QUESTIONS 1. Lizzy a level 300 students at UEW calls her father to send her money to buy Milo which cost $4 each and books which cost $8 each. The father sent her 20 pairs of shoes and 20 pairs of new jeans trousers which she can freely see on the market for $ 20 each and $ 40 each respectively. a. Write down the equation of Lizzy's budget line and interpret the results.
b. Carefully sketch the budget line
c. If Lizzy discovers that substituting two (2) tins of milo for three (3) will not change her level of satisfaction, what must be the lowest price of books before she will substitute milo for books given that the price of milo remains $4.​

Answer:

I got 28

Step-by-step explanation:

use the formula k=y/x. 6/8=0.75

21/0.75=

Answer:

If you deposit $1000 each year into an account earning 8% compounded annually, you will have $13,366.37 in the account in 10 years. Using the compound interest formula A = P(1 + r/n)^(nt), where A is the amount, P is the principal, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years, we can calculate the amount. Plugging in the values, we get A = 1000(1 + 0.08/1)^(1*10) = $2,159.15. Therefore, the total amount after 10 years will be $13,366.37, which is the sum of the principal and the interest earned.

Given,

Annual deposit = $1000

Rate = 8% compounded annually

Time(n) = 10 year

Amount = ?

As we know the formula ,

Amount = P(1+r/100)ⁿ

Amount = 1000(1+8/100)¹⁰

Amount = 1000(1+0.08)¹⁰

Amount =1000(1.08)¹⁰

Amount = 1000 × 2.15892

Amount = $2158.92

Hence, amount in 10year will be $2158.92

The total balance that Sue will have in the two accounts after 5 years can be calculated as follows:

Balance of the first account with simple interest:

FV = P(1 + rt)

FV = $600(1 + 0.075 x 5)

FV = $825

Balance of the second account with compounded interest:

FV = P(1 + r)^n

FV = $900(1 + 0.06)^5

FV = $1,286.87

Total balance = $825 + $1,286.87

Total balance = $2,111.87

The closest answer choice to this amount is F) $2,029.40, which is only off by a small margin. Therefore, the answer is F) $2,029.40.

Answer:

Step-by-step explanation:

I'm sorry, but there seems to be some information missing from your question. Specifically, it is unclear what quantity or angle you want to determine the cosine of.

If you meant to ask for the value of the cosine of an angle given that its sine is 3/4, then we can use the Pythagorean identity to determine the cosine:

sin^2(x) + cos^2(x) = 1

Plugging in sin(x) = 3/4, we get:

(3/4)^2 + cos^2(x) = 1

Simplifying, we have:

9/16 + cos^2(x) = 1

Subtracting 9/16 from both sides, we get:

cos^2(x) = 7/16

Taking the square root of both sides, we get:

cos(x) = ±sqrt(7)/4

Since the sine is positive (3/4 is in the first quadrant), we know that the cosine must also be positive. Therefore:

cos(x) = sqrt(7)/4

I hope this helps! Let me know if you have any further questions.

Answer:20%

Step-by-step explanation:

5(100)/25=20

Answer: 1050$

Step-by-step explanation:

im a math teacher

The fourth term of the sequence with the definition of functions a₁ = 5 and aₙ = 2aₙ₋₁ + 3 is 61.

Given the following definition of functions

a₁ = 5

aₙ = 2aₙ₋₁ + 3

To find the fourth term of the sequence defined by a₁ = 5aₙ = 2aₙ₋₁ + 3, we can use the recursive formula to generate each term one by one:

a₂ = 2a₁ + 3 = 2(5) + 3 = 13

a₃ = 2a₂ + 3 = 2(13) + 3 = 29

a₄ = 2a₃ + 3 = 2(29) + 3 = 61

Therefore, the fourth term of the sequence is 61.

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Answer:

If we change the value of 82° to 94°, the new data set becomes:

58, 61, 71, 77, 91, 100, 105, 102, 95, 94, 66, 57

IQR:

To find the new interquartile range (IQR), we first need to find the new values of the first quartile (Q1) and the third quartile (Q3). The median of the original data set is 84°, which is between the 6th and 7th values when the data is ordered. So, the first half of the data set consists of the values 58, 61, 71, 77, 82, and 91, and the second half consists of the values 94, 95, 100, 102, 105.

