Right answer gets brainlist

Answer: velocity is 20 m/s

Explanation: speed v = v0 + at =0 m/s + 4 m/s²·5s= 20 m/s

Explanation:

Thead are gravitational poles, red is positive and blue is negative. They are attracting, as you can see from the middle. that's all I know, sorry

Answer:

there isn't anything else posted to the question when you ask a question put a picture or write it out so people can see it

Explanation:

Explanation:

TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTIING ON A BODY S ,KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE,THE SUM OF THE CLOCKWISE MOMENTS ,IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.

Answer:

TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTING ON A BODY, KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE, THE SUM OF THE CLOCKWISE MOMENTS,  IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.

We have that  the Time  it took him to reach that speed is

t=1.2sec

From the question we are told

A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of  60 kg, how long did it take him to reach that speed?

Generally the equation for the   is mathematically given as

[tex]P=W/t[/tex]

Therefore

[tex]W=Pt\\\\W=250*t[/tex]

Where

[tex]W=f*d\\\\5*60=250*t\\\\t=\frac{5*60}{250}]\\\\t=1.2sec[/tex]

Therefore

Time  it took him to reach that speed is

t=1.2sec

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Answer:

false : In distance time graph,time is shown on the x -axis

Absorption is defined as the process which involves the energy change of light to heat.

Thus is defined as the transfer of the energy of a wave to matter as the wave passes through it.

During this process, the light energy gets converted to heat energy which is usually felt on the substance which makes option B the most appropriate choice.

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Answer:

Most of the light and heavy elements are within a few astronomical units of the center.  

Explanation:

The solar system is composed of different celestial bodies that are called small or large bodies, which revolve around the sun, all of these bodies are the elements of the solar system, which in addition to having different sizes, have different densities and weights from each other . One thing these elements have in common, regardless of their weight, that most of them have astronomical units of the center, which are units of length generated from the average distance from the Earth to the Sun.

Answer:

30 seconds

Explanation:

A = A02^-(t/hl)

--> ln(A/A0) = -(t/hl)ln2

solving for hl,

hl = -t x ln2 /ln(A/A0)

= -(60 min)xln2/ln(50/200)

= 0.5 min or 30 seconds

The amount of half-life cycles that have occurred is mathematically given as

HL=30sec

Question Parameter(s):

If a sample of radioactive isotopes takes 60 minutes

to decay from 200 grams to 50 grams

Generally, the equation for the half-life cycle   is mathematically given as

A = A02^-(t/hl)

Therefore

HL = -t * ln2 / ln(A/A0)

HL= -(60 min)xln2/ln(50/200)

HL=30

In conclusion, the number of half-live

HL=30

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Answer:

Assume I1 = Io * T1        transmission proportional to thickness

I2 = Io * T2          I is intensity of light absorbed     (3/8 absorbed)

I1 / I2 = T1 / T2

T2 = T1 * (I2 / I1) = 2 * (2/3 / 3/8) = 2 * 16/9 = 32/9   thickness for 2/3 absorbed

The length of the beaker when the transmittance is changed to one-third is 13.78 cm.

The given parameters;

To find:

The length of the beaker is calculated by applying Beer-Lambert law;

[tex]\frac{I}{I_o} = e^{-cl}[/tex]

[tex]\frac{I_1}{I_0} = e^{-cl_1} = \frac{3}{8} \ ----(1)\\\\\frac{I_2}{I_0} = e^{-cl_2}= \frac{1}{3} \ ---- (2)[/tex]

divide equation (1) by equation (2);

[tex]\frac{e^{-cl_1}}{e^{-cl_2}} = \frac{3}{8} \times \frac{3}{1} \\\\ (c \ is \ constant \ for \ both) \\\\e^{-l_1 + l_2} = \frac{9}{8} \\\\l_2 - l_1 = ln(\frac{9}{8} )\\\\l_2 - 0.02 = 0.1178\\\\l_2 = 0.1178 + 0.02\\\\l_2 = 0.1378 \ m\\\\l_2 = 13.78 \ cm[/tex]

Thus, the length of the beaker when the transmittance is changed to one-third is 13.78 cm.

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Answer:

(c) 2

Explanation:

Heat transfer across the walls due to conduction is given by:

[tex]q = -KA\frac{\Delta T}{L}[/tex]

where,

q = heat transfer rate

K = thermal conductivity

A = Area

ΔT = change in temperature

L = thickness

For wall A:

[tex]q_A = -K_AA\frac{\Delta T}{L_A}[/tex]

For wall B:

[tex]q_B = -K_BA\frac{\Delta T}{L_B}[/tex]

Because the change of temperature and area of walls are the same. Dividing both terms:

[tex]\frac{q_A}{q_B} = \frac{\frac{K_A}{L_A} }{\frac{K_B}{L_B}}\\\\ \frac{q_A}{q_B} =\frac{\frac{K_A}{K_B} }{\frac{L_A}{L_B}}[/tex]

using values given in the question:

[tex]\frac{q_A}{q_B} = \frac{4}{2}\\\\\frac{q_A}{q_B} = 2[/tex]

Therefore, the correct answer is:

(c) 2

Answer:14C

Explanation:

Answer:

1.11

Explanation:

The index of the medium can be calculated using below formula

V= c/ n ............eqn(1)

Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s

n= index of the medium

c= speed of light= 3 x 10^8 m/s

Substitute for the values in eqn(1)

2.7 x 10^8 = (3 x 10^8 m/s)/ n

Making " n" subject of the formula, we have

n= (3 x 10^8 )/(2.7 x 10^8)

n= 1.11

Hence, the index of the medium is 1.11

Answer:B

Explanation:

Answer:

The velocity of the red  go-kart after the collision is 3 m/s

Explanation:

Here the principle of conservation of momentum will be used.

Momentum of the system before collision = Momentum of the system after collision

Momentum of the system before collision [tex]= 2*5 + 2*0[/tex]

Momentum of the system after collision [tex]= 2 * 2 + 2 *x[/tex]

[tex]2*5 + 2*0[/tex] [tex]= 2 * 2 + 2 *x[/tex]

[tex]10-4 = 2 x\\6 = 2x\\x = 3[/tex]m/s

The velocity of the red  go-kart after the collision is 3 m/s

Answer:The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object. The speed of sound in air is low, because air is easily compressible.

Explanation:

Answer:

The most important skill in handball is passing or throwing

Explanation:

You need to be able to pass the ball with accuracy. Throwing and shooting drills are normally incorporated into every training session for handball.

Answer:

Explanation:

The most important skill in handball is passing or throwing. You need to be able to pass the ball with accuracy. Throwing and shooting drills are normally incorporated into every training session for handball.

Answer:

The load-distance approach is a model used for assessing locations based on factors of proximity. The aim is to select a position where the weighted cumulative loads that enter and leave the facility will be minimized. The distance between two points is shown by the grid coordinates points on a map

Explanation:

Answer:

15,00kg

Explanation:

here's your solution

=> force = 45,000N

=> acceleration = 30m/s^2

=> mass = ?

=> Mass = force/acceleration

=> mass = 45,000/30

=> mass = 15,00kg

hope it helps

Answer:

antinode i'm pretty sure :) hope this helps

Explanation:

Answer:

b. antinodes

Explanation:

Answer:

108 v

Explanation:

Answer:

3300 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1100 Kg

Acceleration (a) = 3 m/s²

Force (F) =?

Force is defined by the following equation:

Force (F) = mass (m) × acceleration (a)

F = m × a

With the above formula, we can obtain the force of the tow truck as follow:

Mass (m) = 1100 Kg

Acceleration (a) = 3 m/s²

Force (F) =?

F = m × a

F = 1100 × 3

F = 3300 N

Therefore, the force of the tow truck is 3300 N

Answer:

A lot of the earth oxygen comes from the ocean around 50%-80%

Explanation:

Answer:

Explanation:

Answer:

k = 44000 N/m

Explanation:

Given the following data;

Maximum gravitational potential energy = 770 J

Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J

Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m

To find the spring constant, k;

The elastic potential energy of an object is given by the formula;

[tex] E.P.E = \frac {1}{2}kx^{2}[/tex]

Substituting into the equation, we have;

[tex] 107.8 = \frac {1}{2}*k*0.07^{2}[/tex]

[tex] 107.8 = \frac {1}{2}*k*0.0049 [/tex]

Cross-multiplying, we have;

[tex] 215.6 = k*0.0049 [/tex]

[tex] k = \frac {215.6}{0.0049} [/tex]

k = 44000 N/m

The spring constant of the tendon is 44000 N/m.

The following can be depicted from the question:

Elastic potential energy will be:

= 14% × 770J = 107.80 Joule.

The spring constant will be calculated thus:

107.8 = 1/2 × k × 0.07²

107.8 = 0.5 × k × 0.0049

k = 215.6 / 0.0049

k = 44000 N/m.

Therefore, the spring constant of the tendon is 44000 N/m.

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Answer:

K.E = 248 J

Explanation:

Since the child is travelling at a given velocity. The kinetic energy of the child down the hill can be given by the following formula:

[tex]K.E = \frac{1}{2}mv^2\\[/tex]

where,

m = mass of the child = 31 kg

v = velocity of the child = 4 m/s

Therefore,

[tex]K.E = \frac{1}{2}(31\ kg)(4\ m/s)^2\\[/tex]

K.E = 248 J

Answer:

Distnace per unit time

Explanation:

Answer:

Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.

Explanation:

Answer:

No.

Explanation:

Para darnos cuenta de esto tenemos que pensar en lo siguiente:

Pensemos en un vaso de vidrio, lleno de agua hasta la mitad, la otra mitad puede ser manteca derretida

Si metemos el vaso en la heladera durante un par de horas, (sabemos que la manteca en la heladera se mantiene sólida) veremos que la manteca se solidificó en la parte de arriba, mientras que el agua sigue líquida.

Entonces encontramos dos compuestos con distintas temperaturas para cambio de fase, pero materiales es más específico, y puede referirse a materiales puros.

Entonces vamos a dos metales:

Primero tenemos una pieza de hierro y una de mercurio en el congelador (supongamos que ambas están a 0°C).

Ahora los sacamos del congelador y los dejamos llegar a temperatura ambiente.

Como bien sabemos, el mercurio es líquido a temperatura ambiente, entonces el mercurio va a sufrir un cambio de fase

Ahora pensemos en el hierro; claramente va a seguir siendo sólido a temperatura ambiente, entonces podemos ver dos materiales cuyo cambio de fase de sólido a líquido ocurre en distintas temperaturas, por lo que podemos concluir que no, la temperatura de cambio de estado no puede ser igual para todos los materiales, y esto se debe a que la estructura atómica de todos los materiales es diferente.