Randy is walking home from school. According to the diagram above, what is his total distance from school to home? Show your work and include units. If he had a jet pack, would you use distance or displacement? Why?
Answers
Answer:
First, when he walks, we can see in the image that between the school and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.
Then he needs to walk 2km.
Now if he has a jet-pack, he can ignore the buildings and just take the shorter path, here we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.
One of the catheti is the vertical distance (two blocks of 0.5km, so this catheti has a length of 2*0.5km = 1km), and the other one is the horizontal distance, also 1km.
The actual distance of this path is given by the Pythagorean's theorem:
A^2 + B^2 = H^2
Where A and B are the cathetus, and H is the hypotenuse, then:
H^2 = 1km^2 + 1km^2
H = (√2)km = 1.41km.
Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, in this case the distance and the displacement would be the same.
This is because the definitions of distance and displacement are:
Distance: "how much ground an object has covered"
Displacement: "Difference between the final position and the initial position"
When he walks, the distance is 2km and the displacement is 1.41km , but when he uses the jet pack, the distance is equal to the displacement, both are 1.41km.
Answer and Step-by-step explanation:
The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km. The result of this is a total of 4¨*0.5 km = 2 km. The second thing is that he must walk 2 kilometers. On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings. This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home. As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km. The result is that these catheti have a length of 2*0.5 km = 1 km. The other is the distance of the horizontal line, which is 1 km. The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2. Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2. As well, H = (√2)km = 1.41 km. Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow. For this specific situation, the displacement, and the distance would be the exact same. The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered. Also, when he walks, the distance is 2 km and the displacement is 1.41 km. Also, when he utilizes the jet pack, the distance is equal to the displacement. Both of these are 1.41 km.
Related Questions
Players A and B play a basketball game in which they take turns shooting the ball, and the first player to make their shot wins. Player A has probability 2/3 of making each of her shots. Player B has probability 1/2 of making each of his shots. If Player A shoots first, what is the probability that she will win
Answers
Answer:
Player A has a probability 2/3 of making each of her shots, then she has a probability 1/3 of missing each shot.
Player B has a probability 1/2 of making each of his shots, then he also has a probability 1/2 of missing each shot.
Let's separate each case.
Let's define:
P(x) = probability of winning at the "x" shot.
Player A wins on the first shot.
Because she has a probability 2/3 of making each of her shots, the probability of winning at the first shot is
P(1) = 2/3
Now let's see the next case, player A wins at her second shot.
This means that first, she misses her first shot, with a probability of:
p₁ = 1/3
Player B must miss his shot, the probability is:
p₂ = 1/2
Now player A must make her shot, so the probability is:
p₃ = 2/3
The joint probability is the product of the individual probabilities, so we have:
P(2) = (1/3)*(1/2)*(2/3) = 1/9
Now we can see the pattern, for P(3) we have
A misses: p₁ = 1/3 (first shot of A)
B misses: p₂ = 1/2
A misses: p₃ = 1/3 (Second shot of A)
B misses: p₄ = 1/2
A makes the shot: p₅ = 2/3
P(3) = (1/3)*(1/2)*(1/3)*(1/2)*(2/3) = 1/54
We already can see the pattern.
P(n) = (1/3)^(n - 1)*(1/2)*(n - 1)*(2/3)
Player A has a probability P of winning, and we can write P as:
P = P(1) + P(2) + P(3) + ...
Then we will have:
P = 2/3 + 1/9 + 1/54 + 1/324 + ... ≈ 0.8
Layla is going to drive from her house to City A without stopping. Layla plans to drive
at a speed of 30 miles per hour and her house is 240 miles from City A. Write an
equation for D, in terms of t, representing Layla's distance from City A t hours after
leaving her house.
Answers
Answer:
D = 240 - 30t
Step-by-step explanation:
If the equation represents her distance from City A, we need to include 240 in the equation to represent the distance to the city.
Then, we need to subtract 30t from 240 in the equation because 30t represents how far she will have traveled in t hours.
So, D = 240 - 30t is the equation that will represent Layla's distance from the city.
Which of the following correctly shows the quotient of 80 divided by 5 ?
Answers
Answer:16
Step-by-step explanation:
Just divide 80 by 5 or skip count by fives.
. A population is currently 6,000 and has been increasing by 1.2% each day. Write an exponential model for the population.
Answers
Answer: [tex]A=6000(1.012)^t[/tex]
Step-by-step explanation:
General exponential function:
[tex]A=P(1+r)^t[/tex]
, where P= current population
r= rate of growth
t= time period
A= population after t years
As per given , we have P=6,000
r= 1.2% = 0.012
Then, the required exponential function: [tex]A=6000(1+0.012)^t[/tex]
or [tex]A=6000(1.012)^t[/tex]
Subtract 750 -389 plzzz help
Answers
Therefore, 361
Ashley, Milan, and Carlos sent a total of 131 text messages over their cell phones during the weekend. Carlos sent 7 times as many messages as Ashley. Ashley sent 4 more messages than Milan. How many messages did they each send?
Answers
Answer:
Ashley= 15
Milan= 11
Carlos= 105
Step-by-step explanation:
Let, A, M and C denotes Ashley, Milan and Carlos respectively.
A+M+C= 131 (according to the question)
Here,
C= 7A
A= M+ 4
So, M= A - 4
Now,
A+M+C = 131
or, A+ A-4+ 7A = 131 (putting the values)
or, 9A - 4 = 131 (adding like terms i.e. A + A + 7A)
or, 9A = 131 + 4
or, 9A = 135
or, A = 135 / 9
So, A = 15
C= 7A = 7×15= 105
M= A-4 = 15 - 4 = 11
6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally distributed; however we are taking a sample of 25 cars with a sample mean of 96.52 and a sample standard deviation of 10.70. Calculate a 90% confidence interval for the population mean using this sample data.
Answers
Answer:
92.9997<[tex]\mu[/tex]<99.5203
Step-by-step explanation:
Using the formula for calculating the confidence interval expressed as:
CI = xbar ± Z * S/√n where;
xbar is the sample mean
Z is the z-score at 90% confidence interval
S is the sample standard deviation
n is the sample size
Given parameters
xbar = 96.52
Z at 90% CI = 1.645
S = 10.70.
n = 25
Required
90% confidence interval for the population mean using the sample data.
Substituting the given parameters into the formula, we will have;
CI = 96.52 ± (1.645 * 10.70/√25)
CI = 96.52 ± (1.645 * 10.70/5)
CI = 96.52 ± (1.645 * 2.14)
CI = 96.52 ± (3.5203)
CI = (96.52-3.5203, 96.52+3.5203)
CI = (92.9997, 99.5203)
Hence a 90% confidence interval for the population mean using this sample data is 92.9997<[tex]\mu[/tex]<99.5203
[tex]\int\limits^9_3 {\frac{1}{(x+21)\sqrt{x+22} } } \, dx[/tex]
Answers
Let y = x + 22 and dy = dx, so the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{25}^{31} \frac{\mathrm dy}{(y-1)\sqrt{y}}[/tex]
Now let z = √y, so that z ² = y. Then 2z dz = dy, and the integral becomes
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{\sqrt{25}}^{\sqrt{31}} \frac{2z}{(z^2-1)z} \\\\ = \int_5^{\sqrt{31}} \frac{2}{z^2-1}\,\mathrm dz[/tex]
Expand the integrand into partial fractions:
[tex]\dfrac{2}{z^2-1} = \dfrac1{z-1}-\dfrac1{z+1}[/tex]
Then we have
[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_5^{\sqrt{31}}\left(\frac1{z-1}-\frac1{z+1}\right)\,\mathrm dz \\\\ = \left(\ln|z-1|-\ln|z+1|\right)\bigg|_5^{\sqrt{31}} \\\\ =\left[\ln\left|\frac{z-1}{z+1}\right|\right]\bigg|_5^{\sqrt{31}} \\\\ =\ln\left(\frac{\sqrt{31}-1}{\sqrt{31}+1}\right) - \ln\left(\frac{4}{6}\right) \\\\ =\ln\left(32-2\sqrt{31}\right) - \ln\left(\frac23\right) \\\\ =\boxed{\ln\left(48-3\sqrt{31}\right)}[/tex]
Help me please answer this, this will be my first grade for freshman year. The picture of the question is down below.
Answers
Answer:
D
Step-by-step explanation:
-0.81 is a high negative correlation, which means the y is decreasing with x increasing, which means y(the number of broken glass) decreases when x(amount of paper used) increased. So we can say that the toilet paper is surely helping.
make me brainly if you find it correct
in the diagram, POS,QOT and UOR are straight lines. Find the value of y.
