Answer:
b
Explanation:
reflection
Write about
a time you had to ride a bicycle on a difficult
surface. What did you have to do to adjust your
riding?
True or false. When a girl walks the action of pushing and the equal amd opposite reaction is being projected forward
This is true I think
It applies to Newton's Laws
it's true because it's a part of newtons law
A 10kg block is Pulled along a horizontal
Surface by a force
of 50N at an angles
of 37° with the horizontal If the
coefficient of sliding friction b/n the
block and the surface is o.2
(g=10m/s^2 Sin 37=O.6 and cos 37 = 0.8)
A, what frictional forces acting on the block?
B,what is the acceleration of the block?
Answer:
hope u can understand the method
Which is the best way to become familiar with your company's policies and procedures?
O
A. ask the person who hired you
O
B. look in the employee handbook
C. tell your supervisor you need help
D. visit the company's website
PLS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
A) pass the ball to a teammate
B) Smash the shuttlecock downward in your opponents court
C)Do a fake hit . . .
D) Do a fake hit . . .
(Best guess)
An 800 kg charging bull rams through a wooden fence. It was travelling at
5 m/s, now it's travelling at 3 m/s. How much impulse did the bull
experience by smashing the fence?
Answer:
J = 1600 kg-m/s
Explanation:
Given that,
The mass of charging bull rams, m = 800 kg
Initial speed, u = 5 m/s
Final speed, v = 3 m/s
We need to find the impulse the bull experience by smashing the fence. Let it is J. We know that, impulse is equal to the change in momentum such that,
J = m(v-u)
Put all the values,
J = 800(3-5)
= 800(-2)
= -1600 kg-m/s
Hence, the magnitude of impulse is equal to 1600 kg-m/s.
Man-made climate change is an example
of...
when two capacitor 3muF and 6muF are connected in a parallel and combination is charged to a potential of 120 volt the potential difference across the 3muF capacitor is
Answer:
V₁ = V = 120 V
Explanation:
Such a combination of capacitors in which;
1- Potential difference across each capacitor is the same
2- Total charge is distributed amongst the capacitors
; is called Parallel Combination.
Therefore, in this case, the potential difference across each capacitor will also be the same. Because the capacitors are connected in parallel here. So the voltage across 3 μF capacitor will be the same as the voltage across the 6 μF capacitor and they both will be equal to the total potential difference.
V₁ = V = 120 V
You are playing in a volley ball game Your team has 12 and the other team has 18.
How many points does your team needs to win?
How many points does the other team needs to win?
Answer:
you need 7 points and the other team just needs to stop you from scoring
Explanation:
A 25.0 kg mass is traveling to the right with a speed of 2.80 m/s on a smooth horizontal surface when it collides with and sticks to a second 25.0 kg mass that is initially at rest but is attached to one end of a light, horizontal spring with force constant 170.0 N/m. The other end of the spring is fixed to a wall to the right of the second mass.
1) Find the frequency of the subsequent oscillations.2) Find the amplitude of the subsequent oscillations.3) Find the period of the subsequent oscillations.4) How long does it take the system to return the first time to the position it had immediately after the collision?
Answer:
Explanation:
1 ) angular frequency ω = √ ( k / m )
=√ ( 170 / 50 )
= 1.844 rad /s
2πn = 1.844 where n is frequency of oscillation
n = 1.844 / (2 x 3.14 )
= .294 per sec
= .294 x 60 = 18 approx. per minute .
Velocity just after collision of composite mass ( using law of conservation of momentum )
= 25 x 2.8 / 50
v = 1.4 m/s
If new amplitude be A
1/2 k A² = 1/2 m v²
m = 25 + 25 = 50 kg
170 x A² = 50 x 1.4²
A = 0.76 m
3 ) period of oscillation = 1 /n
= 1 / .294
= 3.4 s
4 ) It will take complete one period of oscillation ie 3.4 s to come to its original position.
While traveling along a highway a driver slows from 34 m/s to 17 m/s in 6 seconds. What is the automobiles acceleration?
Answer:
-2.83 m/s²
Explanation:
Initial velocity (u) = 34 m/sFinal velocity (v) = 17 m/sTime taken (t) = 6 seconds❖ Acceleration is defined as the rate of change in velocity with time.
→ a = (v - u)/t
v denotes final velocitya denotes accelerationu denotes initial velocityt denotes time→ a = (17 - 34)/6 m/s²
→ a = -17/6 m/s²
→ Acceleration = -2.83 m/s²(Minus sign implies that the velocity is decreasing.)
Electroconvulsive therapy would be done under the
supervision of a counseling psychologist, where high level
of electric shock would be admistered.
Select one:
True
False
Answer:
the answer of this question is true
A man applies a force of 315 N to push the block of 225 kg onto 10 m ramp. Calculate the efficiency of the person if the mass gains a height of 1.2 m.
Answer:
η = 0.84 = 84%
Explanation:
The efficiency of the man can be given by the following formula:
η = output/input
where,
η = efficiency of man = ?
output = potential energy gain of the block = mgh
input = work done by man = Fd
Therefore,
[tex]\eta = \frac{mgh}{Fd}[/tex]
where,
m = mass of block = 225 kg
g = acceleration due to gravity = 9.81 m/s²
h = height gained by block = 1.2 m
F = force exerted by man = 315 N
d = distance covered by man = 10 m
Therefore,
[tex]\eta = \frac{(225\ kg)(9.81\ m/s^2)(1.2\ m)}{(315\ N)(10\ m)}[/tex]
η = 0.84 = 84%
If a Sam goes above and beyond what is expected in her job duties, what might Sam's supervisor note on Sam's next evaluation?
O A. Sam has good attendance.
O B. Sam shows initiative.
O C. Sam stays focused on assigned tasks.
OD. Sam works well with others.
Answer:
2
Exadadadwwwwwwwplanation:
Which of the following should be practiced among all co-workers in the workplace?
A. bullying
B. discrimination
C. stereotyping
D. tolerance

Please help if you can!
Answer:
C, Red has the longest one
c red
red has longest wavelength
amnh dot org
Light of intensity I0 passes through 4 ideal polarizing sheets. Unpolarized light enters the 1st sheet that has a horizontal transmission axis. Light continues to the 2nd sheet that has its transmission axis at 25 degrees with respect to the 1st sheet, then to the 3rd sheet that has its transmission axis at 47 degrees with respect to the 1st sheet then to the 4th sheet that has its transmission axis at 10 degrees with respect to the 3d sheet. The intensity of the emerging light as percentage of I0 is close to:
Answer:
34.24 %
Explanation:
Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.
The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.
Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°
Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.
So, I₄ = I₃cos²10°
I₄ = I₂cos²22°cos²10°
I₄ = I₁cos²25°cos²22°cos²10°
I₄ = (I₀/2)cos²25°cos²22°cos²10°
I₄/I₀ = cos²25°cos²22°cos²10°/2
I₄/I₀ = (cos25°cos22°cos10°)²/2
I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2
I₄/I₀ = 0.8275²/2
I₄/I₀ = 0.6848/2
I₄/I₀ = 0.3424
So, as a percentage,
I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %
What does it mean when work is positive?
Answer:
When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.
Explanation:
Hope this helps you
Which of the following is a category of mechanical wave?
O A. Transverse
B. Frictional
C. Parallel
D. Perpendicular
Answer:
a
because the mechanical wave is when it goes over and over again
Answer:
The answer is a like i said 3hrs ago i dont know if this guy copied me tbh
Explanation:
Which planet has the greatest gravity (of the choices shown)
Saturn
Venus
Uranus
Earth
Answer:
Earth
Explanation:
Answer:
Saturn/has best gravity out of the 4 planets.
