Petroleum is a nonrenewable energy source. Therefore, the correct option is option B.
What is nonrenewable energy source?The sources of non-renewable energy will deplete or not be renewed within our lifetimes, or perhaps within many, many lifetimes. Coal, oil, and natural gas are the main fossil fuels used as non-renewable energy sources. The primary component of fossil fuels is carbon.
The formation of fossil fuels, which took place between 360 and 300 million years ago, is referred to as the Carboniferous Era for this reason. The formation of all fossil fuels was identical. Prior to the dinosaurs, Earth used to have a different terrain thousands of thousands of years ago. It was entirely covered in swampy forests and broad, shallow oceans. Petroleum is a nonrenewable energy source.
Therefore, the correct option is option B.
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How it affects your lives or the lives of people near the area where soil erosion happened?
Please Answer! thanks!
Answer:
negatively
Explanation:
when soil erosion happens,by the agent of water for example,the soil will eventually lose it's valuable minerals and become infertile, people won't be able to grow crops there.
Please help this is due tonight
Match each element to the correct description of its usual behavior in a
chemical reaction.
Answer:
Calcium (Ca) - will lose electrons
Sulfur (S) - will gain electrons
Carbon (C) could lose or gain electrons
Neon (Ne) Does not gain or lose electrons
Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant? (3 points)
SO2
O2
Fe2O3
FeS2
Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
g What is the relationship between the moles of the limiting reagent and the change in temperature (i.e. directly proportional or indirectly proportional)
Answer:
number of moles is inversely proportional to the Temperature
Explanation:
As we know
PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is the gas constant
and T is the temperature
If we see the equation, we can find that n is inversely proportional to the Temperature
decay mode for cesium-137
Answer:
Beta decay
Explanation:
Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.
Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.
The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.
Beta decay decreases the neutron - proton ratio.
. When is separation of substances necessary ?Name four methods used to separate solid substances ?
the one of 2 who send correct answer will get the brainliest and 40 points
Given 32.0 g of water, if we see a temperature change from 25.0°C to 20.0°C, then how much heat energy (q) is transferred from the water?
(The specific heat of water is 4.184 J/g°C )
Answer:
Q = 669.44 J
Explanation:
Given that,
Mass of water, m = 32 g
The temperature change from 25.0°C to 20.0°C.
We need to find the amount of heat energy transferred. Let it is Q. We know that,
[tex]Q=mc\Delta T[/tex]
Where
c is the specific heat of water
Put all the values,
[tex]Q=32\times 4.184 \times (20-25)\\Q=669.44\ J[/tex]
So, 669.44 J of heat energy is transferred from the water.
Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the negative of the measured value if the polarity is not the same as the standard cell.) Take [Cu2+] to be 1 M. Show your calculations. Ecell=0.4249v, Ecell=-0.00191. M E =E- 0.0592/2 • log ([Cu2+]/[Ag+1?) (10) cell
Answer:
7.16x10⁻⁸M = [Ag+]
Explanation:
Using the equation:
E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)
Where E⁰= 0.4249V
E(Cell) = -(-0.0019V) -Measured value-
[Cu2+] = 1M
Replacing:
0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)
-0.423V = - 0.0296 • log (1M/[Ag+]²)
14.29 = log (1M/[Ag+]²)
1.95x10¹⁴ = 1M / [Ag+]²
[Ag+]² = 5.12x10⁻¹⁵M
7.16x10⁻⁸M = [Ag+]
What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2? 1.4 × 10–4 M H3O+ and 7.1 × 10–11 M OH– 3.8 × 10–6 M H3O+ and 2.6 × 10–9 M OH– 8.3 × 10–9 M H3O+ and 1.2 × 10–6 M OH– 6.3 × 10–11 M H3O+ and 1.6 × 10–4 M OH–
Answering:
It is D
Explanation:
Just took the test
The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] are:
1. Concentration of hydronium ion [H₃O⁺] is 6.3×10¯¹¹ M 2. Concentration of Hydroxide ion [OH¯] is 1.6×10¯⁴ MThe pH of a solution is simply a measure of the acidic or alkalinity of the solution.
The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] can be obtained as illustrated below:
Step 1Data obtained from the question
pH = 10.2
Concentration of hydronium ion [H₃O⁺] =…? Concentration of Hydroxide ion [OH¯] =…? Step 2Determination of the concentration of hydronium ion [H₃O⁺]
pH = 10.2
Concentration of hydronium ion [H₃O⁺] =…?pH = –log[H₃O⁺]
10.2 = –log[H₃O⁺]
Multiply though by –1
–10.2 = log[H₃O⁺]
Take antilog of –10.2
[H₃O⁺] = antilog(–10.2)
[H₃O⁺] = 6.3×10¯¹¹ MStep 3:Determination of the pOH
pH = 10.2
pOH =?
pH + pOH = 14
10.2 + pOH = 14
Collect like terms
pOH = 14 – 10.2
pOH = 3.8Step 4Determination of the concentration of Hydroxide ion [OH¯].
pOH = 3.8
Concentration of Hydroxide ion [OH¯] =…?pOH = –log[OH¯]
3.8 = –log[OH¯]
Multiply through by –1
–3.8 = log[OH¯]
Take the antilog of –3.8
[OH¯] = antilog(–3.8)
[OH¯] = 1.6×10¯⁴ MSUMMARY:1. Concentration of hydronium ion [H₃O⁺] = 6.3×10¯¹¹ M
2. Concentration of Hydroxide ion [OH¯] = 1.6×10¯⁴ M
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hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((
Answer:
Boiling - The process of a liquid changing to gas.
