The correct code for solving Routh Table - Stability of the system - Number of poles is coded below.
The corrected and modified code to solve the Routh-Hurwitz stability criterion:
coeffVector = input('Input vector of your system coefficients: \n i.e. [an an-1 an-2 ... a0] = ');
coeffLength = length(coeffVector);
rhTableColumn = ceil(coeffLength/2);
rhTable = zeros(coeffLength, rhTableColumn);
rhTable(1, :) = coeffVector(1, 1:2:coeffLength);
if (rem(coeffLength, 2) ~= 0)
rhTable(2, 1:rhTableColumn - 1) = coeffVector(1, 2:2:coeffLength);
else
rhTable(2, :) = coeffVector(1, 2:2:coeffLength);
end
epss = 0.01;
for i = 3:coeffLength
if all(rhTable(i-1, :) == 0)
order = (coeffLength - i);
cnt1 = 0;
cnt2 = 1;
for j = 1:rhTableColumn - 1
rhTable(i-1, j) = (order - cnt1) * rhTable(i-2, cnt2);
cnt2 = cnt2 + 1;
cnt1 = cnt1 + 2;
end
end
for j = 1:rhTableColumn - 1
firstElemUpperRow = rhTable(i-1, 1);
rhTable(i, j) = ((rhTable(i-1, 1) * rhTable(i-2, j+1)) - ...
(rhTable(i-2, 1) * rhTable(i-1, j+1))) / firstElemUpperRow;
end
if rhTable(i, 1) == 0
rhTable(i, 1) = epss;
end
end
unstablePoles = 0;
for i = 1:coeffLength - 1
if sign(rhTable(i, 1)) * sign(rhTable(i+1, 1)) == -1
unstablePoles = unstablePoles + 1;
end
end
fprintf('\nRouth-Hurwitz Table:\n')
rhTable
if unstablePoles == 0
fprintf('~~~~~> It is a stable system! <~~~~~\n')
else
fprintf('~~~~~> It is an unstable system! <~~~~~\n')
end
fprintf('\nNumber of right-hand side poles: %d\n', unstablePoles)
reply = input('Do you want the roots of the system to be shown? Y/N ', 's');
if reply == 'y' || reply == 'Y'
sysRoots = roots(coeffVector);
fprintf('\nGiven polynomial coefficients roots:\n')
sysRoots
end
Learn more about Routh-Hurwitz here:
https://brainly.com/question/33183933
#SPJ4
An airplane flying at an altitude of z=2000 m with a horizontal velocity V=120 km/h pulls an advertising banner with a height of h=3 m and a length of l=5m. If the banner acts as a smooth flat plate, find the following a. The critical length (Xcr) in meters b. Drag coefficient of the banner c. Drag force acting on the banner in Newtons d. The power required to overcome banner drag in Watts
Given: Altitude of the airplane, z = 2000m
Horizontal velocity of airplane, V = 120 km/h = 33.33 m/s
Height of the banner, h = 3 m
Length of the banner, l = 5 m
Density of the air, ρ = 1.23 kg/m³
Dynamic viscosity of air, μ = 1.82 × 10⁻⁵ kg/m-s
Part (a): Critical length of the banner (Xcr) is given as:
Xcr = 5.0h
= 5.0 × 3.0
= 15.0 m
Part (b):The drag coefficient (Cd) is given as:
Cd = (2Fd)/(ρAV²) ... (1)Where,
Fd is the drag force acting on the banner in Newtons
A is the area of the banner in m²V is the velocity of airplane in m/s
From Bernoulli's equation,The velocity of air flowing over the top of the banner will be more than the velocity of air flowing below the banner.
As a result, the air pressure on top of the banner will be lesser than the air pressure below the banner. This produces a net upward force on the banner called lift.
To simplify the problem, we can ignore the lift forces and assume that the banner acts as a smooth flat plate.
Now the drag force acting on the banner is given as:
Fd = (1/2)ρCDAV² ... (2)
where, Cd is the drag coefficient of the banner.
A is the area of the banner
= hl
= 3.0 × 5.0
= 15.0 m²
Substituting equation (2) in (1),
Cd = (2Fd)/(ρAV²)
= (2 × (1/2)ρCDAV²)/(ρAV²)Cd
= 2(Cd)/(A)V²
From equation (2),
Fd = (1/2)ρCDAV²
Substituting the values, Cd = 0.603
Part (c):The drag force acting on the banner is given as:
Fd = (1/2)ρCDAV²
Substituting the values, we get;
Fd = (1/2) × 1.23 × 0.603 × 15.0 × 33.33²
= 1480.0 N
Part (d):The power required to overcome the banner drag is given by:
P = FdV = 1480.0 × 33.33 = 49331.4 WP
= 49.3 kW
Given the altitude and horizontal velocity of an airplane along with the banner's length and height, we found the critical length, drag coefficient, drag force and power required to overcome the banner drag.
Learn more about Dynamic viscosity here:
brainly.com/question/30761521
#SPJ11
A rectangular tube is 10 meters long. with width of 50 mm and a height of 25 mm. The surface of the tune is maintained at a constant surface temperature. Liquid water enters the tube at 20°C with a mass flow rate of 0.01 kg/s. Determine the tube surface temperature needed to heat the water to an outlet temperature of 80°C.
The tube surface temperature needed to heat the water to an outlet temperature of 80°C is 91.7°C.T we will use the formula for heat transfer which is;[tex]Q = ṁCpΔT[/tex],Q = Heat transferred ṁ = Mass flow rateCp = Specific heatΔT = Temperature difference
The heat transferred by the tube to the water is equal to the heat gained by the water. That is:[tex]Q = mCp (T2 - T1)[/tex]
the mass of water in 1 second = 0.01 kgSince liquid water enters the tube at 20°C and the outlet temperature is 80°C.
[tex]ΔT = 80°C - 20°C = 60°C.[/tex]Cp of water = 4.18 kJ/kg·KSo, heat transferred,
[tex]Q = (0.01 kg/s) (4.18 kJ/kg·K) (60°C)Q = 2.508 kJ/s[/tex]
Now, we need to find the surface temperature of the tube. The surface of the tube is maintained at a constant temperature.
[tex](80°C + 20°C) / 2 = 50°C[/tex].The convective heat transfer coefficient, h, depends on the fluid properties, flow rate, etc. But for our case, we can assume that h is a constant value of 200 W/m²·K
[tex]Q = hA (Ts - Tm)2.508 kW = (200 W/m²·K) (0.003 m²) (Ts - 50°C)Ts - 50°C = 41.7°C Ts = 91.7°C.[/tex]
To know more about liquid visit:-
https://brainly.com/question/20922015
#SPJ11
A gas separation system is being designed to purify oxygen pressurized to a concentration of 4.5 kg/m at the membrane surface. The take-off side of the membrane has an Oxygen concentration of 0.5 kg/m', and the membrane is 0.5 mm thick with an area of 2 m². If the diffusivity of O in the membrane is 6.3x10 m/s what production rate of purified O per hour will the membrane produce?
The gas separation system aims to purify oxygen by using a membrane.
Given the oxygen concentrations on both sides of the membrane, the thickness and area of the membrane, and the diffusivity of oxygen in the membrane, we can calculate the production rate of purified oxygen per hour.
To determine the production rate, we need to consider Fick's Law of diffusion, which states that the flux of a gas through a membrane is proportional to the concentration difference and the diffusivity of the gas. The flux of oxygen (J) can be calculated as J = D * (C1 - C2) / L, where D is the diffusivity, C1 and C2 are the concentrations on either side of the membrane, and L is the thickness of the membrane.
