REI.C.6 Level 1
below.
2. A student is solving the system,
2x + 3y = 12
5x - 2y = 11
algebraically. Their work is shown below but is unfinished.
Continue where the student left off and solve the system.
2x + 3y = 12
5x - 2y = 11
=
2 (2x + 3y = 12)
3 (5x - 2y = 11)
4x + 6y = 24
15x – 6y = 33
-

Answers

Answer 1

Answer:

The solution is x = 3, y = 2.

Step-by-step explanation:

4x + 6y = 24

15x – 6y = 33    Add these 2 equations:

19x = 57

x = 57/19

x = 3.          Now Substitute for x in the original equation:

2(3) + 3y = 12

3y = 12 - 6

2y = 6

y = 2.


Related Questions

Please help!!!!!!!!!!!!!!

Answers

Answer:

The answer is A.

Step-by-step explanation:

1 plus 2x (276-5y) + 69= A.

11. Given a matrix A, what is A^1?
A=[0 12 0 1]

Answers

[tex]\text{Since det(A) = 0, the inverse of the matrix does not exist.}[/tex]

please help quickly!!!!!!!

If y varies directly with x, determine an equation for the given direct variation. For this question, find the value of the given variable.

Find y when x = 10 if y = 8 when x = 20.

Answers

Answer:

y=K*x equation

k=constant of variation

y= 4 when x = 10

Step-by-step explanation:

8=k*20

divide both sides by 20 to solve for k

2/5=k

y=2/5 *10

y= 4 when x = 10

a natural number multiplied by itself. is it possible for the result to have 66 as the last 2 digits.
yes or no that is all i need

Answers

Yes yes yes yes yes yes yes yes

Q10. Five t-shirts and a hat cost £83.00. Two t-shirts and a hat cost £38.00. How much does one t-shirt cost?

No spam links and plz write down the answer.

Answers

Step-by-step explanation:

Two t-shirts that are(31.80) plus a hat(6.20) cost £38.00.

which means that one t-shirt costs £15.90 :)

Share and Show
MATH
BOARD
Model the product on the grid. Record the product.
1. 3 X 13 =
2. 5 >
Find the product.

Answers

3X13 is 13 added 3 times which is 39

Using the grid model, the product of 3 and 13 is 39

Product refers to the result of multiplying two or more numbers or quantities together. It is a fundamental operation in arithmetic and algebra. When multiplying two numbers, the product is obtained by adding together a number of copies of one of the numbers, equal to the value of the other number.

Given, two numbers 3 and 9, and a grid.

To determine the product of 3 and 13 just count all the grids covered in 3 rows up to 13 columns or adding 3 for 13 times will result in 39.

Count the grids covered in a red box attached in the image below.

3+3+3+3+3+3+3+3+3+3+3+3+3=39

So, the product of 3 and 13 is 39.

Learn more about mathematical operation, here:

https://brainly.com/question/29635854

#SPJ6

I want a way to solve such a problem​

Answers

Answer: Choice A)  11.4

========================================================

Explanation:

Refer to the table below.

The first step is to find the midpoint of each interval.

To do that, we add up the endpoints and divide by 2. The midpoint of the interval from 2 to 6 is 4 because (2+6)/2 = 8/2 = 4. Repeat these steps for the other intervals to find that the remaining midpoints are: 8, 12, 16, 20.

Overall, the midpoints from top to bottom are 4, 8, 12, 16, 20

Note how the midpoints are incrementing by 4 each time, which is the same distance between each successive left endpoint (and right endpoint endpoints as well).

Let's say m represents the set of midpoints which I'll form in the third column. Multiply the frequency column f by each corresponding midpoint m. The result fm forms the fourth column.

Add up everything in that fourth column to get 1140. We then divide that by the sum of the frequencies (100) to get 1140/100 = 11.4 which is the final answer. The average weight is 11.4 pounds.