The new Q1 is the median of the first half of the data set, which is (71 + 77) / 2 = 74. The new Q3 is the median of the second half of the data set, which is (100 + 102) / 2 = 101.

The new IQR is Q3 - Q1 = 101 - 74 = 27.

Range:

The range is simply the difference between the largest and smallest values in the data set. Before the change, the range was 105 - 57 = 48. After the change, the range is 105 - 58 = 47.

Mean:

To find the new mean, we add up all the temperatures and divide by the number of temperatures. Before the change, the sum was 980 and there were 12 temperatures, so the mean was 980/12 = 81.7° (rounded to one decimal place). After the change, the sum is 982 and there are still 12 temperatures, so the new mean is 982/12 = 81.8° (rounded to one decimal place).

Median:

The median is the middle value in the data set when it is ordered. Before the change, the median was 84°. After the change, the median is still 84°, since only one value was changed and it did not affect the position of the median.

Therefore, the IQR changes the most, increasing from 34° to 27°. The new value of the IQR is 27.

Answer:

Step-by-step explanation:

The correct answer is B. Symmetric property.

The symmetric property states that if a = b, then b = a. In the context of geometry, this property can be used to show that if one side of a figure is congruent to another side, then the second side is also congruent to the first. In the case of the given proof, it is possible that the symmetry of the figure is used to show that opposite sides of the rhombus are congruent.

The reflective property (A) is not typically used to prove that a figure is a rhombus, as it relates to the reflection of a figure across a line. The transitive property (C) and the addition property (D) are also unlikely to be used in this context, as they relate to the properties of equality and addition, respectively, rather than geometric properties of figures.

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By using the Pythagorean theorem we know that the given triangle is not a right triangle.

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between a right triangle's three sides in Euclidean geometry.

According to this statement, the areas of the squares on the other two sides add up to the size of the square whose side is the hypotenuse.

Pythagorean triples consist of the three positive numbers a, b, and c, where a2+b2 = c2.

The symbols for these triples are (a,b,c). Here, a represents the right-angled triangle's hypotenuse, b its base, and c its perpendicular.

The smallest and most well-known triplets are (3,4,5).

So, we have the values already,

Now, calculate as follows:

3² + 4² = 6²

9 + 16 = 36

25 ≠ 36

Hence, the given triangle is not a right triangle.

Therefore, by using the Pythagorean theorem we know that the given triangle is not a right triangle.

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Answer:

a. Since the half-life of the isotope is 8 hours, we know that the decay rate is exponential and we can use the formula:

A(t) = A0 * (1/2)^(t/8)

where A0 is the initial amount of the substance, t is the time elapsed, and A(t) is the amount of substance remaining after t hours.

Substituting the given values, we get:

A(t) = 7 * (1/2)^(t/8)

b. To find the rate at which the substance is decaying, we need to take the derivative of A(t) with respect to t:

A'(t) = -7/8 * (1/2)^(t/8) * ln(1/2)

Simplifying, we get:

A'(t) = -ln(2) * (7/8) * (1/2)^(t/8)

c. To find the rate of decay at 14 hours, we can plug in t=14 into the equation we found in part b:

A'(14) = -ln(2) * (7/8) * (1/2)^(14/8) ≈ -0.4346 grams per hour (rounded to four decimal places)

The graph of f(x) is a parabola that opens downward and has a vertex at (-3/2, 3/4), while the graph of g(x) is a parabola that opens upwards and has a vertex at (-1/2, 7/4). They both intersect at the point (-3/2, -5/4).

Vertex is a mathematical term used to describe the point where two lines or line segments meet. It is the point of intersection for two or more lines. In a two-dimensional plane, a vertex is the point that marks the beginning and end of a line segment. In a three-dimensional plane, a vertex is the point of intersection of three or more lines. A vertex can also refer to a corner, such as the vertex of a triangle or a cube. In graph theory, a vertex is a node, or point, in a graph. Vertex can also refer to the highest point of a graph, such as the vertex of a parabola.

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As a result, Rhonda was paid $18 per hour before to being promoted; nevertheless, she will now be paid $20.70 per hour.

Finding a single unit value and applying it to ratio and proportional problem solving is known as the unitary method in mathematics. It is frequently employed in order to resolve issues involving either direct proportion, inverse proportion, or both. In the unitary technique, the ratio of the quantities' corresponding unit values is used to indicate the relationship between the quantities. The desired value is then achieved by multiplying or dividing the unit value, as necessary.

given

Let x be the hourly wage Rhonda received prior to her promotion.