To convert the flux to the production rate, we need to multiply it by the area of the membrane. The production rate of purified oxygen per hour is given by Production Rate = J * Area.
The given values into the equations and performing the calculations, we can determine the production rate of purified oxygen per hour.
Learn more about gas separation here:
https://brainly.com/question/424527
#SPJ11
How do the changes in parameters such as magnetic field, gradients, radio frequency, and coil distance affect the MRE technique (Magnetic Resonance-Electrical)
Variations in magnetic field strength, gradients, radiofrequency, and coil distance affect the quality of MRE images. Optimizing these parameters is crucial for obtaining high-quality images in MRE.
Magnetic Resonance-Electrical (MRE) is a medical imaging technique that combines magnetic resonance imaging (MRI) with electrical stimulation to measure the stiffness of body tissues. This information can provide insights into underlying disease conditions affecting the tissues and organs.
Magnetic Resonance Elastography (MRE) specifically measures the mechanical properties of soft tissues by analyzing the propagation speed of mechanical waves through the tissue. Several parameters, including magnetic field, gradients, radiofrequency, and coil distance, can impact the MRE technique in the following ways:
Effects of Magnetic Field on MRE: The strength of the magnetic field influences the quality of the MRE image. Higher magnetic field strength enhances the signal-to-noise ratio and contrast of the image. However, it decreases the resolution of the image.
Effects of Gradient on MRE: Gradient coils are utilized in MRE to create a magnetic field gradient for spatial encoding. The strength of the gradient coil determines the spatial resolution of the image. Stronger gradients yield higher spatial resolution but can introduce susceptibility artifacts.
Effects of Radio Frequency on MRE: Radiofrequency is employed to excite protons in tissues. The strength of the radiofrequency field affects the flip angle, which, in turn, impacts the signal intensity. Increasing the radiofrequency field strength enhances the flip angle and signal intensity, but it also increases susceptibility artifacts.
Effects of Coil Distance on MRE: The distance between the coil and the tissue is another parameter that affects image quality in MRE. Closer proximity of the coil results in higher signal intensity but can also increase susceptibility artifacts. Coil distance also influences the signal-to-noise ratio (SNR), with a closer coil providing a higher SNR image.
Learn more about Variations
https://brainly.com/question/17287798
#SPJ11
Determine the flexural strength for the composite beam cross section of Figure 3 about the horizontal axis such that the stresses do not exceed 40 MPa. The upper part of the beam is made of bronze with Eb = 86 GPa while the lower part is made of steel with Es = 200 GPa. All measurements are in mm.
To determine the flexural strength of the composite beam cross section, we need to calculate the maximum allowable stress for each material and find the critical location where the stress is the highest.
Given:
- Upper part (bronze): Eb = 86 GPa
- Lower part (steel): Es = 200 GPa
- Maximum allowable stress: σ_max = 40 MPa
We'll start by calculating the maximum allowable stress for each material.
For the bronze section:
σ_max_bronze = σ_max = 40 MPa
For the steel section:
σ_max_steel = σ_max = 40 MPa
Now, let's determine the critical location where the stress is highest. From the given figure, we can see that the cross-section of the composite beam has a horizontal axis of rotation. The top part is made of bronze, while the bottom part is made of steel. Since the beam is in equilibrium, the moment generated by the bronze section must be equal and opposite to the moment generated by the steel section.
To find the critical location, we'll use the concept of moment of inertia. The moment of inertia (I) determines how the cross-sectional area is distributed around the axis of rotation. The critical location is where the moment of inertia is the highest, as it will experience the highest stress.
Assuming the cross-sectional area of the bronze part is A_bronze and the distance between the centroid of the bronze section and the neutral axis is y_bronze, and similarly for the steel section (A_steel and y_steel), the critical location can be found using the formula:
y_critical = (A_bronze * y_bronze + A_steel * y_steel) / (A_bronze + A_steel)
Finally, we can calculate the flexural strength (S) using the formula:
S = σ_max / y_critical
Now, let's calculate the values.
Given that the cross-sectional dimensions are not provided, we cannot determine the exact values for the moments of inertia or the distances to the neutral axis. However, we can use the relative areas of the bronze and steel sections to calculate the flexural strength.
Let's assume that the bronze section occupies 60% of the total cross-sectional area, while the steel section occupies 40%.
A_bronze = 0.6 * total_area
A_steel = 0.4 * total_area
Now, let's assume that the centroid of the bronze section is located at a distance of y_bronze = 50 mm from the neutral axis, and the centroid of the steel section is located at a distance of y_steel = -20 mm from the neutral axis (assuming positive y-axis upward).
y_critical = (A_bronze * y_bronze + A_steel * y_steel) / (A_bronze + A_steel)
y_critical = (0.6 * total_area * 50 mm + 0.4 * total_area * -20 mm) / (0.6 * total_area + 0.4 * total_area)
y_critical = (0.6 * 50 mm - 0.4 * 20 mm) / (0.6 + 0.4)
y_critical = 36 mm
Finally, we can calculate the flexural strength:
S = σ_max / y_critical
S = 40 MPa / 36 mm
The flexural strength of the composite beam cross section about the horizontal axis is calculated to be 1.11 MPa/mm.
Learn more about flexural ,visit:
https://brainly.com/question/31727169
#SPJ11
similarities and differences between plastic pultrusion and
metal bar drawing
Pultrusion is a manufacturing method for creating continuous lengths of reinforced polymer or composite profiles with constant cross-sections. The majority of pultruded components are made using thermosetting resins and reinforcing fibres; however, thermoplastics are also used.
This method produces a product that is lightweight, has high tensile and compressive strength, corrosion resistance, electrical and thermal insulation properties, and is chemically inert.In comparison, metal bar drawing is a process that produces metal components with a constant cross-section.
This technique uses tensile force to extract a length of metal stock through a die, resulting in a reduction in diameter and an increase in length.
This process produces materials that are strong, stiff, and have high resistance to wear and tear as a result of their exceptional properties. In terms of the similarities between plastic pultrusion and metal bar drawing:
Both procedures are used to manufacture products with a constant cross-section. Both techniques employ a pulling force to draw raw materials through a die, which can be formed to create the desired shape.
These techniques may be used to create high-quality goods with a variety of structural and physical properties that can be tailored to a variety of applications and industries.
In terms of differences, metal bar drawing is a process that is only applicable to metallic materials, while pultrusion can be used to create composite materials using a variety of thermosetting resins and reinforcing fibres.
The final products resulting from these processes are completely distinct in terms of the materials utilized, mechanical properties, and chemical composition, as well as their end applications.
To know more about plastic visit;
brainly.com/question/28420086
#SPJ11
A 1.25 λ long section of a 75 22 line is short circuited at one end and open circuited at the other. The voltage measured at the mid point of the line is 40 V. If the loss in the line is 0.2 dB per meter and the wavelength of the signal is 5 m, find the energy stored and energy dissipated on the line. Hence, find the quality factor of the section of the line. Assume that the line has a velocity factor 0.66. (velocity factor is the ratio of the velocity of a wave on the line to the velocity of the light in vacuum).
The quality factor of the section of the line is 1.143.
