Answer:
a. The final speed , v' when it returns is the same speed, u as when it was released. v' = u
b. The time of flight T equals twice the time taken to reach the highest point, t. T = 2t
Explanation:
(a) As long as you can neglect the effects of the air, if you throw anything vertically upward, it will have the same speed when it returns to the release point as when it was released.
Using v² = u² - 2gh, we find the maximum height the object reaches. With u = initial vertical velocity, v = velocity at maximum height = 0 m/s (since it momentarily stops), g = acceleration due to gravity and h = maximum height
So, v² = u² - 2gh
0² = u² - 2gh
0 = u² - 2gh
-u² = -2gh
h = -u²/-2g
h = u²/2g
On its return trip to the point where it is released, the distance covered is h and its initial velocity u' = 0
With v' as the final velocity, we use
v'² = u'² + 2gh
substituting the values of the variables into the equation, we have
v'² = 0² + 2g(u²/2g)
v'² = 0² + u²
v'² = u²
taking square-root of both sides, we have
√v'² = √u²
v' = u
So, the final speed , v' when it returns is the same speed u as when it was released. v' = u
(b) The time of flight will be twice the time it takes to get to its highest point.
At the highest point, its velocity is zero.
Using v = u - gt where u = initial velocity, v = final velocity(velocity at highest point) = 0 (since it is momentarily at rest), g = acceleration due to gravity and t = time taken to reach the highest point.
So, substituting the values of the variables into the equation, we have
v = u - gt
0 = u - gt
-u = -gt
t = u/g
On its return trip, since we know its final velocity = u and its initial velocity is 0 m/s, again, using
v' = u' + gt' where u' = initial velocity = 0 (since it is at its highest point), v' = final velocity = u (velocity on return to release point), g = acceleration due to gravity and t' = time taken to reach release point from highest point
So, substituting the values of the variables into the equation, we have
v' = u' + gt'
u = 0 + gt'
u = gt'
t' = u/g = t
So, the time of flight, T = time taken to reach highest point + time taken to return to release point
T = t + t'
T = u/g +u/g
T = 2u/g
T = 2t
So, the time of flight T equals twice the time taken to reach the highest point, t. T = 2t
11. (2 pts) A photon with energy 44.8 eV is absorbed by a hydrogen atom in its ground state, knocking the
electron out. What is the speed of the electron as it leaves?
Answer: 3.3·10^6 m/s
Explanation: Ionization energy of H is 13.6 eV. So the kinetic energy of electron is 31,2 eV. Kinetic Energy of Electron is E = ½mv^2
1 eV = 1.60·10^-19 J and m = 9.1·10^-31 kg. Solving speed v = √( 2E / m)
v = √(2·31.2·1.60·10^-19 J /9.1·10^-31 kg) = 3.3·10^6 m/s
A plane electromagnetic wave propagates in a vacuum in the z-direction. The wave has a wavelength of 10 m and the electric field is along the x direction and has an amplitude of is 0.20 V/m, with one maximum at x = 0 and t = 0. What is the mathematical expression for the magnetic field?
A. By = 0.067 × 10-8sin[(0.63 m-1)z - (2.1 × 10-9 s-1)t] T.
B. By = 0.067 × 10-8cos[(0.63 m-1)z + (1.9 × 108 s-1)t] T.
C. By = 0.067 × 10-8cos[(10 m-1)z - (2.1 × 10-9 s-1)t] T.
D. By = 0.067 × 10-8cos[(0.63 m-1)z - (1.9 × 10-8 s-1)t] T.
E. By = 0.067 × 10-8sin[(0.63 m-1)z + (2.1 × 10-9 s-1)t] T.
Answer:
B. By = 0.067 × 10-8cos[(0.63 m-1)z + (1.9 × 108 s-1)t] T.
Explanation:
Since the electric field has a maximum at x = 0 and t = 0, it is a cosine function and thus the magnetic field is also a cosine function.
Also, the electric field travels in the x - direction and the wave in the z-direction. Since the magnetic field is perpendicular to both directions, it must thus move in the y - direction.
So, By = B₀cos(kz - ωt). It has a negative sign since the wave is travelling in the positive z - direction.
