The length of the hypotenuse side of the right triangle ΔXYZ, found using Pythagorean Theorem is b·√(10)
What is Pythagorean Theorem?Pythagorean Theorem indicates that the square of the length of the hypotenuse side of a right triangle is equivalent to the sum of the square of the legs of the right triangle.
The specified parameters of triangle are;
The hypotenuse of the triangle, ΔXYZ = [tex]\overline{YZ}[/tex]
The length of the legs of the right triangle are;
[tex]\overline{XY}[/tex] = b, and [tex]\overline{XZ}[/tex] = 3 × [tex]\overline{XY}[/tex]
Therefore;
[tex]\overline{XZ}[/tex] = 3 × b (substitution property of equality)
The length of the hypotenuse side can be calculated as follows;
Therefore;, according to Pythagorean theorem, we get;
[tex]\overline{YZ}[/tex]² = [tex]\overline{XY}[/tex]² + [tex]\overline{XY}[/tex]²
[tex]\overline{YZ}[/tex]² = b² + (3·b)² = b² + 9·b² = 10·b²
[tex]\overline{YZ}[/tex] = [tex]\sqrt{10\cdot b^2} = b \cdot \sqrt{10}[/tex]
The length of the hypotenuse side , [tex]\overline{YZ}[/tex] = b·√(10)
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Greatest common factor of 48, 8, 32
Answer 16
Step-by-step explanation:
Given the graphs of f(x) = –x – 2 and g(x) = –2x + 1, find the solution to this system of equations:
x + y = –2
2x + y = 1
Answer:
(3, -5) or x=3, y=-5
Step-by-step explanation:
Systems of Equations:In a systems of equation, we're looking for what pair of (x, y) values make both equations true. When a pair of (x, y) makes an equation true, that just means it's on the line of the graph. So a pair of (x, y) values that makes both equations true, is simply when both lines intersect.
Solving Systems of Equations:
There are multiple methods to solve a systems of equation including: elimination, substitution, and graphing.
Each way has their advantages, and I'll show to to apply substitution and elimination
Elimination Method:In this method we want to manipulate one of equations (or possibly both) so that they each have a variable with the "same coefficient" but different sign (one positive, one negative).
In the equations given, you may notice that the "y" variables each have the same coefficient, so we could multiply either of the equations by negative one, so one has positive y and another has negative y.
The reason we want the equations set up in this way, is so that we can add the equations which results in one of the variables being "eliminated" so that we can solve for a single value for the other variable.
So we start with:
[tex]x+y=-2\\2x+y=1[/tex]
let's multiply the top equation by -1 (remember to apply this to both sides so you don't actually change the equation)
[tex]-(x+y)=-(-2)\implies -x-y=2[/tex]
So now from here we have the two equations
[tex]-x-y=2\\2x+y=1[/tex]
If we add the two equations we get the following
[tex](-x+2x)+(-y+y)=(2+1)[/tex]
Notice how the -y and y cancel each other out? This is the entire point of the elimination method, so now we can solve for x
[tex]x=3[/tex]
This actually simplifies in our favor since -x + 2x = x, and the right side is just some constant, so we don't need to manipulate the equation anymore to solve for x.
Now that we know what the x-value is, we can plug this into either equation to solve for y. For simplicity I'll use the x + y = -2 equation.
[tex]3+y=-2\\y=-2-3\\y=-5[/tex]
So we know the solution is (3, -5) or [tex]x=3,\ y=-5[/tex]
Substitution MethodThe substitution method has the same goal as the elimination method, that is, get a one-variable equation so we can solve for one value. In this method, we want to define one variable in terms of the other variable, that way we can substitute this into the other equation, giving us a new equation with only one variable.
So let's just start with the top equation:
[tex]x+y=-2[/tex]
From here we can define "y" in terms of x, by subtracting x from both sides.
[tex]y=-2-x[/tex]
Now let's look at our other equation
[tex]2x+y=1[/tex]
Notice how it has a y variable, well we have one way of defining it: y = -2 - x. If we plug this into the bottom equation, now we only have x terms, giving us a one-variable equation.
[tex]2x+(-2-x)=1[/tex]
Now let's add 2 to both sides to cancel out the -2, and simplify 2x - x
[tex]x=3[/tex]
From here we essentially do the same thinkg we did in elimination method, except it may be a bit easier since we already have "y" solved for, we just need an x-value, which we now have!
[tex]y=-2-x\\\text{we know that x = 3}\\y=-2-(3)\\y=-5[/tex]
so now we have our solution: [tex](3, -5)\text{ or }x=-3, y=-5[/tex]
PLS HELP WILL MARK BRANLIEST!!
Find the m
54°
90°
27°
36°
Answer:
[tex]\huge\boxed{\sf < p = 36\°}[/tex]
Step-by-step explanation:
Since, the line is tangent to the circle, it is making an angle of 90 degree with the radius.
So,
∠p + 54 + 90 = 180 (Interior angles of a triangle add up to 180°)
∠p + 144 = 180
Subtract 144 to both sides
∠p = 180 - 144
∠p = 36°[tex]\rule[225]{225}{2}[/tex]
Answer:
36°
Step-by-step explanation:
Tangent lines form Right Angles (90°) with all radii of circles.
Triangle Angle Sum: the three angles in a triangle add to 180°
90 + 54 + p = 180
144 + p = 180
p = 36
Pleas help me this is for today!!
Atennis ball machine can launch 60 tennis balls in 12 minutes. At this rate, how many tennis balls can it launch in 2 hours
At this rate, the number of tennis ball launched by the machine in 2 hours is 600.
How to find the number of tennis launch ?The tennis ball machine can launch 60 tennis balls in 12 minutes. At the same rate the ball machine launched a particular amount of tennis ball in 2 hours.
The number of tennis ball the ball machine launched in two hours can be calculated as follows:
rate = number of tennis ball launched / time in minutes
rate = 60 / 12
rate = 5 tennis ball per minutes
Therefore, in 2 hours
5 = x / 120
x = 120 × 5
x = 600 tennis balls
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Anyone know where I can get the awsners for these? The top of the paper says ACT Skills Prep, Week 1
Answer:
More than likely no full answer key however there might be answers for each individual question.
This is NOT multiple choice
Consider the equation
x+3/x-2 = x-4/x+5
A) solve the equation for x. Show and explain each step used when solving the equation
B) show and explain how the solution can be verified
Step-by-step explanation:
(X+3)/(x-2)=(x-4)/(X+5)
cross multiply
(x+3)(x+5)=(x-4)(x-2)
x(X+5)+3(X+5) = X(x-2)-4(x-2)
x²+5x+3x+15=x²-2x-4x+8
x²+8x+15=x²-6x+8
x²-x²+8x+6x=8-15
14x=-7
X=-7/14
X=-1/2
B)to verify substitute the answer in the equation given
that is RHS
X+3/x-2
=(-1/2+3)/(-1/2-2)
=5/2/-5/2
=-1
from LHS
x-4/(x+5)
=(-1/2-4)/(-1/2+5)
=-9/2/-9/2
=-1
the LHS= RHS
proved
Hi again no teachers are around to help so can u?
10 added to the product of 8 and b
The equation would be (8 x b) + 10 or 8b + 10, hopefully this helped :))
Answer:
8b+10
Step-by-step explanation:
8b+10
hope it helps. please mark brainliest
50 points! Which expression is equivalent to the sum 25 + 60? * 1 point
5(5 + 6)
5 (5 + 8)
5(5 + 10)
5(5 + 12)
I have to explain also!
jacob had some cchips he used 2 2/5 cups to make some muffins .he has 5 2/10 cups of cchips left how many cups if cchips .did he have to start?
a.7
b.7 7/6
c.7 3/5
d.8
Answer: c
Step-by-step explanation:
1) 2 2/5 + 5 2/10
2) 2 2/5 = 12/5 = 24/10
3) 5 2/10 = 52/10
4) 24 + 52 = 76
5) 76/10 = 38/5
6) convert to mixed number
A body A of mass 1.5kg, travelling along the positive x-axis with speed 4.5m/s collides with another body B of mass 3.2kg which, initially, is at rest. Because of the collision, A deflected and moves with a speed 2.1m/s in a direction which is at angle 30° below the x-axis. B Is set in motion at an angle tether above the x-axis. Calculate the velocity of B after the collision.
Answer:
FINAL ANSWER: BODY B was moving at 1.35 m/s, 21 degrees above the x-axis.
Step-by-step explanation:
REFER TO THE IMAGES for the SOLUTIONS TO YOUR PROBLEM. Each step will be explained here.
When you solve for velocities before or after collision, you need to remember the law of conservation of moment which can be expressed through this formula:
BEFORE AFTER
m1v1+m2v2 = m1v1 + m2v2
This basically means, the sum of momentum of 2 objects BEFORE collision is equal to the same 2 objects AFTER collision.
The type of collision we have in your case is a 2D collision, where there is a gliding collision or they touch at an angle. So when you solve these type of problems, you have to consider the x and y components of motion. It makes things easier if you make a table like in the image to sort out your components.
STEP 1: COMPUTE FOR MOMENTUM BEFORE COLLISION for each OBJECT involved.
To solve for momentum, the formula is mass x velocity or mv:
STEP 1a: Body A: The problem states that before collision Body A is moving along the positive X-axis so the velocity will be +4.5 m/s. Notice that the velocity of the y component is 0 m/s. This is because BODY A is moving along the x-axis, with no mention that it deviated from it.
STEP 1b: Body B: Body B is at rest before collision, that is why it is not moving at all, which means both x and y components are equal to 0.
STEP 1c: Get the sum of all X components and the Sum of Y components.
STEP 2: COMPUTE FOR MOMENTUM AFTER COLLISION for each OBJECT involved.
Step 2a: BODY A: Notice that we now have an angle. hence the cos and sin. We do this because we are breaking or decomposing the diagonal velocity into its x and y component. To get the x-component you get the cos of the angle and multiply it to the momentum of the diagonal or overall velocity. For y-component, instead of cos, you get the sin.
Step 2b: BODY B: Here we have unknowns, which we will derive later on. In this step, just plug in what you know into the formula.
Step 2c: We already know the x and y momentum of the objects BEFORE collision and the law of conversation of momentum states that the momentum AFTER is the same. With this total we can move onto the next step.
STEP 3: Solving for the X and y component of the velocity of BODY B AFTER collision.
Step 3a: Using the formula given in the image, we plug in what we know first. We know the momentum of the BODY A already, so we can put it into the equation. We also know the sum of both momenta and we put that into the equation too. Now all we do is derive the formula. DO NOT FORGET THAT WE ARE TO USE ONLY X COMPONENTS.
Step 3b: is the same as the previous step but instead, we use Y COMPONENTS only.
STEP 4: Combining X and Y components to get the resultant velocity:
For this step you need to remember the Pythagorean theorem. This is applied here because when you draw a free body diagram of the velocities, it creates a right triangle where :
the hypotenuse represents the final velocity
the opposite side represents the y-component and;
the adjacent represents the x-component.
Refer to the image for the solution.
STEP 5: Solving for the angle at which BODY B is moving:
For this step you need to remember SOH CAH TOA to find the angle at which BODY B is moving. You already have all the components you need, including the hypotheses. You can use any of the functions, and they should come up with the same approximation.
FINAL ANSWER: BODY B was moving at 1.35 m/s, 21 degrees above the x-axis.
The table shows the percent of each type of sandwich a cafe had available on Sunday. Sandwich Percent Ham 35 Roast Beef 25 Turkey 40 There are a total of 225 ham and turkey sandwiches. How many sandwiches did they have in all on Sunday? sandwiches Part B Fill in the blank question. If the cafe sells all the sandwiches at $4.50 each, how much money will the cafe earn?
The total number of sandwiches they have in all on Sunday is 375 sandwiches.
The amount earned by the cafe if each sandwich cost $4.50 is $1,687.5
What is the total number of sandwiches?Ham sandwich = 35%Roast beef sandwich = 25%Turkey sandwich = 40%Total ham and turkey sandwiches = 225Total number of sandwiches = xTotal percentage of ham and turkey sandwiches = 35% + 25%
= 60%
So,
225 = 60% of x
225 = 0.60 × x
225 = 0.60x
divide both sides by 0.60
x = 225/0.60
x = 375
Hence,
Total number of sandwiches = 375
If the cafe sells all the sandwiches at $4.50 each
The total money earned by the cafe = cost of each sandwich × total number of sandwiches
= $4.50 × 375
= $1,687.5
Therefore, the total sandwiches sold in the cafe on Sunday is 375 sandwiches.
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This week, Ty works 6 hours pulling weeds, 4 hours raking leaves, and 9 hours
cutting grass. How much money does he earn?
Ty earns $
this week.
Answer:6(a)+4(b)+9(c)
Step-by-step explanation:
Im pretty sure there was an equation that you did not put.
But the equal used to solve would be 6(a)+4(b)+9(c)
a= money earned pulling weeds
b=money earned raking leaves
c=money earned cutting grass.
A pillar of height 222 ft casts a shadow of 348 ft long.
Find the measure of the angle of elevation of the sun.
Using tangent of the angle, the angle of elevation is 32.5 degrees
Angle of ElevationThe angle of elevation is an angle that is formed between the horizontal line and the line of sight. If the line of sight is upward from the horizontal line, then the angle formed is an angle of elevation.
In this problem, we have to use the tangent of the angle since we know the opposite and adjacent sides
opposite side = 222adjacent side = 348Tan θ = opposite / adjacent
tanθ = 222 / 348
tan θ = 0.6379
θ = tan⁻¹(0.6379)
θ = 32.5°
The angle of elevation is 32.5 degrees
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Please help. I will give 100 points and brianliest.
Write a linear equation that represents the trend line that you have drawn. Be sure to use points that are located on your trend line to find the equation. Show your work.
Answer: y= 50x+ 100
Step-by-step explanation:the trend line starts below 200 hundred so you
can make an educated guess and say it is 100 then you got to 2 on the fat and it is at 200 but it is 2 so 100+100= 200 for one and 100+50+50= 200 which would give you your x
PLEASE HELP ME
Write the equation of a line in slope intercept form that is perpendicular to Y= -1/3x+4 and pass through the point (-2,-5)
Answer:
y = 3x + 1
Step-by-step explanation:
The general form of the slope intercept form is y = mx + b where m is the slope and b is the y-intercept.
In perpendicular lines, we find the slope of the second equation (m2) using the formula:
[tex]m_{2}=-\frac{1}{m_{1} }[/tex]
Since -1/3 is m1 we have:
[tex]m_{2}=-\frac{1}{-(\frac{1}{3}) } \\ m_{2}=3[/tex]
Now that we've found the slope of the second line, we simply need to find b or its y-intercept by plugging in (-2, -5) and our slope:
[tex]-5=3(-2)+b\\-5=-6+b\\1=b[/tex]
Thus, the equation of the second line is y = 3x + 1
True or False. If the statement is False, explain why.
The decimal of 4/11 will terminate.
Answer:
4/11 is not a terminate
Because it is non- terminate,if we divide those non- terminating numbers than the divided answer is repeated.
Pauline plots the numbers 4 1/3 and -51/8 on a number line. Explain how she can use the number line to determine which number is greater . Write an ineaquality to compare the bumbers
The required inequality is 4¹/₃ > -5¹/8.
What is inequality?Inequality shows relation between two expression which are not equal to each others.
The given numbers are 4¹/₃ and -5¹/8.
The numbers are plotted on the number lines below,
To determine the number which is greater,
The number which is greater than zero will be greater from the numbers 4¹/₃ and -5¹/8.
4¹/₃ is a greater number.
The inequality can be written as,
4¹/₃ > -5¹/8.
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f(t)=-12(t+7)^2(t+6)^3(t+2)^6
Find the zeros and the multiplicities. Please help.
The zeros and the multiplicities of the polynomial are t = -7, t = -6 and t = -2 and 2, 3 and 6, respectively
How to determine the zeros and the multiplicitiesThe equation of the polynomial is given as
f(t) = -12(t+7)²(t+6)³(t+2)⁶
The multiplicities are the powers of the factors while the zeros are calculated by setting the factors to 0
So, we have
t + 7 = 0
t + 6 = 0
t + 2 = 0
Calculate the value of t
t = -7, t = -6 and t = -2
Hence the zeros are t = -7, t = -6 and t = -2
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Find the solution of the system of equations.
4x - y = -1
-4x-6y=-34
Answer:
Step-by-step explanation:
4x-3y=11. 2 (2x-7y=22).=> 4x-14y=44. 4x-3y=11....................1. 4x-14y=44. 11y= -33. y= -3. then,putting it in 1. 4x-3 (-3)=11.
Mackenzie has some red, yellow and blue marbles. She has 3200 more red marbles than yellow marbles. She has 3840 more blue than yellow. She gives 1490 blue marbles away. How many more red marbles than blue marbles does she have left?
Answer:
850
Step-by-step explanation:
Mackenzie has 3200 more red marbles than yellow,
(y + 3200 = r)
And she also has 3840 more blue marbles than the yellow marbles,
(y + 3840 = b)
Then let's assume that Mackenzie has 1 yellow marble.
1 + 3200 = 3201 red marbles
1 +3840 = 3841 blue marbles
If she gives away 1490 blue marbles away, then she is left with 2351 blue marbles.
(3841 - 1490 = 2351)
Now she's left with 2351 blue marbles, and 3201 red marbles.
r - b =?
3201 - 2351 = 850
Mackenzie has 850 more red marbles than blue marbles.
(If you want, you can change the number of yellow marbles, but it will be the same answer.)
8. Two packages of cookies cost $5.90. How much do seven packages cost? Try using a proportion to
solve or finding unit rate!
Answer: 20.65
Step-by-step explanation:
2.95 is the unit rate x 7 equals 20.65
Answer:
Step-by-step explanation:
We set up a proportion to find X, which in this case is the cost of seven packages.
Proportion: 5.90:2=x:7
Unit cost: 5.90/2=2.95
But we want to find the cost of seven cookies.
So, we multiply the unit cost by 7.
2.95*7= 20.65
Thus, seven packages of cookies costs $20.65.
Perform the operations! 30 points
Step-by-step explanation:
5x³-6x³=-x³
5x²--3x²=8x²
-4x--5x= x
11--5=16
overall answer: -x³+8x²+x+16
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"Test I. Encircle the letter that corresponds your answer. 2 points each
1. How many solutions do you get when you solve by completing the square?
a. 1
b. 2
c. 3
d. 4
2. When completing the square, what do you do if your x squared term has a coefficient?
a. Divide both sides by this coefficient
c. Multiply both sides by this coefficient
b. Nothing
d. Move it to the other side
3. Find the value of b in the quadratic equation 2x²=-5 x+7
a. 2
b. 5
c. -7
d. -5
4. Which of the following mathematical statements is not a quadratic equation?
a. 2 r²-3r-5=0
c. 3t²+7t-2=0
b. 7h+12=h²
d. s²=-8s-15
5. It is a polynomial equation of degree two that can be written in the form ax²+bx+c=0, where a, b, and c are real numbers and a≠ 0.
a. Linear Equation
b. Linear Inequality
c. Quadratic Equation
d. Quadratic Inequality)
"
The solutions using completing the square of quadratic equations are;
1) B: 2
2) A: Divide both sides by this coefficient
3) B: 5
4) All are quadratic equations
5) C. Quadratic Equation
How to solve quadratic equations by completing the square?1) Completing the square is basically a method for solving quadratic equations. Now, quadratic equations are second degree polynomials and as such have 2 roots. Thus, the solutions are 2.
2) Usually when using the method of completing the square, we are also trying to get rid of the coefficient attached to x squared and as such if we notice x squared has a coefficient, we will divide both sides by this coefficient.
3) The general form of quadratic equation is;
y = ax² + bx + c
Thus, we have;
2x² + 5x - 7 = 0
Thus, b = 5
4) They are all quadratic equations.
5) The correct one here is Quadratic Equation
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Solve the system of linear equations by substitution.
5x + 2y = 9
-0.5x - y = 7.5
Answer:
Step-by-step explanation:
[tex]\displaystyle\\\left \{ {{5x+2y=9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \atop {-0.5x-y=7.5\ \ \ \ \ \ \ \ |\cdot2}} \right. \\\\\\\left \{ {{5x+2y=9} \atop {-x-2y=15}} \right. \\+\\--------\\4x=24\ \ \Rightarrow\ x=24:4\Rightarrow\ x=6\\\\y=-0.5x-7.5=-0.5\cdot6-7.5=-3-7.5=-10.5\\\\\boxed{(x;y)=(6;-10.5)}[/tex]
A study of 50 high school students showed that exactly 25 of them took Biology, exactly 20 of them took Chemistry, and exactly 12 of them took both subjects. How many of the 50 students took neither Biology nor Chemistry? One tutor has answered for me, but I am still unclear.
The number of student that took neither chemistry nor biology is 17.
How to find the number of student that did not take Biology nor Chemistry?A study of 50 high school students showed that exactly 25 of them took biology, exactly 20 of them took chemistry, and exactly 12 of them took both subjects.
The number of student that took neither biology nor chemistry can be calculated as follows;
Hence,
U = 50
n(C) = 20
n(B) = 25
n(B n C) = 12
n(B n C)' = ?
Therefore,
U = n(C) + n(B) - n(B n C) + n(B n C)'
Therefore,
50 = 20 + 25 - 12 + x
50 - 45 + 12 = x
x = 5 + 12
x = 17
Therefore, 17 student took neither chemistry nor biology.
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The seventh-grade students at Fulmore Middle School are trying to raise at least $7,500 for the local public library. So far, each of the 198 students has raised an average of $20. How much nore money must each seventh grader collect, on average, to reach the goal? AS AN INEQUALITY PLEASE
what I ended up with was each student needs to to collect about $17.87
The microwave oven uses only 1000 watts of electricity. Does this allow you to have both the microwave oven and the toaster plugged into the circuit at the same time? Explain your reasoning.
Suppose that the function h is defined, for all real numbers, as follows.
According to the query that the function h is established, h(-3) = -1/2, h(2) = 4, and h(4) = -4/1 for all real integers.
What are the different kinds of functions?An statement, rule, or law in mathematics that establishes the link between an independent variable and a predictor variables (the dependent variable). Equations may be found all around arithmetic, and they are essential for building physical connections in the sciences. A mappings between A and B will only be a function if every member in set A only has end and only 1 photo in set B. Where A & B even be two separate sets.
Briefing:Have used the top form of h(x) for x = variables -3 and 4 (which deviate from 2):
[tex]\begin{aligned}& h(x)=-\frac{1}{2} x^2+4 \\& h(-3)=-\frac{1}{2}(-3)^2+4=-\frac{9}{2}+4=-\frac{9}{2}+\frac{4}{2}=-\frac{1}{2} \\& h(4)=-\frac{1}{2}(4)^2+4=-\frac{16}{2}+4=-\frac{16}{2}+\frac{4}{1}=-\frac{4}{1}\end{aligned}[/tex]
Alternatively, h(2) must be defined explicitly as stated in the function's second description (specific for when x equals 2). Thus, h(2) equals 4.
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Drag the labels to the correct locations on the image. Each label can be used more than once, but not all labels will be used.
Consider function m.