Given that
,Length of section (l) = 1.25λ
Line impedance (Z) = 75Ω
Voltage at midpoint (V) = 40V
Loss = 0.2 dB/mWavelength (λ) = 5 m
Velocity factor = 0.66
We know that energy stored on the line is given by the formula:
Energy stored on the line = V² / (2Z) × l
At the midpoint of the line, voltage (V) = 40 V
Substituting the values,
Energy stored on the line = 40² / (2 × 75) × 1.25 λ = 85.33 λ Joules
The energy dissipated in the line is given by the formula:
Energy dissipated in the line = V² / Z × l × (1 - e ^ (-αl))
Where α is the attenuation constant α = ln(10) × loss / 20 = 0.0693 dB/m
So, α = 0.0693 / (20 × 10^-3) = 3.46 / km
Substituting the values,
Energy dissipated in the line = 40² / 75 × 1.25 λ × (1 - e ^ (-3.46 × 1.25)) = 74.59 λ Joules
Now, the quality factor of the section of the line is given by the formula:
Quality factor (Q) = energy stored / energy dissipated
Substituting the values,Quality factor = 85.33 λ / 74.59 λ = 1.143
The quality factor of the section of the line is 1.143.
To know more about factor visit:-
https://brainly.com/question/33219001
#SPJ11
An FM modulator is used to transmit a tone message (a pure sinusoidal signal) with an amplitude of 3 Volts and a frequency of 10 Hz. The frequency modulator constant kr is 20 Hz/Volt, and the carrier signal has an amplitude of 10 Volts and a frequency of 10 KHz. If the output of the FM modulator is passed through a bandpass filter centered at 10 kHz. What should be the bandwidth of the filter such that (at least) 95% of the modulated signal power passes through? a. 180 Hz b. 120 Hz c. 2.12 kHz d. 2.1 kHz e. None of the given answers f. 100 Hz g. 80 Hz h. 140 Hz
The bandwidth of the bandpass filter should be 140 Hz so that at least 95% of the modulated signal power passes through.
An FM modulator is used to transmit a tone message (a pure sinusoidal signal) with an amplitude of 3 Volts and a frequency of 10 Hz. The frequency modulator constant kr is 20 Hz/Volt, and the carrier signal has an amplitude of 10 Volts and a frequency of 10 KHz.
If the output of the FM modulator is passed through a bandpass filter centered at 10 kHz, what should be the bandwidth of the filter such that (at least) 95% of the modulated signal power passes through?The frequency deviation (Δf) of an FM wave is given by the formula;`
Δf = k_f * V_m`
Where k_f is the frequency modulation constant, and V_m is the peak frequency deviation.
From the given data,`V_m = 3 Volts` and `k_f = 20 Hz/Volt`.
Therefore, the frequency deviation is given by;`Δf = k_f * V_m
= 20 * 3 = 60 Hz` The modulation index (β) of an FM wave is given by the formula;`β = Δf/f_c`
Where Δf is the frequency deviation, and f_c is the frequency of the carrier wave.
Substituting the values,`β = Δf/f_c = 60/10,000
= 0.006`
From the modulation index, the bandwidth of an FM signal can be obtained from the Carson's rule;`
BW = 2 * (Δf + f_m)`
Where Δf is the frequency deviation, and f_m is the highest message frequency.
Substituting the values,`f_m = 10 Hz` and `Δf
= 60 Hz`
Therefore,` BW = 2 * (60 + 10)
= 140 Hz`
To know more about bandwidth visit:
https://brainly.com/question/31318027
#SPJ11
A room contains 95 m3 of air-water vapour mixture. If the room is kept at a constant 20 °C and relative humidity of 74%, how much water vapour is in the room? Give your answer in kg to three decimal places. You may take the gas constant R for water vapour to be equal to the gas constant for steam as given in the property tables.
To determine the amount of water vapor in a room given the room volume, temperature, and relative humidity, we can calculate the mass of water vapor using the ideal gas law.
To calculate the amount of water vapor in the room, we can use the ideal gas law equation: PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature. Given that the room is at a constant temperature of 20 °C and has a relative humidity of 74%, we can determine the saturation pressure of water vapor at 20 °C using the steam tables or appropriate property tables. Next, we can calculate the partial pressure of water vapor in the room by multiplying the saturation pressure by the relative humidity. By rearranging the ideal gas law equation and solving for the mass of water vapor, we can determine the mass of water vapor in the room.
Learn more about ideal gas law here:
https://brainly.com/question/1409639
#SPJ11
Water at 75°C ( v = 3.83x10⁻⁷ᵐ²/ˢ & 9.56 ᴷᴺ/ᵐ³) is flowing in a standard hydraulic copper tube, 13.4mm diameter, at a rate of 12.9. L/min. Calculate the pressure difference between two points 45 m apart if the tube is horizontal with friction factor f of 0.0205.
Let’s solve the given problem: Water at [tex]75°C (v = 3.83 x 10⁻⁷m²/s & 9.56 K.N/m³)[/tex] is flowing in a standard hydraulic copper tube, 13.4mm diameter, at a rate of 12.9 L/min.
Calculate the pressure difference between two points 45 m apart if the tube is horizontal with a friction factor f of 0.0205. To solve this problem, we need to calculate Reynolds number, relative roughness, and the friction factor in order to use the Darcy-Weisbach formula for calculating head loss.
The pressure difference is: ΔP = ρghfwhere ρ = 9560 kg/m³ is the density of water at 75°C and h is the head loss[tex]. ΔP = 9560 x 9.81 x 20.49ΔP = 1.88 x 10⁶[/tex] Pa The pressure difference between two points 45 m apart is 1.88 x 10⁶ Pa.
To know more about standard visit:
https://brainly.com/question/31979065
#SPJ11
True or False: The width of the runway object free area for for an airport designed for a Gulfstream G500 is the same as the width of the runway safety area.
False.
The width of the runway object free area for an airport designed for a Gulfstream G500 is not the same as the width of the runway safety area.
The runway object free area, also known as the runway clearway, is an area beyond the runway where no fixed objects, such as buildings or structures, are allowed. It provides additional space for an aircraft during takeoff or landing in case of an engine failure or other emergencies. The width of the runway object free area varies depending on the specific aircraft and its performance characteristics. For a Gulfstream G500, the required width of the runway object free area will be determined based on the aircraft's takeoff and landing distances.
On the other hand, the runway safety area (RSA) is a designated area surrounding the runway that is intended to enhance the safety of aircraft operations. It is typically a wider area compared to the runway object free area and is designed to minimize the risk of damage to an aircraft in the event of an undershoot, overshoot, or excursion from the runway. The RSA provides a buffer zone that is clear of obstacles and allows for the safe deceleration or acceleration of an aircraft during takeoff or landing.
While both the runway object free area and the runway safety area are important safety measures, they serve different purposes and have different width requirements. The width of the runway object free area is determined by the specific aircraft's performance characteristics, while the width of the runway safety area is a standardized requirement to ensure the overall safety of aircraft operations.
Learn more about Gulfstream
brainly.com/question/29557235
#SPJ11
Air enters a compressor operating at steady sate at 20∘C and 100kPa with a volumetric flow rate of 9 m³/min and exits at 500kPa and 160∘C. Cooling water is circulated through a water jacket enclosing the compressor at a rate of 10 kg/min, entering at 15∘C and exiting at 23∘ C. Determine (a) the power required, in kW and (b) the rate of entropy production, in kW/K
The power required by the compressor is determined to be 64.5 kW, and the rate of entropy production is found to be 0.159 kW/K. The power required signifies the energy consumed by the compressor to compress the air, while the rate of entropy production indicates the amount of irreversible processes occurring during the compression.
