Propane (C3H8) reacts with oxygen (O2) during a combustion reaction, producing carbon dioxide
(CO2) and water (H2O).
Which equation demonstrates the law of conservation of matter for this reaction?​

Answer:

ΔG°rxn = 28.4kJ/mol at 600K

Explanation:

Using Hess's law, you can find the ΔH°rxn and S°  subtracting ΔH°f of products - ΔH°f of reactants ×its coefficients. In the same way for S°rxn

For example, for the reaction:

aA + bB → cC:

ΔH°rxn = c×ΔH°fC - (a×ΔH°fA + b×ΔH°fB).

S°rxn = c×S°fC - (a×S°fA + b×S°fB).

For the reaction:

SO₂(g) + Cl₂(g) → SO₂Cl₂(g)

ΔH°rxn = 1×ΔH°f{SO₂Cl₂} - (1×ΔH°fSO₂ + 1×ΔH°fCl₂).

S°rxn = 1×S°f{SO₂Cl₂} - (1×S°fSO₂ + 1×S°fCl₂).

As at 298K:

ΔH°f{SO₂Cl₂} = -364.0kJ/mol

ΔH°f{SO₂} = -296.8kJ/mol

ΔH°f{Cl₂} = 0kJ/mol

ΔH°rxn = 1×{-364.4kJ/mol} - (1×-296.8kJ/mol + 1×0).

ΔH°rxn = -67.2kJ/mol at 298K.

S°f{SO₂Cl₂} = 311.9J/molK

S°f{SO₂} = 248.2J/molK

S°f{Cl₂} = 223.0J/molK

S°rxn = 1×{311.9J/molK} - (1×248.2J/molK + 1×223.0J/molK).

S°rxn = -159.3J/molK = -0.159.3KJ/molK

Using:

ΔG°rxn = ΔH°rxn - S°rxn×T

Assuming ΔH°rxn doesn't change at 600K:

ΔG°rxn = -67.2kJ/mol - -0.159.3J/molK×600K

Answer:

so mass in gram=560grams

Explanation:

number of moles=10moles

molar mass=56grams/moles

mass in gram of Fe=?

as we know that

[tex]number of moles=\frac{mass in gram}{molar mass}[/tex]

evaluating the formula

number of moles×molar mass=mass in gram

mass in gram=10moles×56grams/moles

mass in gram=560grams

i hope this will help you :)

Answer:

Its answer A

Explanation:

I just took the test

Answer:

A:

reduction half reaction: HNO3-> NO

oxidation half reaction S->H2SO4

Explanation:

Answer:

15 g

Explanation:

1. According to the Law of Conservation of Mass, the sum of the products should be 105 g because 70 g + 35 g = 105 g.

2. If 90g of solution was produced and there's supposed to be 105 g, then the remaining grams would be equal to the mass of the gas.

3. 105 g - 90g = 15 g

Hydrogen peroxide is one of the most common bleaching agents. It is the primary bleaching agent in the textile industry, and is also used in pulp, paper, and home laundry applications.

bleaching agent is a material that lightens or whitens a substrate through chemical reaction. The bleaching reactions usually involve oxidative or reductive processes that degrade color systems. These processes may involve the destruction or modification of chromophoric groups in the substrate as well as the degradation of color bodies into smaller, more soluble units that are more easily removed in the bleaching process. The most common bleaching agents generally fall into two categories: chlorine and its related compounds (such as sodium hypochlorite) and the peroxygen bleaching agents, such as hydrogen peroxide and sodium perborate. Reducing bleaches represent another category. Enzymes are a new category of bleaching agents. They are used for textile, paper, and pulp bleaching as well as for home laundering. Chlorine‐containing bleaching agents are the most cost‐effective bleaching agents known. They are also effective disinfectants, and water disinfection is often the largest use of many chlorine‐containing bleaching agents. They may be divided into four classes: chlorine, hypochlorites, N‐chloro compounds, and chlorine dioxide. Except to bleach wood pulp and flour, chlorine itself is rarely used as a bleaching agent. The principal form of hypochlorite produced is sodium hypochlorite. Other hypochlorites include calcium hypochlorite and bleach liquor, bleaching powder and tropical bleach. The principal solid chlorine bleaching agents are the chlorinated isocyanurates, eg, sodium dichloroisocyanurate dihydrate. Other N‐chloro compounds include halogenated hydantoins, and sodium N‐chlorobenzenesulfonamide (chloramine B). Chlorine dioxide is a gas that is more hazardous than chlorine. Large amounts for pulp bleaching are made by several processes in which sodium chlorate is reduced with chloride, methanol, or sulfur dioxide in highly acidic solutions by complex reactions. Hydrogen peroxide is one of the most common bleaching agents. It is the primary bleaching agent in the textile industry, and is also used in pulp, paper, and home laundry applications. Hydrogen peroxide reacts with many compounds, such as borates, carbonates, pyrophosphates, sulfates, etc, to give peroxy compounds or peroxyhydrates. Peracids have superior cold water bleaching capability versus hydrogen peroxide because of the greater electrophilicity of the peracid peroxygen moiety. Lower wash temperatures and phosphate reductions or bans in detergent systems account for the recent utilization and vast literature of peracids in textile bleaching. The reducing agents generally used in bleaching include sulfur dioxide, sulfurous acid, bisulfites, sulfites, hydrosulfite (dithionites), sodium sulfoxylate formaldehyde, and sodium borohydride. These materials are used mainly in pulp and textile bleaching.

