Answer:
D 21m/s
Explanation:
because when it leaves the pitcher hand it then possess kinetic energy
14. Name the 3 primary causes for the expected mass migration due to Climate
Change.
Answer: sea-level rise, extreme weather events, and drought, and water scarcity.
Explanation:
true or False? PLEASE HELP ME
Answer:
a. True - Joules is the unit measure for energy.
b. False - Potential energy is associated with position
c. False - Kinetic energy is associated with movement.
d. False - It's climbing, which means it also has kinetic energy.
A solid sphere a solid cylinder, and a hoop each have the same mass and radius. If they are spinning at the same angular velocity, which one has the greatest rotational kinetic energy
Answer:
KE = 1/2 I * w^2 where I = moment of inertia and w the angular velocity
The hoop has all of it mass at a distance of R from the axis of rotation,
I = M R^2 for the hoop, the others have values of I that are less that of the hoop.
What do the planets Saturn, Neptune, and Uranus have in common?
A. They are all smaller than Earth.
B. They are the closest to the Sun.
C. They are all outer planets.
D. They are all inner planets.
Answer:
they are all outer planets
A _____ is used to make magnifying glasses.
convex mirror
concave lens
plane mirror
convex lens
concave mirror
when a car climbs a hill, it only has potential energy
True or false
t
Explanation:
true , a car climbs a hill, it only has potential energy
Answer:
As the car begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the car at the top of the hill is getting converted into kinetic energy. Where "g" is the standard acceleration of gravity which equals 9.8 m/s2.
Explanation:
Part
A block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right). What can you say about the blocks motion?
Answer:
Explanation:
the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.
If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right), then the block would move towards the right side.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right),
The net force acting on the block = 4 Newtons - 3 newtons
= 1 Newton
Thus, we can say that the block would move to the right side.
To learn more about Newton's second law here, refer to the link given below;
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Which three gasses that contribute most to Climate Change?
ans) 1.Green House gasses 2. carbon dioxide 3.nitrious gases
Answer:
Water vapor.
Carbon dioxide.
Methane.
Ozone.
Nitrous oxide.
Chlorofluorocarbons.
Explanation:
thank me later
A good-quality measuring tape can be off by 0.58 cm over a distance of 22 m. What is its percent uncertainty
Answer:
22 m = 2200 cm
.58 / 2200 = .00026 = .026 %
Percent error = +_ .026
A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?
Answer:
18 m
Explanation:
Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s
solving for the final velocity, v
v = a * t
v = 4 m/s^2 * 3 s
v = 12 m / s
Solving for the average velocity. avg v
avg v = (vo + v) / 2
avg v = (0 m / s + 12 m/s) / 2
avg v = 6 m / s
Solving for the distance traveled after 3 s
d = avg v * t
d = 6 m / s * 3 s
d = 18 meters
In the first 3s the car travels 18 meters.
If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem, a car starting from rest has a constant acceleration of 4 meters per second per second,
By using the first equation of the motion,
v = u + at
v = 0 + 4 × 5
v = 20 m / s
Thus,If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
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What is the voltage drop across the 10.0 alpha resistor
Answer:
wow so cool the answer is vr 10
Calculate the mass of earth
earth assum
assuming
that it i a
6.67x106m.
Sphere with radius
Answer:
[tex]m=6.85\times 10^{24}\ kg[/tex]
Explanation:
The radius of Earth is [tex]6.67\times 10^6\ m[/tex]
The density of an object is given by :
[tex]d=\dfrac{m}{V}[/tex]
The density of Erth is, d = 5515 kg/m³
Where
m is the mass of the Earth
So,
[tex]m=d\times V\\\\m=\dfrac{4}{3}\pi r^3\times d[/tex]
Put all the values,
[tex]m=\dfrac{4}{3}\pi \times (6.67\times 10^6)^3\times 5515 \\\\m=6.85\times 10^{24}\ kg[/tex]
So, the mass of the Earth is equal to [tex]6.85\times 10^{24}\ kg[/tex].
What is the electric field at a point 0.450 m to the left of a -5.77*10^-9 C charge?
Include a + or - sign to indicate the direction the field.
The answer is -0.13
256.2 is the answer.
Here, we are asked to calulate the electric field.
Using the following formula:
E=k*lql/r^2
Yeah! Something that can easily bamboozle you.
So:
E=electric field
k=constant (8.99x10^9)
q=charge
ll= absolute value marks ( I still remember from my Algebra Course))
r=distance
Now, let's plug in the numbers.
E=8.99x10^9*l-5.77x10^-9l/(0.450)^2
And yes! That's a LOT!
But I solved the same problem on paper 2 minutes ago:)
If you perform the calculations, you will get 256.2
Well. THIS one was correct or Acellus.
So our answer is:
256.2 N/CNewtons per CoulombHope this helps:)
What do different forms of energy have in common?
A. They can push or pull on objects.
B. They give objects mass.
C. They can cause changes in matter.
D. They can cause objects to move.
Answer:
C because it changes your energy
A hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.2 m/s , a typical raindrop speed. How fast is the raindrop, with the attached mosquito, falling immediately afterward if the collision is perfectly inelastic
Answer:
The speed of the raindrop and the mosquito is 8.02 m/s.
