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a sound wave has a frequency of 85 Hz and a wavelength of 4.2 m. what is the wave speed of the sound wave?

A. 357 seconds

B. 89.2 m/s

C. 357 m/s

D. 20 m/s

Answer:

The speed would be about 80.8 km/h

Explanation:

Notice that the ship really traveled northeast (at 45 degrees north from East) covering eastwards 4727 km.

That means (by using the East projection in a right angle triangle) that the total distance was  (the hypotenuse of the right angle) :

[tex]Distance= \frac{4727}{cos(45^o)} \approx 6685\,\,km[/tex]

Then the velocity of the ship was the quotient between this distance divided the time it took. Now,notice that the time is given in days, hours, and minutes, but we need the final velocity answer in km per hour. Then we reduce the given time to hours:

3 days + 10 hours + 40 min = 3 (24) h + 10 h + (40/60) h = 248/3 hours which is approximately 82.7 hours.

Then this record speed is the quotient:

6685 km / 82.7 h = 80.8 km/h

Answer:

yes

Explanation:

The hypothesis is scientific because there is no solid evidence to draw out the theory. Therefore the idea of other intelligence on other planets is scientific until found unworthy or scientifically proven wrong enough. Hope this helps a little:)

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.

Answer:

approximately 27 days

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis.

Explanation:

because it uses a systematic method of asking and answering problems, and it attempts to develop solution to psychological problems.

Answer:

it uses a systematic method of asking and answering problems,

Explanation:

Answer:

I think C but I'm not sure

The statement that illustrates how engineering has influences society is nuclear power plants provide cheap electricity to power people's homes. The correct option is A.

This claim serves as an example of how engineering has impacted society. Because they offer a practical and economical source of electricity for lighting up homes and other infrastructure, nuclear power plants have had a big impact on society.

The ability to create electricity from the energy held in atoms thanks to improvements in nuclear technology has boosted the availability and affordability of power for users.

This illustrates how advances in engineering can influence and enhance how society fulfils its energy needs.

Thus, the correct option is A.

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Answer:

0.55 hz

Explanation:

Given that the plane fly through the turbulent boundary layer of the atmosphere at a speed of 50 m/sec. And the velocity fluctuations in the atmosphere are of order 0.5 m/sec, the length scale of the large eddies is about 100 m.

The maximum speed attained will be

Maximum speed = 50 + 0.5 = 5.5 m/s

The Length = 100m

Speed = FL

Where F = frequency

Substitute speed and distance length into the formula

55 = 100F

F = 55/100

F = 0.55 Hz

Therefore, the highest frequency the anemometer will encounter will be 0.55 Hz

Answer:

40079 Hz

Explanation:

1. The first step is to calculate energy dissipation ∈=u^3/l and here u is fluctuating velocity

∈=(0.5^3)/100 = 0.00125 m^2/s^3

2. Find out the length scale of the small eddies

η=(viscosity/∈)^1/4

η=(1.470e-5/0.00125)^1/4 = 0.00126 m

3. The frequency associated with these small-scale eddies will be the greatest frequency the anemometer will encounter, thus:

u_max=f_max * η

u_max = u + u' = 50+0.5=50.5 m/s

f_max = u_max/η = 50.5/0.00126 = 40079 Hz

This is the heighest frequency the anemometer will encounter.

Answer:

0.00050, 0.000000000406, 36513

The correct answer is A) d = v * t

Explanation:

When writing an equation the goal is to represent the equality between different mathematical expressions or elements. Due to this, in an equation the symbol = is always used. Additionally, to translate a sentence into an equation, the variables should be represented using numbers or letters.

For example, in the sentence "The distance traveled is the speed multiplied by the time" there are three variables mentioned: distance, speed, and time. Also, these can be represented through the letters d (distance), v (speed or velocity), and t (time). Besides this, the sentence explains speed should be multiplied by time, which means it should be written as v × t or v * t and this is equivalent (=) to distance or t. According to this, the final equation would be d = v * t.