Boiling point - The temperature at which a liquid boils.
Condensing - The process of a gas changing to a liquid.
Distillate - The liquid collect from the condenser.
Residue - The liquid left behind in the distillation flask.
Vapour - Another name for gas.
Hope it helps :)
A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.840 J/g°C and the temperature goes up by 9.25°C of soil. How many grams of soil are there?
Answer:
823.7g
Explanation:
Using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
Using the information given in this question as follows:
Q = 6,400 J
m = ?
c of soil = 0.840 J/g°C
∆T = 9.25°C
Using Q = mc∆T
m = Q ÷ c∆T
m = 6,400 ÷ (0.840 × 9.25)
m = 6400 ÷ 7.77
m = 823.7g
Answer:
There are 823.68 grams.
Explanation:
Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.
Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:
Q= C*m* (T2- T1) = C*m* ΔT
In this case:
Q= 6400 JC= 0.840 [tex]\frac{J}{g*C}[/tex]m= ?ΔT= 9.25 CReplacing:
6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C
Solving:
[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]
m=823.68 grams
There are 823.68 grams.
How many ML of 1.2 52 M KOH would be required to completely neutralize 9.55 ML of 0.114 HF
Answer:
0.871 mL
Explanation:
Step 1: Write the balanced neutralization reaction
KOH + HF ⇒ KF + H₂O
Step 2: Calculate the reacting moles of HF
9.55 mL of 0.114 M HF react.
9.55 × 10⁻³ L × 0.114 mol/L = 1.09 × 10⁻³ mol
Step 3: Calculate the moles of KOH needed to react with 1.09 × 10⁻³ moles of HF
The molar ratio of KOH to HF is 1:1. The moles of KOH needed are 1/1 × 1.09 × 10⁻³ mol = 1.09 × 10⁻³ mol.
Step 4: Calculate the volume of KOH solution that contains 1.09 × 10⁻³ moles of KOH
An unknown volume of 1.252 M KOH solution contains 1.09 × 10⁻³ moles of KOH.
1.09 × 10⁻³ mol × 1 L/1.252 mol = 8.71 × 10⁻⁴ L = 0.871 mL
What would the IUPAC name be?
Answer:
methyl ethanoate
Explanation:
To name the compound given above, the following must be obtained:
1. Determine the functional group of the compound.
In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.
2. Determine the longest chain before the functional group and the compound after the functional group.
In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.
3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.
This is illustrated below:
After the functional group => methyl
Before the functional group => ethane
Name of the compound => methyl ethanoate
The MO diagram of CN is similar to N2. Based on the molecular orbital energy-level diagram of CN, which of the following statements are correct?
i. The CN bond order is 2.
ii. CN is diamagnetic.
iii. The bond enthalpy in CN- ion is higher than CN.
iv. CN has longer bond length than CN-
answer choices:
a. ii, iv
b. iii, iv
c. i, iii
d. i, ii
e. i, iv
Answer:
Nitrogen molecule (N2)
The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.
N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2
Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.
The bond order of N2can be calculated as follows:
Here, Nb = 10 and Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
So your answer should be C3.
If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases from 20.5°C to 47.8 °C.
a. Is this an example of an endothermic or exothermic reaction?
b. What is the q for the reaction? (Remember since the NaOH dissolves in water add the masses to get the m)
c. How many moles of NaOH are dissolved?
d. What is the ΔH for the reaction?
Explanation:
Have a good luck with ur exam
The law of partial pressures was developed by ___________.
Answer:
John Dalton
Explanation:
Look at the table of dissociation constants for some acids.
Acid Ka Acetic acid 18 x 10-6 1.2 x 10-2 Chlorous acid Nitrous acid 4.0 x 10 -4 Propionic acid 1.3 x 10-5
Which of these is the strongest acid?
acetic acid
chlorous acid
nitrous acid
propionic acid
*Answer is B*
Answer:
chlorous acid
Explanation:
The acidic equilibrium of weak acids, HX, occurs as follows:
HX ⇄ H+ + X-
Where Ka is written as:
Ka = [H+] [X-] / [HX]
The strongest acid is the acid that produce more H+. The acid with the higher Ka is the acid that produce more [H+] and is, thus, the strongest acid.
The higher Ka is the Ka of chlorus acid = 1.2x10-2
Right answer is:
chlorous acidAnswer:
chlorous acid :)
Explanation:
In the ground state, the valence electrons of a krypton atom are found in
1. The first shell
2. The outermost shell
3. Both the nucleus and the first shell
4. Both the first shell and the outermost shell
Answer: 2. The outermost shell
Explanation:
In an elements ground state, its electrons have the least amount of energy that they could have so they stay in their shells. When Krypton is in this state therefore, its valence electrons will stay in the outermost shell.
As Krypton has a total of 36 electrons in this state, there will be 8 valence electrons and they will all be in the outer shell.
Student Exploration: Limiting Reactants Vocabulary: chemical equation, chemical formula, chemical reaction, coefficient, limiting reactant, molecule, product, reactant, subscript Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Imagine you and your friends are making hot dogs. A complete hot dog consists of a wiener and a bun. At the store, you buy four packages of eight wieners and three bags of 10 buns. 1. How many total hot dogs can you make
Answer:
30 hot dogs
Explanation:
It is given that :
There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners
There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns
One hot dogs need 1 bun and 1 wiener to make a hot dog.
There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.
Therefore, 30 hot dogs.
And the number of extra wieners left = 32 - 30 = 2 wieners.
What is the total mass of products formed when 64.18 grams of CH4 is burned with excess oxygen?
using a map give the coordinates of the capital of the neighboring countries of the philippines e.g tokyo japan
Answer:
The correct answer is -
1. Malaysia - Kuala Lumpur 3.1390° N, 101.6869° E
2. Indonesia - Jakarta - 6.2088° S, 106.8456° E
3. Vietnam - Hanoi - 21.0278° N, 105.8342° E
4. Taiwan - Taipei -25.0330° N, 121.5654° E
5. China - Beijing - 39.9042° N, 116.4074° E
6. Palau - Ngerulmud - 7.5004° N, 134.6243° E
7. Japan - Tokyo - 35.6762° N, 139.6503° E
Explanation:
The Philippines does not share its land borders with any country, however, the Philippines claims that they share their boundary with Malaysia. Other than land borders they also share maritime borders with Palau, Taiwan, Vietnam, China, Indonesia, and Japan.
All these neighboring countries have capitals that are as follows with their coordinates on the atlas-
1. Malaysia - Kuala Lumpur 3.1390° N, 101.6869° E
2. Indonesia - Jakarta - 6.2088° S, 106.8456° E
3. Vietnam - Hanoi - 21.0278° N, 105.8342° E
4. Taiwan - Taipei -25.0330° N, 121.5654° E
5. China - Beijing - 39.9042° N, 116.4074° E
6. Palau - Ngerulmud - 7.5004° N, 134.6243° E
7. Japan - Tokyo - 35.6762° N, 139.6503° E
Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.
Answer:
See Explanation
Explanation:
In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.
The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.
The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.
How many sides does a dodecahedron have?
Answer:
the correct answer is 12 sides (:
Explanation:
Hydration of alkynes gives good yields of single compounds only with symmetrical or terminal alkynes. Draw the major organic product(s) formed when 3-methylcyclodecyne undergoes hydration in the presence of HgSO4 and H2SO4.
Answer:
Following are the solution to the given choice:
Explanation:
Hex-2-yne is just not alkyne symmetric, therefore two things respectively hexan-3-one and hexan-2-one are to be given.
The attached file it displayed the response along with the mechanism, please find the.
If the temperature decreases, then the pressure will
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s
To Find :
The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s.
Solution :
The horizontal range of a projectile is given by :
[tex]R = \dfrac{u^2 sin 2\theta}{g}[/tex] ( Here, g is acceleration due to gravity = 10 m/s² )
Putting all value in above equation :
[tex]R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m[/tex]
Therefore, the horizontal range of projectile is 80 m.
How many molecules are in 1.75 moles of Caco3?
1.75 molecules
3.440 x 1023 molecules
1.054 x 1024 molecules
O 2.907 x 10-24 molecules
Answer:
1.054 x 10²⁴ molecules
Explanation:
In order to convert moles of any given substance into a number of molecules, we need to use Avogadro's number, which states the number of molecules -or atoms, in the case of elements- present in one mol:
In one mol there are 6.023x10²³ molecules.We now convert 1.75 moles into molecules:
1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ moleculesGiven the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4
a. Write the equilibrium constant expression for the reaction.
b. Write the equation that would allow you solve for the concentration of NO.
c. What is the concentration of NO if [NZ] = 0.166M and [02] = 0.145M?
Answer:
(a): The expression of equilibrium constant is [tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b): The equation to solve the concentration of NO is [tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex]
(c): The concentration of NO is 0.0017 M.
Explanation:
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term [tex]K_{eq}[/tex]
(a):
The given chemical equation follows:
[tex]N_2+O_2\rightarrow 2NO[/tex]
The expression for equilbrium constant will be:
[tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b):
The equation to solve the concentration of NO follows:
[tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex] ......(1)
(c):
Given values:
[tex]K_{eq}=1.2\times 10^{-4}[/tex]
[tex][N_2]_{eq}=0.166M[/tex]
[tex][O_2]_{eq}=0.145M[/tex]
Plugging values in equation 1, we get:
[tex][NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}[/tex]
[tex][NO]=\sqrt{2.88\times 10^{-6}}[/tex]
[tex][NO]=0.0017 M[/tex]
Hence, the concentration of NO is 0.0017 M.