Since c = E₀/B₀ where E₀ = amplitude of electric field = 0.20 V/m, B₀ = amplitude of magnetic field and c = speed of light = 3 × 10⁸ m/s
So, B₀ = E₀/c = 0.20 V/m ÷ 3 × 10⁸ m/s = 0.067 × 10⁻⁸ T
wave number, k = 2π/λ where λ = wavelength = 10 m. So, k = 2π/10 m = 6.28/10 m = 0.628 m⁻¹ ≅ 0.63 m⁻¹
angular frequency, ω = 2πf where f = frequency of wave = c/λ = 3 × 10⁸ m/s 10 m = 3 × 10⁷ s⁻¹. So, ω = 2πf = 2π(3 × 10⁷ s⁻¹) = 18.8 × 10⁷ s⁻¹ = 1.88 × 10⁸ s⁻¹ ≅ 1.9 × 10⁸ s⁻¹
Substituting the variables into By, we have
By = B₀cos(kz - ωt)
By = (0.067 × 10⁻⁸ T)cos[(0.63 m⁻¹)z - (1.9 × 10⁸ s⁻¹)t]
By = 0.067 × 10⁻⁸cos[(0.63 m⁻¹)z - (1.9 × 10⁸ s⁻¹)t] T
Since none of our options contain the given answer, we assume the wave moves in the negative z - direction. So, for that,
By = 0.067 × 10⁻⁸cos[(0.63 m⁻¹)z + (1.9 × 10⁸ s⁻¹)t] T
Answer:
D.
[tex]\mathbf{B_y = 0.067 \times 10^{-8} Cos \Big[ 0.6 3m^{-1} z - (1.9 \times 10^{-6} \ s^{-1})t \Big] T}[/tex]
Explanation:
From the given information:
Let us recall that the direction with which electromagnetic wave proceeds is usually along [tex]E^{ \to} \times B^{\to}[/tex]
Thus; the magnetic field is always along the y-direction.
In the magnetic field, the maximum value of the field is expressed by using the formula:
[tex]\dfrac{E}{C} = \dfrac{0.20 \ V/m}{3\times 110^8 \ m/s} \\ \\ = 0.067 \times 10^{-8} \ T[/tex]
Given that:
the maximum x is starting at 0, then, it implies that it is starting from the extreme position proceeding along +z direction.
As such; the general equation: [tex]y = A sin (\omega t - kz)[/tex]
Also:
[tex]K = \dfrac{2 \pi}{\lambda}[/tex]
where;
[tex]\lambda =10[/tex]
[tex]K = \dfrac{2 \pi}{10}[/tex]
K ≅ 0.63 m⁻¹
Thus;
[tex]\mathbf{B_y = 0.067 \times 10^{-8} Cos \Big[ 0.6 3m^{-1} z - (1.9 \times 10^{-6} \ s^{-1})t \Big] T}[/tex]
Which of the following best explains the greater difficulty in stopping a 1000-kg car
moving at 174 km/h compared to an identical 1000-kg car moving at 100 km/h?
Stopping a 1000 kg car moving at a speed of 174 km/h will be more difficult than stopping an identical car moving at 100 km/h.
This can be explained by using Newton's second law of motion which says that the rate of change of momentum of a body is equal to the force applied.
We know that momentum of a body is the product of its mass and velocity.The momentum of the car moving at 174 km/h = [tex]1000\, kg \times 174\, km/h = 174000 \, kg.km/h[/tex].The momentum of the car moving at 100 km/h = [tex]1000\, kg \times 100\, km/h=100000 kg.km/h[/tex].Therefore, the car moving at 174 km/h has higher momentum and from Newton's second law of motion, a higher force would be required to stop this car.
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If you lived on Saturn, which planets would exhibit retrograde motion like that observed for Mars from Earth? (Select all that apply.)
Mercury
Venus
Earth
Mars
Jupiter
Uranus
Neptune
Answer:
earth , mercury , and neptune
Explanation:
pls mark brainless
a solid cubic centimeter of platinum weighs 21.5 N. if this cube of platinum is placed under water, what volume of water is displaced? what weight of water is displaced? (Hints: 1 cm3 of water has a mass of 1 gram; 1 gram weighs 0.0098 N; density of platinum = 21.5 g/cm3.)
Answer:
Mp =Pp g where p = density of solid Platinum
Wp = Mp Pp g weight of mass M
Volume displaced is 1 cm^3
Weight of water = .0098 N since 1 cm^3 displaced
Or Ww = 1 cm^3 * .001 kg / cm^3 * 9.8 N/kg = .0098 N
Which model below describes the processes of Gamma radiation?
A
B.
C.
D.
Answer:
C
Explanation:
A 16.2-g bullet with an initial speed of 850 m/s embeds itself in a 40.0-kg block, which is attached to a horizontal spring with a force constant of 1000 N/m. What is the maximum compression of the spring
The maximum compression in the spring is 0.06883 meters.