The period of a sound wave coming from an instrument is 2 seconds. What 1 point
is the frequency of the sound? (f = 1/T) *
5 Hz
50 Hz
ОО
0.5 Hz
Answer:
b
Explanation:
g ou drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 kg and is 4.2 m in length. At the other end of the bar sits another 3.6-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. Assume that the bar is horizontal when the dropped ball hits it. How high (in meters) will the other ball go after the collision
Answer:
0.4112 m
Explanation:
The mass of the 1st ball = 3.6 kg
The height of the 1st ball =3.5 m
The mass of the 2nd ball = 3.6 kg
Mass of the bar M = 9.9 kg
Length of the bar L = 4.2 m
The velocity of the ball when it dropped from the height is calculated by using the formula:
[tex]\dfrac{1}{2}mv_1^2 = mgh_1 \\ \\ v = \sqrt{2gh_1} \\ \\ v =\sqrt{2\times9.8 \times 3.5} \\ \\ v = 8.283 \ m/s\\\\[/tex]
Provided that the bar is pivoted at the center and the ball is placed at the two ends, the moment of inertia for the bar is:
[tex]I = \dfrac{1}{12}ML^2 + m_1 (\dfrac{L}{2})^2 + m_2(\dfrac{L}{2})^2 \\ \\ =\dfrac{1}{12}(9.9kg)(4.2m)^2 + [3.6 kg+3.6kg](\dfrac{4.2}{2 \ m})^2 \\ \\ = 46.305 \ kg.m^2[/tex]
The angular momentum of the system due to the ball can be determined by using the formula:
L = mvr
L = (3.6 kg) (8.283 m/s) (2.1 m)
L = 62.61948 kg. m²
Now, Using the law of conservation:
[tex]L_i = L_f \\ \\ 62.61948 \ kg.m^2/s = I \omega \\ \\[/tex]
[tex]\omega = \dfrac{62.6198 \ kg.m^2/s}{46.305 \ kg.m^2}[/tex]
[tex]\omega =1.352 \ rad/s[/tex]
The linear angular velocity is deduced to be:
[tex]v = r \omega \\ \\ v = (2.1 \ m) ( 1.352 \ rad/s) = 2.839 \ m/s[/tex]
∴
the height raised by the second ball is:
[tex]h_2 = \dfrac{v^2}{2g} \\ \\ h_2 = \dfrac{(2.839)^2}{2(9.8 \ m/s^2)} \\ \\ h_2 =0.4112 \ m[/tex]
what is the definition of a moment of force?
Answer:
The Moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.
Answer:
Torque
Explanation:
I serached it up sjdjbdjd
The Equipartition Theorem follows from the fundamental postulate of statistical mechanics--that every energetically accessible quantum state of a system has equal probability of being populated, which in turn leads to the Boltzmann distribution for a system in thermal equilibrium.
a. True
b. False
Answer:
Hello! Your answer would be, A) True
Explanation:
Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥
The length of the slope of a mountain is 2780 m, and it makes
its base?
angle of 14.1° with the horizontal. What is the height of the mountain, relative to
Additional Materials
Reading
Answer:
677 m
Explanation:
Using the definition of the sine of an angle, we can write
sin 14.1 = (height of mountain) / (slope length of mountain)
sin 14.1 = H / (2780 m) ---> H = (2780 m) x sin 14.1
= 677 m
The height of the mountain is 677.21 m
The given parameters;
length of the slope, L = 2780 m
angle of inclination, Ф = 14.1°
let the height of the mountain, = h
A simple sketch of the problem is given below;
↓P
↓
↓ h
↓ 14.1°
↓------------------------------------------------Q
A straight line joining PQ is the hypotenuse of the right triangle.
