Answer:
$14
Step-by-step explanation:
56 × 0.25 = 14
to check this, you can divide 14 ÷ 56 = 0.25
to turn a percentage into a decimal, just divide it by 100
simplify x^2 + ax - 2a^2÷
3a^2 - 2ax - x^2?
Answer:
[tex] - \frac{x + 2a}{3a + x} [/tex]
Step-by-step explanation:
[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]
i) write ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]
ii) write -2ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]
iii) factor out x from the expression
[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
iv) factor out -a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
v) factor out a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]
vi) factor out -x from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]
vii) factor out x+2a from the expression
[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]
viii) factor out 3a+x from the expression
[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]
ix) factor out the negative sign from the expression and rearrange the term
[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]
x) reduce the fraction a-x
[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]
[tex] - \frac{x + 2a}{3a + x} [/tex]
When the price of Xis RM4 and the price of Y is RM10, which of the following combinations would be the intercept of axes
(X,Y) if you have an income of RM 100?
Select one:
A. (25X, 10Y)
B. (20X, 5Y)
C. (10X, 25Y)
D. (5X, 20Y)
What is the GCF of the expression -x2y22 - xy2z?
Answer:
i dont onderstand Thais
Once again Plssssssss Help Meh
Please help me out !!!
Answer:
If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!
Step-by-step explanation:
4x+5 = 2x+19
2x=14
x=7
4(7)+5+2(7)+19 = 42+24 = 66
6 ×3(2+9)..can you give the answer of it please
Answer:
Hope this may helps you
Step-by-step explanation:
6×3(11)
6×33
198
Answer:
198
Step-by-step explanation:
6 ×3(2+9)
= 6×3×11
= 6×33
= 198
help!!!!!please!!!!!!!
4x = 64 + 200
what is x
x=66
Step-by-step explanation:
4x = 200 + 64 > 4x = 264 > x= 66
Answer:
x=66
Step-by-step explanation:
Steps
4x=64+200
4x=264
x=66
12 points!! PLEASE
y =(x-3) - 4
rewrite these in standard and factored form!!
Standard form:
x - y = 7
Factored form:
y = x - 7
Answer:
y = x - 3 - 4
y = x - 7
(x - 7 = y)
(x = y + 7)
Step-by-step explanation:
Hope you got it.
In 1992, Jason bought a gallon of gas for $1.15. Yesterday, he bought a gallon of gas for $2.12. What is the percentage increase of the price of a gallon of gas from 1992 to yesterday? If necessary, round to the nearest tenth of a percent.
A.
84.3%
B.
45.8%
C.
54.2%
D.
15.7%
The rational function f is defined as, where h and g are polynomials.
The degree of h is m and the degree of g is n.
Which of the following statements are TRUE?
I. If m > n the absolute value of the function approaches positive infinity as x gets very large.
II. If m < n the value of the function approaches zero as x gets very large.
III. If m = n the value of the function approaches a constant as x gets very large.
Answer:
g
Step-by-step explanation:
x goes to f m to 5 :-)
Which of these graphs represents a function?
A)
A
B)
B
C)
С
D)
D
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
Mi duda está la final, cuando queda - tcost + sent + k, no sé cómo sustituir t= arcsent
Answer:
Explicación más abajo
Step-by-step explanation:
Integración Indefinida
La integral
[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]
Se resuelve con el cambio de variables:
t=arcsen(x)
Una vez hechos los cambios, la integral se resuelve en función de t:
[tex]I=sen(t)-t.cos(t)+C[/tex]
Hay que devolver los cambios para mostrarla en función de x.
El cambio de variables también se puede escribir:
x=sen(t)
Recordando que
[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]
Entonces:
[tex]cos(t)=\sqrt{1-x^2}[/tex]
Devolviendo los cambios:
[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]
Es la respuesta correcta
Someone help me out please
Caroline is correct because the equation y = (x-1)(x-5) is in factored form. If you solve the terms (x-1) and (x-5), you get the zeros (aka x-intercepts) of the graph.
Solve (set the terms equal to 0):
x-1 = 0 x = 1
x-5 = 0 x = 5
∴ the x-intercepts are (1,0) and (5,0).
The purple graph corresponds to the zeros in the equation, not the green graph. The green graph has negative x-intercepts, whereas the purple graph has positive x-intercepts like in the equation.
Find sin θ. Right Triangle Trigonometry.
Answer:
A. 16/20
General Formulas and Concepts:
Trigonometry
[Right Triangles Only] SOHCAHTOA[Right Triangles Only] sin∅ = opposite over hypotenuseStep-by-step explanation:
Step 1: Identify
Angle θ
Opposite Leg = 16
Hypotenuse = 20
Step 2: Find Ratio
Substitute [Sine]: sinθ = 16/20Answer:
A. 16/20
Step-by-step explanation:
The sine ratio is the opposite leg over the hypotenuse, opp/hyp.
For angle theta, the opposite leg is 16. The hypotenuse is 20.
sin (theta) = 16/20
Answer: A. 16/20
Find 56(−4⋅27). Write your answer in simplest form.