Answer:

They conducted it from earth

Explanation:

There had never been anything capable of observing it from space launched at that time because Sputnik wasn't even launched

Answer:

Atomic particles

Explanation:

A scanning tunneling microscope is an instrument used to view any surfaces at the levels of an atom. It was invented in the nineteenth century.

Answer:

Explanation:

A )

molecular weight of KMnO₄ =   158

75 g KMnO4 = 75 / 158 moles

= ( 75 / 158 )x 6.02 x 10²³ molecules

= 2.857 x 10²³ molecules KMnO4

so 75g KMnO₄ = 2.857 x 10²³ molecules KMnO4

B )

7.23 × 10²⁴ Al atoms = grams Al

72.3 X 10²³ Al atoms = 72.3 X 10²³ / 6.02 X 10²³ moles of Al

= 12 moles of Al

= 12 x 27 gm of Al

= 324 gm of Al .

7.23 × 10²⁴ Al atoms = 324 grams Al

C )

9.23 × 10²³ Au atoms = moles Au

9.23 × 10²³Au atoms = 9.23 × 10²³ / 6.02 x 10²³ moles of Au

= 1.53 moles of Au .

D )

125 g H₃PO₄ =   molecules H₃PO₄

125 g H₃PO₄ = 125 / 98 moles of H₃PO₄

= (125 / 98) x 6.02 x 10²³ molecules

= 7.678 x 10²³ molecules of H₃PO₄

125 g H₃PO₄ = 7.678 x 10²³  molecules H₃PO₄

E )

.75 moles of CO₂

= .75  x 6.02 x 10²³ molecules of CO₂

= 4.515 x 10²³ molecules of CO₂.

one molecule of CO₂ = 3 atoms

4.515 x 10²³ molecules of CO₂ = 3 x 4.515 x 10²³ atoms

= 13.545 x 10²³ atoms .

The molecules, atoms, and weight of all elements and compounds has been calculated.

(A) To calculate the molecules of a compound:

Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]

Moles = [tex]\rm \frac{weight}{molecular\; weight}[/tex]

Moles of [tex]\rm KMnO_4[/tex] = [tex]\rm \frac{75}{158}[/tex]

Moles of [tex]\rm KMnO_4[/tex] = 0.474

Molecules of [tex]\rm KMnO_4[/tex] = [tex]\rm 0.474\;\times\;6.023\;\times\;10^2^3[/tex]

Molecules of [tex]\rm KMnO_4[/tex] = 2.85 [tex]\rm \times\;10^2^3[/tex]

(B) Weight of Al:

moles = [tex]\rm \frac{atoms}{avagadro\;number}[/tex]

Moles of Al = [tex]\rm \frac{7.23\;\times\;10^2^4}{6.023\;\times\;10^2^3}[/tex]

Moles of Al = 12

Weight of Al = [tex]\rm moles\;\times\;molecular\;weight[/tex]

Weight of Al = 12 [tex]\times[/tex] 27

Weight of Al = 324 grams

(C) Moles = [tex]\rm \frac{atoms}{avagadro\;number}[/tex]

Moles of Au = [tex]\rm \frac{9.23\;\times\;10^2^3}{6.023\;\times\;10^2^3}[/tex]

Moles of Au = 1.53 mol/liters

(D) Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]

Moles = [tex]\rm \frac{weight}{molecular\; weight}[/tex]

Moles of [tex]\rm H_3PO_4[/tex] = [tex]\rm \frac{125}{98}[/tex]

Moles of [tex]\rm H_3PO_4[/tex] = 1.275

Molecules of [tex]\rm H_3PO_4[/tex] = 1.275 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]

Molecules of [tex]\rm H_3PO_4[/tex] = [tex]\rm 7.678\;\times\;10^2^3[/tex]

(E) Atoms of [tex]\rm CO_2[/tex]:

Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]

Molecules of [tex]\rm CO_2[/tex] = 0.75 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]

Molecules of [tex]\rm CO_2[/tex] = 4.515 [tex]\rm \times\;10^2^3[/tex]

1 molecule of [tex]\rm CO_2[/tex] = 3 atoms

4.515 [tex]\rm \times\;10^2^3[/tex] molecules = [tex]\rm 4.515\;\times\;10^2^3\;\times\;3[/tex]

Atoms of [tex]\rm CO_2[/tex] = 13.545 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]

For more information about the dimensional analysis conversion, refer the link:

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Answer:

C

2and3

Explanation:

increase in temperature causes the particles to gain more energy

Answer:

The government allocates a budget for research every year. The spending of that money is determined by government priorities. Some of the money is spent directly, in government-funded research centers.

