Question explains itself in the picture.

Answer:

Ryan sprinted 46.33 yards.

Step-by-step explanation:

Ryan sprinted 139 feet.

1 feet = 0.33 Yard

Formula: Divide the length value by 3

Now,

139 ÷ 3 = 46.33

Thus, Ryan sprinted 46.33 yards.

-TheUnknownScientist

Answer:

x = 5

Step-by-step explanation:

Given that,

[tex]63:(5x-3x-1)=21:3\\\\or\\\\\dfrac{63}{(5x-3x-1)}=\dfrac{21}{3}\\\\\dfrac{63}{(2x-1)}=7[/tex]

Cross multiplying both sides,

[tex]63=7(2x-1)\\\\9=2x-1[/tex]

Taking like terms together,

[tex]10=2x\\\\x=5[/tex]

So, the value of x is equal to 5.

9514 1404 393

Answer:

  x : y : z = 63 : 72 : 80

Step-by-step explanation:

We can make the y-value the same by multiplying the first proportion by 9 and the second by 8.

  x : y = 63 : 72

  y : z = 72 : 80

Now, we can write ...

  x : y : z = 63 : 72 : 80

Answer:

7.5

Step-by-step explanation:

By intersecting secants theorem:

[tex]12(12 - x) = 6(6 + 3) \\ \\ 12(12 - x) = 54 \\ \\ 144 - 12x = 54 \\ \\ 144 - 54 = 12x \\ \\ 90 = 12x \\ \\ x = \frac{90}{12} \\ \\ x = 7.5[/tex]

Answer:

(H) is your answer i believe

Step-by-step explanation:

i subtracted 18 from each cost then divided it by 4 and got the numbers of game rented.

Answer:

[tex]r = 4m[/tex] --- small circle

[tex]R =8m[/tex] --- big circle

Step-by-step explanation:

Given

[tex]Area = 80\pi\ m^2[/tex] -- sum of areas

[tex]R = 2r[/tex]

Required

The radius of the larger circle

Area is calculated as;

[tex]Area = \pi r^2[/tex]

For the smaller circle, we have:

[tex]A_1 = \pi r^2[/tex]

For the big, we have

[tex]A_2 = \pi R^2[/tex]

The sum of both is:

[tex]Area = A_1 + A_2[/tex]

[tex]Area = \pi r^2 + \pi R^2[/tex]

Substitute: [tex]R = 2r[/tex]

[tex]Area = \pi r^2 + \pi (2r)^2[/tex]

[tex]Area = \pi r^2 + \pi *4r^2[/tex]

Substitute [tex]Area = 80\pi\ m^2[/tex]

[tex]80\pi = \pi r^2 + \pi *4r^2[/tex]

Factorize

[tex]80\pi = \pi[ r^2 + 4r^2][/tex]

[tex]80\pi = \pi[ 5r^2][/tex]

Divide both sides by [tex]\pi[/tex]

[tex]80 = 5r^2[/tex]

Divide both sides by 5

[tex]16 = r^2[/tex]

Take square roots of both sides

[tex]4 = r[/tex]

[tex]r = 4m[/tex]

The radius of the larger circle is:

[tex]R = 2r[/tex]

[tex]R =2 * 4[/tex]

[tex]R =8m[/tex]

Answer:

[tex]r \frac{\text{60 km}}{\text{1000 min}}[/tex]

Step-by-step explanation:

Suppose Kirsten's running rate is  r  meters per second.  This is to be converted to kilometers per minute.

Set up conversion fractions that will get you from

[tex]\frac{\text{m}}{\text{sec}} \rightarrow \frac{\text{km}}{\text{min}}[/tex]

You want to set up fractions so that the  m  on top is replaced with  km  and the  sec  on the bottom is replaced with  min.

[tex]\frac{\text{m}}{\text{sec}} \times \frac{\text{km}}{\text{m}} \times \frac{\text{sec}}{\text{min}}[/tex]

To see how the units work, cancel the m on top of the first fraction and the m on the bottom of the second fraction.  Do the same with the sec on the bottom of the first fraction and the top of the third fraction.  What units are left?  km per min!