Answers
Answer:
y = 15°
Step-by-step explanation:
Since ∠QOR and ∠UOT are vertical, they are congruent so ∠UOT = 5y. Since POS is a straight line (which has a measure of 180°) and ∠POS = ∠POU + ∠UOT + ∠TOS, we can write:
5y + 5y + 2y = 180
12y = 180
y = 15°
PLS PLS PLS HELP QUICKKKK
Find the value of x in each case
Answers
Answer:
KI and HE are parallel
So we apply the law of exterior angles ;
3X=X + 180– 2X
3X +X = 180
4X= 180
X= 180/4
X= 45
I hope I helped you^_^
A research center project involved a survey of 851 Internet users. It provided a variety of statistics on Internet users. (a) The sample survey showed that 92% of respondents said the Internet has been a good thing for them personally. Develop a 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally. (Round your answers to four decimal places.)
Answers
Answer:
The answer is "(0.9193924 , 0.9206076)".
Step-by-step explanation:
[tex]\text{sample proportion}\ (SP) = 0.92\\\\\text{sample size}\ n = 851\\\\\text{Standard error} \ SE = \sqrt{\frac{(SP \times(1 - SP)}{n})}\\\\[/tex]
[tex]= \sqrt{\frac{(0.92 \times (0.08)}{851})}\\\\= \sqrt{\frac{0.0736}{851}}\\\\= \sqrt{8.648\times 10^{-5}}\\\\=0.00031[/tex]
[tex]\text{CI level is}\ 95\% \\\\\therefore\\\\ \alpha = 1 - 0.95 = 0.05\\\\\frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\ Z_c = Z_{(\frac{\alpha}{2})} = 1.96[/tex]
Calculating the Margin of Error:
[tex]ME = z_{c} \times SE\\\\[/tex]
[tex]= 1.96 \times 0.00031\\\\ = 0.0006076[/tex]
[tex]CI = (SP - z*SE, SP + z*SE)[/tex]
[tex]= (0.92 - 1.96 * 0.00031 , 0.92 + 1.96 * 0.00031)\\\\ = (0.92 - 0.0006076 , 0.92 + 0.0006076)\\\\= (0.9193924 , 0.9206076)[/tex]
f=((-1,1),(1,-2),(3,-4)) g=((5,0),(-3,4),(1,1),(-4,1)) find (fg)(1)
Answers
Answer:
f(g(1)) = - 2
Step-by-step explanation:
Find g(1) then use the value obtained to find f(x)
g(1) = 1 ← value of y when x = 1 (1, 1 ) , then
f(1) = - 2 ← value of y when x = 1 (1, - 2 )
If ABCD is dilated by a factor of 3 the coordinates of A would be
Answers
Answer:
A'=(-9, - 3)
Step-by-step explanation:
A' will be 3*(the coordinates of A), A'=(-9, - 3)
Coordinates of A' are given by (-9,-3).
What is Coordinates?Coordinates of a point suggest the position of that particular point in the Cartesian Plane.
If the coordinates of a point are (x,y) then x is the distance of the point from Y-axis and y is the distance from the X-axis.
Here in the given graph, we can see that the coordinates of A of quadrilateral ABCD are (-3,-1)
ABCD is dilated by a factor of 3.
So the coordinates of the A' which is the point A after dilating by 3 are given by the product of 3 and corresponding original coordinations.
Hence the coordinates of A' are = (3*(-3),3*(-1)) = (-9,-3)
Learn more about Coordinates here -
https://brainly.com/question/20362114
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Martin writes down 4
numbers.
Their mean is 8.
The range is 6.
The largest value is 11.
There is no mode.
Write down the four
numbers.
Answers
Answer:
5, 7, 9, 11
or
5, 6, 10, 11.
Step-by-step explanation:
The mean is 8 so the total value of the 4 numbers = 4*8 = 32.
Range is 6 so largest number - smallest = 6
The largest value is 11 so the smallest is 11-6 = 5
The middle 2 numbers add up to 32-(11+5) = 32 - 16
= 16.
- and as there is no mode they must be 7 and 9
or 6 and 10.
Lillie is saving up for a trip she is taking with friends during her break from school. If Lillie's current monthly net pay is $560.00 and her monthly expenses are $347.49, what percent of her net pay is left for savings? (2 points)
19%
23%
38%
Answers
Answer:
38%
Step-by-step explanation:
First determine her savings
560-347.49
212.51
Then divide by the total amount
212.51/560
.379482143
Change to percent form
37.948%
Answer:
38%
Step-by-step explanation:
[tex]560.00-347.49=212.51\\212.51\div560.00==38[/tex]
A restaurant is doing a special on burgers. If the home team get a sack, the next day, burgers will cost$1
Normally, they cost $3,99. If every fan who attended the game (86,047 people) buys a $1.00 burger, how™
money did the restaurant lose with this discount?
