Answer:
For Year Ended 2013
(in thousands)
Cash flow From Operations BLANK
Net Income 792,000
Add:
Depression Expense 300,000
Amortization expense 12,000
Less:
Gain on Sale of Investments
Accounts receivable (net) -180,000
Inventory 18,000
Accountable Payable Answer 60,000
Cash Flow From Operations 1,002,000
Cash Flow for Investing
Marketable securities -240,000
Long-term investments 96,000
Purchase of property and equipment -1,380,000
Sale of Property and Equipment 280,000
Cash Flow for Investing -1,244,000
Cash From Financing
Short-term bank debt 228,000
Common stock + additional paid in capital 96,000
Dividends Paid 8,000
Cash From Financing 332,000
Decrease in Cash 90,000
Cash, beginning of year 18,000
Cash, end of year 108,000
108,000
0
Step-by-step explanation:
Assets
Current
Cash $18,000 $108,000
Marketable securities 240,000
Accounts receivable (net) 708,000 528,000
Inventory 720,000 738,000
Total current assets 1,686,000 1,374,000
Noncurrent
Long-term investments 372,000 468,000
Property & equipment 2,160,000 1,320,000
Less: Accumulated depreciation -600,000 -600,000
Property & equipment (net) 1,560,000 720,000
Intangibles (net) 114,000 126,000
Total noncurrent assets 2,046,000 1,314,000
Total assets $3,732,000 $2,688,000
Liabilities & Shareholders' Equity
Accounts payable $1,080,000 $1,020,000
Short-term bank debt 228,000
Total liabilities 1,308,000 1,020,000
Shareholders' equity
Common stock, $10 par value 930,000 810,000
Additional paid-in-capital 456,000 360,000
Retained earnings 1,038,000 498,000
Total shareholders' equity 2,424,000 1,668,000
Total liabilities & shareholders' equity $3,732,000 $2,688,000
AMPHLETT CORPORATION
Consolidated Income Statement
For Year Ended ($ thousands) 2013 2012
Revenues $1,716,000 $1,440,000
Less: Cost of goods sold 600,000 504,000
Gross margin 1,116,000 936,000
Less: Selling, general & administrative expenses 180,000 144,000
Operating income 936,000 792,000
Gain on sale of investments 84,000
Net income before taxes 852,000 792,000
Less: Income taxes 60,000 13,200
Net income after taxes $792,000 $778,800
For Year Ended 2013
(in thousands)
Cash flow From Operations BLANK
Net Income 792,000
Add:
Depression Expense 300,000
Amortization expense 12,000
Less:
Gain on Sale of Investments
Accounts receivable (net) -180,000
Inventory 18,000
Accountable Payable Answer 60,000
Cash Flow From Operations 1,002,000
Cash Flow for Investing
Marketable securities -240,000
Long-term investments 96,000
Purchase of property and equipment -1,380,000
Sale of Property and Equipment 280,000
Cash Flow for Investing -1,244,000
Cash From Financing
Short-term bank debt 228,000
Common stock + additional paid in capital 96,000
Dividends Paid 8,000
Cash From Financing 332,000
Decrease in Cash 90,000
Cash, beginning of year 18,000
Cash, end of year 108,000
108,000
0
Help plz I’ll mark brainliest
Answer:
you're answer is definitely d
You've decided to give your best friend a
bag of marbles for his birthday.
Since you know that your friend likes
green marbles better than red ones, the
bag has twice as many green marbles as
red.
The label on the bag says it contains a
total of 84 marbles.
How many green marbles are in the bag?
Number of green marbles in the bag is equals to [tex]56.[/tex]
What is number?
" Number is defined as the count of any given quantity as per condition."
According to the question,
Given,
Total number of marbles [tex]= 84[/tex]
[tex]'x'[/tex] represents the number of red marbles
As per given condition,
[tex]'2x'[/tex] represents the number of green marbles
Required equation we have,
[tex]x + 2x = 84\\\\\implies 3x =84\\\\\implies x = \frac{84}{3} \\\\\implies x = 28[/tex]
Substitute the value of [tex]'x'[/tex] to get number of green marbles ,
Number of green marbles [tex]2x = 2\times 28[/tex]
[tex]= 56[/tex]
Hence, number of green marbles in the bag is equals to [tex]56.[/tex]
Learn more about number here
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Which polynomial represents the sum below? (-x^3 + 3x^2 + 3) + (3x^2 + x + 4)
Answer:
Cddd
Step-by-step explanation:
A giant panda lives in the Washington, DC zoo. What does the point shown tell you about the panda?