The function v(t) is the velocity in m/sec of a particle moving along the x-axis. Use analytic methods to do each of the following: (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particle's displacement for the given time interval. If s(0) = 3, what is the particle's final position? (c) Find the total distance traveled by the particle. v(t) = 5 (sint)^2(cost); 0 ≤ t ≤ 2π

Answers

Answer:

(a) The particle is moving to the right in the interval  [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].

(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].

(c)  The total distance traveled by the particle is 9.67 (2 d.p.)

Step-by-step explanation:

(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).

Situation 1: When the particle stops.

[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].

Situation 2: When the particle moves to the right.

[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]

Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .  

*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.

Situation 3: When the particle moves to the left.

[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]

Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or  [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].

(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.

[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]

To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where

[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].

[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]

Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].

The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].

(c)

[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]

[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]

[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].

The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].

For the school play, tickets cost $9.50 for adults and $3 for kids under 12. What would be the total cost for 8 adult tickets and 21 kids tickets? What would be the total cost for aa adult tickets and kk kids tickets?

Answers

Answer:

$1399.5aa +3kk

Step-by-step explanation:

a)

8 adult tickets cost 8($9.50) = $76

21 kids tickets cost 21($3) = $63

The total cost of these tickets is $76 +63 = $139.

__

b)

aa adult tickets cost 9.50aa

kk kids tickets cost 3.00kk

The total cost of these tickets is 9.50aa +3.00kk.

_____

Additional comment

We ordinarily expect a variable to be a single letter. This problem statement defines each variable using a double letter, so that is what we have used. (Sometimes Brainly doubles up variable content in copied text, so we suspect that may have happened here.)

Help help help help math

Answers

Answer:

60

Step-by-step explanation:

To begin solving think of just the pants and the shirts. Each of the 3 pair of pants can be paired with one of the 5 shirts giving you. 5x3=15 combinations

Therefore to apply this type of situation to all 5 shirts 3 pairs of pants and 4 ties

(5)(3)(4)=60

Given the following computer output, select the correct least-squares regression line:

Answers

The correct form of the regression line is [tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D).

According to the information presented in the figure, we know the following function:

The independent variable is 'length'.The dependent variable is 'time'.The regression line is of the form: [tex]\ln y = A + B\cdot \ln x[/tex].

Hence, the correct form of the regression line is:

[tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D)

The correct form of the regression line is [tex]\log time = 0.699 + 0.500\cdot \log length[/tex] (Correct choice: D).

To learn more on regression lines, we kindly invite to check this verified question: https://brainly.com/question/7656407

Answer:

D: logTime=0.699 + 0.500

Step-by-step explanation:

0.699 is the x value which can be found in data under Coef and Constant. The y value can be found under coef and log(length)

What is the slope of the line?

Answers

3/1 is the answer follow the line

slope:change in x\change in y

Which of the following rational functions is graphed below

Answers

Answer:

C

Step-by-step explanation:

Ti-83 graph proves it.

HELP ANSWER PART A AND B

Answers

Answer:

part A: median is 12

part B: interquartile rage is 10

Step-by-step explanation:

Part A: to find your median on a box and whisker plot, you just need to look at your middle line in your box. In this case it's 12.

Part B: to find your interquartile range on a box and whisker plot, you subtract your Q1 and Q3. Your Q1 and Q3 will be the two outside lines that make up the rest of your box, in this case would be 6 and 16. To find your Q1 if you don't already have your plot set up, you separate the numbers that are given to you in half and find the median of each side. The first half will be your Q1 and the second half your Q3.

Bethany posts a lit selfie yo, and she receives 49 likes in the first 7 minutes. At this rate, how many likes will she have in 10 minutes?

