Answer:
Login
Check for availability
Select flight from available options
Book a ticket
Select seat
make a payment
Check flight status
Update flight schedule
Explanation:
The ticket reservation system allows a passenger to easily book a ticket at a convenient time and he does not have to rush to travel agents. This feature enables the passengers to book a flight themselves. There are few pre requisites that a passenger needs to go through. He first have to login the credentials and then choose the flight options and availability by entering the desired destination at a desired date. He then selects a flight, books a ticket and makes a payment for the chosen ticket.
A duct for an air conditioning system has a rectangular cross section of 2ft by 9in. The duct is fabricated from galvanized iron (e 0.006in). Calculate the pressure drop in psi for a horizontal 50-ft section of pipe with a flow rate of air of 5000cfm at 100F and atmospheric pressure
Answer:
The answer is '[tex]2.9584 \ \frac{lbf}{ft^2}[/tex]'
Explanation:
Given:
[tex]\mu=3.96 \times 10^{-7} \ \frac{lbfs}{ ft^2}\\\\\gamma=0.0709 \ \frac{lfb}{ft^3}\\\\v= 1.8 \times 10^{-4} \ \frac{ft^2}{s}[/tex]
energy balance equation:
[tex]\ P_1 - P_2 = \rho gh_{L}[/tex]
[tex]V= \frac{\ Q}{ A}\\\\V= \frac{\frac{5000}{60}}{2 \times \frac{9}{12}}\\\\V= 55.55 \frac{ft}{s}[/tex]
calculating [tex]D_h[/tex]:
[tex]D_h= \frac{4 \times \ scetor \ area }{ wetted \ permetor}\\\\D_h=\frac{4 \times 2 \times \frac{9}{12}}{2(2+\frac{9}{12})}\\\\D_h= 1.0909 ft\\\\[/tex]
calculating [tex]R_e[/tex]:
[tex]R_e=\frac{VD_h}{V}\\\\R_e=\frac{55.55 \times 1.0909}{1.8 \times 10^{-4}}\\\\R_e=3.366 \times 10^5\\\\[/tex]
calculating relative vovghness:
[tex]\frac{k_s}{D_h}= \frac{\frac{0.006}{12}}{1.0909}\\\\[/tex]
= 0.0006875
If [tex]R_e= 3.366 \times 10^5 \ and \ \ \frac{K_s}{D_h} = 0.0006875 \ \ \ so, \ \ f= 0.019[/tex]
Calculating [tex]H_f[/tex]:
[tex]H_f= \frac{f \ l\ v^2}{ 2 \ g \ D_h}\\\\[/tex]
[tex]=\frac{0.019 \times 50 \times 55.55^2}{2\times 32.2\times 1.0909}\\\\= 41.727 \ ft[/tex]
Calculating pressure drop:
[tex]P_1-P_2= \gamma h_{L}\\\\[/tex]
[tex]= 0.0709 \times 41.727\\\\= 2.9584 \ \frac{lbf}{ft^2}[/tex]
Which material is used in a photovoltaic cell? A photovoltaic cell converts solar radiation into electric current using a thin sheet of____ like silicon.
Answer:
first on is silicon
Explanation:
Answer:
Silicon
Explanation:
Copper indium dieseline (CIS), cadmium telluride (CdTe), and thin-film silicon are certain polycrystalline thin film materials often used, whereas high-efficiency material such as gallium arsenide (GaAs) often comprise single-crystalline thin film materials3.
A piston-cylinder device contains 0.1 kg of hydrogen gas (PG model: cv=10.18, k = 1.4, R= 4.12 kJ/kg-K) at 1000 kPa and 300 K. The gas undergoes an expansion process and the final conditions are 500 kPa, 270 K. If 10 kJ of heat is transferred into the gas from the surroundings at 300 K, determine (a) the boundary work (Wb), and (b) the entropy generated (Sgen) during the process
Answer:
(a) 151.84 kJ
(b) 2.922 kJ/K
Explanation:
(a) The parameters given are;
Mass of hydrogen gas, H₂ = 0.1 kg = 100 g
Molar mass of H₂ = 2.016 g/mol
Number of moles of H₂ = 100/2.016 = 49.6 moles
V₁ = mRT/P = 0.1×4.12×300/1000 = 0.1236 m³
P₁/P₂ = (V₂/V₁)^k
V₂ = (P₁/P₂)^(1/k)×V₁ =0.1236 × (1000/500)^(1/1.4) = 0.3262 m³
Boundary work done = (V₂ - V₁)(P₂ + P₁)/2 = (0.3262 - 0.1236)*(500 + 1000)/2 = 151.84 kJ
(b) Entropy generated ΔS = Cv · ㏑(T₂/T₁) + R ·㏑(v₂/v₁)
=10.18 × ㏑(270/300) + 4.12 ·㏑(0.3262/0.1236) = 2.922 kJ/K.
Determine size of a standard square key made of 1045 hot rolled steel for a 2 inch DIA shaft transmitting 100 HP at 500 rpm with factor of safety 2.5 for yield in direct shear. W____inch L_____inch
Answer:
Width = Length = 1.148 inches
Explanation:
We have been given the following data:
D = diameter = 2 inch = 0.0508m
P = Power = 100 HP = 74570 W
N = 500 rpm
Safety Factor = 2.5
Step 1:
We need to find yield strength which is represented by σ(y).
σ(y) for 1045 hot rolled steel = 330MPa
Step 2:Find Shear Strength. Formula is given:
τ(y) = σ(y) / 2
τ(y) = 330 / 2
τ(y) = 165 MPa
τ(y) = 165 × 10⁶ Pa
τ(y) = 165 × 10⁶ kg.m⁻¹.s⁻²
Step 3:
Find Torque. Formula is given:
T = 60P / 2πN
T= (60)(74570) / 2π(500)
T = 1424.9 Nm
Step 4:Find Shear Force. Formula is given:
F = 2T/d
F = 2(1424.9)/0.0508
F = 56098.43 N
F = 56098.43 kg.m.s⁻²
Step 5:Find length by the given formula:
F/L² = τ(y)/Safety factor
Rearrange for L:
L = √(F· Safety factor / τ(y))
Substitute the values found in previous steps to calculate L.
L = 0.02915 meters
Convert it into inches:
L = 1.148 in
As it si a square key:
L = W
Width = 1.148 in
The new Boeing 777 aircraft was designed and engineered by a group of Boeing employees from manufacturing, marketing, and engineering departments and by representatives of Boeing’s customers (major airlines such as United and American Airlines), all working closely together in an intensive effort. This design and engineering group for the 777 can be classified as_________.
Answer:
A cross-functional team
Explanation:
A cross-functional team are a customer centric collection of professionals with diverse area of expertise that come together to attain a common purpose by collaboration which aids in the maximization of effort, investment, and time in achieving customer satisfaction and the goals of the organization
The team can comprise members from different departments within the organization such as marketing, finance, safety and quality, human resources as well as operations.
A widebody aircraft
The Boeing 777 is accounted as a wide body aircraft because it has 2 isles and other aircraft have one like the Boeing 737 is not considered as widebody because it has only one isle and like the Airbus A330-900 is a competitor to the Boeing 777 and has 2 isles in the aircraft so it is considered a wide body aircraft.