Answer:
he is 36 months old or 3 years old, and he ways 82 kilograms.
Step-by-step explanation:
quick mafs
The point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.
How to read the data from the graph?In a graph, the line which is horizontal is known as the x-axis of the graph. The vertical line in the graph is called the y-axis of it. These axis helps to read the data from graph in following way-
The value of a point parallel to x axis in graph gives the value x-value. It is the value of parameter which is titled on x-axis.The value of a point parallel to y axis in graph gives the value y-value. It is the value of parameter which is titled on y-axis.In the given graph, the x-axis is labeled with age in months and y-axis is labeled with weight of panda.
The point with coordinates (36,82) tells that the age of panda is 36 months and the weight of the panda is 82 kilograms.
Hence, the point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.
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Select the correct answer.
The equation of a line is y = -3x – 2. What are the slope and the y-intercept of the line?
A.
slope = -3 and y-intercept = 2
B.
slope = 3 and y-intercept = -2
C.
slope = 3 and y-intercept = 2
D.
slope = -3 and y-intercept = -2
Answer:
The answer is D slope = -3 y-intercept = -2
Step-by-step explanation:
Answer
D.
Step-by-step explanation:
The first part of the equation is -3 and the second part is -2. The number attached to the variable is the "slope" and the number coming after the variable is the y intercept.
please help if you are good at math :( thank you
Answer:
your answer will be
A)(6,10)
B)(2,12)
C)(4,4)
Step-by-step explanation:
hope this helps
have a nice day/night ^_^
What is the area of this circle? Use 3.14 for π
Question 7 options:
530.66 cm squared
81.64 cm squared
2122.64 cm squared
849.56 cm squared
Answer:
530.66 cm squared
Step-by-step Explanation:
Diameter of the circle = 26 cm
Radius of the circle (r) = 26/2 = 13 cm
[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]
Answer:
The area of 530.66 cm squared.
Option (a) 530.66 cm² is the correct answer.
Step-by-step explanation:
Given :
Diameter of circle = 26 cm.To Find :
Radius of circle Area of circleUsing Formulas :
[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]
R = Radius D = Diameter[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]
π = 3.14 r = radiusSolution :
Finding the radius of circle by substituting the values in the formula :
[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]
[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]
[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]
[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]
[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]
Hence, the radius of circle is 13 cm.
[tex]\rule{200}2[/tex]
Now, finding the area of circle by substituting the values in the formula :
[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]
[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]
[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]
Hence, the area of circle is 530.66 cm².
[tex]\rule{300}{1.5}[/tex]
PleSee help!!! 10 points for it
Answer:
ben birşey anlamadım sorundan
HOW DO YOU FIND PERCENT INCREASE
Answer:
Step-by-step explanation:
First: work out the difference (decrease) between the two numbers you are comparing.
Decrease = Original Number - New Number
Then: divide the decrease by the original number and multiply the answer by 100.
% Decrease = Decrease ÷ Original Number × 100
If your answer is a negative number, then this is a percentage increase
detrmine if 7, 5, 84, 48 are in proportion or not
Answer:
No, the numbers are not in proportionStep-by-step explanation:
The proportion between the first two and the second two numbers are:
7/5 and 84/48Simplifying the second fraction:
84/48 = 7*12/4*12 = 7/4Comparing the fractions:
7/5 ≠ 7/4The answer is no
4/5 - 2/3 =
Find equivalent fractions and rewrite the problem and solve
Answer:
1001/1500
Step-by-step explanation:
The easiest method for doing this is to just average the two numbers.
e.g. to find a number x between the two numbers ab and cd
x=12[ab+cd]
=12[adbd+bcbd]
=ad+bc2bd
In this case…
x=(2×5)+(3×4)2×2×5=10+1230=2230=1115
You can easily see where that came from.