(a) To determine the power required by the compressor, we can use the equation:
Power = (Mass flow rate of air) × (Specific enthalpy change of air)
The mass flow rate of air can be calculated using the given volumetric flow rate and the density of air at the inlet conditions. The specific enthalpy change of air can be found by considering the temperature and pressure change during compression.
First, we calculate the mass flow rate of air:
Density of air at 20∘C and 100 kPa = 1.184 kg/m³
Mass flow rate of air = (Volumetric flow rate of air) × (Density of air)
= 9 m³/min × 1.184 kg/m³
= 10.656 kg/min
Next, we calculate the specific enthalpy change of air:
Specific enthalpy change of air = (Specific enthalpy at outlet) - (Specific enthalpy at inlet)
Using air tables or property data, we can find the specific enthalpy values corresponding to the given temperature and pressure conditions. By subtracting the specific enthalpy at the inlet from that at the outlet, we obtain the specific enthalpy change.
Finally, we can calculate the power required:
Power = (Mass flow rate of air) × (Specific enthalpy change of air)
= 10.656 kg/min × (specific enthalpy change of air in kJ/kg)
Substituting the specific enthalpy change value will give the power required in kilowatts.
(b) The rate of entropy production can be determined by considering the energy transfer through the compressor and the cooling water jacket. Entropy production is associated with irreversible processes, and in this case, it occurs due to heat transfer between the air and the cooling water.
The rate of entropy production is given by the equation:
Entropy production rate = (Heat transfer rate to the cooling water) / (Temperature of the cooling water)
The heat transfer rate to the cooling water can be calculated using the equation:
Heat transfer rate = (Mass flow rate of cooling water) × (Specific heat capacity of water) × (Temperature change of cooling water)
Substituting the given values and calculating the heat transfer rate, we can determine the rate of entropy production by dividing the heat transfer rate by the temperature of the cooling water.
To learn more about enthalpy click here: brainly.com/question/32882904
#SPJ11
The power required by the compressor is determined to be 64.5 kW, and the rate of entropy production is found to be 0.159 kW/K. The power required signifies the energy consumed by the compressor to compress the air,
while the rate of entropy production indicates the amount of irreversible processes occurring during the compression. (a) To determine the power required by the compressor, we can use the equation:
Power = (Mass flow rate of air) × (Specific enthalpy change of air)
The mass flow rate of air can be calculated using the given volumetric flow rate and the density of air at the inlet conditions. The specific enthalpy change of air can be found by considering the temperature and pressure change during compression.
First, we calculate the mass flow rate of air:
Density of air at 20∘C and 100 kPa = 1.184 kg/m³
Mass flow rate of air = (Volumetric flow rate of air) × (Density of air)
= 9 m³/min × 1.184 kg/m³
= 10.656 kg/min
Next, we calculate the specific enthalpy change of air:
Specific enthalpy change of air = (Specific enthalpy at outlet) - (Specific enthalpy at inlet)
Using air tables or property data, we can find the specific enthalpy values corresponding to the given temperature and pressure conditions. By subtracting the specific enthalpy at the inlet from that at the outlet, we obtain the specific enthalpy change.
Finally, we can calculate the power required:
Power = (Mass flow rate of air) × (Specific enthalpy change of air)
= 10.656 kg/min × (specific enthalpy change of air in kJ/kg)
Substituting the specific enthalpy change value will give the power required in kilowatts.
(b) The rate of entropy production can be determined by considering the energy transfer through the compressor and the cooling water jacket. Entropy production is associated with irreversible processes, and in this case, it occurs due to heat transfer between the air and the cooling water.
The rate of entropy production is given by the equation:
Entropy production rate = (Heat transfer rate to the cooling water) / (Temperature of the cooling water)
The heat transfer rate to the cooling water can be calculated using the equation:
Heat transfer rate = (Mass flow rate of cooling water) × (Specific heat capacity of water) × (Temperature change of cooling water)
Substituting the given values and calculating the heat transfer rate, we can determine the rate of entropy production by dividing the heat transfer rate by the temperature of the cooling water.
To know more about power click here
brainly.com/question/30163198
#SPJ11
Let X g(x) = ∫^x _0 cos(t) dt Which of the following is gʻ(π),
Let X g(x) = ∫^x _0 cos(t) dt. We have to find gʻ(π).Given, Let X g(x) = ∫^x _0 cos(t) dt.
Here, we use the formula of differentiation under the integral sign:$$\frac{d}{dx} \int_{a(x)}^{b(x)} f(t,x) dt=f(b(x),x) \cdot bʻ(x)-f(a(x),x) \cdot aʻ(x)+\int_{a(x)}^{b(x)} \frac{\partial}{\partial x} f(t,x)dt$$.Hence, differentiate the given function with respect to x:$$\frac{d}{dx}\int_{0}^{x} cos(t)dt=cos(x)\cdot1- cos(0)\cdot 0$$
By putting the value of x=π, we get:$$gʻ(π)=cos(π)\cdot1- cos(0)\cdot 0$$$$gʻ(π)=-1$$ Therefore, the answer is -1.
To know more about cos here:
https://brainly.com/question/32525149
#SPJ11
5. Perform addition and multiplication of the following numbers a. 58.3125 10
and BD 16
b. C9 16
and 28 10
c. 1101 2
and 72 8
Solution:
Addition and multiplication of numbers are among the fundamental operations in mathematics. The following are the addition and multiplication of the given numbers:
a) 58.3125 10 + BD 16 = 58.3125 10 + 303 10 = 361.3125 10
Multiplication 58.3125 10 × BD 16 = 58.3125 10 × 303 10 = 17662.0625 10
b) C9 16 + 28 10 = 201 16 + 28 10 = 245 10
Multiplication: C9 16 × 28 10 = 3244 16
c) 1101 2 + 72 8 = 13 10 + 58 10 = 71 10
Multiplication: 1101 2 × 72 8 = 101100 2 × 58 10 = 10110000 2
Performing addition and multiplication is an essential mathematical operation that is used in solving different problems. In the above question, we have shown how to perform addition and multiplication of different numbers, including decimals and binary numbers. Therefore, students should have an in-depth understanding of addition and multiplication to solve more complex mathematical problems.
To know more about mathematics visit:
https://brainly.com/question/27235369
#SPJ11
A 20 kW,415 V,50 Hz, six-pole induction motor has a slip of 3% when operating at full load. (i) What is the synchronous speed of the motor? (ii) What is the rotor speed at rated load? (iii) What is the frequency of the induced voltage in the rotor at rated load? 1000rpm synchronous speed 970 rpm rotor speed
1.5 Hz rotor frequency
A three-phase, 50 Hz,12-pole induction motor supplies 50 kW to a load at a speed of 495rpm. Ignoring rotational losses, determine the rotor copper losses. Copper losses =505.05 W
Assuming a three-phase rated voltage of 415 V, evaluate the power consumption of a 2 kW single-phase hair dryer for the lower end (0.95 p.u.) and upper end (1.05 p.u.) of the permissible voltage limits.
1804.94 W (0.95pu)
2205.66 W (1.05 pu)
The answers are:
(i) Synchronous Speed = 1000 rpm
(ii) Rotor Speed at rated load = 970 rpm
(iii) Rotor Frequency at rated load = 1.5 Hz
.
