WILL GIVE BRAINLIEST!!!
Which of the following conditions remain constant in Boyle's law?
Volume and pressure
Density and temperature
Pressure and number of moles
Temperature and number of moles
Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.
Explanation:
Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.
Mathematically, it is represented as follows.
[tex]P \propto \frac{1}{V}[/tex]
As equation for ideal gas is as follows.
PV = nRT
And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.
Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.
Answer:
Temperature and number of moles
Explanation:
Benzaldehyde and benzyl alcohol can be distinguished by NMR. The proton on the aldehyde group will appear at approximately _____ ppm; the methylene peak on the alcohol is the only peak ______ ppm for either compound.
Answer:
9-10 ppm.
0.2-0.4 ppm.
Explanation:
The proton on the aldehyde group will appear at approximately 9-10 ppm whereas the methylene peak on the alcohol is the only peak 0.2-0.4 ppm for either compound. Aldehydes and aromatics are quite distinctive in the Nuclear magnetic resonance (NMR). Aldehydes show up from 9-10 ppm, usually as a small singlet; aromatic protons show up from 6.5-8.5 ppm. NMR spectroscopy is the use of NMR to study the physical, chemical, and biological properties of matter.
A 10.00 mL sample of a solution containing formic acid (a weak acid) was placed in a 25 mL volumetric flask and diluted to the mark with water. A 10.00 mL sample of the diluted formic acid solution was then titrated with 0.1322 M sodium hydroxide. The titration required 15.80 mL of sodium hydroxide to reach the equivalence point. Calculate the molarity and the percentage (by mass) formic acid in the original solution. The density of the formic acid solution was found to be 1.02 g/mL.
Answer:
Molarity: 0.522M
Percentage by mass: 2.36 (w/w) %
Explanation:
Formic acid, HCOOH reacts with NaOH as follows:
HCOOH + NaOH → NaCOOH + H₂O
To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:
Moles NaOH = Moles HCOOH:
0.01580L * (0.1322mol / L) =0.002089 moles HCOOH
Moles in the original solution:
0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH
Molarity of the solution:
0.005222 moles HCOOH / 0.01000L =
0.522MMass HCOOH in 1L -Molar mass: 46.03g/mol-
0.522moles * (46.03g / mol) = 24.04g HCOOH
Mass solution:
1L = 1000mL * (1.02g / mL) = 1020g solution
Mass percent:
24.04g HCOOH / 1020g solution * 100
2.36 (w/w) %
28. If the total pressure of a mixture of four gases (neon, carbon dioxide, oxygen and hydrogen) is 1245 mm
Hg, what is the pressure of neon gas if the pressure of carbon dioxide is 145 mm Hg, the pressure of hydrogen is
499 mm Hg and the pressure of oxygen is 228 mm Hg?
A) 601 mm Hg
B) 746 mm Hg
C) 872 mm Hg
D) 373 mm Hg
Answer:
D) 373 mm Hg.
Explanation:
We can solve this problem by keeping in mind Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:
Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm HgNe Pressure = 373 mm HgThe answer is option D) 373 mm Hg.
Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.
Answer:
The total energy absorbed is 32.171 kilojoules.
Explanation:
The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:
[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)
Where:
[tex]m[/tex] - Mass of the ice, in kilograms.
[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.
[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.
[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.
[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.
[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.
[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.
[tex]Q[/tex] - Total energy absorbed, in kilojoules.
If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:
[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]
The total energy absorbed is 32.171 kilojoules.
In a thermonuclear device, the pressure of 0.050 liters of gas within the bomb casing reaches 458000 atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion
Answer:
22900 L
Explanation:
Assuming the gas behaves ideally, we can solve this problem by using Boyle's law, which states that:
P₁V₁=P₂V₂Where subscript 1 refers to the initial conditions of pressure and volume (within the bomb, namely), while 2 refers to the final conditions.
Meaning that in this case:
P₁ = 458000 atmV₁ = 0.050 LP₂ = 1.00 atmV₂ = ?We input the data:
458000 atm * 0.050 L = 1.00 atm * V₂And solve for V₂:
V₂ = 22900 Lhelp please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?