Answer:

vertical axis measures voltage while

The horizontal axis of an oscilloscope measures time

2) we are told that Period

T = 25 microseconds = 25*10^-6 s

So we also know that

frequency f = 1/T

So

= 1/(25*10^-6)

= 40,000 Hz

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

F = 1.6 N

Answer:

No

Explanation:

Hurricanes always do not bring heat. For example, Hurricane Sandy brought snow.

Answer:

The correct answer is:

It asks about a cause-and-effect relationship between two variables (A)

Explanation:

Scientific investigations are aimed as developing a hypothesis and proving the validity or not of the hypothesis developed. In order for these hypotheses to be tested, experiments must be done, and the experiments are designed based on the identification of a cause-and-effect relationship existing between two variables to be tested, where the "cause" is varied to various degrees and the "effect" of the variation is recorded. Therefore, knowing the cause-and-effect relationship will guide the experimental design, which will be aimed at manipulating the causes to see how these manipulations affect the second variable.

Answer:

A

Explanation:

Let both the balls have the same mass equals to m.

Let [tex]v_1[/tex] and [tex]v_2[/tex] be the speed of the ball1 and the ball2 respectively, such that

[tex]v_1>v_2\;\cdots(i)[/tex]

Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.

The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, [tex]v[/tex], is [tex]\frac 12 m v^2[/tex]

and the potential energy is due to the change in height is [tex]mgh[/tex] [where [tex]g[/tex] is the acceleration due to gravity]

So, the total energy of ball1,

[tex]=\frac 12 m v_1^2 + mgh\;\cdots(ii)[/tex]

and the total energy of ball1,

[tex]=\frac 12 m v_2^2 + mgh\;\cdots(iii)[/tex].

Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)

So, [tex]\frac 12 m v_1^2 >\frac 12 m v_2^2[/tex]

Now, from equations (ii) and (iii)

The total energy of ball1 hi higher than the total energy of ball2.

The magnitude of the resultant vector is D, 7.0 meters/second, and the direction is to the left.

To add these two velocity vectors, find the magnitude and direction of each vector. The magnitude of the first vector is 5.8 meters/second, and the direction is to the right. The magnitude of the second vector is 1.2 meters/second, and the direction is to the left.

To find the magnitude of the resultant vector, add the magnitudes of the two vectors. The magnitude of the resultant vector is 5.8 meters/second + 1.2 meters/second = 7.0 meters/second.

To find the direction of the resultant vector, find the angle between the two vectors. The angle between the two vectors is 180 degrees. The direction of the resultant vector is 180 degrees from the first vector, which is to the left.

Therefore, the magnitude of the resultant vector is 7.0 meters/second, and the direction is to the left.

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Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

[tex]v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s[/tex]

Hence, the student's average velocity is 1.69 m/s.

The student's average velocity will be "1.69 m/s".

The main distinction between velocity as well as speed would be that velocity, like speed, seems to have a direction and therefore it is a vector quantity.

This same distance travelled together along a straight line throughout a particular direction from either the beginning point is defined as displacement. Because displacement has both size as well as the direction, it's a vector quantity.

Given values:

We know,

The velocity (v):

= [tex]\frac{Displacement}{Time}[/tex]

By substituting the values, we get

= [tex]\frac{304}{180}[/tex]

= [tex]1.69 \ m/s[/tex]

Thus the answer above is correct.

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Answer:

I hope you fall down a 40 floor hotel resort onto the porch, and explode into the gushing body you are!

Explanation:

Answer:

(a) The velocity of the car before the brakes were applied is 77.46 ft/s

(b) The time required for the car to stop is 7.8 s

Explanation:

Given;

acceleration of the car, a = 10 ft/s²

distance traveled by the car, d = 300 ft

(a) the velocity of the car before the brakes were applied is given;

v² = u² + 2ad

v² = 0 + 2(10 x 300)

v² = 6000

v = √6000

v = 77.46 ft/s

(b) the time required for the car to stop

d = ut + ¹/₂at²

d = 0 +  ¹/₂at²

d = ¹/₂at²

t² = 2d / a

t = √ ( 2d / a)

t = √ ( 2 x 300 / 10)

t = 7.8 s

Therefore, the time required for the car to stop is 7.8 s

The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.

Using the formula:

v² = u² + 2as

Where S is the distance = 300 ft, u is the initial velocity, a is the acceleration = -10 ft/s², v is the final velocity = 0 ft/s (stops)

0² = u² + 2(-10)(300)

0 = u² - 6000

u² = 6000

u = 77.46 ft/s

b)

v = u + at

0 = 77.46 - 10t

t = 7.75 s

The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.

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[tex]\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}[/tex]

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Explanation:

They speed up, slow down, or change direction.

Answer:In order for object to be accelerating, the net force (sum of all forces) acting on the object has to be non-zero. According to Newton's Second Law of Motion, Force = Mass x Acceleration. ... If the object is sitting motionless on the ground, then the net force (sum of all forces) acting on it is zero.

Explanation:

Answer:

0.3

Explanation: when you average out the number sthat is the answer you get

Answer:

electrical energy-found in the flow of electrical charges

chemical energy-found in the bonds BTW atoms

thermal energy-found when internal energy is transferred

nuclear energy-found in the nucleus of an atom.

The correct match is: nuclear energy: found in the nucleus of an atom, thermal energy: found when internal energy is transferred, electrical energy: found in the flow of electrical charges, chemical energy: found in the bonds between atoms.

Nuclear energy: This type of energy is obtained from an atom's nucleus. It is released by processes such as nuclear fission or fusion, which utilise the energy held inside atomic nuclei.

Thermal energy is the energy associated with an object's or a system's temperature. When there is a temperature differential, it is a type of internal energy that is exchanged between objects.

Electrical energy is associated with the passage of electric charges, such as electrons, via a conductor.

Chemical energy is contained in the bonds that connect atoms and molecules. When these connections are broken or created, it is released or absorbed during chemical processes.

Thus, this can be the match for the given forms of energy.

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Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

t = 13.43 s

Answer:

total work done = -5960.8 J

Explanation:

given data

initial volume v1 = 0.22 m³

initial pressure  p1 = 86 kPa

final pressue p2 = 101.3 kPa

solution

we apply here  isothermal expansion that is express as

p1 × v1 = p2 × v2    ......................1

put here value

86 × 0.22 = 101.3 × v2

v2 = 0.1867 m³  

and

work done will be here

w1 = p1 × v1  × ln([tex]\frac{p1}{p2}[/tex])      ....................2

w1 = 86 × 10³ × 0.22 × [tex]ln(\frac{86}{101.3})[/tex]

w1 = -3.097  × 10³ J

and

it is cooled to initial volume at constant pressure  so here work done will be

w2 = p(v2 - v1)    .................3

w2 =  86 × 10³ × ( 0.1867 - 0.22 )

w2 = -2863.8 J

so

total work done is

total work done = w1 + w2

total work done = -3097 +  -2863.8

total work done = -5960.8 J

Answer:

b) 40.5 m

Explanation:

Given:

v₀ = 0 m/s

a = 9 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (3 s) + ½ (9 m/s²) (3 s)²

Δx = 40.5 m

Answer:

The value is [tex]a_r = 3.81 *10^{-3} m/s^2[/tex]

Explanation:

Generally the moon's radial acceleration is mathematically represented as

[tex]a_r = r * w^2[/tex]

Here [tex]w[/tex] is the angular velocity which is mathematically represented as

[tex]w =\frac{2 \pi }{ T}[/tex]

substituting [tex]1760 * 10^3 \ seconds[/tex] for T(i.e the period of the moon ) we have

[tex]w =\frac{2 * 3.142 }{ 1760 * 10^3}[/tex]

=> [tex]w = 3.57 *10^{-6} \ rad/s [/tex]

From the question r(which is the radius of the orbit ) is evaluated as

[tex]r = R + H[/tex]

substitute [tex]3.60 * 10^6 m[/tex] for R and [tex]295.0 * 10^6 \ m[/tex] H

       [tex]r =  295.0 * 10^6   +3.60 * 10^6[/tex]

=>   [tex]r =  2.986 *10^{8} \  m [/tex]

So

    [tex]a_r  =   2.986 *10^{8} *  ( 3.57 *10^{-6} )^2[/tex]

      [tex]a_r  = 3.81 *10^{-3} m/s^2[/tex]

i cant understand your question define briefly

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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