Other money is distributed to other research institutions.

Money spent by other institutions for research has no government oversight.

Explanation:

Answer:

voltage I'm just guessing

Answer:

Option A

Explanation:

Looking at the following formula:

I = V/R

Where V is voltage, I is current and R is resistance

In the above equation, Current and Voltage are in direct relationship such that if I is increased , V is also increased and vice versa. So, To increase the current, voltage should be increased.

Answer: 20 protons,20 electrons and 21 neutrons

Explanation: because the number of protons is the same as the atomic number, and if the atom is neutral it has the same number of protons and electrons. if the mass number is 41 it means that there are 21 neutrons because to find the mass number you have to add protons and neutrons, so 20 + 21 = 41 and to confirm it the neutrons have been subtracted from the mass number and the atomic number, so 41-20 = 21

Answer:

14.91 Joules

Explanation:

First you just plug stuff into the potential energy due to gravity equation [Potential Energy=acceleration due to gravity * Mass * Height].

PEg= (9.81m/s2)*(2kg)*(0.76 m) <<<<<<<<

(Just plug in all the values)

We get PEg= 14.91 Joules

Physics is pretty much just converting one unit to another, Joules are also known as (kg m2/s2)

Answer:

BE3N2

Explanation:

Answer:

A central C is double bonded to an O, and single bonded to 2 H

Explanation:

Methanal, also known as formaldehyde, is a chemical compound used to preserve dead biological specimens for further study. It is called formalin when in a solution and it helps keep specimens in a fresh state by hardening the tissues of the specimen involved.

Formaldehyde is a gaseous compound that has an aldehyde functional group i.e. -CHO and has a chemical formula, H-CHO or CH2O as described in the question that a central C is double bonded to an O, and single bonded to 2 H (see attached image for structural formula).

The chemical for the preservation of biological specimens has consisted of central C with a double-bonded O and two single-bonded hydrogens. Thus, option A is correct.

The biological compound that has been used to preserve biological specimens has been methanal. It has been the simplest aldehyde. The chemical formula of formaldehyde, also known as methanal has been H-CHO.

The structure of formaldehyde has been consisted with single bond between H and C. The central carbon has been associated with a double bond between the C and O, with single-bonded H.

Thus, the chemical for preservation of biological specimen has been consisted of central C with a double-bonded O and two single-bonded hydrogens. Thus, option A is correct.

For more information about the biological specimen, refer to the link:

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Answer:

The vinegar is not enough to neutralize the pool.

Explanation:

The [OH⁻] in the pool is 1.0x10⁻¹mol / L. To know how many moles of OH⁻ are in the solution, you must calculate volume of the pool thus:

V(pool) = πr²h

Where r, radius is d/2 = 12m/2 = 6m  and h is deep of the pool = 10m

V(pool) = π(6m)²*10

V(pool) = 1131m³

As 1m³ = 1000L:

1131m³  × (1000L / 1m³) = 1131000L in the pool.

And moles of OH⁻ are:

1.0x10⁻¹mol / L ₓ 1131000L = 131100 moles of OH⁻ are in the pool

The neutralization of OH⁻ with H⁺ is:

OH⁻ + H⁺ → H₂O

That means to neutralize the pool you must add 131100 moles of H⁺.

The H⁺ concentration in a vinegar pH = 2 is:

pH = -log [H⁺]

2 = -log [H⁺]

1x10⁻²M = [H⁺]

4L are just 4x10⁻² moles of [H⁺]. As you need 131100 moles of H⁺:

Answer:

B: Mechanical waves only.

Explanation:

'Mechanical waves require medium in order to transport their energy from one location to another.'

Hope this helps!

Answer:

Mechanical waves requires matter to carry enegry.

As mechanical waves are defined as the wave which requires any medium to transfer enegry from one place to another place.

so, the answer is Mechanical waves.

hope it helps..

Answer:

Things made of thermoplastics

1) Plastic chairs

2) Plastic table

3) Plastic cups and plates

4) Nylon bags

5) Plastic cabinet

6) PVC pipes-

7) Internal electronic component such as gears

8) Vehicle dashboard

Things made of Thermosetting plastics

1) Electrical insulation

2) Handles of electrical fittings

3) Plastic hoses

4) Electric switch covering

5) Coverings of electronic gadgets

6) Silicone in adhesives

7) Keyboard

Explanation:

A plastic polymer material that becomes soft upon heating and hard once again when cooled such that the material can be repeatedly or cyclically cooled and heated numerous times with its chemical and physical properties remaining constant is known as a thermoplastic.