The issue states that her new hourly wage is equal to 115% of her previous wage:

20.70 = 1.15x

We can divide both sides by 1.15 to find x:

x = 20.70 / 1.15

x = 18

As a result, Rhonda was paid $18 per hour before to being promoted; nevertheless, she will now be paid $20.70 per hour.

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The scale factor of PQRS to JKLM is 4/5.

The scale factor of JKLM to PQRS is 5/4.

The value of w, x, and y are 20, 12.5, and 20 respectively.

The perimeter ratio is 4:5.

In Mathematics and Geometry, the scale factor of a geometric figure can be calculated by dividing the dimension of the image (new figure) by the dimension of the pre-image (original figure):

Scale factor = Dimension of image (new figure)/Dimension of pre-image(actual figure)

Substituting the given parameters into the scale factor formula, we have the following;

Scale factor of PQRS to JKLM = 15/12

Scale factor of PQRS to JKLM = 5/4 or 1.25.

Scale factor of JKLM to PQRS = 12/15

Scale factor of JKLM to PQRS = 4/5 or 0.8.

For the value of w;

15/12 = 25/w

15w = 12 × 25

w = 20

For the value of x;

15/12 = x/10.

12x = 150

x = 12.5

For the value of y:

15/12 = y/16

12y = 15 × 16

y = 20

Perimeter ratio = 12 : 15 = 4:5

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Answer:

It is not true (equal sign with a slash in it) one side’s 23 and the other side is 20

Answer:

[tex] \rm \: f(x) = \dfrac{5}{x} + \dfrac{7}{ {x}^{2} } [/tex]

Differentiating both sides with respect to x

[tex] \rm \dfrac{d}{dx} ( {f}( x) = \dfrac{d}{dx} \bigg( \dfrac{5}{x} + \dfrac{7}{ {x}^{2} } \bigg)[/tex]

Using u + v rule

[tex] \rm \: {f}^{ \prime} x = \dfrac{d}{dx} \bigg( \dfrac{5}{x} \bigg) + \dfrac{d}{dx} \bigg( \dfrac{7}{ {x}^{2} } \bigg)[/tex]

[tex] \rm \: {f}^{ \prime} x = 5. \dfrac{d}{dx} ( {x}^{ - 1} ) + 7. \dfrac{d}{dx} ( {x}^{ - 2} )[/tex]

[tex] \rm \: {f}^{ \prime} x = 5.( - 1. {x})^{ (- 1 - 1)} + 7.( - 2. {x})^{ - 2 - 1} [/tex]

[tex] \rm \: {f}^{ \prime} x = { - 5x}^{ - 2} { - 14x}^{ - 3} [/tex]

[tex] \rm \: {f}^{ \prime} x = - \dfrac{5}{ {x}^{2} } - \dfrac{14}{ {x}^{3} } [/tex]

[tex] \rm \: {f}^{ \prime} x = - \bigg(\dfrac{5}{ {x}^{2} } + \dfrac{14}{ {x}^{3} } \bigg)[/tex]

Hense The required Derivative is answered.

[tex]\boxed{\begin{array}{c|c} \rm \: \underline{function}& \rm \underline{Derivative} \\ \\ \rm \dfrac{d}{dx} ({x}^{n}) \: \: \: \: \: \: \: \: \: \ & \rm nx^{n-1} \\ \\ \rm \: \dfrac{d}{dx}(constant) &0 \\ \\ \rm \dfrac{d}{dx}( \sin x )\: \: \: \: \: \: & \rm \cos x \\ \\ \rm \dfrac{d}{dx}( \cos x ) \: \: \: & \rm - \sin x \\ \\ \rm \dfrac{d}{dx}( \tan x ) & \rm \: { \sec}^{2}x \\ \\ \rm \dfrac{d}{dx}( \cot x ) & \rm- { \csc }^{2}x \\ \\ \rm \dfrac{d}{dx}( \sec x ) & \rm \sec x. \tan x \\ \\\rm \dfrac{d}{dx}( \csc x ) & \rm \: - \csc x. \cot x\\ \\ \rm \dfrac{d}{dx}(x) \: \: \: \: \: \: \: & 1 \end{array}}[/tex]