23=1015 and 45=1215
and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11
But you can also say…
23=100150 and 45=120150
and choose any of 101150,102150,...,119150
or
23=10001500 and 45=12001500
and choose any of 10011500,10021500,...,11991500
Answer:4/5 and 2/3 each have a common bottom of 15 so 4/5 is
12/15 and 2/3 will be 10/15
Step-by-step explanation:So than 12/15 forget the bottom don't subtract the bottom just look at it like [12-10] then you got 2 then you go back to the bottom and put it together so your answer is [2/15]
Find the range of the data in the box plot below.
cokies
Number of cookies eaten
by each contestant
Answer:
20 cookies
Step-by-step explanation:
Range of a data set plotted on a box plot = the maximum value - the minimum value
The maximum value is indicated by the whisker to your extreme right = 25
The minimum value is indicated by the whisker to your extreme left = 5
Range = 25 - 5 = 20
Let X be a normal random variable with mean 3 and variance 4. (a) Find the probability P(2 < X < 6). (b) Find the value c such that P(X > c) = 0.33. (c) Find E[X2 ]. Hint: You can integrate with the density function, but it is quicker to relate E[X2 ] to the mean and variance.
Answer:
a) the probability of (2 < X < 6) is 0.6247
b) the value of c is 3.878
c) the value of E[ x² ] is 13
Step-by-step explanation:
Given that;
mean μ = 3
variance = 4
standard deviation s = √variance = √4 = 2
(a) Find the probability P(2 < X < 6)
P(2 < X < 6) = p( (x - μ / s ) < z < (x - μ / s ) )
= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )
= p( -0.5 < z < 1.5)
from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085
so
P(2 < X < 6) = 0.9332 - 0.3085 = 0.6247
Therefore, the probability of (2 < X < 6) is 0.6247
b) Find the value c such that P(X > c) = 0.33
with p-value = 0.33, the corresponding z -score to the right is 0.439
we know that;
z = x - μ / s
we substitute
0.439 = x - 3 / 2
x - 3 = 2 × 0.439
x - 3 = 0.878
x = 0.878 + 3
x = 3.878
Therefore, the value of c is 3.878
c) Find E[ x² ].
Variance = E[ x² ] - [ mean ]²
E[ x² ] = Variance + [ mean ]²
we substitute
E[ x² ] = 4 + [ 3 ]²
E[ x² ] = 4 + 9
E[ x² ] = 13
Therefore, the value of E[ x² ] is 13
The distribution follows a normal distribution.
[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]The value of c is 3.878The value of [tex]\mathbf{E(x^2) }[/tex] is 13The given parameters are:
[tex]\mathbf{\mu = 3}[/tex] --- mean
[tex]\mathbf{\sigma^2= 4}[/tex] --- variance
(a) P(2 < x < 6)
Start by calculating the standard deviation
[tex]\mathbf{\sigma = \sqrt{\sigma^2}}[/tex]
This gives
[tex]\mathbf{\sigma = \sqrt{4}}[/tex]
[tex]\mathbf{\sigma =2}[/tex]
Calculate the z-scores for x = 2 and 6
[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]
So, we have:
[tex]\mathbf{z = \frac{2 - 3}{2} = -0.5}[/tex]
[tex]\mathbf{z = \frac{6 - 3}{2} = 1.5}[/tex]
So, the probability becomes
[tex]\mathbf{P(2 < x < 6) = P(-0.5 < z < 1.5)}[/tex]
Using z table of probabilities, we have:
[tex]\mathbf{P(2 < x < 6) =0.9332 - 0.3085}[/tex]
[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]
(b) Calculate c if P(X > c) = 0.33
Start by calculating the z-score for p-value = 0.33
From the z table, z = 0.439 when p-value = 0.33
Recall that:
[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]
So, we have:
[tex]\mathbf{0.439 = \frac{x - 3}{2}}[/tex]
Multiply both sides by 2
[tex]\mathbf{0.878= x - 3}[/tex]
Add 3 to both sides
[tex]\mathbf{3.878= x}[/tex]
Rewrite as:
[tex]\mathbf{x = 3.878}[/tex]
Replace x with c
[tex]\mathbf{c = 3.878}[/tex]
The value of c is 3.878
(c) Calculate E[x²]
The variance of a dataset is:
[tex]\mathbf{\sigma^2 =E(x^2) - \mu^2}[/tex]
Substitute known values
[tex]\mathbf{4 =E(x^2) - 3^2}[/tex]
[tex]\mathbf{4 =E(x^2) - 9}[/tex]
Add 9 to both sides
[tex]\mathbf{13 =E(x^2) }[/tex]
Rewrite as:
[tex]\mathbf{E(x^2) = 13 }[/tex]
Hence, the value of [tex]\mathbf{E(x^2) }[/tex] is 13
Read more about normal random variables at:
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Estimate the product of 3.8 and 11.9 rounding.