A 201kpa
B 200kpa
C 400kpa
D 78kpa
Answer:
A. 201 kPa
Explanation:
We can solve this problem by using Boyle's law, which states:
P₁T₂ = P₂T₁Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:
P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 KWe input the data:
125 kPa * 487 K = P₂ * 303 KAnd solve for P₂:
P₂ = 201 kPaTo prepare 250mL of calcium chloride solution with a molar concentration of 1.20mol/L, what mass of calcium chloride would be required?
Answer:
33.30 grams of CaCl2 will be required
Explanation:
Given,
Volume of solution, V= 250 ml
Molarity of solution, M= 1.20 mol/L
Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111
We know,
Required mass, W= SVM/1000
Now,
W = (111 X 250 X 1.20)/1000
= 33300/1000
= 33.30
Therefore, 33.30 grams of Calcium Chloride will be required.
1. How many moles of hydrogen are needed to completely react with two moles of nitrogen?
_N2 + _H2 -->_NH3
Please hurry it is for a big assignment
N2 + 3H2 --> 2NH3
Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.
Explanation:
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to its final temperature is 200 J/K. What is the final temperature of the gas
Answer:
668.9K is the final temperature
Explanation:
The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:
ΔS = n*Cv*ln (T2/T1)
Where ΔS is change in entropy = 200J/K
n are moles = 20.0mol
Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)
T2 is final Temperature and T1 initial temperature = 300K
Replacing:
ΔS = n*Cv*ln (T2/T1)
200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)
0.80186 = ln (T2/300K)
2.23 = T2 / 300K
668.9K is the final temperatureEqual molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for CaY2- is 5.0 x 1010 and the fraction of unprotonated EDTA (Y4-) is 0.35 at pH10. Calculate the concentration of free Ca2 in this solution.
Answer:
the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
Explanation:
Given the data in the question;
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
Formation constant Kf
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰
Now,
[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35
so the equilibrium is;
[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄ [tex]CaY^{2-[/tex] + 4H⁺
Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] { 1 mol [tex]Ca^{2+[/tex] reacts with 1 mol [tex]H_4Y[/tex] }
so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x
∴
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
x + x 0.010-x
since Kf is high, them x will be small so, 0.010-x is approximately 0.010
so;
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ 0.010 / ( [x][ 0.35 × x] ) = 5.0 × 10¹⁰
⇒ 0.010 / 0.35x² = 5.0 × 10¹⁰
⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 5.7142857 × 10⁻¹³
⇒ x = √(5.7142857 × 10⁻¹³)
⇒ x = 7.559 × 10⁻⁷
Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
What is the [OH-] of a solution with a pH of 1.4?
Answer:
If a solution has pH=8 , then its pOH is 14−8=6 and the corresponding concentration of hydroxyl OH− ions is 10−6 mol per litre.
Explanation:
Identify the specific element that corresponds to each of the following electron configuration 1s2, 2s2, 2p6,3s2, 3p6
Explanation:
It's argon
As argon has atomic number 18 so it's configuration is
1s2, 2s2, 2p6,3s2, 3p6
Hope it will help :)❤
The given electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
Each number and letter in the electron configuration corresponds to a specific electron orbital and the number of electrons present in that orbital.
In this case, the electron configuration indicates that:
The first shell (n=1) has 2 electrons in the 1s orbital.
The second shell (n=2) has 2 electrons in the 2s orbital and 6 electrons in the 2p orbital.
The third shell (n=3) has 2 electrons in the 3s orbital and 6 electrons in the 3p orbital.
By adding up the total number of electrons (2 + 2 + 6 + 2 + 6), we find that the configuration represents 18 electrons. The element that has 18 electrons is argon, which has an atomic number of 18.
Therefore, the electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
Know more about argon:
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Question 1
3 pts
TI
Which part(s) of the following ground state electron configuration holds the valence
electrons?
At
o
1s22s22p63523p4
ОЗр
03s
O2s
O 35 and 3p
Answer:
3s and 3p
Explanation:
From the question given above, the following data were obtained:
Electronic configuration =>
1s² 2s²2p⁶ 3s²3p⁴
Location of valence electron =?
From the electronic configuration given above, we can see clearly that the atom has three (3) shells.
Valence electron(s) are located at the outer most shell of an atom.
The outer most shell of the atom above is 3s and 3p.
Therefore, 3s and 3p will contain the valence electron(s)
Select all of the abiotic factors in an ecosystem.
