Answer:
The force needed to lift a 500 newton-load is 125 newtons.
The mechanical advantage of the lever is 4.
Explanation:
Needed force is equal to the weight of the load. The Law of Lever, which is a particular case of the definition of Torque, states that force is inversely proportional to distance from fulcrum, that is:
[tex]F_{F} \cdot r_{F} = F_{L}\cdot r_{L}[/tex] (1)
Where:
[tex]F_{F}[/tex] - Needed force, in newtons.
[tex]r_{F}[/tex] - Force arm, in meters.
[tex]F_{L}[/tex] - Load force, in newtons.
[tex]r_{L}[/tex] - Load arm. in meters.
The mechanical advantage of the lever ([tex]n[/tex]), no unit, is determined by following formula:
[tex]n = \frac{F_{F}}{F_{L}}[/tex] (2)
If we know that [tex]F_{F} = 500\,N[/tex], [tex]r_{F} = 2\,m[/tex] and [tex]r_{L} = 8\,m[/tex], then the load force needed to lift is:
[tex]F_{L} = F_{F} \cdot \left(\frac{r_{F}}{r_{L}} \right)[/tex]
[tex]F_{L} = 125\,N[/tex]
The force needed to lift a 500 newton-load is 125 newtons.
And the mechanical advantage of the lever is:
[tex]n = 4[/tex]
The mechanical advantage of the lever is 4.
In addition to being good problem solvers, which of the following do engineers need to be?
O wealthy
O rigid
O respected
O practical
Question 1: What is the power observed in the energy analyzer when the rated voltage(U1) is applied to the primary of the transformer, and there is no load at the secondary?
Question 2: Find the transformation ratio of the transformer using the values U1,U2 recorded in the experiment.
Question 3: Sketch the no-load operation graph of the transformer using the values U1, I2 and the values read in the energy analyzer.
Question 4: How can we find the number of turns of transformer?
Question 5: Explain the operation principle of the transformer.
Question 6: State your final observations about the experiment.
Answer:
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