Answers
ans: 257,256.59
if it was sold for $3.99
it would have been 86,047 × $3.99 = 343,303.59 and it was sold for $1 instead so automatically it's $86,047
therefore
343, 303.59
-86, 047 which is equal to a loss of $257, 256.59
here is my question hope this works now
Answers
Answer:
[tex]\boxed{x=1}[/tex] and [tex]\boxed{x=7}[/tex]
Step-by-step explanation:
This quadratic is already factored down to its factors (x - 1) and (x - 7).
Set these equal to zero and solve for x by adding 1 or 7 to both sides of the equation.
[tex]x-1=0\\\\\boxed{x=1}[/tex]
[tex]x-7=0\\\\\boxed{x=7}[/tex]
Determine the positive integer values of k for which the following polynomia
over the integers given: c^2 – 7c+ k
Answers
Explanation:
c^2 - 7c + 10
= (c -5)(c-2)
c^2 - 7c + 12
= (c - 4)(c -3)
c^2 - 7c + 6
= (c - 1)(c - 6)
evaluate the expression for -c-12=
Answers
Answer:
-10
Step-by-step explanation:
We can substitute c into the equation as -2.
[tex]-(-2) - 12[/tex]
Two negatives make a positive:
[tex]2-12[/tex]
And [tex]2 - 12 = -10[/tex].
Hope this helped!
0.18 divided by 0.04
Answers
If f(x) = 3x-1 and g(x)= x+2 find (f-g) (x)
Answers
Answer:
2x-3
Step-by-step explanation:
f(x) = 3x-1
g(x)= x+2
(f-g) (x) = 3x-1 - (x+2)
Distribute the minus sign
= 3x-1 -x-2
Combine like terms
= 3x-x -1-2
=2x -3
The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 100, and the standard deviation is 2. You wish to test H0: μ = 100 versus H1: μ ≠ 100 with a sample of n = 9 specimens.
A. If the acceptance region is defined as 98.5 le x- 101.5, find the type I error probability alpha.
B. Find beta for the case where the true mean heat evolved is 103.
C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?
Answers
Answer:
A.the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]
B. β = 0.0122
C. β = 0.0000
Step-by-step explanation:
Given that:
Mean = 100
standard deviation = 2
sample size = 9
The null and the alternative hypothesis can be computed as follows:
[tex]\mathtt{H_o: \mu = 100}[/tex]
[tex]\mathtt{H_1: \mu \neq 100}[/tex]
A. If the acceptance region is defined as [tex]98.5 < \overline x > 101.5[/tex] , find the type I error probability [tex]\alpha[/tex] .
Assuming the critical region lies within [tex]\overline x < 98.5[/tex] or [tex]\overline x > 101.5[/tex], for a type 1 error to take place, then the sample average x will be within the critical region when the true mean heat evolved is [tex]\mu = 100[/tex]
∴
[tex]\mathtt{\alpha = P( type \ 1 \ error ) = P( reject \ H_o)}[/tex]
[tex]\mathtt{\alpha = P( \overline x < 98.5 ) + P( \overline x > 101.5 )}[/tex]
when [tex]\mu = 100[/tex]
[tex]\mathtt{\alpha = P \begin {pmatrix} \dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{\overline 98.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} + \begin {pmatrix}P(\dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{101.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} }[/tex]
[tex]\mathtt{\alpha = P ( Z < \dfrac{-1.5}{\dfrac{2}{3}} ) + P(Z > \dfrac{1.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\alpha = P ( Z <-2.25 ) + P(Z > 2.25) }[/tex]
[tex]\mathtt{\alpha = P ( Z <-2.25 ) +( 1- P(Z < 2.25) })[/tex]
From the standard normal distribution tables
[tex]\mathtt{\alpha = 0.0122+( 1- 0.9878) })[/tex]
[tex]\mathtt{\alpha = 0.0122+( 0.0122) })[/tex]
[tex]\mathbf{\alpha = 0.0244 }[/tex]
Thus, the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]
B. Find beta for the case where the true mean heat evolved is 103.
The probability of type II error is represented by β. Type II error implies that we fail to reject null hypothesis [tex]\mathtt{H_o}[/tex]
Thus;
β = P( type II error) - P( fail to reject [tex]\mathtt{H_o}[/tex] )
∴
[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]
Given that [tex]\mu = 103[/tex]
[tex]\mathtt{\beta = P( \dfrac{98.5 -103}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-103}{\dfrac{2}{\sqrt{9}}}) }[/tex]
[tex]\mathtt{\beta = P( \dfrac{-4.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-1.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\beta = P(-6.75 \leq Z \leq -2.25) }[/tex]
[tex]\mathtt{\beta = P(z< -2.25) - P(z < -6.75 )}[/tex]
From standard normal distribution table
β = 0.0122 - 0.0000
β = 0.0122
C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?
[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]
Given that [tex]\mu = 105[/tex]
[tex]\mathtt{\beta = P( \dfrac{98.5 -105}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-105}{\dfrac{2}{\sqrt{9}}}) }[/tex]
[tex]\mathtt{\beta = P( \dfrac{-6.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-3.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\beta = P(-9.75 \leq Z \leq -5.25) }[/tex]
[tex]\mathtt{\beta = P(z< -5.25) - P(z < -9.75 )}[/tex]
From standard normal distribution table
β = 0.0000 - 0.0000
β = 0.0000
The reason why the value of beta is smaller here is that since the difference between the value for the true mean and the hypothesized value increases, the probability of type II error decreases.
look at the image for the question
Answers
Answer:
3166.7
Step-by-step explanation:
V = πr²h
V = π * (12 km)² * 7 km
V ≈ 3166.7 km³
Hey there!
First, let's review the formula for finding a cylinder's volume.
Formula: [tex]\pi r^2h[/tex]
Our new equation would look like this: [tex]\pi[/tex] x [tex]12^{2}[/tex] x 7.
The original answer would be 3166.72539482, but the question states that it want it rounded to the nearest tenth. So, your answer would be 3166.7.
Hope this helps! Have a great day!
How do you write 5.44 in words?
Answers
Answer:
five and forty-four hundredths
Step-by-step explanation:
Answer:
five point four four
Step-by-step explanation:
17. what is the value of x?
18. what is the value of z?
please help me fast!!
Answers
for x ,
8x + 10x = 180°
[sum of linear pair is equal to 180°]
or, 18x = 180°
or, x = 180/18
therefore, x = 10°……
for z,
10z =8x
[ being corresponding angles are equal ]
or, 10z = 8 × 10°
( replacing x by 10°)
or, 10z = 80°
or, z = 80/10
thus z = 8°…………
It can be shown that the line with intercepts (a, 0) and (0, b) has the following equation:
x/a + y/b= 1, a ≠ 0, b ≠ 0.
Use this result to write an equation of the line.
Point on line:
(−2, 4)
x-intercept: (a, 0)
y-intercept: (0, a)
(a ≠ 0)
Answers
The equation of the straight line is [tex]x+y=2[/tex].
Given:
The line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex] Point on the line: (-2, 4)x-intercept: (a, 0)y-intercept: (0, a)[tex]a\neq 0[/tex]To find: The equation of this line
It is given that a line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex]
Now, it is given that the referred line has intercepts (a, 0) and (0, a). Then, using the above statement, the equation of this line can be written as,
[tex]\frac{x}{a} +\frac{y}{a}=1[/tex]. It is already given that [tex]a\neq 0[/tex]. So, we need not mention it again.
It is also given that the point (-2, 4) lies on this line. Then, the coordinates of this point must satisfy the equation of the line.
This implies that,
[tex]\frac{-2}{a} +\frac{4}{a} =1[/tex]
[tex]\frac{2}{a} =1[/tex]
[tex]a=2[/tex]
Now, put [tex]a=2[/tex] in the equation of the line, [tex]\frac{x}{a} +\frac{y}{a}=1[/tex] to get,
[tex]\frac{x}{2} +\frac{y}{2} =1[/tex]
[tex]x+y=2[/tex]
So, the equation of the line is [tex]x+y=2[/tex].
Learn more about equations of straight lines here:
https://brainly.com/question/18879008
I need help with these
Answers
Answer:
2. 20 oranges
3. 18 yellow tulips
4. 23 students
Complete the function table
Answers
Fuller bought 4 cantaloupes at the grocery store. Each cantaloupe weighed between 4.5 and 6.3 pounds. Fuller estimates a reasonable weight of all the cantaloupes to be 21.2 pounds.
Answers
Answer:
Step-by-step explanation:
3w + 2c = 32
4w + 3c = 44
Multiply the 1st equation by 4 and 2nd equation by 3, we get:
12w + 8 c = 128
12w + 9 c = 132
Subtracting the top equation from the bottom equation, we get: c = 4
Substituting c = 4 in any one of the above equations and solving, we get: w = 8
Therefore, weight of 2w + 1c = 2(8) + 4 = 20 pounds (Answer)