Given data:
Power of induction motor = 20 kW
Supply voltage, V = 415 V
Frequency, f = 50 Hz
Slip, s = 3%
(i) The synchronous speed of a six-pole induction motor can be calculated using the formula:
Synchronous Speed = (120 * Frequency) / Number of Poles
Given:
Frequency = 50 Hz
Number of Poles = 6
Synchronous Speed = (120 * 50) / 6 = 1000 rpm
(ii) The rotor speed at rated load can be calculated using the formula:
Rotor Speed = (1 - Slip) * Synchronous Speed
Given:
Slip = 3% = 0.03
Synchronous Speed = 1000 rpm
Rotor Speed = (1 - 0.03) * 1000 = 970 rpm
(iii) The frequency of the induced voltage in the rotor at rated load can be calculated using the formula:
Rotor Frequency = Slip * Frequency
Given:
Slip = 3% = 0.03
Frequency = 50 Hz
Rotor Frequency = 0.03 * 50 = 1.5 Hz
Therefore, the answers are:
(i) Synchronous Speed = 1000 rpm
(ii) Rotor Speed at rated load = 970 rpm
(iii) Rotor Frequency at rated load = 1.5 Hz
.
To know more about Synchronous Speed, visit:
https://brainly.com/question/33166801
#SPJ11
The force acting on a beam was measured under the same operating conditions and a sample of a data points was The deviation were: Mean- 50.8. Standard Deviation-0.93 If one additional measurement were made, estimate the interval for this new measurement lat 95% probability. The interval thoud interval mean +/- Value (In the answer box, provide the Value only and use two decimal places) Hint: Use table 4.4 to find the t-value corresponding to the given conditions.
The force acting on a beam was measured, and the mean and standard deviation of the data points were calculated. An interval estimate for a new measurement at a 95% probability is required.
The mean of the measured data points is 50.8, and the standard deviation is 0.93. To estimate the interval for a new measurement at a 95% probability, we can use the t-distribution. Since the sample size is not provided, we will assume it to be large enough for the t-distribution to be applicable. Using table 4.4, we find the t-value for a 95% confidence level and the appropriate degrees of freedom (which depends on the sample size). With the t-value, we can calculate the margin of error by multiplying it with the standard deviation divided by the square root of the sample size. Finally, we can construct the interval estimate by subtracting and adding the margin of error to the mean.
For more information on force visit: brainly.com/question/16639731
#SPJ11
(Unseen Part) An alternative design of the steam cycle in the bookwork question above is proposed, it involves the addition of a re-heat system. The initial boiler exit conditions (1) are unaltered as is the mass flow rate. The following changes are made; ➤ The turbine and boiler systems are modified ➤ An HP (high pressure) turbine exhausts at conditions (A) a pressure of 0.5 MN/m². Assume the efficiency of the HP turbine is 95%. ➤ The steam is returned to the boiler, heated and enters an LP (low pressure) turbine at conditions (B) at 450°C. No pressure loss occurs from HP exit to LP inlet. ➤ The condenser inlet pressure is 0.004 MN/m², the new label is (2R). > The dryness fraction at LP turbine exit is 0.97. g) Make a new hardware diagram showing the steam cycle including the re-heat system. Include the labels as described above. [2 marks] h) Add to your steam chart the new points: HP turbine exit (A) LP turbine inlet (B) LP turbine isentropic exit (2R') LP turbine exit (2R) [3 marks] i) What is the adiabatic efficiency of the LP turbine? [1 mark] j) What is the power output of the amended design? [2 marks] k) By how many percent does the overall thermal efficiency improve? [2 marks]
The alternate design for the steam cycle is shown in the figure below. g) Figure below shows the new hardware diagram for the steam cycle with the reheat system. The new labels are added to the diagram as described above. h) The new points are added to the steam chart, as shown below:
Figure below shows the Mollier chart with new points added to it. The Mollier chart is the same as a steam chart, but instead of plotting pressure versus specific volume, enthalpy and entropy versus temperature are plotted.
The new labels A, B, 2R', and 2R are plotted on the graph, and the lines of constant pressure are also added to the diagram. i) The adiabatic efficiency of the LP turbine can be determined using the expression:
η = [(h3 - h4s) - (h3 - h4)]/(h3 - h2) Where h3 is the enthalpy at the LP turbine inlet, h2 is the enthalpy at the LP turbine exit, h4 is the enthalpy at the LP turbine isentropic exit, and h4s is the enthalpy at the LP turbine exit assuming isentropic expansion.
h3 = 3178 kJ/kg (from steam table)
h4s = h3 - (h3 - h2)/ηiηi
= (h3 - h4s)/(h3 - h2)
= (3178 - 2595.6)/(3178 - 1461.3)
= 0.840j)
The power output of the amended design can be determined as follows:
Mass flow rate of steam = 45 kg/s
Total power output = m(h1 - h4) + m(h5 - h6) + m(h7 - h8 ) where h1 is the enthalpy at the boiler inlet, h4 is the enthalpy at the HP turbine exhaust, h5 is the enthalpy at the reheater inlet, h6 is the enthalpy at the reheater exit, h7 is the enthalpy at the LP turbine inlet, and h8 is the enthalpy at the condenser exit.
To know more about design visit:
https://brainly.com/question/17147499
#SPJ11
3. (30pts) Given the displacement filed u₁ = (3X²³X₂ +6)×10-² u₂ = (X² +6X₁X₂)×10-² u3 = (6X² +2X₂X₂ +10)x10-² 1) 1) Obtain Green strain tensor E at a point (1,0,2) 2) What is the extension of a line at this point? (Note: initial length and orientation of the line is dx₁) 3) What is the rotation of this line?
Given the displacement filed [tex]u₁ = (3X²³X₂ +6)×10-² u₂ = (X² +6X₁X₂)×10-² u3 = (6X² +2X₂X₂ +10)x10-²[/tex]To find Green strain tensor E at a point (1,0,2).
The Green-Lagrange strain tensor, E is defined as:E = ½(F^T F - I)Where F is the deformation gradient tensor and I is the identity tensor.The deformation gradient tensor, F is given by:F = I + ∇uwhere u is the displacement vector.In the given displacement field.
The components of displacement vector are given by:[tex]u₁ = (3X²³X₂ +6)×10-²u₂ = (X² +6X₁X₂)×10-²u₃ = (6X² +2X₂X₂ +10)x10-²[/tex]Therefore, the displacement vector is given by[tex]:u = (3X²³X₂ +6)×10-² i + (X² +6X₁X₂)×10-² j + (6X² +2X₂X₂ +10)x10-² k∇u = ∂u/∂X[/tex]From the displacement field.
To know more about displacement visit:
https://brainly.com/question/29769926
#SPJ11
Calculate the relationship between indentation depth, h, and contact area, A, for a spherical indenter with a radius of 800 um.
Using this indenter, the stiffness of a material is measured to be 3.9x10⁹N/m at a h of 100 nm. What is the elastic modulus of this material? Assume that the modulus of the indenter is much higher than the elastic modulus of the material, and a Poisson ratio of 0.3. What is this material?
Therefore, the elastic modulus of the material is 14.84 GPa.
Relationship between indentation depth, h, and contact area, A, for a spherical indenter with a radius of 800 um:
Spherical indentation geometry can be described in terms of the following parameters:
R is the radius of the indenter, δ is the depth of the indentation, and A is the projected contact area of the indenter. By introducing a non-dimensional term H to describe the indentation, the relationship between the elastic modulus and the contact stiffness can be derived.
