Ram obtains 40% of the marks in a paper of 200 marks. Shyam is ahead of Ram by 25% of Ram' s marks, while Bhuvan is ahead of Shyam by one month of his own marks. How many marks does Bhuvan get?​

Answer:

First, we start with:

"Ram obtains 40% of the marks in a paper of 200 marks"

In this case, 200 marks represent the 100%

Then how much is the 40%?

we have the relations:

40% = X

100% = 200 marks

Now we can take the quotient of both equations:

(40%/100%) = X/200marks

(40%/100%)*200marks = X = 80 marks

So Ram obtained 80 marks.

Now we have:

"Shyam is ahead of Ram by 25% of Ram's marks"

Now the 100% is the number of marks that Ram has, this is:

100% = 80 marks

And Shyam has 25% more than that, then we have:

125% = X

Same as before, we take the quotient of both equations:

(125%/100%) = X/80 marks

1.25*80 marks = 100 marks.

Shyam has 100 marks.

The last part is (this is not written correctly, it says "one month", it should be "one-ninth")

"while Bhuvan is ahead of Shyam by one-ninth of his own marks."

if his own marks are X, we have the equation

X = 100 + (1/9)*X

X - 1/9*X = 100

X*(8/9) = 100

X = (9/8)*100 = 112.5

So Bhuvan has 112.5 marks

A srtuv
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D rsvut

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