To finish this, put the appropriate numbers into each fraction.

[tex]\frac{\text{m}}{\text{sec}} \times \frac{\text{1 km}}{\text{1000 m}} \times \frac{\text{60 sec}}{\text{1 min}} = \frac{\text{60 km}}{\text{1000 min}}[/tex]

This is what you multiply Kirsten's rate by, so she runs

[tex]r \frac{\text{60 km}}{\text{1000 min}}[/tex]

Answer:

The pvalue of the test is 0.3641 > 0.025, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 444 gram setting. Test if they are underfilled:

At the null hypothesis, we test if the mean is the correct mean of 444, that is:

[tex]H_0: \mu = 444[/tex]

At the alternate hypothesis, we test if it is underfilled, that is, the mean is less than 444.

[tex]H_a: \mu < 444[/tex]

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

444 is tested at the null hypothesis:

This means that [tex]\mu = 444[/tex]

A 9 bag sample had a mean of 441 grams with a standard deviation of 25.

This means that [tex]n = 9, X = 441, s = 25[/tex]

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{441 - 444}{\frac{25}{\sqrt{9}}}[/tex]

[tex]t = -0.36[/tex]

Pvalue of the test and decision:

The pvalue of the test is the probability of finding a mean of 441 or less, which is the pvalue of t = -0.36, with 9 - 1 = 8 degrees of freedom on a one-tailed test.

Using a calculator, the pvalue is 0.3641.

The pvalue of the test is 0.3641 > 0.025, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

Answer:

Is this the full question?

Answer:

-3

Step-by-step explanation:

Answer:

The function f(x) is graphed below.

Use the graph of the function to find, f(-6).

A. -3

B. -1

C. 1

D. 3

Step-by-step explanation:

The function f(x) is graphed below.

Use the graph of the function to find, f(-6).

A. -3

B. -1

C. 1

D. 3

answer -3

Answer:

9.72

Step-by-step explanation:

s1 = 10.6383 ; s2 = 5.21289

x1 = 147.583 ; x2 = 136.417

n1 = 12 ; n2 = 12

df1 = n1 - 1 = 12 - 1 = 11

df2 = n2 - 1 = 12 - 1 = 11

The test statistic :

(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]

Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)

Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926

Test statistic, T* :

(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))

11.166 / √(7.926 * (1/6)

11.166 / √1.321

11.166 / 1.1493476

T* = 9.7150766

Test statistic = 9.72

Answer:

I agree with gabby because if a bank is robbed you will get your money back from the bank.

if a piggy bank is stolen then you cant get the money inside it back.

Step-by-step explanation:

Answer:

Option (3)

Step-by-step explanation:

Properties of the equal matrices,

1). Every element of the one matrix are equal to the elements of other.

2). Both the matrices have same dimensions.

If,  [tex]\begin{bmatrix}x+3 & y+4\\ 7 & -5\end{bmatrix}=\begin{bmatrix}5 & 0\\ 7 & z\end{bmatrix}[/tex]

[tex]x+3=5[/tex]

[tex]x=2[/tex]

[tex]y+4=0[/tex]

[tex]y=-4[/tex]

[tex]x=-5[/tex]

Therefore, Option (3) will be the correct option.

Answer:

The simplest radical form of the cubic root is [tex]3x^2y^4\sqrt[3]{2x}[/tex]

Step-by-step explanation:

Cube root of 54x^8y^12

That is:

[tex]\sqrt[3]{54x^8y^12}[/tex]

Can be simplified as:

[tex]\sqrt[3]{54x^8y^12} = \sqrt[3]{54}\sqrt[3]{x^8}\sqrt[3]{y^12}[/tex]

We find each separate simplification, and multiply them:

Cubic root of 54:

[tex]54 = 2*3^3[/tex]

So

[tex]\sqrt[3]{54} = \sqrt[3]{2*3^3} = 3\sqrt[3]{2}[/tex]

Cubic root of x^8

[tex]\sqrt[3]{x^8} = \sqrt[3]{x^6*x^2} = x^2\sqrt[3]{x^2}[/tex]

Cubic root of y^12

[tex]\sqrt[3]{y^{12}} = y^4[/tex]

Multiplying all these terms:

[tex]\sqrt[3]{54}\sqrt[3]{x^8}\sqrt[3]{y^12} = 3\sqrt[3]{2}(x^2\sqrt[3]{x^2})(y^4) = 3x^2y^4\sqrt[3]{2x}[/tex]

The simplest radical form of the cubic root is [tex]3x^2y^4\sqrt[3]{2x}[/tex]

Answer:

w = 90 feet and l = 490 feet

Step-by-step explanation:

First, determine what you're given:

Perimeter = 1,160 feet

Perimeter = 1,160 feetlength = (w)idth + 400

idth + 400width = w

Next, solve for the length and the width using the perimeter equation (2l + 2w = Perimeter)

2(400+w) + 2w = 1,160 feet

(800 + 2w) + 2w = 1,160 feet

800 + 2w + 2w = 1,160 feet

800 + 4w = 1,160 feet

{ Subtract 800 from both sides }

4w = 360 feet

{ Divide both sides by 4 to isolate w }

w = 90 feet

Finally, you've solved for the width which is 90 feet. Plug this back into your equation for length;

[ l = 400 + w ]

l = 400 + (90)

l = 490 feet

Since it never hurts to check;

2l + 2w = 1,160 feet

2(400+w) + 2w = 1,160 feet

2(400+90) + 2w = 1,160 feet

✅2(490) + 2(90) = 1,160 feet

Answer: Hello Luv......

Factor the numerator and denominator and cancel the common factors.

−2x2+4x−8

Step-by-step explanation:

Hope this helps. Mark me brainest please.

Anna ♥

Answer:

[tex] = \frac{( - 4 {x}^{3} + 8 {x}^{2} - 16x) }{2x} \\ = \frac{ - 4 {x}^{3} }{2x} + \frac{8 {x}^{2} }{2x} - \frac{16x}{2x} \\ = - 2 {x}^{2} + 4x - 8[/tex]

Answer:

C) f(x) = 6.25x + 3

Step-by-step explanation:

In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be

f(x) = 6.25x + 3

We can input the # of candies for x and see that it provides the exact results every time as seen in the table.

f(x) = 6.25(1) + 3 = 9.25

f(x) = 6.25(2) + 3 = 15.50

f(x) = 6.25(3) + 3 = 21.75

f(x) = 6.25(4) + 3 = 28

Answer:

19,500 I'm pretty sure

Step-by-step explanation:

3,000 x 6.5 = 19,500

Answer:

719/721

Step-by-step explanation:

Subtract 2 from 721

Answer:

[tex]S(n-1)=2^{n-2}[/tex]

Step-by-step explanation:

Given that,

The value of [tex]S_n=2^{n-1}[/tex]

We need to find an expression for [tex]S(n-1)[/tex]. To find it, put the value of n as (n-1). So,

[tex]S_{n-1}=2^{n-1-1}\\\\=2^{n-2}[/tex]

Hence, the value of S(n-1) is equal to [tex]2^{n-2}[/tex].

Answer:

y = 16x^5

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

[tex]\hat p_1 = \dfrac{57}{200000}[/tex]

=  0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

[tex]\hat p_2 = \dfrac{142}{200000}[/tex]

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.  

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic  can be computed as:

[tex]Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}[/tex]

[tex]Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}[/tex]

[tex]Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}[/tex]

Z = - 6.03

P-value =  2P(Z < -6.03)

From the Z - tables

P-value =  2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

Answer:

( x+1 ) ( 6x - 1 )

Answer:

A. f(x)= 8(2)^x

Step-by-step explanation:

hope that helped

[tex] {a}^{3}. {b}^{2} [/tex]

:D

Explanation:

We have three copies of 'a' multiplied, so that's why the exponent for 'a' is 3.

Similarly, the b^2 means we have b*b or two copies of b multiplied together.