Question 9 (5 points)
Find the distance between a point (6,9) and a horizontal line at y= 5.
OA) 15
B) 4
OC) 11
D) 14

Answer:

[tex]Factor = 6w^4 v^3[/tex]

Step-by-step explanation:

Given

[tex]30x^8 w^4 v^3[/tex] and [tex]12w^7 v^5[/tex]

Required

Determine the common factor.

To do this, we simply factorize each. SO, we have:

[tex](1)\ 30x^8 w^4 v^3=: 2 * 3 * 5 * x^8 * w^4 * v^3[/tex]

[tex](2)\ 12w^7 v^5:=\ 2 * 2 * 3 * w^4*w^3 * v^3 * v^2[/tex]

Check for similar factors.

[tex]Factor = 2 *3 * w^4 * v^3[/tex]

[tex]Factor = 6w^4 v^3[/tex]

The above represents the similar factor

Answer:

A is 14 and P is 17

Step-by-step explanation:

working is above mentioned

Answer:

12345678910

Step-by-step explanation:

CHARRRRRRRRR joke lang bestie

Answer:

24

Step-by-step explanation:

Sara = x age

Amy = x+2        when Sara  x = 22    Amy is x + 2 = 24

Product of ages = 528 so............

    x(x+2) = 528

    x² + 2x - 528 = 0     solve for x         I did it graphically first to get x = -24, 22

    (x+24) (x-22)  = 0

   (x+24) = 0         (x-22) = 0

           x = -24             x = 22        since you really can't have a negative age

Answer:

D

Step-by-step explanation:

This is a pythagoream thereom question, the area of a square can be found by multiplying the sides. All the sides of a sqaure are the same so we are basically sqauring the side lengths. That is where the [tex]BE^{2}[/tex] and [tex]BH^{2}[/tex] come from. The problem tells us that the area of the two small squares are equal to the one bigger square. And the area of the bigger sqaure can be found by squaring that side EH. So [tex]BE^{2}[/tex]+[tex]BH^{2} =EH^{2}[/tex].

Answer:

3:00 p.m. in Houston.

Step-by-step explanation:

Answer:

137/1000

Step-by-step explanation:

Because we have 3 numbers after 0....

hope it helps

Answer:

A) £650 = $1053

B) $405 = £250

Step-by-step explanation:

For a) Since £1 is equal to $1.62 you would just do £650 times 1.62 to get $1053

For b) Since £1 is equal to $1.62 you would do $405 divided by 1.62 to get £250

Answer:

The answer to this inequality is 70<x<500

Answer:

t ≥ 570

Step-by-step explanation:

Answer:

4.8

Step-by-step explanation:

Answer:

120

Step-by-step explanation:

LCM of (2^3×3×5) and (3×5) is​

The LCM of the expression will be the product of all the factors that are in both expressions

(2^3×3×5) = 2 * 2 * 2 * 3 * 5

(3 * 5) = 3 * 5

since 3 * 5 is common to both factors, we will not have to repeat it twice to get our LCM again. Hence the LCM is expressed as;

LCM = 2 * 2 * 2 * 3 * 5

LCM  = 8 * 3 *5

LCM = 24 * 5

LCM = 120

Hence the required LCM is 120

Answer:

if you have the value of x then y =x +7

Answer:

1: mean equals 17.417, median is 12.75, mode is 8.2, range is 33, the minimum is 8.2 the maximum is 41.2. The IQR is 16.55, the quartiles is q1: 8.95, q2: 12.75, q3 is 25.5, there are no outliers.

2: the best middle is 12.75 because the median is usually the middle number but if you orgainze the numbers there will be two but you will end up getting 12.75 as your median. take the two middle number add together then divide by 2 then that is your answer.

Step-by-step explanation:

GOOD LUCK

Answer:

One solution

Step-by-step explanation:

The slopes are different which means, the systems has one solution.

hope this helps and is right p.s. i really need brainliest :)

Answer:

a) lilla has 1/5 of the book left to read

b) lilla has 15 pages left to read

Step-by-step explanation:

a) 1/5 + 3/5 = 4/5

b) 75÷ 5= 15

15× 4= 60

75-60= 15

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

[tex]H_a: \mu_1 - \mu_2 > 0[/tex]

In which [tex]\mu_1[/tex] is the mean pine trees height while [tex]\mu_2[/tex] is the mean spruce trees height.