The height of the right triangle is calculated as follows;
[tex]sin(14.1) = \frac{h}{PQ} \\\\\h = PQ \times sin(14.1)\\\\h = 2780 \times sin(14.1)\\\\h = 677.21 \ m[/tex]
Thus, the height of the mountain is 677.21 m
Learn more here: https://brainly.com/question/4326804
Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods are held 8.0 cm apart by insulating blocks mounted every 1.5 m. If each block can tolerate a maximum tension force of 200 N, what is the maximum allowable current
Answer:
the maximum allowable current is 7302.967 amperl
Explanation:
The computation of the maximum allowable current is shown below;
Force F = mean ÷ 4π 2 I_1 I_2 ÷d × ΔL
200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5
200 = 3.75 × 10^-6 I^2
I = √200 ÷ √ 3.75 × 10^-6
= 7302.967 amperl
Hence, the maximum allowable current is 7302.967 amperl
Basically we applied the above formula
g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 kg and is 4.2 m in length. At the other end of the bar sits another 3.6-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. Assume that the bar is horizontal when the dropped ball hits it. How high (in meters) will the other ball go after the collision
Answer:
h = 3.5 m
Explanation:
First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:
[tex]2gh = v_f^2 - v_i^2\\[/tex]
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 3.5 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,
[tex](2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s[/tex]
Now, we will apply the law of conservation of momentum:
[tex]m_1v_1 = m_2v_2[/tex]
where,
m₁ = mass of colliding ball = 3.6 kg
m₂ = mass of ball on the other end = 3.6 kg
v₁ = vf = final velocity of ball while collision = 8.3 m/s
v₂ = vi = initial velocity of other end ball = ?
Therefore,
[tex](3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s[/tex]
Now, we again use the third equation of motion for the upward motion of the ball:
[tex]2gh = v_f^2 - v_i^2\\[/tex]
where,
g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)
h = height = ?
vf = final speed = 0 m/s
vi = initial speed = 8.3 m/s
Therefore,
[tex](2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\[/tex]
h = 3.5 m
An astronaut is a distance L from her spaceship, and is at rest with respect to the ship, when she discovers that her tether has broken. She tosses a wrench with a speed Vw in the opposite direction of the ship to propel herself back to the ship. The astronaut has mass MA, and the wrench has mass Mw.
Required:
a. Draw a sketch, showing the subsequent motion of the astronaut and the wrench.
b. What is the initial momentum (before toss) of the astronaut plus wrench system? What is the final momentum?
c. Use conservation of momentum to solve for the speed of the astronaut VA, relative to the ship, in terms of MA, Mw and Vw.
d. How long does it take her to reach the ship in terms of L, MA, Mw and Vw?
e. How far has the wrench traveled from its original position when the astronaut reaches the ship? Express your answer in terms of L, MA and Mw.
Answer:
B) I₀ = I_f= 0, C) vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex] , D) t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]
Explanation:
A) in the attachment you can see a diagram of the movement of the key and the astronaut that is in the opposite direction to each other.
B) Momentum equals the change in momentum in the system
I = ∫ F dt = Δp
since the astronaut has not thrown the key, the force is zero, so the initial impulse is zero
I₀ = 0
The final impulse of the two is still zero, since it is a vector quantity, subtracting the impulse of the two gives zero, since it is an isolated system
I_f = 0
C) We define the system formed by the astronaut and the key, for which the forces during the separation are internal and the moment is conserved
initial instant.
p₀ = 0
final instant
p_f = [tex]m_a v_a - m_w v_w[/tex]
We used the subscript “a” for the astronaut and the subscript “w” for the key
the moment is preserved
po = p_f
0 = mₐ vₐ - m_w v_w
vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex]
D) as the astronaut goes at constant speed we can use the uniform motion relationships
vₐ = x / t
t = x / vₐ
t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]
An object of mass 45 kg is observed to accelerate at the rate of 6 m/s2. Calculate the force required to produce this acceleration
Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22.9 Newtons at an angle of 35 degrees above the horizontal to drag his backpack a horizontal distance of 129 meters to the right. Determine the work (in Joules) done upon the backpack.
Answer:
2420 J
Explanation:
From the question given above, the following data were obtained:
Force (F) = 22.9 N
Angle (θ) = 35°
Distance (d) = 129 m
Workdone (Wd) =?
The work done can be obtained by using the following formula:
Wd = Fd × Cos θ
Wd = 22.9 × 129 × Cos 35
Wd = 22.9 × 129 × 0.8192
Wd ≈ 2420 J
Thus, the workdone is 2420 J.