Answer:
[tex]-6048[/tex]
Step-by-step explanation:
[tex]---------------------------------[/tex]
[tex]56\left(-4\cdot27\right)[/tex] = [tex]-6048[/tex] [tex]because[/tex]
[tex]---------------------------------[/tex]
[tex]56\left(-4\cdot27\right)[/tex] = [tex]?[/tex]
[tex]\left(-4\cdot27\right)[/tex] = [tex]-108[/tex]
[tex]56\left(-108\right)[/tex] = [tex]?[/tex]
[tex]56\left(-108\right)[/tex] = [tex]-6048[/tex]
[tex]---------------------------------[/tex]
Hope this helps! <3
[tex]---------------------------------[/tex]
yall the answer is 0.17 hope this help
Answer:
I just saw a girl post the nastiest nu!des EVER
Help ASAP!!!!!A side of the triangle below has been extended to form and exterior angle of 159 degrees.Find the value of s
Answer:
x=21
Step-by-step explanation:
45+x+the last angle=180
x+159=180
180-159=21
21+45= 66
180-66=114
so i think x would be 21 degrees but im not entirely sure do not quote me on this sorry
Explain how to solve the equation.
B - 7 = 12
Answer:
So if you take the 12 and add it to the 7 you get 19 then do 19 mines 7 and you get 12 so always add the sum to the number given to get the missing number
Step-by-step explanation:
Have a great day
Evaluate the limit, if it exists. PLEASE SHOW WORK
lim x 5 x^2-3x-10\2x-10
Answer:
-350
Step-by-step explanation:
5×2-3×-10/2×-10
=10-3×-50
=7×-50
=-350
please help with this question (d+2)(-7)
Answer:
-7d-14
Step-by-step explanation:
First, let's distribute -7 to (d+2)
-7xd
-7x2
We will get -7d-14
Suppose a country's population at any time t grows in accordance with the rule dP dt = kP + I where P denotes the population at any time t, k is a positive constant reflecting the natural growth rate of the population, and I is a constant giving the (constant) rate of immigration into the country. If the total population of the country at time t = 0 is P0, find an expression for the population at any time t.
Answer:
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
Step-by-step explanation:
Given that:
A country population at any given time (t) is:
[tex]\dfrac{dP}{dt}= kP+I[/tex]
where;
P = population at any time t
k = positive constant
I = constant rate of immigration into the country.
Using the method of separation of the variable;
[tex]\dfrac{dP}{kP+1}= dt[/tex]
Taking integration on both sides:
[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]
[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]
[tex]log (kP + I) =k t+kc_1[/tex]
By applying the exponential on both sides;
[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]
[tex]KP+I = e^{kt} *e^{kc_1}[/tex]
Assume [tex]e^{kc_1 }= C[/tex]
Then:
[tex]kP + I = Ce^{kt}[/tex]
[tex]kP = Ce^{kt}-I[/tex]
[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]
When time t = 0, The Total population of the country is also [tex]P_o[/tex]
[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]
[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]
[tex]P_o = \dfrac{C-I}{k}[/tex]
C - I = kP₀
C = kP₀ + I
Substituting the value of C back into equation(1), we have:
[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]
[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
Lacey is buying a new car. She can get a station wagon, a truck, a hatchback, or a convertible. The outside paint comes in yellow or green. The seats can be covered with white leather or gray fabric. Given these choices, how many different combinations does Lacey have to choose from?
Step-by-step explanation:
4 different vehicles,
2 different paints,
2 different seats.
Total number of combinations = 4 * 2 * 2 = 16.
PLZ HELP ME WITH THIS!!! I WOULD MARK YOU BRAINLIEST!!!
the answer will be 2.5 hope that helps you
Answer:
2.5 or in other terms 2 1/2
Step-by-step explanation:
Compré 18 cuadernos, 24 carpetas y 17 lapiceras. El precio de las carpetas excede al de los cuadernos en un 40%, mientras que el precio de las lapiceras es el 20% del precio de los cuadernos. Si el importe de la compra fue de $11.825, calcular el precio unitario de cada artículo
Answer:talk some English dude
Step-by-step explanation:
In a class 3/4 of the boys like math, 1/2 like science, 1/4 of those who like science do not like math. How many boys like neither math nor science?
A. 1/4
B. 1/6
C. 1/2
D. 1/8
By what percent is 16 greater than 12.
Answer:
28 i assume.
Answer:
The answer is 28% :))
I need help please I am having hard time doing this
Answer:you are corect its negetive
Step-by-step explanation:
A certain radioactive isotope has a half-life of 50 years. A scientist determines that there are 200 grams of the radioactive material present today. How
Much of the isotope was present 200 years ago?
im guessing 800 50X4 = 200 and 200X4 = 800
i never learned this but i hope its correct.
If point C lies between two points A and B such that AC=BC, then
Answer:
If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.
You’ve learned to identify whether a function is even or odd both graphically and algebraically. How does the notation for reflections over the x-axis and over the y-axis relate to the notation for even and odd functions? Remember that if f(-x) = f(x), a function is even, and if f(-x) = -f(x), then the function is odd.
Answer:
Because even and odd are 2 different ways to determine whether or not you get the right answer for the chosen function.
Step-by-step explanation:
Hope this helps!!!
Answer:
For even functions, we take f(-x) to be the starting function. The y-axis reflection of this function is f(-(-x)), which is equal tof(x). So the relationship f(-x) = f(x) means that the function is the same as its y-axis reflection.
For odd functions, there are two reflections that must occur. First, we start with f(-x). The y-axis reflection of this function is f(-(-x)) = f(x). When we apply an x-axis reflection to this result, we get -f(-(-x)) = -f(x). So the fact that f(-x) = -f(x) means that odd functions are the same as sequential reflections across both the x-axis and the y-axis. (The same sequence of reflections also represents a rotation 180 degrees about the origin).
Step-by-step explanation: