Pumped up gym has a membership plan that charges $35 a month plus a one time initiation fee of $20. If Jeremy has spent $545 on his membership, how long has he been a member?

Answers

Answer 1

Answer:

15 months

Step-by-step explanation:

35x+20=545

Subtract 20 from both side to figure out how many months he paid for....

35x+20-20=545-20

35x=525

Divide 35 on both sides....

x=15

Therefore, he has been a member for 15 months

Check:

35(15)+20=545

525+20=545

545=545

IT'S CORRECT!!!

MARK ME BRAINLEST PLS THANKS :)


Related Questions

Evaluate the expression (1/4) {x(2y+3z)} when x=8, y=3, and z=2

Answers

Answer:

24

Step-by-step explanation:

x = 8, y = 3, z = 2

(1/4) x {8[2(3)+3(2)]}

(1/4) x {8(6 + 6)}

(1/4) x {48 + 48} (by distributing)

1/4 x 96

= 24

If c= 16, solve for b

Answers

Answer:

8√3

Step-by-step explanation:

cos30=b/16

equating:

√3/2=b/16

b=8√3

is this function linear or exponential?​

Answers

Answer:

This function is not linear.  

if x and y varies directly and x = 4 when y = 16. find y when x = 9?

Answers

9514 1404 393

Answer:

  36

Step-by-step explanation:

"Varies directly" means the relationship is proportional:

  y/9 = 16/4

  y = 9·16/4 = 36

The value of y is 36 when x = 9.

A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine cover is enlarged by a factor of 3. enlarged by a factor of One-third. reduced by a factor of 3. reduced by a factor of One-third.

Answers

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

Answer: D-reduced by a factor 1/3

Step-by-step explanation:

got it correct on edge 2021

5. Grace has $39 She has 8 less than her brother. How much
money does Grace's brother have?

Answers

Answer:

Grace's brother has $47.

He has $47. If you need me to explain then I will

3x+8-2(1-x)=1
What is the value of x

Answers

Answer:

3x+8-2+2x=1

5x=1-8+2

5x=-5

x=-5/5

x=-1

Answer:

7

Step-by-step explanation:

delta math help plz im stuck

Answers

Step-by-step explanation:

-70x^4 + 30x

= 10x(-7x^3 + 3)

ANSWER: 10x(-7x^3 + 3)

what is 1/2x + 8 < -4 ?

Answers

Answer:

-1/24 < x < 0

Step-by-step explanation:

1/2x + 8 must be less than -4 therefore x can only be x<-24

Which expression is equivalent to sqrt 2x^5/18 assume x is greater than or equal to 0

Answers

Answer:

  [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]   = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

Given expression

            [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]

we know that the algebra formula

[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]

[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]

          = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

HELP ME RIGHT NOW GRAND PRIZE IS 10 POINTS COME ON COME ON PLEASE SJNDINKOJDEWNIOEW
Solve the system of equations using the substitution method. Make sure to check your solution.

y = 3x + 2

-4x + 4y = 16

In the blanks below, type just the number for the x-coordinate in blank 1 and just the number for the y-coordinate in blank 2.

x-coordinate:
y-coordinate:

Answers

Answer: X = 1

Y= 5

Step-by-step explanation:

Plug in y = 3x + 2 in the Y coordinate to find X

-4x + 4(3x + 2) = 16

Now you can solve for X

X = 1

Then plug in 1 in the X coordinate to find Y

-4(1)+ 4y= 16

Now you can solve for Y

Y= 5

YOUR WELCOME

(What did Benjamin Franklin use to lighten the mood in Philadelphia where the Constitution was being written?)

Sense of humor.

Ice cream.

An air-cooling device he had invented.

Poetic readings.

Answers

Answer:

Ice cream

Step-by-step explanation:

During the 1787 convention in Philadelphia when the constitution was being formed by the founding fathers, their sessions would usually end in heated arguments and disagreements.

To calm the delegates after the draining sessions, Benjamin Franklin who was then mostly in his home and 81 years old at that time, came up with the idea of entertaining the delegates in his home with the cold cream. His idea was helpful in reducing tensions.

Answer:

An air cooling he has invented

Step-by-step explanation:

A store used to sell an MP3 for $72which is 50% more than the wholesale cost. At a special holiday sale, the price of the MP3 was 20% less than the wholesale cost. What was the special sale price of the MP3?

Answers

Answer:

$115.2

Step-by-step explanation:

Step one:

Given data

A store used to sell an MP3 for $72 and we are told that this 50% of the wholesale price.

Therefore the wholesale price is

72*2= $144

Required:

The special sales cost at 20% discount

Step two:

We are told that the special sale is at a 20% discount on the wholesale

= 20/100*144

=0.2*144

=$28.8

Therefore the special sales price is

= 144-28.8

=$115.2

22(10p - 79) if p = 9 and q = 2

Answers

Answer:

the anwser is 242

Step-by-step explanation:

I dont see a q anywhere but you would sub p and 9 and do the equation so times 10 and 9 and then distribute 22 or in your calculator jus enter 22(90-79) and you would get 242

6x + 57= 135 solve x​

Answers

Answer:

can't find answer sorry

The lines graphed below are perpendicular. The slope of the red line is
What is the slope of the green line?

Answers

Answer:

Is there a picture for this one and also you didn't mention the slope of the red line is?

Step-by-step explanation:

Answer:

The slope of the Green line should be the same as the red line- but a negative number instead of a positive.

Step-by-step explanation:

This is the inverse of the line

So by reflecting it over the y-axis, the slope remains the same but will change from positive to negative and vise versa

Mariah025 answer here please

Answers

Answer:

wht

!?

............

..............

..

.

2) 8(x - y); user-5, and y = 2

Answers

Answer:

8(x-y);use x=5,and y=2

8(5 - 2) = 8(3) = 24

answer

24

Step-by-step explanation:

good? Brainliest?

Anna wants to add compatible numbers to find the following sum. 27.95 + 19.37 + 34.05 + 21.63 Which pairs of numbers are compatible? Choose Yes or No for each pair. 27.95 and 34.05 Choose.. 27.95 and 21.63 Choose... 19.37 and 34.05 Choose... 19.37 and 21.63 Choose...​

Answers

Answer:

27.95 and 34.05 are compatible because when you add up the decimals, the equal 0, which makes it easier to add. 27. 95 + 34.05 = 61.00.

Same with 19.37 and 21.63, it adds up to 40.00

The answer to all of this would be 101.00

cousin needs help and im not allowed to help lol dp it for me thx

Answers

Answer:

s

Step-by-step explanation:

Peaches are being sold for $2 per pound.The customer created a model to represent the total cost of peaches bought. If x represents the number of pounds of peaches bought and y represents the total cost of the peaches, which best describes the values of x and y?

The values of both x and y can be any real number.
The values of both x and y will be real numbers greater than or equal to 0.
The value of x and y will always be zero
The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.

Answers

Answer:

B - The values of both x and y will be real numbers greater than or equal to 0.

The answer choice that best describes the values of x and y is B - The values of both x and y will be real numbers greater than or equal to 0.

Calculations and Parameters:

Given that peaches are being sold for $2 per lb.

If we define x as the number of pounds that you buy, and y as the cost of these peaches, we can write the function:

y = $2*x

Therefore, the best description of the values of x and y is found in option B. The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.

Read more about equations here:

https://brainly.com/question/17939759

#SPJ9

A company has two factories, factory A and factory B. The cost per item to produce q items in factory A is
200 + 3/q
q
. The cost per item to produce q items in factory B is
300 + q/
3q
. Find an expression for the sum of these costs per item. Then divide this expression by 2 to find an expression for the average cost per item to produce q items in each factory.

The average cost per item to produce q items in each factory is

Answers

Answer:

(700 + 51q)/4q

Step-by-step explanation:

Given costs:

(200 + 13q)/q and (300 + 25q)/2q

Sum of the costs:

(200 + 13q)/q + (300 + 25q/2q) =(400 + 26q)/2q + (300 + 25q)/2q =(700 + 51q)/2q

Average cost is sum divided by number:

(700 + 51q)/2q ÷ 2 = (700 + 51q)/4q

Integrate the integral:

[tex]\int \frac{1}{\sqrt{x} \sqrt{1-x} }[/tex]

Answers

Answer:

[tex]\displaystyle \int {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx = 2arcsin(\sqrt{x}) + C[/tex]

General Formulas and Concepts:

Calculus

U-SubstitutionIntegration Property: [tex]\int {cf(x)} \, dx = c\int {f(x)} \, dx[/tex]Arctrig Integration: [tex]\displaystyle \int\limits {\frac{1}{\sqrt{a^2-u^2} } } \, du = arcsin(\frac{u}{a} ) + C[/tex]

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int\limits {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx[/tex]

Step 2: Identify

Set up variables for u-substitution and integral trig.

[tex]\displaystyleu = \sqrt{x}\\a = 1\\du = \frac{1}{2\sqrt{x}}dx[/tex]

Step 3: integrate

Rewrite Integral:                                                                                           [tex]\displaystyle 2\int {\frac{1}{2\sqrt{x} \sqrt{1-x} } } \, dx[/tex][Integral] U-Substitution:                                                                              [tex]\displaystyle 2\int {\frac{du}{\sqrt{1^2-(\sqrt{x})^2 } }[/tex][Integral] U-Sub Arctrig:                                                                                [tex]\displaystyle 2\int {\frac{du}{\sqrt{1^2-u^2 } }[/tex][Integral] Arctrig:                                                                                           [tex]\displaystyle 2arcsin(\frac{u}{1}) + C[/tex]Simplify:                                                                                                         [tex]\displaystyle 2arcsin(u) + C[/tex]Back-substitute:                                                                                             [tex]\displaystyle 2arcsin(\sqrt{x} ) + C[/tex]

We are given the expression:                                                                              

[tex]\int\limits {\frac{1}{\sqrt[]{x} }*\frac{1}{\sqrt[]{ 1-x^{2}}} } \, dx[/tex]

U-substitution:                                                                                                      

let u = [tex]x^{1/2}[/tex]             [So, x = u²]

[tex]\frac{du}{dx} = \frac{1}{2\sqrt[]{x}}[/tex]                 [differentiating both sides wrt x]

dx = du*2√(x)

dx = 2u(du)            [Since u = √x]

Finding the Integral:                                                                                              

Plugging these values in the given expression:

[tex]\int\limits {u^{-1}*(1-u^{2})^{-1/2} } \, 2\sqrt[]{x}*du[/tex]

[tex]\int\limits {\frac{1}{u}*\frac{1}{\sqrt[]{ 1-u^{2}}}*2u } \, du[/tex]

The 'u' in the numerator and denominator will cancel out

[tex]\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}}*2 } \, du[/tex]

Since 2 is a constant

[tex]2\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}} } \, du[/tex]

Using the property: [tex]\int\limits {\frac{1}{\sqrt[]{1-x^{2}} }} \, dx[/tex] = ArcSin(x) + C

2*ArcSin(u) + C

Since u = √x :

2*ArcSin(√x) + C

6. Solve for the variable in the following proportion: 45 g = 5/1​

Answers

Answer:

g=9

Step-by-step explanation:

assuming you actually meant 45/g, then it would be 5g=45

2 w = 2p - 3z
a Find w when p = 8 and z = -2

Answers

Answer:

11

Step-by-step explanation:

2w = 2×8 - (-2×3)

2w = 16 - (-6)

2w = 22

w = 11

What is the slope of the line that passes through the following g points
(6,3) and (4,-2)

Answers

Answer:

2.5

Step-by-step explanation:

The slope of the line is; [tex]\frac{rise}{run}[/tex] and can be found using the formula;

[tex]\frac{y_{2} - y_{1}}{x_{2}-x_{1}}[/tex]

Given the points;

( 6, 3 ) and ( 4, -2)

Substitute the points in and solve;

[tex]\frac{(-2) - (3)}{(4) - (6)}[/tex]

[tex]\frac{-5}{-2}\\\\\frac{5}{2}\\\\= 2.5[/tex]

Need help with these

Answers

Answer:

3x

7-k

m/4

(5x)+12

Step-by-step explanation:

most of the words like and are just fillers. and basically means together in this instance

15. A county fair charges $9.50 to get in and $2.50 per ride ticket. What is the cost of entering the fair and buying 4 ride tickets? *​

Answers

Answer:

$19.50

Step-by-step explanation:

Multiply $2.50 by 4, which will give you $10.00.

Then, add $9.50 and $10 together, which gives you. a total of.

$19.50

Answer:

Hi,  The answer is

Step-by-step explanation:

Well all you have to do is multiply 2.50 by 4=10 and add 9.50. And it all equals 19.50$.

I REALLY hope this helps you!  :)

DESPERATE (please answer with picture of the graph)
WILL MARK BRAINLIST AND THANKS

Answers

Answer:

so the square root of 23 is 4.79583152331 but rounded is 4.8 so your right where  you need to be!

Step-by-step explanation:

Pleaze help me asap
And please no fake answers.

Answers

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}}[/tex] :

a = dk³ , b = dk² , c = dk

[tex] \underline{ \underline{ \text{To \: prove}}} : [/tex]

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd} = \sqrt{(a - b - c)(b - c - d)} } [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

Left hand side ( L.H.S ) :

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd}} [/tex]

⟶ [tex] \tt{ \sqrt{d {k}^{3} \cdot \: d {k}^{2} } - \sqrt{d {k}^{2} \cdot \: dk } - \sqrt{dk \cdot \: d} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} {k}^{5} } - \sqrt{ {d}^{2} {k}^{3} } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: {k}^{2} \cdot \: k } - \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: k \: } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} } \cdot \sqrt{ {k}^{2} } \cdot \: \sqrt{ {k}^{2} } \cdot \: \sqrt{k} } - \sqrt{ {d}^{2} }\cdot \: \sqrt{ {k}^{2}} \cdot \: \sqrt{k} \: - \sqrt{ {d}^{2} } \cdot \: \sqrt{k} [/tex]

⟶ [tex] \tt{d {k}^{2} \sqrt{k} - dk \sqrt{k} - d \sqrt{k} }[/tex]

⟶ [tex] \tt{ d\sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

Right Hand Side ( R.H.S) :

[tex] \tt{ \sqrt{(a - b - c)(b - c - d)}} [/tex]

⟶ [tex] \tt{ \sqrt{(d {k}^{3} - d {k}^{2} - dk)( d{k}^{2} - dk - d)} }[/tex]

⟶ [tex] \tt{ \sqrt{ \{dk( {k}^{2} - k - 1) \} \: \{d( {k}^{2} - k - 1) \}} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k( {k}^{2} - k - 1) ^{2} } } [/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k } \cdot \: \sqrt{ {( {k}^{2} - k - 1)}^{2} } } [/tex]

⟶[tex] \tt{ \sqrt{ {d}^{2} } \cdot \: \sqrt{k} \cdot \: \sqrt{( {k}^{2} - k - 1) ^{2} } }[/tex]

⟶ [tex] \tt{d \sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

L.H.S = R.H.S

Hence , Proved !

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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