Answer:
0.1082M of Barium Hydroxide
Explanation:
KHP reacts with Ba(OH)2 as follows:
2KHP + Ba(OH)2 → 2H2O + Ba²⁺ + 2K⁺ + 2P²⁻
Where 2 moles of KHP reacts per mole of barium hydroxide
To solve this question we must find the moles of KHP in 1.37g. With these moles and the reaction we can find the moles of Ba(OH)2 and its molarity using the volume of the solution (31.0mL = 0.0310L) as follows:
Moles KHP -Molar mass: 204.22g/mol-
1.37g * (1mol / 204.22g) = 0.006708 moles KHP
Moles Ba(OH)2:
0.006708 moles KHP * (1mol Ba(OH)2 / 2mol KHP) =
0.003354 moles Ba(OH)2
Molarity:
0.003354 moles Ba(OH)2 / 0.0310L =
0.1082M of Barium Hydroxide[H3O+] = 3.6 x 10-2 M
Answer:
om pH
The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH) Example: What is the hydronium ion concentration in a solution that has a pH of 8.34?
Explanation:
What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Hg2 concentration is 7.36E-4 M and the Al3 concentration is 1.05 M
Answer:
Explanation:
Concentration of Hg⁺² = 7.36 x 10⁻⁴ M
Concentration of Al⁺³ = 1.05 M
2Al + 3Hg⁺² = 2Al⁺³ + 3Hg .
E = E₀ + RT / nF ln [ Al⁺³]² / [ Hg⁺² ]³
E₀ = reduction potential of Hg⁺² minus reduction potential of Al⁺³
= 0.92 V - ( - 1.66 V )
= 2.58 V
E = 2.58 + .059 /n log [ Al⁺³]² / [ Hg⁺² ]³
n = 6 , [Al⁺³] = 1.05 M ; [Hg⁺²] = 7.36 x 10⁻⁴ M
E = 2.58 + .059 /6 log [ 1.05]² / [ 7.36 x 10⁻⁴ ]³
= 2.58 + .059 /6 log 27.65 x 10⁸ .
= 2.58 + .059 /6 [8+ log 27.65 ].
= 2.58 + .059 /6 [8+ log 27.65 ].
= 2.58 + .09
= 2.67 V .
Small amount of acid is added to Water during electrolysis of water . Why?
Answer:
Water doesn't have ions that are needed to pass the electricity so in order to increase the no of ions we poor acid into the water. Just increasing the no ions will increase the electricity flow faster
In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is obtained for liquids when the resulting solution is ideal. For real solutions we introduced activities and activity coefficients. Derive the molar Gibbs energy of mixing and the molar excess Gibbs energy of mixing in terms of activity coefficients.
Answer:
Attached below
Explanation:
Free energy of mixing = ΔGmix = Gf - Gi
attached below is the required derivation of the
a) Molar Gibbs energy of mixing
ΔGmix = Gf - Gi
hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )
b) molar excess Gibbs energy of mixing
Ni = chemical potential of gas
fi = Fugacity
N°i = Chemical potential of gas when Fugacity = 1
ΔG = RT In ( a2 / a1 )
I need help with this question...
Find the molarity of a solution in which 0.99 mol of NaCl are dissolved in 2.5 L of solution.
Answer:
0.369M
Explanation:
[tex]\boxed{Molarity = mole \div volume}[/tex]
☆ Volume has to be in litres
Molarity of solution
= 0.99 ÷2.5
= 0.369 M
Atoms bond by ______ electrons.
O gaining
O sharing
O losing
O all of the above
4. A student poured 50 cm^3
water into a beaker and
measured the water's
temperature. The student added
1.00 g calcium chloride to the
water, stirred the mixture and
then recorded the temperature.
The concentration of a calcium
chloride solution is 12 g/dm^3.
Calculate the volume of this
solution, in cm^3, that contains
9.0 g of calcium chloride.
Answer:
V = 750 cm³
Explanation:
The volume of the solution can be calculated by the following formula:
[tex]V = \frac{M}{C}[/tex]
where,
V = Volume of solution = ?
M = Mass of Calcium Chloride = 9 g
C = Concentration of Solution = 12 g/dm³
Therefore,
[tex]V = \frac{9\ g}{12\ g/dm^3}\\\\V = (0.75 dm^3)(\frac{1000\ cm^3}{1\ dm^3})[/tex]
V = 750 cm³
Why does a ball eventually stop bouncing? Write a three- four sentence explaination
Answer:
The ball will stop bouncing because where the starting point of the ball dropping is the most potential energy it will have. The energy decrease will cause it to bounce lower and lower by each bounce. The ball's lowered energy will cause it to stop bouncing.
example of stains remover in chemistry
Bi-phosphate detergents
Hypochlorous
Spilled oil is considered a pollutant. Why is this so? Describe some way of cleaning oil after a spill
Answer: use methods to clean up ocean oil spills
Explanation:
In a nuclear fission reaction, a freely moving neutron is introduced to a
nuclear fuel, such as uranium-235. What happens next?
O A. A neutron is absorbed by an atom's nucleus.
B. The neutron breaks apart.
O C. Heat is released by the neutron.
D. The nucleus becomes unstable.
The nucleus becomes unstable when a freely moving neutron is introduced to a nuclear fuel.
What is Nuclear fission?This is a reaction in which the nucleus of an atom splits into two or more smaller nuclei.
This reaction produces more neutrons and the nucleus becomes unstable when a freely moving neutron is introduced to a nuclear fuel to form fission fragments.
Read more about Nuclear fission here https://brainly.com/question/3992688
#SP2
Which statement is correct about the rate of a chemical reaction? (5 points)
a. It increases when the concentration of reactants increases.
b. It does not depend on the concentration of reactants.
c. It increases when the temperature decreases.
: d. It does not depend on the temperature.
Answer:
they don't depend on the temperature
What is an extinction event
The moon phase takes about a year to complete.....True or false?
Answer:
the answer is false and the reason why is because every 29 days it completes one full cycle
Explanation:
Half equations for oxidation of HCL
Explanation:
The other half of the equation involves the hydrogen ions (initially bonded to the chloride ion in the hydrochloric acid). The hydrogen ions gain the electrons lost by the zinc atom, and bond together to form hydrogen gas. Since the hydrogen ions gain electrons, it is a reduction reaction.
_ S8 +_02 +_ SO3
How many grams of sulfur are needed to produce 167.82 grams of sulfur trioxide?
6.547 g sulfur
4302 g sulfur
67.22 g sulfur
537.7 g sulfur
9)
Which solution will have the highest concentration of solute particles?
A) 0.50 M NaCl
B) 1,00 M CaCl2
C) 2.00 M sodium ions
D) 2.50 M C6H1206
Answer: The answer is B) 1.00 M CaCl2
Explanation: I just did it on usatestprep and it said it was correct .
These steps are followed when using the half-life of carbon-14 to determine
the age of an object that contains carbon. What is the correct order of these
steps?
A. Use the half-life of carbon-14 to determine the number of half-lives
that have passed.
B. Use the number of half-lives that have passed to determine the age
of the object.
C. Measure the ratio of parent and daughter nuclei.
A. B, C, A
B. C, A, B
O C. A,B,C
OD. A,C,B.
Answer:
B. C, A, B
Explanation:
We can measure the age of an artifact by comparison of the activities a living sample with that of the artifact. This is so because the activity of the living sample represents the original activity of the artifact.
So, the steps involved in determining the age of an artifact is to measure the ratio of the parent and daughter nuclei. Then we use the half life of carbon to find out how many half lives have passed. Using this number of half lives that has passed, we can compute the age of the object.
Answer: B.A.C
Explanation:
(b) C.H.(g) + O2(g)
CO2(g) + H2O(g) balance ?
The complete question is: [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex] balance?
Answer: [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex]
Here, number of atoms on reactant side are as follows.
C = 1H = 4O = 4Number of atoms on product side are as follows.
C = 1H = 2O = 3To balance this equation multiply [tex]O_{2}[/tex] by 2 on reactant side and multiply [tex]H_{2}O[/tex] by 2 on product side. Hence, the equation can be re-written as follows.
[tex]CH_{4}(g) + 2O_{2} \rightleftharpoons CO_{2}(g) + 2H_{2}O(g)[/tex]
Here, number of atoms on reactant side are as follows.
C = 1H = 4O = 4Number of atoms on product side are as follows.
C = 1H = 4O = 4Since, there are same number of atoms on both reactant and product side. So, this equation is a balanced equation.
Thus, we can conclude that [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.
Answer ASAP Pls don't use links
Questions:
Answer the following on your answer sheet.
1. What will happen if you use a triangle with a steeper inclination?
2. What will happen if the triangle has a less steep inclination?
3. How will the new and old screws be compared?
Answer:
3 The Shank and the Threads
A gas occupies 400.0 mL at 20.00 C and 70.00 kPa. What will the pressure be at 40.00 C and 200.0 mL ?
Answer: The new pressure is 280 kPa.
Explanation:
Given: [tex]V_{1}[/tex] = 400.0 mL, [tex]T_{1} = 20^{o}C[/tex] , [tex]P_{1}[/tex] = 70.0 kPa
[tex]V_{2}[/tex] = 200.0 mL, [tex]T_{2} = 40.0^{o}C[/tex], [tex]P_{2}[/tex] = ?
Now, combined gas law is used to calculate the new pressure as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{70.0 kPa \times 400.0 mL}{20^{o}C} = \frac{P_{2} \times 200.0 mL}{40.0^{o}C}\\P_{2} = 280 kPa[/tex]
Thus, we can conclude that the new pressure is 280 kPa.
A block of metal has a mass of 18.361kg and the following dimensions: 22.35 cm x 7.34 cm x 22.05 mm. What is the density of the metal in g/cm^3
Answer:
50.76 g/cm³
Explanation:
We'll begin by converting 18.361 Kg to g. This can be obtained as follow:
1 Kg = 1000 g
Therefore,
18.361 Kg = 18.361 Kg × 1000 g / 1 Kg
18.361 Kg = 18361 g
Next, we shall express the dimension in the same unit of measurement.
Dimension = 22.35 cm x 7.34 cm x 22.05 mm
Thus, we shall convert 22.05 mm to cm. This can be obtained as follow:
10 mm = 1 cm
Therefore,
22.05 mm = 22.05 mm × 1 cm / 10 mm
22.05 mm = 2.205 cm
Thus, the dimension is 22.35 cm x 7.34 cm x 2.205 cm.
Next, we shall determine the volume of the metal. This can be obtained as follow:
Dimension = 22.35 cm x 7.34 cm x 2.205 cm.
Volume = 361.728045 cm³
Finally, we shall determine the density of the metal. This can be obtained as follow:
Mass of metal = 18361 g
Volume of metal = 361.728045 cm³
Density of metal =?
Density = mass / volume
Density of metal = 18361 / 361.728045
Density of metal = 50.76 g/cm³
Which of the living things in the pond system uses the energy from sunlight
to make its own food?
A:water lily
B:insect
C:frog
D:small fish
A. water lily
It is a plant. Plants are autotrophs. They make their own food.
Answer:
i am not sure with the answer.
but i think it will be water lily Or insects
How many calcium ions are in 0.9 mol of CaCl2?
× 10 Ca2+ ions Enter your answer in scientific notation.
Answer: There are [tex]5.42 \times 10^{23}[/tex] [tex]Ca^{2+}[/tex] ions present in 0.9 mol of [tex]CaCl_{2}[/tex].
Explanation:
According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole of a substance.
As here, 0.9 mol of [tex]CaCl_{2}[/tex] are present. Also, there is only one atom of Ca is present in a molecule of [tex]CaCl_{2}[/tex].
Hence, calcium ions present in 0.9 mol of [tex]CaCl_{2}[/tex] are calculated as follows.