Plants
Sunlight
Soil
Animals
Rocks
Dead deer in the forest
Temperature
Answer:
Sunlight, Soil, Rocks, Temperature and dead deer
Explanation:
You could say the dead tree is now an abiotic factor because biotic factors refer to living things
b. Calculate the empirical formula of a formula unit with the following percent compositions: 59.7%
lithium (Li) and 40.3% nitrogen (N). Complete the table to help with the calculations. (5 points)
Given
Li - 59.7 %
N - 40.3 %
Solution,
First get the molar mass of each Atom,
Li- 6.941
N- 14.00
Second find the moles of both atom,
moles of Li = 59.7/6.941 = 8.60
Moles of N = 40.3/14 = 2.87
Third devide both the moles with smaller mole,
first- 8.6÷2.87 = 2.99 ~ 3
second 2.87÷2.87 = 1
Ratio of Li to N is 3:1
The compound is Li3N.
Write the Ksp expression for the sparingly soluble compound cobalt(II) sulfide, CoS. If either the numerator or denominator is 1, please enter 1.
Answer:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write the chemical equation for this reaction as shown below:
[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]
Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Regards!
Using what you know about the structures of the amino acid side chains and the mechanisms presented in this chapter, which of the following amino acid side chain may play the following roles in an enzymatic mechanism: a. participate in proton transfer, b. act as a nucleophile
Answer:
a. participate in proton transfer - His
b. acts as a nucleophile - Ser
Explanation:
Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.
Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.
Answer:
HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER
As the temperature increases from 0°C to 25°C the amount of NH3 that can be dissolved in 100 grams of water.
A) decreases by 10 grams
B) decreases by 40 grams
C) increases by 10 grams
D) increases by 40 grams
Answer:
decreases by 10 gram
Explanation:
What is the hydrogen ion concentration of a solution with a pH of 2.0?
Answer:
[H+] = 10^-2
Explanation:
pH = -log[H+]
2 = -log[H+]
[H+] = 10^-2
True or False
Low temperatures lead to faster dissolution rates compared to high temperatures
Answer:
false
Explanation:
this is because , high temperature speeds up the the random motion of particles which leads to high dissolution
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
Answer:
[tex]V_2=600mL[/tex]
Explanation:
Hello there!
In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:
[tex]V_2M_2=V_1M_1[/tex]
Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:
[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]
Regards!
Oh no! I dash (lose) my purse
Answer:
Ok
Explanation:
If g of chlorine gas occupies a volume of mL at a particular temperature and pressure, what volume will g of chlorine gas occupy under the same conditions
The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?
Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
Explanation:
Given: [tex]Mass_1[/tex] = 1.04 g, [tex]V_{1}[/tex] = 872 mL
[tex]Mass_2[/tex] = 2.08 g, [tex]V_{2}[/tex] = ?
As molar mass of chlorine is 35.5 g/mol.
Number of moles is the mass of a substance divided by its molar mass.
Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]
Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.
[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]
Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]
Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
The total number of sodium atoms in 46.0 grams of sodium
is
Is nuclear energy good or bad?
Answer:
It is bad
Explanation:
Is nuclear energy good or bad?
Water potential is the potential energy for water to move from one area to another. Water
always moves from a high water potential area to a lower water potential area. According
to the water potential formula, which factors affect the water potential?
a) Pressure and the amount of solute
b) Volume and temperature
c) Surface area and depth
d) Speed and concentration
Answer:
A
Explanation:
The water potential depends upon the pressure and amount of solute according to the water potential formula.
The following points can be considered:
The water potential formula defines as the summation of the solute potential, pressure component, gravimetric component, potential due to humidity, potential due to matrix effects, and the reference correction. The water potential does not depend on the volume and temperature of the system. The water potential does not depend on the surface area and depth of the system. The water potential does not depend on the speed and concentration of the system.Therefore, the correct answer is a) pressure and the amount of solute.
Learn more about water potential:
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Write an equation for sodium chloride and sodium oxide
Answer:
Explanation:
The Chemical Equation for each one of these compounds would be the following
Sodium Chloride: NaCl
This compound contains 1 Sodium atom and 1 Chlorine atom
Sodium Oxide: Na₂O
This compound contains 2 Sodium atoms and 1 Oxygen atom.
What are anti-oxidants? Why are they added to fat and oil containing food?
Answer:
A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.