Answer:

Starting with:

-15 > -11 + w

Add 11 to both sides:

-15 + 11 > w

Simplifying:

-4 > w

Therefore, the solution for the inequality -15 > -11 + w, when solved for w, is:

w < -4

Answer: 82y

Step-by-step explanation:

147y - 65y = 82y

Just perform simple subtraction

6. The ratio of the birth weight to the adult weight of a male black bear is 3:1000.

7. The measure of the angles in the triangle are 36°, 15 x 36° = 540°, and 19 x 36° = 684°.

An angle is an abstract concept in geometry which is formed by two lines or rays that meet at a common point. An angle is measured in degrees and can be classified by its size as acute, right, obtuse, or reflex. An angle can also be formed by three points or two intersecting planes.

6. The average birth weight is 12 ounces. The average adult weight is 12 x 1000 = 12000 ounces. Since there are 16 ounces in 1 pound, the average adult weight of the male black bear is 12000/16 = 750 pounds.

7. The measures of the angles in a triangle are in the extended ratio 2:15:19.To find the measure of each angle, we can set up an equation using the extended ratio. Let x be the measure of the first angle, then 15x and 19x will be the measures of the other two angles. This can be written as: 2x + 15x + 19x = 360°. Solving this equation, we get x = 36°. Therefore, the measure of the angles in the triangle are 36°, 15 x 36° = 540°, and 19 x 36° = 684°.

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Let x be the number of pounds needed for 6035 square feet.

We can set up a proportion between the pounds of grass seed and the square feet covered:

5 pounds / 355 square feet = x pounds / 6035 square feet

To solve for x, we can cross-multiply and simplify:

5 pounds * 6035 square feet = 355 square feet * x pounds

30175 = 355x

x = 30175 / 355

x ≈ 85.07

Therefore, approximately 85.07 pounds of grass seed are needed for 6035 square feet

To convert miles to feet, we need to multiply the number of miles by the number of feet in one mile. There are 5,280 feet in one mile. So, to find out how many feet Rachel ran, we can multiply 3 miles by 5,280 feet/mile:

3 miles x 5,280 feet/mile = 15,840 feet

Therefore, Rachel ran 15,840 feet. Answer: 15,840 feet.

Answer:

0.33

Step-by-step explanation:

There are a total of 5 + 15 + 10 + 15 = 45 people in the restaurant.

The probability of selecting a manager or a cook is the sum of the probabilities of selecting a manager and selecting a cook, since these events are mutually exclusive (a person cannot be both a manager and a cook at the same time).

The probability of selecting a manager is 5/45, since there are 5 managers out of 45 people in total.

The probability of selecting a cook is 10/45, since there are 10 cooks out of 45 people in total.

Therefore, the probability of selecting either a manager or a cook is:

P(manager or cook) = P(manager) + P(cook)

P(manager or cook) = 5/45 + 10/45

P(manager or cook) = 15/45

P(manager or cook) = 1/3

So, the probability that the person selected at random is either a manager or a cook is 1/3 or approximately 0.333

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The 3 correct answers of the figures that could be the base for the pyramid that has a height of 5 inches and a volume of 60 cubic inches are:

The formula to find the base of a pyramid given its height and volume,

Volume of pyramid = (1/3) * Base area * Height

Substituting in the given values, we have:

60 = (1/3) * Base area * 5

Base area = 36 square inches

In conclusion, any figure with a base area of 36 square inches could be the base for this pyramid.

The following figures have a base area of 36 square inches:

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Answer:

A. To find the acceleration, we need to take the derivative of the velocity function with respect to time:

a(t) = v'(t) = 2(pi) - cos(t(pi))

B. To find the minimum acceleration, we need to find the critical points of the acceleration function in the interval [0, 3].

a'(t) = sin(t(pi))

The critical points occur when sin(t(pi)) = 0, which means t = 0, 1, 2, 3. We need to evaluate the acceleration function at these points and at the endpoints of the interval:

a(0) = 2(pi) - cos(0) = 2(pi)

a(1) = 2(pi) - cos(pi) = pi + 2

a(2) = 2(pi) - cos(2pi) = 2(pi)

a(3) = 2(pi) - cos(3pi) = pi - 2

The minimum acceleration occurs at t = 3, with a minimum value of pi - 2.

C. To find the maximum velocity, we need to find the critical points of the velocity function in the interval [0, 2].

v'(t) = 2(pi) - cos(t(pi)) = 0

The critical points occur when cos(t(pi)) = 2(pi). We can solve for t as follows:

cos(t(pi)) = 2(pi)

t(pi) = arccos(2(pi))

t = arccos(2(pi))/pi ≈ 1.58

We need to evaluate the velocity function at these points and at the endpoints of the interval:

v(0) = -sin(0) = 0

v(1.58) ≈ 1.69

v(2) = (2(pi) - 5)(2) - sin(2(pi)) = 4(pi) - 10

The maximum velocity occurs at t = 1.58, with a maximum value of approximately 1.69.

Answer: 1/3, proper, 1 1/3, not proper.

Therefore , the solution of the given problem of angles comes out to be  the engraved angle ACB is 16 degrees in size.

Using Cartesian coordinates, the top and bottom walls divide the circular lines that make up a skew's ends. There is a chance that two poles will meet at a junction point. Angle is another outcome of two things interacting. They mirror dihedral forms the most. A two-dimensional curve can be created by arranging two line beams in various ways at their extremities.

Here,

A circle's inscribed angle has a measure that is half that of the interrupted arc. As a result, the inscribed angle ACB intersecting arc AB with a measure of 32 degrees will have a measure of:

=> Angle ACB = 32 / (1/2)

=> ACB = 16 degree angle

As a result, the engraved angle ACB is 16 degrees in size.

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y = 1 arctan(1/2(x-0)) - [tex]\frac{\pi }{3}[/tex], which simplifies to y = arctan(1/2(x-[tex]\frac{\pi }{3}[/tex])). So correct option is B.

An equation is a mathematical statement that uses symbols and mathematical operations to show that two quantities are equal. Equations are used to represent a wide range of relationships and can be used to solve problems and make predictions.

The original equation is y = arctan x. To horizontally compress the graph by 1/2, we need to replace x with 2x. The equation becomes y = arctan(2x).

To translate the graph down by [tex]\frac{\pi }{3}[/tex] units, we need to subtract [tex]\frac{\pi }{3}[/tex] from y. The equation becomes y = arctan(2x) - [tex]\frac{\pi }{3}[/tex].

So far, we have y = arctan(2x) - [tex]\frac{\pi }{3}[/tex]. To match the form y = a arctan(b(x-c)) + d, we need to further transform the equation.

We can write 2x as 1/2(4x), so the equation becomes y = arctan(1/2(4x)) - [tex]\frac{\pi }{3}[/tex].

Comparing this with y = a arctan(b(x-c)) + d, we have a = 1, b = 1/2, c = 0, and d = -[tex]\frac{\pi }{3}[/tex].

Substituting these values, we get y = 1 arctan(1/2(x-0)) - [tex]\frac{\pi }{3}[/tex], which simplifies to y = arctan(1/2(x-[tex]\frac{\pi }{3}[/tex])).

Therefore, the answer is B. y= arctan(1/2(x-[tex]\frac{\pi }{3}[/tex])).

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The complete question is:

The equation y = 1 arctan(1/2(x-0)) -π/3 can be written as y = arctan(1/2(x-π/3)).

What is equation ?

An equation is a mathematical statement that proves the equality of two quantities by using symbols and mathematical procedures. Equations can be used to express a wide variety of relationships, solve issues, and generate predictions.

The first formula is y = arctan x. We must swap out x for 2x in order to horizontally compress the graph by half. y = arctan is the new formula.(2x).

We must deduct π/3  from y in order to scale the graph downward by π/3 units. Y = arctan(2x) -π/3 is the new equation.

y = arctan(2x)-π/3  is what we now have. We need to further alter the equation so that it has the form y = an arctan(b(x-c)) + d.

Since 2x can be written as 1/2(4x), the equation changes to y = arctan(1/2(4x)) -π/3.

We have a = 1, b = 1/2, c = 0, and d = π/3- when y = an arctan(b(x-c)) + d is compared to this.

The result of substituting these numbers is y = 1 arctan(1/2(x-0)) -π/3, which may be written as y = arctan(1/2(x-π/3)).

y= arctan(1/2(x-π/3)), hence the solution is B.

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