Answer:
48
Step-by-step explanation:
round off 3.8 to 4 and 11.9 to 12 and multiply the values
3/4(1/6x+16)=3/7(4 3/8x-21) I WILL AWORD BRILLENEST :>
Answer:
x=12
Step-by-step explanation:
Let's solve your equation step-by-step.
34(16x+16)=37((438)(x)−21)
Step 1: Simplify both sides of the equation.
18x+12=158x−9
Step 2: Subtract 15/8x from both sides.
18x+12−158x=158x−9−158x
−74x+12=−9
Step 3: Subtract 12 from both sides.
−74x+12−12=−9−12
−74x=−21
Step 4: Multiply both sides by 4/(-7).
(4−7)*(−74x)=(4−7)*(−21)
x=12
Answer:
x=12
Answer:
x = 12
Step-by-step explanation:
34(16x + 16) = 37((438)(x) − 21)
18x + 12 = 158x − 9
18x + 12 − 158x = 158x − 9 − 158x
−74x + 12 = −9
−74x + 12 −12 = −9 −12
−74x = −21
(4−7) × (−74x) = (4−7) × (−21)
x = 12
ASAP!! Find the length of side x in simplest form with a rational denominator
Answer:
[tex]x=\sqrt{14}[/tex]
Step-by-step explanation:
This triangle is a 45-45-90 triangle.
By using the image I posted, we can find x easily.
So, we have [tex]\sqrt{7}[/tex] as one of the sides.
They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]
Simplify and we get x = [tex]\sqrt{14}[/tex]
Last week, the Bay City Bus Company tracked how long their school buses took to complete their routes. This box plot shows the results. Length of route (min.) 24 26 28 30 32 34 What percent of the buses completed their routes in 27 to 30 minutes?
Answer:
See Explanation
Step-by-step explanation:
Given
[tex]Plot: \{24, 26, 28, 30, 32, 34\}[/tex]
Required
Determine the percentage of those who uses the bus for 27 to 30 mins
The box plot is not given. So, I will make assumptions in order to solve this question.
Assume the following readings from the box plot:
[tex]Total\ Buses= 60[/tex]
[tex]27-30\ Minutes = 20\ buses[/tex]
Using these assumptions, the required percentage is:
Total = 6
27 to 30 minutes = 2
[tex]Percent = \frac{27\ to\ 30\ mins}{Total} * 100\%[/tex]
[tex]Percent = \frac{20}{60} * 100\%[/tex]
[tex]Percent = \frac{2000}{60} * \%[/tex]
[tex]Percent = 33.33 * \%[/tex]
Answer:
50%
Step-by-step explanation:
I took the test!
What is the y-intercept of the equation of the line that is perpendicular to the line and passes through the point (15,-5)?
Answer:
hi
Step-by-step explanation:
First of all let’s find out the slope of the line y = x +10
As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1
Now, we know that the product of two perpendicular lines is -1.
Thus, mn = -1 (considering slope of the second line as n)
Putting the value of m we get , n = -1
Now , y+5= -1( x -15) i.e y=-x + 10
if we compare again with the general equation then we find that.
The y intercept of the required equation is 10.
Thank You
Answer:
10
Step-by-step explanation:
First of all let’s find out the slope of the line y = x +10
As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1
Now, we know that the product of two perpendicular lines is -1.
Thus, mn = -1 (considering slope of the second line as n)
Putting the value of m we get , n = -1
Now , y+5= -1( x -15) i.e y=-x + 10
if we compare again with the general equation then we find that.
The y intercept of the required equation is 10.
Thank You
MY
2B =
Cou
Round your answer to the nearest hundredth.
SA
A
MY
Pro
9
Pro
Tea
B
5
Answer:
<B = 56.25°
Step-by-step explanation:
Reference angle = B
Hypotenuse = AB = 9
Adjacent = BC = 5
Applying trigonometric ratio:
[tex] cos (B) = \frac{adj}{hyp} [/tex]
[tex] cos (B) = \frac{5}{9} [/tex]
[tex] B = cos^{-1}(\frac{5}{9}) [/tex]
B = 56.25° (nearest hundredth)
Cab A charges $20 at the start and $5 every mile after . Cab B charges $30 no matter how far you go. What are their initial values and their rates of change? When will their fares be equal?