Given to us,
mass of bullet, [tex]m= 16.2\ grams[/tex]
velocity of bullet, [tex]v= 850\ meter/second[/tex]
mass of the block, [tex]m_2= 40\ kilograms[/tex]
velocity of block, [tex]v_2= 0\ meter/second[/tex]
spring constant, [tex]k = 1000\ Newton/meter[/tex]
Combined mass after collision,
[tex]\begin{aligned}M&= m_1+m_2\\&= 40.0162\ Kilograms\end{aligned}[/tex]
Using the momentum conservation equation, to find out final velocity of the system(bullet and block combined)
[tex]m_1v_1+m_2v_2= MV\\[/tex]
[tex]0.0162\times 850+40\times 0 = 40.0162\times V\\V= 0.3441 meter/sec[/tex]
Now using the Conservation of Energy (Kinetic energy of the system will be equal to potential energy in the spring), to find out the displacement of the spring [tex](x)[/tex]
[tex]\frac{1}{2}kx^2 = \frac{1}{2}MV^2\\\\\frac{1}{2}\times 1000\times x^2= \frac{1}{2} \times40.0162\times0.3441^2\\\\x^2= 0.004738\\\\x= 0.06883\ meters[/tex]
Hence, the maximum compression in the spring is 0.06883 meters.
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otd-vbut-uao
Answer:
Weird
Explanation:
Tara kain tayo sardinas lang ulam
How are both electromagnetic and mechanical waves used when people communicate with each other?
THe Wilson cloud chamber is used to study the appearance of individual atoms?
Answer:
The Wilson cloud chamber is used to study the direction, speed, and distance of charged particles. Explanation; ... The Wilson cloud chamber works by producing a super-saturated vapor, as explained by florin.
Explanation:
I hope it's help u
180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?
Explanation:
Work done= MGH
180=m×10×3
180/30=m
m=6kg
You are exploring a small moon of a distant planet. Measurements indicate that this moon is a sphere of uniform density rho = 5000 kg/m3. You dig a very deep hole into the moon that reaches within r0 = 1000 m of the center of the moon. With your spacesuit, you have a mass of m = 85 kg. Find the force of gravity on you when you stand at the bottom of the hole.
Answer:
The force of gravity will be "0.11874 N"
Explanation:
The given values are:
Density of planet,
Q = 5000 Kg/m³
Inside radius,
r₀ = 1000 m
Now,
The mass of inside sphere will be:
⇒ [tex]m_p=density\times volume[/tex]
⇒ [tex]=5000\times \frac{4}{3}\pi r^3[/tex]
On putting the values, we get
⇒ [tex]=5000\times \frac{4}{3}\times \pi\times (1000)^3[/tex]
⇒ [tex]=85 \ kg[/tex]
hence,
The force of gravity will be:
= [tex]\frac{Gm_{planet} m_{person}}{r^2}[/tex]
= [tex]\frac{6.67\times 10^{-11}\times 5000\times 4\pi\times 85\times 1000}{3}[/tex]
= [tex]\frac{6.67\times 10^{-11}\times 4\pi\times 425000000}{3}[/tex]
= [tex]0.11874 \ N[/tex]
what electrical devices that belong to physiological effect?
Answer:
Most of us have experienced some form of electric “shock,” where electricity causes our body to experience pain or trauma. If we are fortunate, the extent of that experience is limited to tingles or jolts of pain from static electricity buildup discharging through our bodies.
When we are working around electric circuits capable of delivering high power to loads, electric shock becomes a much more serious issue, and pain is the least significant result of shock.
As electric current is conducted through a material, any opposition to the current (resistance) results in a dissipation of energy, usually in the form of heat. This is the most basic and easy-to-understand effect of electricity on living tissue: current makes it heat up. If the amount of heat generated is sufficient, the tissue may be burnt.
The effect is physiologically the same as damage caused by an open flame or other high-temperature source of heat, except that electricity has the ability to burn tissue well beneath the skin of a victim, even burning internal organs.
What unit is current measured in?
If 84 J of work are exerted to pull a wagon, how much force does it take to pull the wagon 7.0 m? Round your answer to the nearest whole number.
Answer: It takes 12 N of force to pull the wagon.
Explanation:
how to prepare a trading stock account
Answer:
Opening stock details of raw material, semi-finished goods and finished goods.
Closing stock details of raw material, semi-finished goods, and finished goods.
Total purchases of goods fewer Purchase Returns.
Total sales of goods fewer Sales Returns.
describe an experiment to show that air support burning
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.13 mm apart and position your screen 3.75 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 647 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
Explanation:
slit separation d = 1.13 x 10⁻³ m
screen distance D = 3.75 m
wavelength of light λ = 647 x 10⁻⁹ m
Distance of first bright fringe = fringe width = λ D / d
λ D / d = 647 x 10⁻⁹ x 3.75 m / 1.13 x 10⁻³ m
= 2.147 x 10⁻³ m
= 2.147 mm .