[tex]No. of ions = 1 \times 0.9 \times 6.022 \times 10^{23}\\= 5.42 \times 10^{23}[/tex]
Thus, we can conclude that there are [tex]5.42 \times 10^{23}[/tex] [tex]Ca^{2+}[/tex] ions present in 0.9 mol of [tex]CaCl_{2}[/tex].
Consider the following chemical reaction:
4 Al(s) + 3 O2(g) ⟶2 Al2O3(s)
If 4.2 grams of Al reacts with 3.0 grams of O2,
1. How many grams of Al2O3 could be produced?
2. Which reactant is limiting?
3. Which reactant is excess?
4. How much of the excess reactant would remain?
Answer:
1. mAl₂O₃ = 6.42 g
2. O₂
3. Al.
4. mAl = 1.67 g
Explanation:
Let's calculate the moles of Al and O2 first before doing any other calculations. The molecular weights of Al and O are 26.98 g/mol and 16 g/mol, so the moles are:
moles = mass / Atomic weight or molar mass
moles Al = 4.2 / 26.98 = 0.156 moles
moles O2 = 3 / (2*16) = 0.094 moles
The molar mass of Al2O3 is:
MM = (2 * 26.98) + (3*16) = 101.96 g/mol
With these data, let's determine each part:
1, 2 and 3. Grams of Al2O3, limiting and excess reactant:
To do this, we need to know which is the limiting reactant. this reactant will tell us how many moles are produced of Al2O3 and then, with the previously calculated molar mass, we can determine its mass. Let's see again the overall reaction taking place:
4Al + 3O₂ ---------> 2Al₂O₃
According to this reaction, 4 moles of Al reacts with 3 moles of oxygen, so:
If: 4 moles Al ---------> 3 moles O₂
Then: 0.156 moles ----------> X
X = 0.156 * 3/4 = 0.117 moles of O₂ required.
However, we do not have 0.117 moles of O₂, we have 0.094 moles, therefore we can conclude that the oxygen is the limiting reactant and Aluminum is the excess reactant.
Now, the moles produced of Al₂O₃ will be:
3 moles O₂ -------> 2 moles Al₂O₃
0.094 moles -------> Y
Y = 0.094 * 2/3 = 0.063 moles of Al₂O₃
Finally the mass would be:
mAl₂O₃ = 0.063 * 101.96
mAl₂O₃ = 6.42 g4. mass of excess reactant:
The mass of excess reactant would be:
moles Al = 0.156 - 0.094 = 0.062 moles
mAl = 0.062 * 26.98
mAl = 1.67 gHope this helps
Which of the following is an electrolyte?
CH4OH
O Ca(NO3)2
O C12H22011
O CH3CH2OH
Answer:
B. Ca(NO3)2
Explanation:
edg 2022
Answer:
b
Explanation:
What are the uses of the metal Magnesium?
Answer:
use of sterile injections for clearanti bodies
Explanation:
Answer:
Hello There!!
Explanation:
They can be used in making products that make it lightweight such as in power tools and luggages.
hope this helps,have a great day!!
~Pinky~
Consider the unbalanced reaction Ti(s) + Cl2(g) --> TiCl4(s). When 4.21 g of Ti react with 15.4 g of Cl2, 16.2 g of CCl4 are obtained. The theoretical yield of TiCl4 is ___, the limiting reactant is ____ and the percent yield is ____.
Answer:
Theoretical yield: 16.68g Limiting reactant: Ti %yield=97.12%
Explanation:
Balanced reaction : Ti(s) +2 Cl2 (g) -> TiCl4(s)
g of substance = # of mole x molar mass
# of mole= g of substance/molar mass
%yield= actual yield x100/ theoretical yield
Ti is limiting reactant since it has the smallest amount of moles- 0.08795 causing it to run out first
identify a biological problem in your community and describe how you will use the scientific method to solve it
Answer:
There is a pawpaw here that is not producing any fruit.. so I will take a pollen grains from another pawpaw and pollinate it..