Explanation:
mass of mosquito = m
mass of drop = 45 m
initial velocity of mosquito, u = 0 m/s
initial velocity of drop, u' = 8.2 m/s
During the inelastic collision, the momentum of the system is conserved.
Let the speed of rain drop and the mosquito is v.
Use the conservation of momentum
m x u + 45 m x u' = (m + 45 m) v
m x 0 + 45 m x 8.2 = 46 m x v
v = 8.02 m/s
At an amusement park, a 7.00 kg swimmer uses a water slide to enter the main pool. The swimmer starts at rest, slides without friction, and descends through a vertical height of 0.40 m. Find the total energy present when the swimmer is at the top of the slide.
Answer:
27.44 J
Explanation:
We can find the energy at the top of the slide by using the potential energy equation:
PE = mghAt the top of the slide, the swimmer has 0 kinetic energy and maximum potential energy.
The swimmer's mass is given as 7.00 kg.
The acceleration due to gravity is 9.8 m/s².
The (vertical) height of the water slide is 0.40 m.
Substitute these values into the potential energy equation:
PE = (7.00)(9.8)(0.40) PE = 27.44Since there is 0 kinetic energy at the top of the slide, the total energy present is the swimmer's potential energy.
Therefore, the answer is 27.44 J of energy when the swimmer is at the top of the slide.
g A circular swimming pool has a diameter of 10 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Joules) is required to pump all of the water over the side
Answer:
[tex]W=2.69*10^{6}J[/tex]
Explanation:
Generally the equation for momentum is mathematically given by
Diameter [tex]d=10m[/tex]
Radius [tex]r =\frac{d}{2}=>5m[/tex]
Height [tex]h=4m[/tex]
Depth [tex]d=3m[/tex]
Generally the equation for Area of the circle is mathematically given by
[tex]A=\pi r^2[/tex]
[tex]A=\pi 5^2[/tex]
[tex]A=78.5m^2[/tex]
Generally the equation for Work done is mathematically given by
[tex]d_w=d_f*x[/tex]
Where
[tex]d_f=(\rho*d_v)*g[/tex]
Therefore
[tex]d_w=((\rho*d_v)*g)*x[/tex]
[tex]d_w=((1000*78.5)*9.8)*x dx[/tex]
[tex]d_w=769300x dx[/tex]
[tex]W=\int dw[/tex]
[tex]\int dw=769300 \int^4_{3}x dx[/tex]
[tex]W=(769300\2)*7[/tex]
[tex]W=2.69*10^{6}J[/tex]
what is hydrofluorocarbon
Answer:
Hydrofluorocarbons (HFCs) are man-made organic compounds that contain fluorine and hydrogen atoms, and are the most common type of organofluorine compounds. Most are gases at room temperature and pressure.
Answer:
Hydrofluorocarbons (HFC) are man-made organic compounds that contain fluorine and hydrogen atoms and are the most common type of organofluorine compounds. Most are gases at room temperature and pressure. HFCs are produced synthetically and are used primarily as refrigerants. In general, they are relatively non-flammable, chemically stable, and nonreactive.
3. A small statue is recovered in an archaeological dig. Its weight is measured to be 96 lb, and its volume 0.08 ft3. a. What is the statue’s weight density?
Answer:
[tex]d=1200\ lb/ft^3[/tex]
Explanation:
Given that,
The weight of the statue, m = 96 lb
The volume of the statue = 0.08 ft³
We need to find the statue’s weight density. We know that the density of an object is the mass of an object divided by its volume. So,
[tex]d=\dfrac{m}{V}\\\\d=\dfrac{96\ lb}{0.08\ ft^3}\\\\d=1200\ lb/ft^3[/tex]
So, the density of the statue is equal to [tex]1200\ lb/ft^3[/tex].
A proton moves across a magnetic field and feels a force. If an electron were to
move at the same speed in the same direction across the same magnetic field, the
force
O 1) would be smaller in the opposite direction
O2) would be the same magnitude in the same direction
3) would be the same magnitude in the opposite direction
4) would be larger in the opposite direction
5) would be smaller in the same direction
potang ina mooooooo bubu hayop kaaaaapestrng yawa
Explanation:
peste kakkkkaaaaaaaa bubu pesteng yawaaaayaka kaayu kaaaaaaa
Atoms of elements in the same group have the same
Explanation:
The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.
what is the length of x of the side of the triangle below?
Match each date to the correct description.
1. autumnal equinox
June 21
2. vernal equinox
September 22
3. longest day in Northern Hemisphere
December 22
4. longest day in Southern Hemisphere
March 21
June 21: longest day in Northern Hemisphere
December 22: longest day in Southern Hemisphere
September 22: autumnal equinox
march 21: vernal equinox
Answer:
Autumnal Equinox: September 22nd
Vernal Equinox: March 21st
Longest day in the Northern Hemisphere: June 21st
Longest day in the Southern Hemisphere: December 22nd
Explanation:
I hope this helps! <3
What are possible units for impulse? Check all that apply.