A plastic, polymer or resin that is hardened from its soft or liquid state by curing irreversibly such that it cannot be made soft again without a change in its chemical properties is known as a thermosetting plastic.

Answer:

The Solar Nebula Theory accounts for the creation of solar systems, stars, and planets. The theory accounts for planet composition by stating that iron compounds, silicates, and dust clump together to form planetesimals. Because of the proximity of the sun, ices and gases cannot condensate near them, so they do not become gas giants. The planetesimals then collide together due to gravity and collect to form our rocky planets.

Explanation:

Answer:

volcanic eruption.

mark my answer as brainlest......

Answer:

Solution:

Explanation:

V1   =   3.00m3

T1   =    150kPa

V2  =   1.20m3

T2  =     x

As ,

    V1    =    V2

     T1            T2

    3.00  =  1.20

      150        X

3.00 x X  =  150 x  1.20

3.00X  =   180

X   =  180

         3.00

X  =  60 kPa

The final pressure can be calculated using Boyle's law. The final pressure of the gas if the volume is increased from 3 m³ to 1.20 m³ with an initial pressure of 150 kPa is obtained as 375 kPa.

Boyle's law states that at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas. Hence, volume decreases with increase in pressure and vice versa.

If P₁ and V₁ be the initial pressure and volume respectively and P₂, V₂ be their final quantities, then the relation between them can be written as:

P₁  V₁  =  P₂ V₂ .

It is given that the initial volume and pressure is  3 m³ and 150 kPa and the final volume is  1.20 m³ . Then, the final pressure is calculated as follows:

P₂ =  P₁  V₁ / V₂

   = (3 m³  ×  150 kPa) /  1.20 m³

   = 375 kPa

Hence, the final pressure of the gas will be 375 kPa.

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Answer:

sodium chloride is a component is a salt made of a metal Sodium and a non chlorine is a alone only and element and very less stable until bonded with them metal like a n, a, k or H

Answer:

C. Glass

Explanation:

Amorphous solids have a non-crystalline structure and no order. In that case, Diamonds, Graphite, and Iron all have a crystalline structure and order. You are left with C as your answer.

Answer:

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

Explanation:

The pressure is determined by the definition of stress, which is the force exerted by the buggy on the martian surface divided by the contact area of the latter:

[tex]\sigma = \frac{F}{A}[/tex]

Where:

[tex]\sigma[/tex] - Stress, measured in pascals.

[tex]F[/tex] - Force, measured in newtons.

[tex]A[/tex] - Area, measured in square meters.

The force is the weight of the buggy (40 N) and [tex]A = 0.025\,m^{2}[/tex], the stress is now calculated:

[tex]\sigma = \frac{40\,N}{0.025\,m^{2}}[/tex]

[tex]\sigma = 1600\,Pa[/tex]

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

Answer:

it digests food more slowly at lower temperatures

It digests food more slowly at lower temperatures.  

• Based on the given question, it can be stated that the cold blooded animal's surroundings determine the temperature of their body and as an outcome, they possess the tendency to eat food differently.  

• It can be said that the cold blooded animals like amphibians, reptiles, and fishes all digest food more gradually at the time of cold in comparison to warmer climates.  

Thus, a cold blooded animal's tendency to digest food varies in colder temperatures as they digests food more slowly at lower temperatures.

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Answer:

It is a eukaryotic cell because prokaryotes don't have a nucleus, rather, they have a nucleoid.

Answer: The equilibrium concentration of [tex]CH_4[/tex] , expressed in scientific notation is [tex]5.9\times 10^{-2}M[/tex]

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

                          [tex]CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)[/tex]

At eqm. conc.     (0.30) M     (0.10) M      (x) M   (0.020) M

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[CH_4]\times [H_2O]}{[CO]\times [H_2]^3}[/tex]

Now put all the given values in this expression, we get :

[tex]3.90=\frac{x\times (0.020)}{(0.30)\times (0.10)^3}[/tex]

By solving the term 'x', we get :

x = 0.059 M=  [tex]5.9\times 10^{-2}M[/tex]

Thus, the concentrations of [tex]CH_4[/tex] at equilibrium is :

Concentration of [tex]CH_4[/tex] = (x) M  = [tex]5.9\times 10^{-2}M[/tex]

The equilibrium concentration of [tex]CH_4[/tex] , expressed in scientific notation is [tex]5.9\times 10^{-2}M[/tex]

Answer:B

Explanation:B

Answer: the longest a virus that can be kept on a plastic bag is a few hours to a couple of days.

Explanation: hope that helped!(:

Answer:

B

Explanation:

Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J