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

[tex]X = 35 - 30 = 5[/tex]

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2[/tex]

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}[/tex]

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

[tex]s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495[/tex]

Test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{5 - 0}{2.4495}[/tex]

[tex]z = 2.04[/tex]

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Answer:

∠RQO and ∠STV

∠PQO and ∠UTV

Step-by-step explanation:

Answer:

Bussy

Step-by-step explanation:

Answer:

- The population in 2001 is 23.1 million

- It will reach 28.3 million in 2013

Step-by-step explanation:

Given

[tex]A =23.1e^{0.0152t}[/tex]

Solving (a): Population in 2000.

This implies that

[tex]t = 2000 - 2000[/tex]

[tex]t = 0[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]A =23.1e^{0.0152*0}[/tex]

[tex]A =23.1e^{0}[/tex]

Solve the exponent

[tex]A =23.1*1[/tex]

[tex]A =23.1[/tex]

The population in 2001 is 23.1 million

Solving (b): When will it reach 28.3 million

This implies that:

[tex]A =28.3[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]28.3 = 23.1e^{0.0152t}[/tex]

Divide both sides by 23.1

[tex]1.225 = e^{0.0152t}[/tex]

Take natural logarithm of both sides

[tex]ln\ 1.225 = ln(e^{0.0152t})[/tex]

Rewrite as:

[tex]ln\ 1.225 = 0.0152t\ ln(e)[/tex]

[tex]ln(e) = 1[/tex]

So:

[tex]ln\ 1.225 = 0.0152t*1[/tex]

[tex]ln\ 1.225 = 0.0152t[/tex]

Make t the subject

[tex]t = \frac{ln\ 1.225}{0.0152}[/tex]

[tex]t = \frac{0.2029}{0.0152}[/tex]

[tex]t \approx 13[/tex]

Add the value of t to 2013 to get the actual year

[tex]Year = 2000 +13[/tex]

[tex]Year = 2013[/tex]

It will reach 28.3 million in 2013

Answer:

Step-by-step explanation:

Answer:

1 : 6

Step-by-step explanation:

this my answer not sure you like it or not

Answer:

8: 0,-2  9: 7,-3  10: 7,1/2

Step-by-step explanation:

Hello, for question 8 (the top equation), you trying to find y and x so lets find y first. You need y to be by itself so you divide all the numbers by -3 like this:

6x/-3-3y/-3=6/-3

The equation simplifies to -2x+y=-2. You need y to be by itself so you move it to the other side and you get -2 for y. Now you need x. Go to the second equation and take the number that is y and plug it into the equation like this:

6x+8(-2)=-16

Multiply 8 with -2 which is -16. Then, you add -16 with -16 which makes 0.

6x=0

You then divide 6 on both sides and x is 0. You basically do the same process for questions 9 and 10 which are 7,-3 and 7,1/2. And your done!

Answer:

it is likely because the majority of the outcomes are in your favor

Answer:

A

Step-by-step explanation:

Impossible, did it on usatestprep

Answer:

a) attached below

b) Eigen values : λ1 = -1  and λ2 = - 1/2

  Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

c) since the Oscillator is > 0 hence  it is Overdamped

Step-by-step explanation:

Lets take  : m = 2 , k = 1 and b = 3

a) Second -order differential equation and the first order system

attached below

b) determine the eigenvalues and eigenvectors of the Linear system

Eigen values : λ1 = -1  and λ2 = - 1/2

Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

attached below is the detailed solution

c) The oscillator is classified as OVERDAMPED

To determine if the oscillator is damped, underdamped, or overdamped we will apply the relation below

 b^2 - 4km

 ( 3 )^2 - 4(1)(2)  = 1

since the Oscillator is > 0 hence it is Overdamped

d) Attached below is the phase portrait of the associated linear system

y(0) = 0

v(0) = 0

Answer:

3z

Step-by-step explanation:

When you write a number followed by a variable with no operation in between them, it means multiplication.

3 multiplied by z is 3 * z, but you can write it without the multiplication sign simply as 3z.