The following equation expresses the relationship between H and the contact stiffness of a material:
E/(1-ν²) = [(2πR)/H³]P
Where P is the contact load, and E and ν are the Young’s modulus and Poisson’s ratio of the material, respectively. In general, spherical indenters with different sizes, shapes, and materials have different values of R, and therefore, different values of H as well.
Solving the first part of the question, we have:
H=δ/(0.75 R)where R = 800 µm
Thus,H = δ / 600 µm
The relationship between the elastic modulus and the contact stiffness can be derived. The following equation expresses the relationship between H and the contact stiffness of a material:
E/(1-ν²) = [(2πR)/H³]P
Where P is the contact load, and E and ν are the Young’s modulus and Poisson’s ratio of the material, respectively.
We have the following information:
R = 800 µmδ = 100 nm = 0.1 µmK = 3.9 × 10⁹ N/mν = 0.3
Poisson’s ratio We know that the elastic contact stiffness, K, of a material is defined as the ratio of the applied force to the displacement of the indenter during the contact process.
E = (K (1 - ν²))/[(2πR) / (h³)]
Putting all the values we get,E = 14.84 GPa
Therefore, the elastic modulus of the material is 14.84 GPa.
The material is elastic, brittle and has a low modulus. It may be a glass or a ceramic.
To know more about elastic modulus visit:
https://brainly.com/question/30402322
#SPJ11
5- Two different alloys have a similar corrosion rate, but show different weight loss. Is it possible? Use classical formula for corrosion rate, CR= (534 weight loss)/ (density. Area. Time). (2)
Yes, it is possible for two different alloys to have a similar corrosion rate but show different weight loss.
The classical formula for corrosion rate, CR = (534 * weight loss) / (density * area * time), calculates the corrosion rate based on the weight loss of the material. However, the weight loss alone does not provide a complete picture of the corrosion process. Different alloys may have different densities or surface areas, which can affect the weight loss. For example, if Alloy A has a higher density or a larger surface area compared to Alloy B, it may exhibit a higher weight loss even with a similar corrosion rate.
Additionally, the corrosion process can involve other factors such as localized corrosion or selective dissolution, which may result in non-uniform weight loss across the surface of the alloys. Therefore, while the corrosion rate provides a measure of the overall corrosion process, the weight loss alone may not accurately represent the extent of corrosion for different alloys. Other factors, such as density, surface area, and corrosion mechanism, should be considered to fully understand the differences in weight loss between two alloys with similar corrosion rates.
Learn more about corrosion rate here:
https://brainly.com/question/29697991
#SPJ11
find the driving pressure for a stack that has a height of 18 m and carry a hot gas mixture with an average density of 1.2 k/m3. If you know that the total heat rejection by the stack is 1450 KJ and the cp of the hot gas is 1.8 KJ/Kg.K while the hot gas inlet and outlet temperature are 650 K and 500 K respectively. Assume the hot gas pressure as 2.3 bar while the ambient pressure is 1 bar, Answer:
The driving pressure for the given stack height, density, total heat rejection, hot gas cp, inlet and outlet temperatures and pressure values can be calculated as follows: Firstly, the mass flow rate should be determined using the formula.
Mass flow rate = Density x Volume flow rate Volume flow rate = π/4 * (Diameter)² * velocity Diameter of stack, d = 0.3 area of the stack = A = π/4 * (d)² = 0.07 m²Velocity, v = (2 * Volumetric flow rate) / (π * d²) Total heat rejected,
The value of driving pressure is 67.42. Hence, the driving pressure of the stack is 67.42 Pa.
To know more about mass visit:
https://brainly.com/question/11954533
#SPJ11
A steam power plant operating on a simple Rankine cycle uses geothermal water as heat source as shown in Figure Q1. Steam enters the turbine at 10 MPa and 600°C at a rate of 35 kg/s and leaves the condenser as saturated liquid at a pressure of 40 kPa. Heat is transferred to the cycle by a heat exchanger in which geothermal liquid water enters at 230°C at a rate of 200 kg/s and leaves at 80°C. The specific heat of geothermal water is given as 4.18 kJ/kg-°C, and the pump has an isentropic efficiency of 85 percent. Geothermal water out Geothermal water in Heat Exchanger 2 3 Turbine Pump 1 Air-cooled condenser Figure a) Sketch the cycle on a T-s diagram with respect to saturation lines, clearly showing the corresponding labels and flow direction. Identify all work and heat transfers. b) It is known that the actual quality of the steam leaving the turbine is 0.92. Determine the isentropic enthalpy of the turbine, and subsequently the isentropic efficiency of the turbine. c) Determine the net power output of the plant and the thermal efficiency of the cycle. d) Suggest one way to improve the Rankine cycle efficiency. Explain how this method increases the cycle's efficiency.
A steam power plant that uses geothermal water as heat source is operating on a simple Rankine cycle as shown in. Steam enters the turbine at 10 MPa and 600°C at a rate of 35 kg/s and leaves the condenser as saturated liquid at a pressure of 40 kPa.
Heat is transferred to the cycle by a heat exchanger in which geothermal liquid water enters at 230°C at a rate of 200 kg/s and leaves at 80°C. The specific heat of geothermal water is given as 4.18 kJ/kg-°C, and the pump has an isentropic efficiency of 85 percent.The cycle is sketched on a T-s diagram with respect to saturation lines, clearly showing the corresponding labels and flow direction. Feedwater heating before entering the boiler is one of the most important and cost-effective methods for enhancing thermal efficiency.
The temperature of the fluid being pumped is raised before it enters the boiler by taking a portion of steam from a stage of the turbine at a higher pressure and temperature and condensing it in the feedwater stream's heat exchanger. This improvement is due to the fact that the average temperature of heat addition to the cycle is higher as a result of the preheating of the fluid before it enters the boiler. Consequently, the thermal efficiency of the cycle is increased.
To know more about geothermal visit:
https://brainly.com/question/21441767
#SPJ11
Design a cam in non-dimensional form that has the following characteristics: In segment 1 from 0<θ<β (a) Has a parabolic profile (b) It Starts from dwell at the height of zero. (c) Rises to the height of L (d) Dwells at the height of L
Cam Design:A cam refers to a device that transforms rotary motion into linear motion. Cams are used in several machines, such as internal combustion engines, to control movement. A cam is often a part of a rotating shaft that's out of contact with the machine's primary mechanism.
When a cam rotates, a follower, typically in the shape of a needle, moves on its surface. Cam design necessitates understanding a few geometric and kinematic principles. The cam's main purpose is to actuate the follower and change its motion over time. The follower's movement is dependent on the shape and size of the cam.To solve the problem of designing a cam, we must first create a non-dimensional form. To do so, we must first define the variables. These variables include the dwell angle, which is the angle through which the cam rotates without moving the follower, and the pressure angle, which is the angle between the normal force to the follower and the line of centers.In segment 1 from 0<θ<β, the cam will have the following characteristics:
(a) Parabolic profile(b) Starting from dwell at the height of zero(c) Rising to the height of L(d) Dwelling at the height of LThe cam's main answer can be written as follows:f(θ) = aθ^2where a is a constantTo meet the necessary criteria, the following parameters are chosen:(i) Starting position of the cam = 0(ii) Ending position of the cam = β(iii) Starting height of the cam = 0(iv) Ending height of the cam = L(v) Dwell position of the cam = LSubstituting the parameters in the equationf(θ) = aθ^2we get:L = aβ^2Therefore, a = L/β^2Thus the equation of the cam is:f(θ) = (L/β^2)θ^2This is the non-dimensional form of the cam. Thus, the main answer is as follows: f(θ) = (L/β^2)θ^2. Explanation:Cam design involves converting rotary motion to linear motion. When a cam rotates, a follower, typically in the shape of a needle, moves on its surface. Cam design necessitates understanding a few geometric and kinematic principles. The cam's main purpose is to actuate the follower and change its motion over time. The follower's movement is dependent on the shape and size of the cam.
To Know more about Cam Design visit;
https://brainly.com/question/33286123
#SPJ11
a) Fill in the blanks with the provided phrases that describe the working principal of the following amplifiers. semiconductor comparators proportional optical coupling reference voltages high lever electrically diode bipolar transistor isolation barrier An isolation amplifier is a device that consists of two ___ isolated stage. The input stage and the output stage are separated from each other by an ___ so that a signal must be processed in order to be coupled across it. Some isolation amplifiers use ___ or transformer coupling to provide isolation between the stages. A flash analog to digital convertor utilizes ___ that compare the ___ with analog input voltages. When the analog voltage exceeds the reference voltage for a given comparator, a ___ output is generated A log amplifier produces an output that is ___ to the logarithmn of the input voltage. The key element in a basic log amplifier is a___ pn junction in the form of either a __ or base-emitter junction of a ___ A pn junction exhibits a natural logarithmic current for many decades of input voltages b) What is the neutral zone in a two position controller? [1 mark] c) Explain the function of a constant-current source circuit? [1 mark] d) The output shown below is the characteristics of a controller.
a) An isolation amplifier uses an isolation barrier to separate the input and output stages, allowing signal processing for coupling. Optical or transformer coupling may be employed for isolation. Flash analog-to-digital converters utilize comparators to compare reference voltages with analog inputs, generating high-level outputs when the analog voltage exceeds the reference. Log amplifiers produce outputs proportional to the logarithm of the input voltage using a diode pn junction, which exhibits logarithmic current characteristics.
b) The neutral zone in a two-position controller is a range of input values around the setpoint where the controller output remains unchanged. It prevents unnecessary switching of the output within a tolerance range, reducing wear on the controlled system.
c) A constant-current source circuit maintains a consistent output current regardless of load resistance or input voltage variations. It uses active components and feedback networks to ensure precise current control in various applications.
d) Without specific information about the output characteristics provided, a response cannot be given. Please provide more details for further assistance.
Learn more about amplifier
https://brainly.com/question/33224744
#SPJ11
Combustion in the gas turbine In the combustor, the initial temperature and pressure are 25°C and 1 atm. Natural gas reacts with moist air with a relative humidity of 80%. The air is excessive for the complete combustion of the fuel, with 110% of stoichiometric air. After combustion, products reach a temperature of 1400 K at the combustor exit. Making necessary assumptions as you deem appropriate, complete the following tasks. a) Determine the balanced reaction equation. [6 marks] b) Calculate the mole fraction of each gas in the products. [3 marks] c) Determine the enthalpy of reaction for combustion products at a temperature of 1400 K (in kJ/kmol). [6 marks] d) Suggest two strategies to make the power plant zero-carbon emissions. [2 marks]
a) Balanced reaction equation depends on the composition of the natural gas.
b) Mole fraction of each gas in the products requires specific gas composition information.
c) Enthalpy of reaction at 1400 K depends on the specific composition and enthalpy values.
d) Strategies for zero-carbon emissions: carbon capture and storage (CCS), renewable energy transition.
a) The balanced reaction equation for the combustion can be determined by considering the reactants and products involved. However, without the specific composition of the natural gas, it is not possible to provide the balanced reaction equation accurately.
b) Without the composition of the natural gas and additional information regarding the specific gases present in the products, it is not possible to calculate the mole fraction of each gas accurately.
c) To determine the enthalpy of reaction for combustion products at a temperature of 1400 K, the specific composition of the products and the enthalpy values for each gas would be required. Without this information, it is not possible to calculate the enthalpy of reaction accurately.
d) Two strategies to make the power plant zero-carbon emissions could include:
1. Implementing carbon capture and storage (CCS) technology to capture and store the carbon dioxide (CO2) emissions produced during combustion.
2. Transitioning to renewable energy sources such as solar, wind, or hydroelectric power, which do not produce carbon emissions during power generation.
Learn more about natural gas
brainly.com/question/12200462
#SPJ11
Draw the following sinusoidal waveforms: 1. e=-220 cos (wt -20°) 2. i 25 sin (wt + π/3) 3. e = 220 sin (wt -40°) and i = -30 cos (wt + 50°)
Sinusoidal waveforms are waveforms that repeat in a regular pattern over a fixed interval of time. Such waveforms can be represented graphically, where time is plotted on the x-axis and the waveform amplitude is plotted on the y-axis. The formula for a sinusoidal waveform is given as:
A [tex]sin (wt + Φ)[/tex]
Where A is the amplitude of the waveform, w is the angular frequency, t is the time, and Φ is the phase angle. For a cosine waveform, the formula is given as: A cos (wt + Φ)To draw the following sinusoidal waveforms:
1. [tex]e=-220 cos (wt -20°).[/tex]
The given waveform can be represented as a cosine waveform with amplitude 220 and phase angle -20°. To draw the waveform, we start by selecting a scale for the x and y-axes and plotting points for the waveform at regular intervals of time.
To know more about waveforms visit:
https://brainly.com/question/31528930
#SPJ11
How many revolutions of crankshaft does it take to complete one working cycle in a four stroke engine? 2 4 6 8
In a four-stroke engine, it takes two revolutions of the crankshaft to complete one working cycle. A working cycle refers to the four-stroke cycle that a piston undergoes in an internal combustion engine.
A four-stroke engine is an internal combustion engine that employs four different piston strokes to complete an operating cycle, including the intake stroke, the compression stroke, the power stroke, and the exhaust stroke. The piston moves up and down in a cylinder in a four-stroke engine, and there is a combustion process that occurs during each stroke.
Four-stroke engines are used in a wide range of applications, including in cars, motorcycles, generators, and many others. In general, they tend to be more efficient and cleaner than two-stroke engines because they are capable of producing more power per revolution.
Internal combustion engines with four distinct piston strokes (intake, compression, power, and exhaust) are known as four-stroke engines. A total situation in a four-phase motor requires two upsets (7200) of the driving rod.
Know more about four-stroke engine:
https://brainly.com/question/12950144
#SPJ11
In a four-stroke engine(FSE) , it takes two revolutions of the crankshaft to complete one working cycle.
During these two revolutions, all four strokes—intake, compression, power, and exhaust—are completed.
Plagiarism free answer.
to know more about crankshaft visit:
https://brainly.in/question/21789425
#SPJ11
The polynomial f(x) = x³ - 8x² + 4x + 48 has three roots, which can be found using the following four datapoints f(-11.983) = -2869.255, f(1.178) = 43.249, f(4.666) = -5.922, and f(8.745) = 139.990. (a) Write a Matlab function entitled "the_function_of_problem2.m" that takes x as an input and returns y at the output, where y = x³ – 8x² + 4x + 48. (b) Write a Matlab function entitled "Combined_BiSection_False Position_method.m" that carries out first a total of M Bi-Section iterations that are followed by N False Position iterations in order to find the root of f(x). This Matlab function should have four inputs (M, N, as well as the upper and lower limit of the root). This Matlab function should return two outputs the upper and lower limit of the root. This function should not display anything in the command line. (c) Write a Matlab script entitled "main_problem2.m" that computes all three roots of f(x) using the function developed in (b) with M = 3, N = 5, and appropriate upper and lower boundaries of the root estimate. Store the three different roots under the Matlab variables xr1, xr2, and xr3.
