Answer:
The SUV can run 204 miles with half a gas of tank.
Step-by-step explanation:
Divide 17 by 2=8.5 gallons
Then do the formula for distance which is:
miles per gallon times gallon
24 times 8.5 would be 204
204 is your answer :3
If 3/4 of one of the acute angles of a right-angled triangle is 15 1/4 larger than 1/6 of the other, find the acute angles.
Answer:
Step-by-step explanation:
A + B = 90
A/6(15.25) = 3B/4
61A/18 = B
18A/18 + 61A/18 = 90
A = 90(18)/79
A = 20 40/79°
B = 90 -A = 69 39/79°
Help help help help math please ASAP
Answer:
I think its 86
Step-by-step explanation:
As the two lines going in the same direction are parallel and angles within parallel lines add to 180.
so 180-94=86
1. The side of a square is 5 units long. What is the area of the square?
20 units?
25 units
10 units?
15 units?
Answer: 25 units squared
Step-by-step explanation:
1) A square has 4 equal sides.
2) The area of a square is length x width.
3) Therefore, 5x5 = 25 units squared (area is always reported in units squared).
Express sin U as a fraction in simplest terms.
S
12
13
5
U
Answer:
12/13
Sine is opposite over hypotenuse. The opposite side of U is 12 and the hypotenuse is 13, so the answer is 12/13
an amount ogf $3700 id deposited into an account that pays 8.25% confounded semi-annually. how much money eill you receive in 15 years
Answer: The answer is seventeen
Step-by-step explanation:
i just answered this question
arithmetic sequence, can anyone help with this questions plz?
Answer:
Add 2/3
Step-by-step explanation:
2/3 + 2/3 = 4/3 + 2/3 = 6/3 (or 2) + 2/3 = 8/3 +2/3 = 10/3
A race director is preparing for an upcoming marathon and estimates that the mean time to
finish is 310 minutes. Assume
that the times are normally distributed, with a standard deviation of 50 minutes.
Use a standard normal table or a calculator to find the percentage of times that are longer than 236 minutes. For your
intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example
98.23%).
93.06% of the race is longer than 236 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation[/tex]
Given that μ = 310, σ = 50
For x > 236:
[tex]z=\frac{236-310}{50}=-1.48[/tex]
From the normal distribution table:
P(x > 236) = P(z > -1.48) = 1 - P(z < -1.48) = 1 - 0.0694 = 0.9306 = 93.06%
93.06% of the race is longer than 236 minutes.
Find out more on z score at: https://brainly.com/question/25638875
What is Power rule, Product rule, Quotient rule and Chain rule? Detail please
What are the coordinates of A? someone help
Answer:
(7,10)
Step-by-step explanation:
The x coordinate is the first coordinate, it is how far you go across
X = 7
The next coordinate is the y coordinate, it is how for you go up or down
y = 10
(7,10)
MODELING REAL LIFE The table shows the amount y (in fluid Ounces) of carpet cleaner in a tank after x minutes of
cleaning.
x ll y
5 ll 108
10 ll 88
15 ll 68
a. Write an equation that represents the amount of cleaner in the tank after x minutes.
b. How much cleaner is in the tank when the cleaning begins?
C. After how many minutes is the tank empty?
Answer:
a. Write an equation that represents the amount of cleaner in the tank after x minutes
y= -4x + 128
b. How much cleaner is in the tank when the cleaning begins?
128
c. After how many minutes is the tank empty?
The tank is empty in 32 minutes
A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimate the percentage of computers that use a new operating system. How many computers must be surveyed in order to be % confident that his estimate is in error by no more than percentage point Complete parts (a) through (c) below.
A) Assume nothing is known about the percentage of computers with new operating systems
n =
round up to the nearest integer
b) Assume that the recent survey suggest that about 96% of computers use a operating system.
n =
round up to the nearest integer
C) Does the additional survey information from part (b) have much of an effect on the sample size that is required?
A.
Yes, using the additional survey information from part (b) dramatically reduces the sample size.
B.
No, using the additional survey information from part (b) does not change the sample size.
C.
Yes, using the additional survey information from part (b) dramatically increases the sample size.
D.
No, using the additional survey information from part (b) only slightly increases the sample size.
Using the z-distribution, we have that:
a) A sample of 601 is needed.
b) A sample of 93 is needed.
c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which z is the z-score that has a p-value of [tex]\frac{1+\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so [tex]z = 1.96[/tex].
For this problem, we consider that we want it to be within 4%.
Item a:
The sample size is n for which M = 0.04.There is no estimate, hence [tex]\pi = 0.5[/tex][tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}[/tex]
[tex]0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}[/tex]
[tex]\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}[/tex]
[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2[/tex]
[tex]n = 600.25[/tex]
Rounding up:
A sample of 601 is needed.
Item b:
The estimate is [tex]\pi = 0.96[/tex], hence:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}[/tex]
[tex]0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}[/tex]
[tex]\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}[/tex]
[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2[/tex]
[tex]n = 92.2[/tex]
Rounding up:
A sample of 93 is needed.
Item c:
The closer the estimate is to [tex]\pi = 0.5[/tex], the larger the sample size needed, hence, the correct option is A.
For more on the z-distribution, you can check brainly.com/question/25404151