Answer:
Car A: Initial Charge = 20
Car B: Initial Charge = 30
Car A: Rate = 5
Car B: Rate = 0
At 2 miles, their charges will be the same
Step-by-step explanation:
Given
Car A
[tex]Base\ Charge = \$20[/tex]
[tex]Rate = \$5[/tex] per mile
Car B
[tex]Base\ Charge = \$30[/tex]
Solving (a): The initial charge
First, we get the linear equation that represents both car's charges.
Represent number of miles with m.
So, the charges is:
Car A
[tex]A = Base\ Charge + Rate * m[/tex]
[tex]A = 20 + 5 * m[/tex]
[tex]A = 20 + 5m[/tex]
Set m to 0 to get the initial charge:
[tex]A = 20 + 5*0[/tex]
[tex]A=20[/tex]
and
[tex]Rate = 5[/tex]
Car B:
[tex]B = Base\ Charge + 0 * m[/tex] i.e. Rate is 0
[tex]B = 30+ 0 * m[/tex]
[tex]B = 30[/tex]
So:
[tex]Initial = 30[/tex] and [tex]Rate = 0[/tex]
Solving (b): When their charge wil be equal.
To do this, we set:
[tex]A = B[/tex]
[tex]20 + 5m = 30[/tex]
[tex]5m = 30- 20[/tex]
[tex]5m = 10[/tex]
[tex]m = 2[/tex]
At 2 miles, their charges will be equal
Help ASAP please!
The question is attached
Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?
a box contains 24 balls , some of which are red, some of which are green , and the rest are blue . the probabilities of drawing a red ball and a green ball at random from the box are 1\3 and 1\6 respectively . find the number of blue balls in the bag.
Step-by-step explanation:
I think it's 15 but I'm not sure
hacmin birimi ...... ve ......dır
Answer:
?
Step-by-step explanation:
don't get your question
jojo makes 100 working eight hours. Trish earned 25 working one hour. How much more money does Trish make than Jojo after 10 hours?
Answer:
Jojo makes 1000 and Trish makes 250
Step-by-step explanation:
I hope this helped
Answer:
Trish makes $125 more than Jojo after 10 hours
Step-by-step explanation:
$125 jojo
$250 Trish
Find the solutions to x2 = 18.
O A.
- +32
B. X = +63
O c. X = +376
O D. X = +2/3
Answer:
what in the math equations is this???
Step-by-step explanation:
HELP PLS ASAP!!!
these figures are congruent. What series of transformations moves quadrilateral FGHI onto quadrilateral F’G’H’I’?
Answer:
D
Step-by-step explanation:
It must first translate 1 unit to the left because quadrilateral F'G'H'I is one unit away from to y axis. It can then translate across the y-axis.
Answer:
ITS B!
Step-by-step explanation:
Ape x!
A bag of candies contains 5 red candies, 7 purple candies, and 3 green candies. What is the probability that a candy picked
at random is green?
Answer:
P(E) = 1/3
Step-by-step explanation:
Given that,
Red candies = 5
Purple candies = 7
Green candies = 3
We need to find the probability that a candy picked at random is green.
The probability of getting an event is given by :
P(E) = favorable outcomes/total no of outcomes
Probability of getting a green candy,
P(E) = 5/(5+7+3)
P(E) = 5/15
P(E) = 1/3
Hence, the required probability is (1/3).
write the equation of the image y=x^2 after vertically stretched by a factor of 2 and horizontally shifted 3 units to the left
Answer:
2=3^2?????
Step-by-step explanation:
y=x^2
(3,2)
substitute
2=3^2
pls help me math its due today
Answer:
For multiplication you added the exponents and for division you minus the exponents
Answer:
kdkdjdduidddsisiodiod
Simplify the following monomials 1-12
Answer:
1. [tex]x^{8}[/tex]
2. [tex]k^{45[/tex]
3. [tex]m^{6}n^{21}[/tex]
4. [tex]64w^{18}[/tex]
5. [tex]81y^{12}[/tex]
6. [tex]16x^{4}[/tex]
7. [tex]-125y^{9}[/tex]
8. [tex]a^{36}b^{4}[/tex]
9. [tex]\frac{1}{128} x^{28}[/tex]
10. [tex]54a^{6}[/tex]
11. [tex]8k^{10}[/tex]
12. [tex]-\frac{16}{9} p^{24}[/tex]
Step-by-step explanation: