Q. What is the area of the parallelogram above?
13cm squared
28.5cm squared
45.6cm squared
40cm squared ​

Q. What Is The Area Of The Parallelogram Above?13cm Squared28.5cm Squared45.6cm Squared40cm Squared

Answers

Answer 1

9514 1404 393

Answer:

  40 cm²

Step-by-step explanation:

The area is given by the formula ...

  A = bh

  A = (8 cm)(5 cm) = 40 cm²

__

The length of the slanted side is irrelevant. The height is measured perpendicular to the base.


Related Questions

I NEED HELP NOW PLEASE

Answers

Answer: B : Stretches vertically by factor 3

Step-by-step explanation: Can you mark this brainliest if this is right?

look at pic 10 pts will mark brainilest
C: ( 9 x 18) + (6 x 2)
D: (20 x 6) + (18 x 3)
E: (20 x 9) - (3 x 2)

Answers

E because area is lxw

which one of the following piecwise graphs is not a function

Answers

Answer:

Perhaps this could be answered, if the graphs were included.

Step-by-step explanation:

pls answer quick, I need an answer.
Steve bought a triangular mat to cover a corner of his room.

Answers

24 square feet

Triangle = 1/2 base x height
= 1/2 x 8 x 6
= 24

Find the mode of the data. 65, 65, 60, 62, 60, 69, 60, 68, 63, 66 mode =​

Answers

Answer:

60

Step-by-step explanation:

The mode is the value which occurs the most in the set. We see that 60 occurs three times, 62 occurs once, 63 occurs once, 65 occurs twice, 66 occurs once, 68 occurs once, and 69 occurs once.

Thus, the mode is 60.

Answer:

The mode is 60

Step-by-step explanation:

The mode is the number that appears most in the set of data. 60 appears the most, appearing 3 times.

If the spinner to the right is spun once, what is the probability

that it lands on a star or a shaded region?

Answers

Answer: i think its star because it sounds right and well i tryed it before and you should to.

It is estimated that 52% of drivers text while driving.
A. What is the probability that exactly 3 drivers text while driving if a police officer pulls over five drivers?
B. What is the probability the next driver texting while driving that the police officer pulls over is the fifth driver?

Answers

Answer:

a) 0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers

b) 0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Step-by-step explanation:

For each driver pulled, there are only two possible outcomes. Either they are texting, or they are not. The probability of a driver being texting is independent of any other drivers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

It is estimated that 52% of drivers text while driving.

This means that [tex]p = 0.52[/tex]

A. What is the probability that exactly 3 drivers text while driving if a police officer pulls over five drivers?

This is [tex]P(X = 3)[/tex] when [tex]n = 5[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{5,3}.(0.52)^{3}.(0.48)^{2} = 0.324[/tex]

0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers.

B. What is the probability the next driver texting while driving that the police officer pulls over is the fifth driver?

None of the first four([tex]P(X = 0)[/tex] when [tex]n = 4[/tex]), and then the fifth, with 52% probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.52)^{0}.(0.48)^{4} = 0.0531[/tex]

0.0531*0.52 = 0.0276

0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Lines a and bare perpendicular. If the slope of line a is - 2/3 is the slope of line b?

Answers

Answer:

B.   3/2

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals

The negative reciprocals of -2/3

is 3/2

The Goodman Tire and Rubber Company periodically tests its tires for tread wear under simulated road conditions. To study and control the manufacturing process, 20 samples, each containing three radial tires, were chosen from different shifts over several days of operation, with the following results. Tread wear measurements are in hundredths of an inch. Sample Tread Wear 1 31 42 28 2 26 18 35 3 25 30 34 4 17 25 21 5 38 29 35 6 41 42 36 7 21 17 29 8 32 26 28 9 41 34 33 10 29 17 30 11 26 31 40 12 23 19 25 13 17 24 32 14 43 35 17 15 18 25 29 16 30 42 31 17 28 36 32 18 40 29 31 19 18 29 28 20 22 34 26 Assuming that these data were collected when the manufacturing process was believed to be operating in control, develop the R chart. Compute the upper and lower control limits for the R chart. (Round your answers to two decimal places.) UCL = LCL =

Answers

Answer:

LCL = 4.72

UCL = 18.08

Step-by-step explanation:

Sample size, n = 20

Sample _ tread wear, x __ Range

1 ______ 33.67 ___ 14

2______ 26.33 ___ 17

3 _____ 29.67 ____ 9

4 ______ 21 ______ 8

5 ______ 34 ______ 9

6 ______ 39.67 ___ 6

7 ______ 22.33 ___ 12

8 ______ 28.67 ___ 6

9 ______ 36 ______8

10 _____ 25.33 ___ 13

11 _____ 32.33 ____14

12 _____ 22.33 ___ 6

13 _____ 24.33 ___ 15

14 _____ 31.67 ___ 26

15 _____ 24 _____ 11

16 ____ 34.33 ____ 12

17 ____ 32 _______ 8

18 ____ 33.33 ____ 11

19 ____ 25 _______11

20 ___ 27.33 _____12

Sample mean, xbar = Σx / n = 29.167

Rbar = ΣR/ n = 11.4

The R chart control limit is given by :

Rbar(1 - 3(d3/d2))

From the R chart :

d3 = 0.729 ; d2 = 3.735

Hence,

LCL = 11.4(1 - 3(0.729/3.735))

LCL = 11.4(0.4144578) =

LCL = 4.72481892 = 4.72

UCL = 11.4(1 - 3(0.729/3.735))

UCL = 11.4(1.5855421)

UCL = 18.075180 = 18.08

Applicants for the University of Statland take two tests, one for writing ability and the other on critical thinking, and normalised scores are recorded on each between 0 and 1. For a given applicant, let XX be the score on the writing test and YY the score on the critical thinking test. A model for the joint probability density function for the two test scores can be taken as:

Answers

Answer:

hello your question is incomplete attached below is the complete question

answer :   1

Step-by-step explanation:

Given Function:

F(x,y)=[tex]\left \{ {{1/4(2x+y)} \atop {0}} \right.[/tex]      for    0<x<1, 0<y<2

                                            elsewhere.

Evaluating the marginal density of the writing test score at point

X = 1/2  = 1/4 ( 4x + 2 ) = 1/4 ( 4 * 1/2 + 2 ) = 1

attached below is the detailed solution

(25points) Which of the following is the ratio of the area of the shaded region to the total area of the square
a)1/2
b)1/3
c)3/8
d)3/4

Answers

Answer:

C

Step-by-step explanation:

We want to find ratio of the area of the shaded region to the total area of the square.

First, we can find the total area of the square. Since QR = 7, each side of the square measures 7. Therefore, its area is:

[tex]A=(7)^2=49\text{ units}^2[/tex]

Instead of finding the shaded area, we can find the areas that are not shaded. Subtracting that into the total area will then give us the shaded area.

QRP is a triangle. Since PQRS is a square, QR = 7 = RS = SP = PQ.

So, the area of ΔQRP is:

[tex]\displaystyle A_{\Delta QRP}=\frac{1}{2}(7)(7)=24.5[/tex]

UTS is also a triangle. We are given that RU = US and PT = TS. So, Points U and T bisect RS and SP, respectively. Since RS = SP = 7, RU = US = PT = TS = 3.5. So, the area of ΔUTS is:

[tex]\displaystyle A_{\Delta UTS}=\frac{1}{2}(3.5)(3.5)=6.125[/tex]

Therefore, the total area of the white region is:

[tex]A_{\text{white}}=6.125+24.5=30.625[/tex]

Thus, the shaded region is:

[tex]A_{\text{shaded}}=49-30.625=18.375[/tex]

Then the ratio of the shaded region to the total area of the square will be:

[tex]\displaystyle R_{\text{shaded:total}}=\frac{18.375}{49}=\frac{3}{8}[/tex]

Our answer is C.

Divide by using long division:
(8x ^2+ 4x – 3) = (2x - 3)

Answers

Answer: Hello Luv......

The chosen topic is not meant for use with this type of problem. Try the examples below.

45665

8723

209÷32

Step-by-step explanation:

Hope this helps.

Mark me brainest please.

Anna ♥

¿Qué es el Círculo Unitario​

Answers

Answer:

In mathematics, a unit circle is a circle of unit radius—that is, a radius of 1. Frequently, especially in trigonometry, the unit circle is the circle of radius 1 centered at the origin in the Cartesian coordinate system in the Euclidean plane.

Step-by-step explanation:

Answer:

El círculo unitario se divide en 4 partes, denominadas cuadrantes. El primer cuadrante (I) está formado por los ejes xey positivos. El primer cuadrante (I) está formado por los ejes xey positivos. Si dibujamos cualquier radio del círculo unitario en el primer cuadrante, el ángulo con el eje x positivo puede tener cualquier valor entre 0 y 90 °.

(Can Someone Help Answer This Problem) + No Links

Answers

Answer:

50 + 100n  

Step-by-step explanation:

The cost is the cost of the visit plus the cost of the cavities

50 + 100n  where n is the number of cavities

Answer:

P = 50 + 100*n

Step-by-step explanation:

1. The visit is $50

2. Additional cavity is $100

3. n cavities would cost 100*n

What is the equation for this word problem?:
Ravi needs to read 3 novels each month.
Let N be the number of novels Ravi reads in M months
Help!

Answers

Answer:

N = 3M

Step-by-step explanation:

how to find the length of EF?

Answers

[tex]CD = \frac{HG + EF}{2} \Leftrightarrow EF = 2CD - HG[/tex]

[tex]2x - 2 = 2x - x + 3\\2x - 2x + x = 3 + 2\\x = 5[/tex]

[tex]EF = 2 * 5 - 2 = 10 - 2 = 8[/tex]

Answer: 8.

Answer:

EF=8

Step-by-step explanation:

HG=x-3

CD=x

EF=2x-2

Since HG is 3 less than CD, EF has to be 3 more than CD

x+3=2x-2

3+2=2x-x

5=x

x=5

HG=2

CD=5

EF=8

pls help PLS PLS PLS PLS
20 POINTS

Answers

Answer:

Step-by-step explanation:

X squared over 6

+

2x cubed over 3

Answer:

x^2/6 + 2x^3/3

Step-by-step explanation:

I used (m)athway to simplify the expression

increase 53.20 by 7%

Answers

Answer:

56.924

Step-by-step explanation:

Step-by-step explanation:

Change the problem into something you recognize

7% = 7 x 10^-2 = 0.07

Multiply by this decimal

53.20 x 0.07 = a

Then add this to the original

53.20 + a

rolling an odd number on a six-sided die with its expected probability?

Answers

Answer:

The probability when rolling a regular six-sided dice that the score is an odd number is three-sixths or three out of six. Both three and six are divisible by three. Therefore, this fraction could be simplified to one-half. Three divided by three is equal to one.

1/3 is the answer hope this helps

5 liters of water weighs 11 pounds. A bucket contains 143 pounds of water. How many liters of water are in the bucket

Answers

Answer:

65 liters

Step-by-step explanation:

11/5=2.2

143/2.2=65

Find the greatest power of 3 that is divisible of 100!

Answers

Answer:

There is no greatest power of 3 that is divisible of 100.

Step-by-step explanation:

Since any number can always be divisible of 100, there would be no greatest power of 3 that is divisible of 100 since the powers can go on and on forever without stopping, and all powers of 3 is able to be divided by 100.

1. Which expression represents the
factored form of x2 - 13x + 36?
A (x - 4)(x - 9)
B (x - 3)(x - 12)
C (x + 9)x - 4)
D (x + 12)(x - 3)

Answers

Answer: Hello, There! your Answer is Below

A (x - 4)(x - 9)

Step-by-step explanation:

Find p, and q, knowing sum = b = 13 and product c = 36. Compose factor pairs of 36-> (2, 18)(2, 12)(4, 9). this last sum is 9 = b. Then p = 4 and q = 9

Hope this Helps you!!

Have a great day!!

The answer is choice A. The middle number, the one with the x, in this case 13, is what the factors should add up to. so, -4 plus -9 equals -13, which is our middle number. the last number, without the x, is what the numbers must multiply to, in this case 36. so, -4 times -9 equals positive 36. So, choice A is the answer.

20. A biologist studied the populations of geckos and salamanders at Huntington Beach State Park over
a five year period. The biologist modeled the populations, in thousands, with the following polynomials
where x is time, in years.
Geckos: 9.7 x 2 - 0.8x + 2.3
Salamanders: -1.1 x2 + 7.7 x + 5.4
Which of the following polynomials models the total number of geckos and salamanders at Huntington Beach State Park?

Answers

Answer: b

Step-by-step explanation:

There are risks associated with drinking potable water.


Please select the best answer from the choices provided

Answers

Answer:

Where are the choices? There is no choices

What is the value of x?

Answers

Answer:

value we donnot know so we try to find it by equations

Answer:

Any number of possibilities...

Step-by-step explanation:

In the diagram below, line MN is a perpendicular bisector. Which of the following is true?
1. MT=MN
2.MS=MN
3.MT=MS
4.MN=QN

Answers

Answer:

MT is congruent to MS

Step-by-step explanation:

Answer:

[tex]MT[/tex]≅[tex]MS[/tex]

Step-by-step explanation:

Because line MN is a perpendicular bisector, and point on the bisector will be equidistant from the end points of the segment it bisects.

Show all steps 2a=22

Answers

Answer:

Hello! answer: a = 11

Step-by-step explanation:

2 × 11 = 22 So therefore a = 11 HOPE THAT HELPS!

Complete the statement.
63 mi
mi
h
sec

Please answer ASAP worth 25 points

Answers

0.0175 mi/sec, that is the answer

Answer:

63miles/hour=63miles/[60×60]sec=

0.0175miles/sec

[tex]3/11 divided by 44[/tex]

Answers

Answer:

3/484

Step-by-step explanation:

3/11 ÷ 44

~Turn whole number into a fraction and use copy dot flip

3/11 ÷ 44/1

3/11 * 1/44

3/484

Best of Luck!

(√2)^3
[tex] (\sqrt{2) {?}^{3 \\} [/tex]

Answers

[tex]\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf[/tex]

[tex]\sf 2 ^1\cdot \:2^{\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Refine}}\\\\\\\\\boxed{\sf =2\sqrt{2}}[/tex]

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