Distance of first bright fringe = 2.147 mm .
Distance of second dark fringe = 1.5 x fringe width
= 1.5 x 2.147 mm .
= 3.22 mm .
A balloon with a charge of 4.0 µC is held a distance of 0.70 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force. (Hint: µ is a metric prefix that means micro or 10 -6 so 4.0 µC means 4.0 microcoulombs
Answer:
Im sorry I do not know how to do this, I hope you will be able to figure it out
Explanation:
What drives waves?
Soda
Carbohydrates
Energy
A bicycle possesses 1000 units of momentum. what would be the bicycle's momentum if,
A.its velocity is doubled
B. its mass is tripled
Sources A and B emit long-range radio waves of wavelength 360 m, with the phase of the emission from A ahead of that from source B by 90°. The distance rA from A to a detector is greater than the corresponding distance rB from B by 130 m. What is the magnitude of the phase difference at the detector?
Answer:
[tex]X=165 \textdegree[/tex]
Explanation:
From the question we are told that:
Wavelength [tex]\lambda =360m[/tex]
Angle [tex]\theta=90 \textdegree[/tex]
Distance variation [tex]d=130m[/tex]
Generally the equation for phase difference X is mathematically given by
[tex]X=\theta+\frac{d}{\lambda}*100[/tex]
[tex]X=90+\frac{150}{360}*100[/tex]
[tex]X=165 \textdegree[/tex]
Therefore Phase difference X is given as
[tex]X=165 \textdegree[/tex]
What is the answer to question 4
In order to make it all the way from the opening to the detector, a wave has to travel through air, glass, water, plastic, and vacuum.
-- The siren and the tuning fork are sounds.
-- Sound cannot travel through vacuum.
-- That knocks out choices B, C, and D.
The answer is A.
Note: Making a big exception here. We don't do test questions on Brainly. That would be cheating. Don't let me catch you doing it again.
What is the light speed formula?
If ' c ' is the speed of light, then the formula for it is . . .
c = 299,792,458 meters per second
7
The periodic table displays
A.
only the important compounds that exist in the world.
OB.
all of the known compounds that exist in the world today.
C.
only the important elements that exist in the world.
D.
all of the known tements that exist in the world today.
Determine how would the frequency of the pendulum change if it was taken to the moon by finding the ratio of its frequency on the moon fM to its frequency on the earth fE. Suppose that gE is the free-fall acceleration on the earth and gM is the free-fall acceleration on the moon.
Express your answer in terms of some or all of the variables l, m, gE, gM.
fM/fE = ?
For the pendulum taken to the moon, The frequency change that would occur is mathematically given as
[tex]\frac{Fmoon}{Fearth}=0.408[/tex]
What frequency change would occur to the pendulum if it was taken to the moon?Generally, the equation for the Time period is mathematically given as
[tex]T=2\pi\sqrt{L/g}[/tex]
Therefore
[tex]\frac{Fmoon}{Fearth}=\frac{\sqrt{g/6L}}{\sqrt{g/6L}}\\\\\frac{Fmoon}{Fearth}=\sqrt{1/6}[/tex]
[tex]\frac{Fmoon}{Fearth}=0.408[/tex]
In conclusion, The frequency change
[tex]\frac{Fmoon}{Fearth}=0.408[/tex]
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Answer:
.408
Explanation:
when a light beam emerges from water into air, the average light speed ____.
a. increases
b. decreases
c. remains the same
d. not provided
Answer:
Increases
Explanation:
The light is emerging from a denser medium to rarer medium so the average light speed increases.
When a light beam emerges from water into air, the average light speed increases.
What is refraction?The bending of a ray passes at an angle from one medium to another in which the speed will be different, as when light passes from air into water and also from water into air can be known as refraction.
When light travels from water to air, the angle from water to air the light gets speeds up and then its changes direction. The light turns away from the normal line. Because the light moves from a denser medium to the rarer medium. But from air to water the speed will be decreased because in that case the light travels from the rarer medium to the denser medium.
Hence, the light beam when passes, the average speed gets increased.
So, Option A is the correct answer.
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the path of the earth around the sun is called
Answer:
Orbit.Explanation:
An orbit is a regular, repeating path that one object in space takes around another one, it's an imaginary path of the Earth around the Sun.
Bent over row trains what specific muscle?
O A. triceps
O B. trapezius
O C. latissimus dorsi
D. pectoralis major
QUICK RETURN MOTION IS USED IN a whAt
Answer:
A quick return motion mechanism is used in the shaper and slotter machine in which the circular motion is converted into reciprocating motion so that the slider moves forward and backwards. In the forward direction, the cutting process occurs while in return there is no such cutting.