1) A matlab function entitled "The_function_of_problem2.m" that takes x as an input and returns y at the output, where y = x³ – 8x² + 4x + 48 has been provided.
2) A a Matlab function entitled "Combined_BiSection_False Position_method.m" has been provided.
3) A Matlab script entitled "main_problem2.m" that computes all three roots of f(x)
How to use MatLab to solve the Polynomial?The polynomial function is given as:
f(x) = x³ - 8x² + 4x + 48
1) The_function_of_problem2.m that takes x as an input and returns y at the output, where y = x³ – 8x² + 4x + 48 is:
function y = the_function_of_problem2(x)
y = x.^3 - 8*x.^2 + 4*x + 48;
end
2) A Matlab function entitled "Combined_BiSection_False Position_method.m" that carries out first a total of M Bi-Section iterations that are followed by N False Position iterations in order to find the root of f(x) is as follows:
function [a, b] = Combined_BiSection_FalsePosition_method(M, N, a0, b0)
% Bi-Section method
for i = 1:M
c = (a0 + b0) / 2;
if the_function_of_problem2(c) * the_function_of_problem2(a0) < 0
b0 = c;
else
a0 = c;
end
end
% False Position method
for i = 1:N
c = (a0 * the_function_of_problem2(b0) - b0 * the_function_of_problem2(a0)) / (the_function_of_problem2(b0) - the_function_of_problem2(a0));
if the_function_of_problem2(c) * the_function_of_problem2(a0) < 0
b0 = c;
else
a0 = c;
end
end
% Return the updated boundaries
a = a0;
b = b0;
end
c) A Matlab script entitled "main_problem2.m" that computes all three roots of f(x) using the function developed in (b) with M = 3, N = 5, and appropriate upper and lower boundaries of the root estimate is as follows:
% Initial boundaries for root estimation
a = -15;
b = 15;
% Compute the three roots
[xr1, xr2] = Combined_BiSection_FalsePosition_method(3, 5, a, b);
[xr2, xr3] = Combined_BiSection_FalsePosition_method(3, 5, xr2, b);
% Display the results
disp('Root 1:');
disp(xr1);
disp('Root 2:');
disp(xr2);
disp('Root 3:');
disp(xr3);
Read more about Polynomials at: https://brainly.com/question/7693326
#SPJ4
Q4: A) Derive expressions for the von Mises and Tresca criteria for 1)pure tension and 2)pure torsion interms of the constant k. B) In a general state of biaxial stress 01 and 02, find the von Mises and Tresca yield loci in the 01 and 02 plane so that the two criteria coincide for simple tension. What is the greatest difference in the stresses predicted by the two theories?
The stress on a material can be tested by either applying tensile stress or torsional stress, the terms von Mises and Tresca are common for evaluating the failure of materials. The expressions for von Mises and Tresca criteria for pure tension and pure torsion are given below:von Mises Criteria:
The von Mises criterion for pure tension is:σ1 = σt, σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σt²The von Mises criterion for pure torsion is:σ1 = σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:[tex](σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 3k²τt²[/tex]Tresca Criteria: The Tresca criterion for pure tension is:σ1 = σt, σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:max(│σ1 − σ2│, │σ2 − σ3│, │σ3 − σ1│) = kσtThe Tresca criterion for pure torsion is:σ1 = σ2 = σ3 = 0and k is the constant, the criterion is given by the equation:
max[tex](│σ1 − σ2│, │σ2 − σ3│, │σ3 − σ1│) = 2kτt[/tex]Given that in a general state of biaxial stress 01 and 02, we need to find the von Mises and Tresca yield loci in the 01 and 02 planes so that the two criteria coincide for simple tension.To find the von Mises yield locus for the state of stress, let σ2 = σ3 = 0, and substitute σ1 = σ0 in the von Mises equation:[tex](σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σ0²Substituting σ1 = 0 and σ2 = σ3 = σ0/2[/tex]in the equation:(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)² = 2k²σ0²/2²
To know more about equation visit:
https://brainly.com/question/30164981
#SPJ11
Verify that y1 and y2 are solutions to the differential equation. Then find a particular solution of the form y(x) = c1y1 + c2y2 that satisfies the given initial conditions: y′′ + 4y = 0; y1 = cos2x; y2 = sin2x; y(0) = 3; y′(0)=8
To verify if y1 = cos^2(x) and y2 = sin^2(x) are solutions to the differential equation y'' + 4y = 0, we need to differentiate them twice and substitute them back into the equation. Next, we can find a particular solution of the form y(x) = c1y1 + c2y2 that satisfies the initial conditions y(0) = 3 and y'(0) = 8.
To verify if y1 = cos^2(x) and y2 = sin^2(x) are solutions to the differential equation y'' + 4y = 0, we differentiate them twice with respect to x:
For y1 = cos^2(x):
y1' = -2cos(x)sin(x)
y1'' = -2(sin^2(x) - cos^2(x))
Substituting y1'' into the differential equation:
y1'' + 4y1 = -2(sin^2(x) - cos^2(x)) + 4cos^2(x)
= 2cos^2(x) - 2sin^2(x) + 4cos^2(x)
= 6cos^2(x) - 2sin^2(x)
Simplifying, we have:
6cos^2(x) - 2sin^2(x) = 4(cos^2(x) - sin^2(x))
= 4cos(2x)
Since 4cos(2x) is equal to 4cos^2(x) - 2sin^2(x), y1 satisfies the differential equation.
For y2 = sin^2(x):
y2' = 2sin(x)cos(x)
y2'' = 2(cos^2(x) - sin^2(x))
Substituting y2'' into the differential equation:
y2'' + 4y2 = 2(cos^2(x) - sin^2(x)) + 4sin^2(x)
= 2cos^2(x) - 2sin^2(x) + 4sin^2(x)
= 2cos^2(x) + 2sin^2(x)
= 2(cos^2(x) + sin^2(x))
= 2
Since 2 is a constant, y2 satisfies the differential equation.
Now, to find a particular solution of the form y(x) = c1y1 + c2y2, we substitute y1 = cos^2(x) and y2 = sin^2(x) into the equation and solve for c1 and c2.
y(x) = c1cos^2(x) + c2sin^2(x)
To satisfy the initial condition y(0) = 3, we substitute x = 0 and y = 3:
3 = c1cos^2(0) + c2sin^2(0)
3 = c1 + c2
To satisfy the initial condition y'(0) = 8, we differentiate y(x) and substitute x = 0 and y' = 8:
y'(x) = -2c1sin(x)cos(x) + 2c2sin(x)cos(x)
8 = -2c1sin(0)cos(0) + 2c2sin(0)cos(0)
8 = 0 + 0
8 = 0
The equation 8 = 0 implies that there is no solution that satisfies the initial condition y'(0) = 8.
Hence, there is no particular solution of the form y(x) = c1y1 + c2y2 that satisfies the given initial conditions y(0) = 3 and y'(0) = 8.
To learn more about equation
brainly.com/question/29538993
#SPJ11