Answers

Answer:

70 likes

Step-by-step explanation:

49 likes / 7 minutes = 7 likes / minute

10 minutes * 7 likes / minute = 70 likes / 10 minutes

4.
The expression V-18 can be rewritten as ✓-1. 9. 2. What is a simplified version of the
expression?
А 3iv2
8 312
C -3iv2
D-3V2

Answers

i tink its a water balon bcuz i sad so, and my dad left at age 1 cuz he wanted too

If ABCD is a parallelogram, m

Answers

Answer:

ABCD are the first 4 letters ina alphabet sooooo brooo wheres the parallelogram??

Step-by-step explanation:

A farmer's total payment for tools and compost over the course of two years is $27,894. Write and
solve an equation to find the payment for the second year if the first year’s payment is $10,205.

Answers

Answer:

The second years payment is 17689.

Step-by-step explanation:

If the first year is $10,205 then you subtract 10205 from 27894 which is 17689.

Equation: $27894-$10,205= $17689

Which value of x is a solution of the equation 4(x + 3) - 10 =6 (x -2)

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{4(x + 3) - 10 = 6(x -2)}\\\large\textsf{4(x) + 4(3) - 10 = 6(x) + 6(-2)}\\\large\textsf{4x + 12 - 10 = 6x - 12}\\\large\textsf{4x + 2 = 6x - 12}\\\large\text{SUBTRACT 6x to BOTH SIDES}\\\large\textsf{4x + 2 - 6x = 6x - 12 - 6x}\\\large\text{SIMPLIFY IT!}\\\large\text{NEW EQUATION: \textsf{-2x + 2 = -12}}\\\large\text{SUBTRACT 2 to BOTH SIDES}\\\large\textsf{-2x + 2 - 2 = 6x - 12 - 6x}\\\large\text{SIMPLIFY IT!}\\\large\textsf{-2x = -14}\\\large\text{DIVIDE -2 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{-2x}{-2}= \dfrac{-14}{-2}}\\\large\text{CANCEL out: }\rm{\dfrac{-2}{-2}}\large\text{ because it gives you 1}\\\large\text{KEEP: }\rm{\dfrac{-14}{-2}}\large\text{ because it helps solve for the x-value}\\\large\text{NEW EQUATION: }\mathsf{x = \dfrac{-14}{-2}}\\\large\text{SIMPLIFY IT!}\\\large\textsf{x = 7}\\\\\\\huge\boxed{\text{Therefore, your answer is: \boxed{\textsf{x = 7}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Third-degree, with zeros of -4, -2, and 1, and a y-intercept of -11.

Answers

[tex]\begin{cases} x = -4\implies &x+4=0\\ x=-2\implies &x+2=0\\ x=1\implies &x-1=0 \end{cases}\qquad \implies (x+4)(x+2)(x-1)=\stackrel{y}{0}[/tex]

now, that's the equation or polynomial in factored form, hmmm we also know that it has a y-intercept of -11, namely, when x = 0  y = -11, well let's plug in a factor to it, that will reflect those values, namely say hmmm factor "a", so

[tex](x+4)(x+2)(x-1)=y\qquad \stackrel{\textit{adding "a" factor for vertical shift}}{a(x+4)(x+2)(x-1)}=y \\\\\\ \stackrel{\textit{we know that when x = 0, y = -11}}{a(0+4)(0+2)(0-1)=-11}\implies -8a=-11\implies a=\cfrac{-11}{-8}\implies a = \cfrac{11}{8} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\mathbb{FOIL}}{\cfrac{11}{8}(x^2+6x+8)}(x-1)=y\implies \cfrac{11}{8}(x^3+6x^2+8x-x^2-6x-8)=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{11}{8}(x^3+5x^2+2x-8)=y~\hfill[/tex]

1. Gavin buys 89 blue pansies and
86 yellow pansies. He will plant the flowers
in 5 rows with an equal number of plants
in each row. Draw a bar model to help you
find how many plants will be in each row,
O
17
Spiral Review

Answers

nose nilo que dise perdoooooooon xd

The sum of two angles of a triangle is
110°. Calculate the third angle in
degrees.