▪️kg•m
▪️kg• m/s
▪️N•s
▪️N•m
▪️N•m/s
Answer:
kg.m/s
Explanation:
it is a division of a mass and a speed
If U= <4, -6> and V= <-3, 8> Find U+V
Answer:
[tex]\langle 1,\, 2\rangle[/tex].
Explanation:
Both [tex]U[/tex] and [tex]V[/tex] are two-dimensional vectors. In other words, each of them has two components. Each component is a number.
When adding two vectors, add each component separately. The sum should include the same number of components as the vectors that are being added.
Since [tex]U[/tex] and [tex]V[/tex] has two components each, their sum, [tex](U + V)[/tex], would also include two components.
Sum the first components of [tex]U[/tex] and [tex]V[/tex] to find the first component of [tex](U + V)[/tex]: [tex]4 + (-3) = 1[/tex].
Similarly, sum the second components of [tex]U[/tex] and [tex]V[/tex] to find the second component of [tex](U + V)[/tex]: [tex]-6 + 8 = 2[/tex].
Hence, [tex](U + V) = \langle 1,\, 2 \rangle[/tex].
what mass of water will release 60000 J of energy while cooling from 40.0 degrees celsius to 20.0 degrees celsius?
Answer:
714.286g
Explanation:
Q=mcT
60000=m×4.2×(40-20)
m=714.285....g
Research indicates that genetics does not influence levels of aggression.
Please select the best answer from the choices provided
True or
False
Answer:
False
Explanation:
Took the test and got a 100%
The statement " Research indicates that genetics does not influence levels of aggression." is False.
What is genetics?Genetics is the branch of biology that studies genes, heredity, and genetic variation in living organisms. It involves the study of how traits and characteristics are passed down from one generation to another through the genetic material, such as DNA, that is contained in the chromosomes of cells. Genetics plays a crucial role in understanding the development, growth, and functioning of organisms, as well as the causes and treatment of genetic diseases.
Here in the Question,
The statement that "genetics does not influence levels of aggression" is not entirely accurate. While there is no single gene that determines aggressive behavior, research has shown that genetics can play a role in influencing aggression.
Studies have found that certain genes are associated with increased risk for aggressive behavior, including those involved in the regulation of neurotransmitters such as serotonin and dopamine, which are known to affect mood and behavior. Additionally, environmental factors can interact with genetic factors to increase or decrease the expression of genes that influence aggression.
So, it is important to note that genetics is not the sole determinant of aggression. Environmental factors, such as childhood experiences, exposure to violence, and social and cultural influences, also play a significant role in shaping behavior.
Therefore, it is more accurate to say that aggression is a complex interplay between genetic and environmental factors.
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How does image differ from shadow?
Answer:
Image is formed by the reflection of light rays by an object. Image has the colour of the object. ... Shadow is formed by the obstruction of light by an opaque object. Shadow is always black.
Image is formed by the reflection of light rays by an object. Image has the colour of the object.
Shadow is formed by the obstruction of light by an opaque object. Shadow is always black.
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.5 km away
Answer:
0.8712 m/s²
Explanation:
We are given;
Velocity of first car; v1 = 33 m/s
Distance; d = 2.5 km = 2500 m
Acceleration of first car; a1 = 0 m/s² (constant acceleration)
Velocity of second car; v2 = 0 m/s (since the second car starts from rest)
From Newton's equation of motion, we know that;
d = ut + ½at²
Thus,for first car, we have;
d = v1•t + ½(a1)t²
Plugging in the relevant values, we have;
d = 33t + 0
d = 33t
For second car, we have;
d = v2•t + ½(a2)•t²
Plugging in the relevant values, we have;
d = 0 + ½(a2)t²
d = ½(a2)t²
Since they meet at the next exit, then;
33t = ½(a2)t²
simplifying to get;
33 = ½(a2)t
Now, we also know that;
t = distance/speed = d/v1 = 2500/33
Thus;
33 = ½ × (a2) × (2500/33)
Rearranging, we have;
a2 = (33 × 33 × 2)/2500
a2 = 0.8712 m/s²
You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that slopes upward at a 12 angle with the horizontal. As you face the window (0.90 m high, 2.0 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall
Questions Diagram is attached below
Answer:
[tex]T=2.08s[/tex]
Explanation:
From the question we are told that:
Speed of Train [tex]V=3.0m.s[/tex]
Angle [tex]\theta=12\textdegree[/tex]
Height of window [tex]h_w=0.90m[/tex]
Width of window [tex]w_w=2.0m[/tex]
The Horizontal distance between B and A from Trigonometric Laws is mathematically given by
[tex]b=\frac{0.9}{tan12}[/tex]
[tex]b=4.23[/tex]
Therefore
Distance from A-A
[tex]d_a=2.0+4.23[/tex]
[tex]d_a=6.23[/tex]
Therefore
Time Required to travel trough d is mathematically given as
[tex]T=\frac{d_a}{v}[/tex]
[tex]T=\frac{6.23}{3}[/tex]
[tex]T=2.08s[/tex]