. Carbon dating

Explanation:

I took the test proof

                                 

Scientists Discover Remains Of Wooden Structures Near A Celtic Runes Site. What Kind Of Testing Will

Related Questions

Which property of a sound wave increases as the pitch of the sound
increases?
A. Amplitude
B. Wavelength
C. Rest position
ОО
D. Frequency

Answers

Answer:

the answer is d. frequency

A solution has a concentration of 0.001 M NaOH (MM = 40.00
g/mol). Suppose you have 1000 g of this solution which
occupies a volume of 1 L. What is the percent by mass
concentration of NaOH?

Answers

Percent by mass : 4.10⁺³%

Further explanation

The concentration of a solution can be expressed in units such as molarity, normality, mass percent, volume percent etc.

[tex]\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%[/tex]

mass solute= mass of NaOH  

mass of NaOH :

[tex]\tt 0.001~mol/L\times 1~L\times 40~g/mol=0.04~g[/tex]

mass solution = 1000 g

% mass :

[tex]\tt \dfrac{0.04}{1000}\times 100=4.10^{-3}\%[/tex]

The percent by mass concentration of NaOH in the given solution is approximately 0.004%.

To calculate the percent by mass concentration of NaOH, we must find the mass of NaOH in solution.

First, we determine how many moles of NaOH are present in the solution:

Molarity (M) is calculated as moles of solute per liter of solution.

1 L = 0.001 M = mole of NaOH

We rearrange the equation to find that one mole of NaOH is equal to 0.001 moles.

Mass of NaOH = moles of NaOH * molar mass of NaOH

Mass of NaOH = 0.001 mol * 40.00 g/mol

Mass of NaOH = 0.04 g

The mass of the solution is 1000 g which is given in the question.

Percent by mass concentration of NaOH = (mass of NaOH / mass of solution) * 100%

Percent by mass concentration of NaOH = (0.04 g / 1000 g) * 100%

Percent by mass concentration of NaOH = 0.004%

Hence, the percent by mass concentration of NaOH in the given solution is approximately 0.004%.

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What happens to a Lithium atom for it to become an Li+1 ion?

Answers

Answer:

If an atom gains or loses an electron, it bacomes an ion. An atom that gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion

Explanation:

A lithium atom has 3 protons and 3 electrons. It can lose one of its electrons, making it an ion. It now has more positive protons than electrons so it has an overall positive charge. Therefore it is a positive ion.

A fluorine atom will tend to gain, rather than lose, an electron. By gaining a negative electron, it has an overall negative charge. It has become a negative ion.

I WILL GIVE YOU A BRAINLIEST: Bryce observes that the sun always seems to rise in the east. He talks with others and finds that everyone has the same observation. Which term describes this equation? A) the sun rises in the east B) Why does the sunrise in the east? C) The sun appears in the east because of Earth’s rotation pattern. D) If the sun appears in the east, then I am in the Western Hemisphere.

Answers

Answer: C

Explanation:

No matter the location on Earth, the sun always rises in the east due to its rotation pattern.

an 11.5g sample of ethonal 6.00g of Carbon 1.51g of hydrogen what is the percent composition of each element

Answers

C : 52.2%, H : 13.1%, O:34.7%

Further explanation  

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

11.5 g of Ethanol-C₂H₅OH contains 6.00 g of Carbon and 1.51 g of Hydrogen.

mass of Oxygen :

[tex]\tt 11.5-(6+1.51)=4~g[/tex]

Percent composition :

C

[tex]\tt \dfrac{6}{11.5}\times 100\%=52.2\%[/tex]

H

[tex]\tt \dfrac{1.51}{11.5}\times 100\%=13.1\%[/tex]

O

[tex]\tt \dfrac{4}{11.5}\times 100\5=34.7\%[/tex]

A 11.1-g sample of granite initially at 76.0°C is immersed into 22.0 g of water initially at 22.0°C. What is the final temperature of both substances when they reach thermal equilibrium? (For water, Cs=4.18J/g⋅∘C and for granite, Cs=0.790J/g⋅∘C.)

Answers

Answer:

[tex]T_f=26.7\°C[/tex]

Explanation:

Hello.

In this case, when two substances at different temperature are placed in contact in an isolated container, we can say that the heat lost by the hot substance is gained by the cold substance. In such a way, since granite is at 76.0 °C and water at 22.0 °C we infer granite is hot and water is cold, so we write:

[tex]Q_{granite}=-Q_{water}[/tex]

In terms of mass, specific heat and change in temperature, we write:

[tex]m_{granite}C_{granite}(T_f-T_{granite})=-m_{water}C_{water}(T_f-T_{water})[/tex]

Thus, since the temperature is the same for both substance, we can solve for it as shown below:

[tex]T_f=\frac{m_{granite}C_{granite}T_{granite}+m_{water}C_{water}T_{water}}{m_{granite}C_{granite}+m_{water}C_{water}}[/tex]

By plugging in each variable, we obtain:

[tex]T_f=\frac{11.1g*0.790\frac{J}{g\°C} *76.0\°C+22.0g*4.18\frac{J}{g\°C} *22.0\°C}{11.1g*0.790\frac{J}{g\°C} +22.0g*4.18\frac{J}{g\°C}}\\\\T_f=26.7\°C[/tex]

Best regards!

Determine the molarity of 1.2 mol KCl in 1.1 L of a solution?

Answers

Answer:

1.1 M

General Formulas and Concepts:

Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define variables

1.2 mol KCL

1.1 L of solution

M = unknown

Step 2: Solve for Molarity

Substitute:                    M = 1.2 mol/1.1 LEvaluate:                       M = 1.09091

Step 3: Check

We are given 2 sig figs. Follow sig fig rules.

1.09091 M ≈ 1.1 M

How many moles of H are present in 3 moles of carbon trihydride?

Answers

Answer:

4moles of carbon trihydride

Calculate the number of moles of MgF2 that dissolved.

Answers

Moles of MgF₂ : 1.2 x 10⁻⁴

Further explanation

Maybe the complete question is like this

A student prepares 100. mL of a saturated solution of MgF2 by adding 0.50 g of solid MgF2 to 100. mL  of distilled water at 25°C and stirring until no more solid dissolves. (Assume that the volume of the  undissolved MgF2 is negligibly small.) The saturated solution is analyzed, and it is determined that [F−] in  the solution is 2.4 × 10−3 M.

The dissociation reaction of MgF₂

MgF₂(s)⇒ Mg²⁺(aq)+2F⁻(aq)

mol ratio MgF₂ : F⁻ = 1 : 2

mol of F⁻ in 100 ml solution :

[tex]\tt mol=M\times V\\\\mol=2.4\times 10^{-3}\times 0.1=2.4\times 10^{-4}[/tex]

mol MgF₂ :

[tex]\tt \dfrac{1}{2}\times 2.4\times 10^{-4}= 1.2\times 10^{-4}[/tex]

Explain on the chemical structural basis why the products of the saponification reaction are soluble in water while the starting triglyceride is insoluble in water.

Answers

Answer:

The description is outlined in subsection downwards and according to the query given.

Explanation:

Saponification seems to be a procedure that requires the conversion or transformation of fat, grease, or lipid by either the intervention of heating a mixture of aqueous alkali towards soap as well as an alcoholic. Soaps contain fatty acid salts, however, mono-fatty acids contain carbon atoms, such as sodium palmitate. Therefore, throughout the water, individuals were indeed soluble. However, on another hand, owing to large hydrocarbon strings, triglycerides do not partake in hydrogen bonding. Therefore in water, they aren't dissolved.

The solubility of a soap is due to the hydrophilic head which interacts with water.

A triglyceride is a compound that is based on propane 1,2,3 - triol where all the -OH groups have been replaced with fatty acid chains. The triglycerides are insoluble in water because it contains a long alkyl chain which does not interact with water.

However, a soap is a salt of a glyceride having a hydrophilic head and a hydrophobic tail. The hydrophilic head is responsible for the solubility of the soap in water.

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At 298 K and 1 atm which noble gas has the lowest density? Why?

1) Ne

2) Kr

3) Xe

4) Rn

Answers

Answer:

Ne

Explanation:

It has the lowest density.

Neon has the lowest density since it has the smallest atomic size and the lowest atomic number.

At a standard temperature of 298K and a pressure of 1 atm;

The atomic density of an element refers to the number of atoms contained in an element per unit volume.

The size of an atom has an effect on atomic density. The size of an atom increases from left to right across the period and top to bottom down the group.

As such, on the periodic table, as we move from top to bottom down the group, the density of an atom increases.

The atomic element of the given elements are:

Neon (Ne) = 10Krypton (Kr) = 36Xenon (Xe) = 54Radon (Rn) = 36

Therefore, we can conclude that Neon (Ne) will have the lowest density since it has the smallest atomic size and the lowest atomic number.

Learn more about the Periodic table here:

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Which of the following correctly identifies and explains the charge on an atom of
sodium?

Answers

Answer:

The best and most correct answer among the choices provided by your question is the fourth choice.

The data explains that sodium atoms hardly ever form 2+ ions.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Explanation:

A bicycle has a momentum of 25.00 kg x m/s and a velocity of 2.5 m/s. What is the bicycle’s mass

Answers

Answer:

10 kg

Explanation:

The mass of the bicycle can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

p is the momentum

v is the velocity

From the question we have

[tex]m = \frac{25}{2.5} \\ [/tex]

We have the final answer as

10 kg

Hope this helps you

If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
Cuo, which is the limiting reactant? How many grams of N2
will be formed?​

Answers

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = [tex]\frac{mass}{molar mass}[/tex]  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = [tex]\frac{18.1}{143.2}[/tex]   = 0.13moles

Number of moles of NH₃   = [tex]\frac{90.4}{17}[/tex]   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

THIS QUESTION IS HARD BUT I NEED HELP AND ITS DUE IN 20 MINS. YOU HAVE TO ANSWER A AND B FOR EVERYTHING TO BE CORRECT. I KNOW YALL ARE SMART PLSS HELP. THANKS!!

Answers

With the batteries wire and paper clips you can make a spare to have a fire if use a compass to tell where I’m located the strong and leak magnet and put it under your hand put 2 nails on your hand and it will show you where your strongest magnetic force is.

NEED ANSWERS NOW 100 PTS

Is iron iii fluoride ionic or covalent

Is carbon disulfide ionic or covalent

Answers

Answer:

iron i believe is ionic and carbon is covalent

Explanation:

if im wrong correct me

Classify which compounds will dissolve in water and which ones will not dissolve in water.

a. Accetone
b. I-propanol
c. Hexane
d. Methanol
e. Decane

Answers

Answer:

Dissolves in water: Acetone, 1-propanol, Methanol

Do not dissolve in water: Hexane, Decane

Explanation:

From the principle that like dissolves like,polar substances will dissolve in polar solutions, while non-polar substances will dissolve in non-polar substances.

Water is a polar solution, therefore, polar substances will dissolve in it.From the given options:

Acetone is a polar molecule, therefore, it will dissolve in water.

1-propanol is a polar molecule, therefore, it will dissolve in water.

Hexane is a non-polar molecule, therefore, it will not dissolve in water.

Methanol is a polar molecule, therefore, it will dissolve in water.

Decane is a non-polar molecule, therefore, it will not dissolve in water

How many moles is 3.01 x 10 24 molecules of oxygen ( g)?

Answers

Answer:

5.00 moles O₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

3.01 × 10²⁴ molecules O₂

Step 2: Convert

[tex]3.01 \cdot 10^{24} \ mc \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ mc \ O_2} )[/tex] = 4.99834 moles O₂

Step 3: Check

We are given 3 sig figs. Follow sig fig rules and round.

4.99834 moles O₂ ≈ 5.00 moles O₂

A sled is at rest at the top of a slope 2 m high. The sled has a mass of 45 kg. What is the sleds potential energy

Answers

Answer:

[tex]\boxed {\boxed {\sf882 \ Joules}}[/tex]

Explanation:

Potential energy can be found by multiplying the mass by the height by the gravitational acceleration.

[tex]PE=mgh[/tex]

The mass is 45 kilograms. The height is 2 meters. The gravitational acceleration on Earth is 9.8 meters per seconds squared.

[tex]m=45 \ kg \\h= 2 \ m \\g=9.8 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]PE=45 \ kg * 2 \ m * 9.8 m/s^2[/tex]

Multiply.

[tex]PE=441 kg*m/s^2*2 \ m[/tex]

[tex]PE= 882 \ kg *m/s^2 *m[/tex]

1 kg*m/s^² is equal to 1 Newton (N). Substitute N in for kg*m/s²

[tex]PE=882 \ N*m[/tex]

1 Newton meter (N*m) is equal to 1 Joule (J). Our current answer is equivalent to 882 Joules.

[tex]PE= 882 \ J[/tex]

The sled's potential energy is 882 Joules.

Answer:

882 J

Explanation:

Is calcium oxide a Element or compound or mixture?

Answers

Answer:

compound

Explanation:

Answer:

The answer is compound

Explanation:

What amount of moles of sodium chloride is needed to prepare 1.25 L of a salt solution with a concentration of 0.750 mol/L

Answers

Answer:

Number of moles = 0.94 mol

Explanation:

Given data:

Number of moles of sodium chloride = ?

Volume of sodium chloride = 1.25 L

Concentration of solution = 0.750 mol/L

Solution:

Formula:

Concentration = number of moles/ volume in L

By putting values.

0.750 mol/L = number of mole / 1.25 L

Number of moles =  0.750 mol/L×1.25 L

Number of moles = 0.94 mol

A student measures the length of two pieces of paper as 8.21 in
and 8.0 in. What is the total length? Be sure to use sig. figs. in
your answer. Do not include the unit.

Answers

Answer: 16.21

Explanation:

A student measures the length of two pieces of paper as 8.21 in and 8.0 in. the total length is 16.21 with 4 significant figures.

What are significant figures?

The significant figures or digits are the form of scientific methd which represent the digit from zero to nine and use when the value is uncertain where starting zeros are not significant and decimal is also not a significant figure.

In the given value the total is 16.21 with 4 significant figures with it has 4 significant digits and the decimal with it is not significant after adding from which the respective value is here.

Therefore,  with 4 significant figures where the student measures the length of two pieces of paper as 8.21 in and 8.0 in. the total length is 16.21.

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The combustion of ethane (C 2 H 6 ) produces carbon dioxide and steam.

2C 2 H 6 (g)+7O 2 (g) 4CO 2 (g)+6H 2 O(g)

How many moles of CO 2 are produced when 5.95 mol of ethane is burned in an excess of oxygen?

Answers

CO₂ produced : 11.92 moles

Further explanation

Reaction

2C₂H₆ (g)+7O₂ (g) ⇒4CO₂ (g)+6H₂O(g)

mol ratio C₂H₆ : CO₂ = 2 : 4

moles of CO₂ :

[tex]\tt \dfrac{4}{2}\times 5.95=11.92~moles[/tex]

How many molecules are in 650.0 g Mg(OH)₂ ?

Answers

Answer:

6.711 × 10²⁴ molecules Mg(OH)₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

650.0 g Mg(OH)₂

Step 2: Define conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of Mg(OH)₂ - 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol

Step 3: Convert

[tex]650.0 \ g \ Mg(OH)_2(\frac{1 \ mol \ Mg(OH)_2}{58.33 \ g \ Mg(OH)_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ Mg(OH)_2}{1 \ mol \ Mg(OH)_2} )[/tex]

= 6.71061 × 10²⁴ molecules Mg(OH)₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules.

6.71061 × 10²⁴ molecules Mg(OH)₂ ≈ 6.711 × 10²⁴ molecules Mg(OH)₂

Production of 6.5 grams of C2H2 requires consumption of how many grams of H2O

Answers

Answer:

C

Explanation:

Grams 3/4

Answer:

9g

Explanation:

number of moles × the moleculars mass

A student performed the experiment in this module but failed to follow the procedure exactly, keeping the crucible completely covered during the entire heating and cooling processes. Be specific.
1. Explain the probable effect of this procedural change on the experimental results.
2. Would the student's calculated percent water in the hydrate be high, low, or unaffected? Briefly explain

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but the answer to the question can be correctly predicted from the available information from the question.

1. If a "container" (in this case a crucible) is closed throughout a heating experiment. Then it must be noted that water vapor will not be able to escape during the course of the experiment. The water vapor will form a "cloud" of water droplets under the cover of the crucible. And when this crucible is cooled, this water droplets return back to the content/substance inside the crucible.

2. When compared with the initial amount of water present in the substance in the crucible, the percentage of water "left" in the hydrate or substance in the crucible would be high. This is because the water vapor that was suppose to leave the crucible did not leave because the crucible was closed (thus causing very low amount of water vapour to leave).

Because of the student error, the percent water of crystallization value the hydrate will be lower than its actual value.

What is evaporation?

Evaporation is the process by which a liquid changes spontaneously to vapor.

In the experiment to determine percentage water of crystallization, the crucible is left open to ensure all the water molecules are removed by evaporation.

However,, since the student did not remove the crucible cover during heating, some water molecules will not be able to escape completely, but will return back to the salt.

Hence, the percent water of crystallization value the hydrate will be lower because the of mass of the anhydrous salt will be higher than its actual value.

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Which of the following is a renewable source of energy?

Answers

Answer: D

Explanation:

Hydropower

How many molecules are there in .0023kg of NH4SO2?

Answers

Answer:

Molar mass of NH4SO2=104gmol`

No of moles of NH4SO2=2.3g/104gmol`=0.022×(avagadro's constant)

What is the formula for Mercury ii monohydrogen phosphate?​

Answers

Answer:

CaHPO4 i think

Explanation:

Given that 10.00mL of 0.1894M CH3COOH was titrated with 0.2006M NaOH in this experiment, calculate the volume, in mL, of NaOH required

Answers

Answer:

[tex]V_{base}=9.442mL[/tex]

Explanation:

Hello!

In this case, when acetic acid is titrated with sodium hydroxide, the following chemical reaction is carried out:

[tex]CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O[/tex]

Whereas there is a 1:1 mole ratio between the acid and the base, which means that at the equivalence point we evidence:

[tex]n_{acid}=n_{base}[/tex]

Which in terms of volumes and concentrations is written as:

[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]

Thus, solving for the required volume of base, we obtain:

[tex]V_{base}=\frac{M_{acid}V_{acid}}{M_{base}}=\frac{0.1894M*10.00mL}{0.2006M}\\\\ V_{base}=9.442mL[/tex]

Best regards!

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