Answers

Answer:

70

Step-by-step explanation:

the sum of all angles is 180°

so 180-110= 70

What is thermodynamics ​

Answers

Answer:

Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, entropy, and the physical properties of matter and radiation.

In ΔABC, m∠1=70° and m∠4=35°. What is m∠3?

Answers

Answer:

75

Step-by-step explanation:

A triangle can only have 3 angles that add up to 180 degrees. Subtract 70 and 35 from 180 to get 75.

180=x+70+35

180-(70+35)=x

PLEASE HELP -7y + 11 = 75 + y

Answers

Answer:

y = -8

Step-by-step explanation:

-7y + 11 = 75 + y

Bring the "y" variable on one side, and rest on the other.

Rearranging, we get,

-7y - y = 75 - 11

-8y = 64

-y = 8

y = -8

Hope it helps :)

Simplify -3(-4x + 2)

Answers

Step-by-step explanation:

12x - 6 is your answer in simplified form

Lisa is earning 7.50 dollars per hour she worked for 33 hours last week. how much money did she earn?

Answers

Answer:

Lisa earned $247.50 for working 33 hours.

Step-by-step explanation:

WAY 1: proportional reasoning

7.50 x

------ = ----

1 h 33h

33 / 1 = 33

7.50 x 33 = 247.5

WAY 2: unit rate reasoning

7.50 per hour so x value of money for 33 h

7.50 x 33 = 247.5

Answer:

247.50 Dollars

Step-by-step explanation:

If Lisa earns 7.50$ per hour and she has worked for 33 hours, and then if the question asks how much money she earned it'd have to be 7.50*33. Which is 247.50, and its asking how much money so then you'd have to write the dollars next to the answer, so the answer is,

247.50 Dollars

Chang works as a tutor for $11 an hour and as a waiter for $13 an hour. This month, he worked a combined total of 90 hours at his two jobs. Let t be the number of hours Chang worked as a tutor this month. Write an expression for the combined total dollar amount he earned this month.

Answers

Can you show more information please? I need more.

T = 90t + 90w

Step-by-step explanation:

90t = 90x11 = 990

90w = 90 x 13 = 1170

T = 90t + 90w

T = 990 + 1170

T = 2160

Tropical dried fruit costs $1.50 per pound and regular dried fruit costs $0.90 per pound. You want to create a mixed bag of tropical dried fruit and regular dried fruit that is worth $1.30 per pound. How many pounds of tropical dried fruit do you need if you have already purchased 50 pounds of regular dried fruit?

Answers

t = total amount of lbs of Tropical dried fruit

m = total amount of lbs of mixed bag

[tex]\begin{array}{lcccl} &\stackrel{fruit}{lbs}&\stackrel{per~lb}{price}&\stackrel{total}{price}\\ \cline{2-4}&\\ \textit{tropical fruit}&t&1.50&1.5t\\ \textit{regular fruit}&50&0.90&45\\ \cline{2-4}&\\ \textit{mix bag}&m&1.30&1.3m \end{array}~\hfill \begin{cases} t+50=m\\ 1.5t+45=1.3m \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{substituting on the 1st equation}}{1.5t+45=1.3\stackrel{m}{(t+50)}}\implies 1.5t+45=1.3t+65\implies 0.2t+45=65 \\\\\\ 0.2t=20\implies t=\cfrac{20}{0.2}\implies \boxed{t=100}[/tex]

QUESTION 17 PLEASE HELP ME ASAPP

Answers

Answer: change over time
Explanation: it is decreasing in height therefore is decreasing in altitude

Hey there!

• If it CHANGES it means your temperature/time changes a bit overtime

• If it CONSTANT your temperature/time remains the same

So, basically to this question it was INCREASED then it was DECREASED

Therefore, your answer is: “Option A. “

Because it didn’t stay same

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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